Hi

I cannot test it in absence of data. Anyway I would not use saving single 
objects but use list instead.

Something like

lll <- vector(mode="list", nrow(met))

for (i in 1:nrow(met)) {
form <- as.formula(paste(met[i], "~ egfr_v1_ckdepi+pc1+pc2+pc3+V1AGE01+GENDER"))
lll[i] <- Scores(Z=metalofGT,formula=form)
}

Cheers
Petr


> -----Original Message-----
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Lida
> Zeighami
> Sent: Thursday, July 02, 2015 6:48 PM
> To: r-help@r-project.org
> Subject: Re: [R] question
>
> Thank you so much for replying me!
> for better understanding my problem, I explain my problem more:
>
> I have a 682*1 matrix called "met" , the first 5 rows similar below:
>
> >  rownames(met)[1:5]
>
> [1]  "glycine_imp"
> [2]  "Nacetylglycine_imp"
> [3]  "sarcosine_imp"
> [4]  "dimethylglycine_imp"
> [5]  "betaine_imp"
>
> and I have a function in R that each time use one of the row names of
> "met"
> matrix and create a new object file and I should save the objects!
>
> my function is  "
> Scores(Z=metalofGT,formula="met[i]~egfr_v1_ckdepi+pc1+pc2+pc3+V1AGE01+G
> ENDER")
> " that each time just I should change the met[i] and replace by row
> names
> "met" one by one and for each of them I should rename the function and
> after that I should save each object!
> for example for first row of "met" I have
>
> >   prep1<-
> Scores(Z=metalofGT,formula="glycine_imp~egfr_v1_ckdepi+pc1+pc2+pc3+V1AG
> E01+GENDER")
> #creat the object file for first row and called prep1###
>
> >   save(prep1, file="prep1.RData", compress="bzip2")      ##save the
> object file as "prep1.RData"#####
>
> I should do this process for 682 row names of "met" matrix and at the
> end I
> should have    "prep1.RData"  ,   "prep2.RData"   , "prep3.RData"
>
> so, would you please help me how to do it?
>
> Many Thanks,
> Ati
>
> On Wed, Jul 1, 2015 at 1:07 PM, Lida Zeighami <lid.z...@gmail.com>
> wrote:
>
> > I have 682 variables in a data frame , and a function that  I should
> feed
> > 682 variables in this function one by one and each time save the file
> as a
> > special name!
> > for emaple:
> > my data frame file includes 682 names :
> > 1  aaa
> > 2  bbb
> > 3  dfdsfg
> > 4 fghh
> > .
> >
> > 682 fgfhg
> > and a function like prep(Z, aaa, .....) and each time I should change
> the
> > variable name in this function and read the variable from the data
> frame
> > and each time I should save the file as a special name such as:
> >
> > prep1<- prep(z, aaa,...)
> > prep2<- prep(z, bbb,...)
> > prep3<- prep(z, dfdsfg,..)
> > Prep4<- prep(z, fghh,...)
> >
> > How can I use loop function in R to that?
> >
> > Thanks
> >
>
>       [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.

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