It doesn’t appear to me that mpfr was ever designed to handle expressions
as the first argument.
>>>
>>> This could be a start. Obviously one would wnat to include code to do other
>>> substitutions probably using the all.vars function to pull out the other
>>> “constants” and ’numeric
> On Jul 3, 2015, at 11:05 PM, Duncan Murdoch wrote:
>
> On 04/07/2015 3:45 AM, David Winsemius wrote:
>>
>>> On Jul 3, 2015, at 5:08 PM, David Winsemius wrote:
>>>
>>>
>>>
>>> It doesn’t appear to me that mpfr was ever designed to handle expressions
>>> as the first argument.
>>
>> This
On 04/07/2015 3:45 AM, David Winsemius wrote:
>
>> On Jul 3, 2015, at 5:08 PM, David Winsemius wrote:
>>
>>
>>
>> It doesn’t appear to me that mpfr was ever designed to handle expressions as
>> the first argument.
>
> This could be a start. Obviously one would wnat to include code to do other
On 04/07/2015 12:26 AM, Rolf Turner wrote:
> On 04/07/15 06:27, Yihui Xie wrote:
>> Sigh, how natural it is to say "This package ...", but you probably
>> don't know a package can be easily rejected by CRAN simply because of
>> this phrase "This package" (it has been clearly stated in the R-exts
>>
Lida,
I expect that there is a better way to solve your problem than the process you
propose.
However, something like this may do what you want.
###
## met <- read.csv("your_met_file”)
## Since I do not have your file a made a small 5*1 character vector.
met <- c("glycine_imp",
"Nac
Use dev.off and re-open the device.
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#
Dear list,
I define a function to export a bunch of plots. A sample code is something
like the follow
export.plots<-function(export.type='pdf',...){
match.fun(export.type) (...)
print(plot.func1(...))
print(plot.func2(...))
print(plot.func3(...))
...
print(plot.funcn(...))
dev.off()
}
If I d
> On Jul 3, 2015, at 5:08 PM, David Winsemius wrote:
>
>
>
> It doesn’t appear to me that mpfr was ever designed to handle expressions as
> the first argument.
This could be a start. Obviously one would wnat to include code to do other
substitutions probably using the all.vars function to p
Rich
Just a thought
Have you set pch colour values somewhere else?
see also https://stat.ethz.ch/pipermail/r-help/2010-March/230329.html
Duncan
-Original Message-
From: rshep...@localhost.appl-ecosys.com
[mailto:rshep...@localhost.appl-ecosys.com] On Behalf Of Rich Shepard
Sent: Saturday
It doesn’t appear to me that mpfr was ever designed to handle expressions as
the first argument.
—
David
> On Jul 3, 2015, at 12:01 PM, Ravi Varadhan wrote:
>
> Thank you all. I did think about declaring `pi' as a special constant, but
> for some reason didn't actually try it.
> Would i
Thank you all. I did think about declaring `pi' as a special constant, but for
some reason didn't actually try it.
Would it be easy to have the mpfr() written such that its argument is
automatically of extended precision? In other words, if I just called:
mpfr(exp(sqrt(163)*pi, 120), then al
On 04/07/15 03:43, Sarah Goslee wrote:
Hi,
On Fri, Jul 3, 2015 at 10:33 AM, Zander, Joscha
wrote:
Good day R-community,
i just wondered if it is a bug or a feature...
When i have a matrix "mat" with one column and i delete the last row with
mat <- mat[-nrow(mat),] the result is a list.
I
On 04/07/15 06:27, Yihui Xie wrote:
Sigh, how natural it is to say "This package ...", but you probably
don't know a package can be easily rejected by CRAN simply because of
this phrase "This package" (it has been clearly stated in the R-exts
manual).
Urrr! I *did* "know" that, but had for
Sigh, how natural it is to say "This package ...", but you probably
don't know a package can be easily rejected by CRAN simply because of
this phrase "This package" (it has been clearly stated in the R-exts
manual).
I don't think the grammar is the problem here. When in doubt, I always
check what
> On Jul 3, 2015, at 8:08 AM, John Nash wrote:
>
>
>
>
> Third try -- I unsubscribed and re-subscribed. Sorry to Ravi for extra
> traffic.
>
> In case anyone gets a duplicate, R-help bounced my msg "from non-member" (I
> changed server, but not email yesterday,
> so possibly something chang
Yes, use fixef(mod) instead of mod@fixef. It is recommended to use the
accessor functions instead of reading the slots with the @.
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie & Kwaliteitszorg / team Biometrics & Quality As
Hi,
On Fri, Jul 3, 2015 at 10:33 AM, Zander, Joscha
wrote:
> Good day R-community,
>
> i just wondered if it is a bug or a feature...
>
> When i have a matrix "mat" with one column and i delete the last row with
>
> mat <- mat[-nrow(mat),] the result is a list.
I have no idea how you're getting
> On Jul 3, 2015, at 9:33 AM, Zander, Joscha wrote:
>
> Good day R-community,
>
> i just wondered if it is a bug or a feature...
>
> When i have a matrix "mat" with one column and i delete the last row with
>
> mat <- mat[-nrow(mat),] the result is a list.
>
> So my next call mat[10,] will t
> On 03-07-2015, at 14:18, Federico Calboli
> wrote:
>
> As I said, I found a formulation that pleased the check and that’s it for me.
> I am befuddled by the check in the first place though.
>
And what would that formulation be (replacing the original one) ?
Berend
> BW
>
> F
>
>
>> O
As I said, I found a formulation that pleased the check and that’s it for me.
I am befuddled by the check in the first place though.
BW
F
> On 3 Jul 2015, at 15:14, PIKAL Petr wrote:
>
> Hi
>
> without going deep into this matter, what if you remove "/" from your
> sentence.
>
> Cheers
>
Dear Thierry,
Thank you very much. Do you mean I should add a line to the function with
the code "fixef(my.model)", retaining everything else, even the "beta0 <-
as.numeric(mod@fixef)" line? Or should I replace something? Also, when you
say "fixef(my.model), do you mean "fixef(mod)"
Third try -- I unsubscribed and re-subscribed. Sorry to Ravi for extra
traffic.
In case anyone gets a duplicate, R-help bounced my msg "from non-member" (I
changed server, but not email yesterday,
so possibly something changed enough). Trying again.
JN
I got the Wolfram answer as follows:
l
That exists already: last slide here — it looks like it is a know issue.
BW
F
> On 3 Jul 2015, at 14:13, Hadley Wickham wrote:
>
> In that case, you need to create a minimal reproducible example and make it
> publicly available.
>
> Hadley
>
> On Friday, July 3, 2015, Federico Calboli
Good day R-community,
i just wondered if it is a bug or a feature...
When i have a matrix "mat" with one column and i delete the last row with
mat <- mat[-nrow(mat),] the result is a list.
So my next call mat[10,] will throw an "wrong dimension" error.
The proper call must be:
mat <- as.matrix
Dear all
I am plotting a time series using time Plot function. All goes well until i
try to modify the legend by taking it from the standard location at the
bottom, to the right side in a vertical way.
How can i do this?
This is my code:
filename <- sprintf('%s/TS_CO_all.png',folderPLOTS)
y_la
Also when I try the following with Rmpfr, it works jut fine.
> exp(sqrt(mpfr(163, 120)) * Const("pi", 120))
1 'mpfr' number of precision 120 bits
[1] 262537412640768743.25007601
and
> exp(sqrt(mpfr(163, 400)) * Const("pi", 400))
1 'mpfr' number of precision 400 bits
[1]
2625
> On 3 Jul 2015, at 12:14, Hadley Wickham wrote:
>
> It might be a line break problem - I think you want:
>
> Description: Functions designed to test for single gene/phenotype
> association and
>for pleiotropy on genetic and genomic data.
Tried this and unfortunately it does not help.
BW
I would like help understanding why a survival regression with no censored
data-points does not give the same variance estimates as a linear model
(see code below).
I think it must be something to do with the fact that the variance is an
actual parameter in the survival version via the log(scale),
Here is what it does locally on my PC:
> library("igraph")
> topo_data <- read.table(text = "ibcore01ibswitch01
+ ibcore01ibswitch02
+ ibcore01ibswitch03
+ ibcore02ibswitch01
+ ibcore02ibswitch02
+ ibcore02ibswitch03
+ ibswitch01 node001
On 03/07/15 20:09, Federico Calboli wrote:
Hi All,
I am upgrading a package for CRAN, and I get this note:
checking DESCRIPTION meta-information ... NOTE Malformed Description
field: should contain one or more complete sentences.
This is puzzling because:
cat DESCRIPTION
... Description: Fun
On Fri, 3 Jul 2015, Duncan Mackay wrote:
I usually avoid global settings as they may change between graphs therefore
I use the par.settings in each plot
My settings are
...
Duncan,
Thank you very much. Sound advice and excellent example.
I suspect that part of my issues with tryin
Hi
without going deep into this matter, what if you remove "/" from your sentence.
Cheers
Petr
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Hadley
> Wickham
> Sent: Friday, July 03, 2015 1:14 PM
> To: Federico Calboli
> Cc: R-help
> Subject: Re:
In that case, you need to create a minimal reproducible example and make it
publicly available.
Hadley
On Friday, July 3, 2015, Federico Calboli
wrote:
>
> > On 3 Jul 2015, at 12:14, Hadley Wickham > wrote:
> >
> > It might be a line break problem - I think you want:
> >
> > Description: Funct
Dear Iker,
The internals of the mer model have changed. Use fixef(your.model).
Best regards,
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie & Kwaliteitszorg / team Biometrics & Quality Assurance
Kliniekstraat 25
1070 Anderl
Hi Ati,
Let's start from the top and see where we finish up. I'll use a
somewhat smaller matrix:
met<-matrix(runif(5),ncol=1)
rownames(met)<-c("glycine_imp","Nacetylglycine_imp","sarcosine_imp",
"dimethylglycine_imp","betaine_imp")
met
[,1]
glycine_imp 0.61532855
I have a small dataframe xxF, a summary of which looks like this:
> summary(xxF)
T Dev
Min. :10.44 Min. :0.008929
1st Qu.:10.44 1st Qu.:0.012048
Median :18.61 Median :0.031250
Mean :17.87 Mean :0.028286
3rd Qu.:22.24 3rd Qu.:0.041667
It might be a line break problem - I think you want:
Description: Functions designed to test for single gene/phenotype
association and
for pleiotropy on genetic and genomic data.
Hadley
On Fri, Jul 3, 2015 at 10:09 AM, Federico Calboli
wrote:
> Hi All,
>
> I am upgrading a package for CRAN,
Hi
I cannot test it in absence of data. Anyway I would not use saving single
objects but use list instead.
Something like
lll <- vector(mode="list", nrow(met))
for (i in 1:nrow(met)) {
form <- as.formula(paste(met[i], "~ egfr_v1_ckdepi+pc1+pc2+pc3+V1AGE01+GENDER"))
lll[i] <- Scores(Z=metalofGT
Hi All,
I am upgrading a package for CRAN, and I get this note:
checking DESCRIPTION meta-information ... NOTE
Malformed Description field: should contain one or more complete sentences.
This is puzzling because:
cat DESCRIPTION
...
Description: Functions designed to test for single gene/pheno
Hi Rich,
The Wolfram answer is correct.
http://mathworld.wolfram.com/RamanujanConstant.html
There is no code for Wolfram alpha. You just go to their web engine and plug
in the expression and it will give you the answer.
http://www.wolframalpha.com/
I am not sure that the precedence matters
In my experience package "dplyr" has all functions to deal with this kind
of problems in a simple and compact way
Sergio
Il 03/lug/2015 07:26, "Charles Thuo" ha scritto:
> I have a data frame whose rows are 678013 . I would like to remove rows
> from 30696 to 678013 and then attach a new column
Try
y <- x[ -( 30596:678013 ), ]
Please note that I have replaced 30595 with 30596 which is I think what you
mean.
You can add a new column with
y$new <- new_column # this is your vector of length 30595
Good luck,
Rainer
On Friday 03 July 2015 07:23:28 Charles Thuo wrote:
> I have a data
Hi,
With the following data
ibcore01ibswitch01
ibcore01ibswitch02
ibcore01ibswitch03
ibcore02ibswitch01
ibcore02ibswitch02
ibcore02ibswitch03
ibswitch01 node001
ibswitch01 node002
ibswitch01 node003
ibswitch02 node004
ibswitch02
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