We need to keep the discussion on the list. When I run your code, there are
several problems.
strain.data <- read.xlsx("Dee rhiz.xlsx", sheetName ="strain", header = T,
row.names = 1)
str(strain.data) # lists 9 columns at the end with all NAs
strain.data1 <- (strain.data, sqrt.dist = TRUE) #
Better to post on the mixed models list, r-sig-mixed-models rather than here.
And post in plain text,not html.
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comi
Not really the correct mailing list. Please read the Posting Guide and
re-submit a plain text version to R-SIG-mixed-models
https://stat.ethz.ch/mailman/listinfo/r-sig-mixed-models
-- David.
> On Jul 18, 2017, at 3:43 PM, Ahreum Maeng wrote:
>
> Hello,
>
> I am trying to run the following mo
Hello,
I am trying to run the following model:
domi ~ type*ratio+((1|id)+(0+type|id)+(1|face_id)+(1|car_id))
My question is whether the data coding for "face_id" and "car_id" variables
is correct.
As you see on the following sample data structure, "type" is repeated
measure where 1=car, 0=face.
Hi all,
I am trying to analyse a time series data and want to make trend-season
decomposition using STL approach in R. However I found the decomposition
result seems to be sensitive to data points even with the robust option.
More specifically, suppose I have a few years of monthly data. Using st
On Tue, 18 Jul 2017 22:35:17 +0530
Christofer Bogaso wrote:
> Thanks for your pointer.
>
> Is there any way in R how to replace " ' " with " /' "
> programmatically?
>
Hi,
perhaps you should simply read the content of a corresponding text
file? There's a simple way using the readr package. Us
Hello,
I have a netcdf file for summer monsoon rainfall gridded data over Indian
region. How can I find the linear trend in R?
regards
Sourabh Bal
Dr. Sourabh Bal
Assistant Professor
Department of Physics
Swami Vivekananda Institute of Science and Technology
Kolkata 700145
[[alternati
On Tue, Jul 18, 2017 at 12:05 PM, Christofer Bogaso <
bogaso.christo...@gmail.com> wrote:
> Thanks for your pointer.
>
> Is there any way in R how to replace " ' " with " /' " programmatically?
>
> My actual string is quite lengthy, so changing it manually may not be
> possible. I am aware of gsub
Thanks for your pointer.
Is there any way in R how to replace " ' " with " /' " programmatically?
My actual string is quite lengthy, so changing it manually may not be
possible. I am aware of gsub() function, however not sure I can apply
it directly on my original string.
Regards,
On Tue, Jul 1
Try:
String = '
your string opens with single quote ', and has a single quote ' in the middle.
R sees that as the end of the string. You will need to escape the
interior ' with
\'
See ?Quotes
for details.
On Tue, Jul 18, 2017 at 12:48 PM, Christofer Bogaso
wrote:
> Hi again,
>
> Let say I have below string (ar
Hi again,
Let say I have below string (arbitrary)
> Anthony Damico
> on Sun, 16 Jul 2017 06:40:38 -0400 writes:
> hi, the text file that prompts the segfault is 4gb but only 80,937 lines
>> file.info( "S:/temp/crash.txt")
> size isdir mode mtime
> ctime atime exe
> S:/temp/crash.txt 407
I don't know much about what you are doing with your data, but I do know that
your example is not reproducible [1][2][3].
It is very important to be clear both to yourself and to anyone you ask to help
you what your data are like. Details like what the column names are, whether
they are numer
The definition of 'order' is that x[order(x)] is in increasing order. E.g.,
> x <- c(19,17,23,11)
> order(x)
[1] 4 2 1 3
> x[order(x)]
[1] 11 17 19 23
You may be looking for what 'rank' does:
> rank(x)
[1] 3 2 4 1
(If x has no ties, then rank(x) is order(order(x)).)
Bill Dunlap
TIB
We don't have enough information to replicate your results, but the warning in
the output is suggestive: "Some constraints were aliased because they were
collinear (redundant)".
Are some of your columns perfectly correlated with other columns? This could
easily happen if there are more columns
You may get some help here, but you should also do your own homework
by looking at the CRAN Machine Learning Task view here:
https://cran.r-project.org/web/views/MachineLearning.html
Cheers,
Bert
Bert Gunter
"The trouble with having an open mind is that people keep coming along
and sticking t
Hello Sir
I am getting problem in plotting in CCA . Could you please help me? I wrote the
below command but I don't know why it is taking only first 5 env data rather
than all 9.
> strain.data <- read.xlsx("Dee rhiz.xlsx", sheetName="strain", header = T,
> row.names = 1)
> env.data <- read.xls
Hai all,
We are working on Multi-class Classification. Currently up to 1.1 million
records Ranger package in R is able to handle. Training time on 128 GB RAM
is 12 days, which is not a practically feasible method to proceed further.
In future we will have dataset of dimension 10 million records,
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