Hi Luigi
add strip.custom argument
barchart(test ~ count|assay, df,
groups = res,
stack = TRUE,
main = "Comparison of test results",
xlab = "Count",
col = c("yellow", "blue"),
strip= strip.custom(factor.levels = c("molecular
test","serological test"),
This is very hard to read. Please use dput to provide data. I believe the
answer is in the manual. Look at the aggregation function argument.
Please excuse my brevity; this message was sent from my telephone.
On Sep 1, 2015 12:11 AM, "Matt Pickard"
wrote:
> Hi,
>
> I have data that looks like th
Hi,
I have data that looks like this:
*> head(ratings) QCode PID RaterName SI1 SI2 SI3 SI4 SI5 SI6 SI7 SI8 SI9
SI10 SI111 GUILT 1123 cwormhoudt 2 2 3 1 1 1 3 3 3
212 LOVE 1123 cwormhoudt 1 2 3 2 1 1 1 1 11
33 GUILT 1136 cwormhoudt 1 2
In your example, how would you know that it is not 2015-11-9 06:00. ?
Cheers,
Bert
On Monday, August 31, 2015, Dominic Roye wrote:
> Hello,
>
> How can I convert date-time in which month and day have non zero padding?
>
> For example: "2015119_06" ("2015-01-19 06:00")
>
> Thanks
>
> Dominic
you will probably have to take a guess since your example is also
2015-11-09 06:00; so how do you determine which one. come up with an
algorithm and the solution is easy.
Jim Holtman
Data Munger Guru
What is the problem that you are trying to solve?
Tell me what you want to do, not how you wan
> For example: "2015119_06" ("2015-01-19 06:00")
How would the ninth of November be represented?
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Mon, Aug 31, 2015 at 1:11 PM, Dominic Roye
wrote:
> Hello,
>
> How can I convert date-time in which month and day have non zero padding?
>
> For exa
Hello,
I was wondering if anyone has successfully implemented the non-metric pls
regression algorithm presented by Giorgio Russolillo in the appendix of his
PhD dissertation.
I am having issues calling the function with his example matrices (tea data
set) and I think there may be a few mistakes
Hello,
How can I convert date-time in which month and day have non zero padding?
For example: "2015119_06" ("2015-01-19 06:00")
Thanks
Dominic
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I have an issue ans i posted it , so i would like to receive a solution
please
On Mon, Aug 31, 2015 at 8:35 PM, shawin [via R] <
ml-node+s789695n4711689...@n4.nabble.com> wrote:
> I have a data frame csv file and I'm trying to calculate median for each
> group separately row by row . When I sepa
On Aug 31, 2015, at 1:49 PM, Luigi Marongiu wrote:
> Dear all,
> I have a data frame and I would like to do the following:
> a) replace value of one variable "a" according to the value of another one "b"
> b) remove all the instances of the variable "b"
>
> For the sake of argument, let's say I
On Aug 31, 2015, at 1:17 PM, Luigi Marongiu wrote:
> Dear all,
> I am drawing a barchart plot with lattice and the resulting strips are
> taking the value of the variable being compared (in this example
> "assay"). However I would like to write myself the value to place into
> the strips, let's s
Hi, I would appreciate if someone could send me or indicate where to find
information on how to interpret second order interactions (especially when
variables are both continuous) in the context of glmm R output.
Thanks in advanced,
Joaquín
--
*Joaquín Aldabe*
*Grupo Biodiversidad, Ambiente y S
Dear all,
I have a data frame and I would like to do the following:
a) replace value of one variable "a" according to the value of another one "b"
b) remove all the instances of the variable "b"
For the sake of argument, let's say I have the following data frame:
test <- rep(c("Adenovirus", "Rotav
Dear all,
I am drawing a barchart plot with lattice and the resulting strips are
taking the value of the variable being compared (in this example
"assay"). However I would like to write myself the value to place into
the strips, let's say I want to call the variables as "molecular test"
and "serolo
Dear All,
I am trying to mine a small dataset.
Admittedly, it is a bit odd since it is an example of
multi-classification task where I have more than 300 different classes for
about 600
observations.
Having said that, the problem is not the output of my script, but the
fact that it gets stuck, wi
Dear Wolfgang,
Kindly please i have an issue with R code could you please help me.
Best Regards
On Mon, Aug 31, 2015 at 6:24 PM, Viechtbauer Wolfgang (STAT)-2 [via R] <
ml-node+s789695n4711682...@n4.nabble.com> wrote:
> Have you read help(rma.mv)? It describes in detail what "random = ~ 1 |
> a
Have you read help(rma.mv)? It describes in detail what "random = ~ 1 | author"
does. Also, I think you may find some of these useful:
http://www.metafor-project.org/doku.php/analyses#multivariate_multilevel_meta-analysis_models
Especially: http://www.metafor-project.org/doku.php/analyses:konsta
The solution that you proposed works perfectly, thank you very much.
I'll wait for Wolfgang answer as I'm having few doubts about the models.
Thanks
On 31 August 2015 at 18:34, Michael Dewey wrote:
> Comments in line
>
> On 31/08/2015 16:08, Marco Colagrossi wrote:
>>
>> Thanks for your help,
>
Comments in line
On 31/08/2015 16:08, Marco Colagrossi wrote:
Thanks for your help,
I got the mistake I was making and I managed to find a solution
regarding those graphs; I don't want to abuse of your patience but I
have three further questions:
1. Always regarding the forest plots, it is pos
Hi Peter and Gerrit,
Sorry about my confusion with the results I was
not entirely sure what they were. I was expecting some form of a table and
i didn't realize that with the results of a fisher test, one just gets a
p-value. I had tried the 'estimate' and 'null.value' w
Hi R package users,
You may be interested in these two new packages now available on CRAN:
*googleAuthR* lets you easily authenticate with Google OAuth2 APIs and make
your own packages with them. It also is multi-user Shiny compatible, so
you can publish your apps and users can work with their o
Dear Terry,
Thank you for the extended explanation -- it's helpful.
Best,
John
From: Therneau, Terry M., Ph.D. [thern...@mayo.edu]
Sent: August 31, 2015 9:56 AM
To: r-help@r-project.org; Fox, John; Göran Broström
Subject: Re: using survreg() in survival
Thanks for your help,
I got the mistake I was making and I managed to find a solution
regarding those graphs; I don't want to abuse of your patience but I
have three further questions:
1. Always regarding the forest plots, it is possible to make a
cross-subset? I try to explain my self better; I
On 08/30/2015 05:00 AM, r-help-requ...@r-project.org wrote:
I'm unable to fit a parametric survival regression using survreg() in the survival package with
data in "counting-process" ("long") form.
To illustrate using a scaled-down problem with 10 subjects (with data placed on
the web):
As
Paul,
in addition to Peter's suggestion about the missing of theory you are also
completely missing to explain what you mean by "[it] is not giving me the
results for the calculations" or "[how] to get the results of the fisher
test". They are there in the output of R's fisher.test() (if you h
> On 30 Aug 2015, at 13:54 , paul brett wrote:
>
> Fisher's Exact Test for Count Data with simulated p-value (based on 1e+07
> replicates)
>
> data: Trapz
> p-value = 1e-07
> alternative hypothesis: two.sided
>
>
> Dispite these chages, the changes equations is not giving me the results
> fo
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