On Mon, Jan 6, 2014 at 7:36 PM, Peter Maclean wrote:
> With these toy data, how can I remove unused empty space between the bars?
There is no unused space. It is very hard to see how you could remove
the empty space and still have a meaningful graph.
Best,
Ista
>
> #Toy data
> x1 <- as.data.fram
This looks like a PATH problem. Most likely Miktex isn't where you
told R to find it.
FInd out where miktex is by typing pdflatex in the Start button search box.
Right click on it when it appears and then click properties.
The properties window has a Location field.
The value in the location fiel
Hi everybody,
I have created a package without documentation and now I want to create it with
a pdf manual. That is the reason why I have created the .Rd files in man
folder. In this way I obtain a pdf manual usind "R CMD check packagename", but
it ignores the \code{\link{function.name}}... I
Hi all,
I have a matrix which I want to plot in color. I have extensively looked at
level plot and heatmap/heatmap.2, but I would like to be able to manage the
size of the bins (boxes) on my X axis. So I thought of simply using the rect()
function, but I can’t get around assigning the correct c
Just before the holiday, I asked the freetype developers what is the context
of these two comments about freetype in the code of R's grDevices:
=== R/src/library/grDevices/src/cairo/cairoFns.c around line 720 =
/* some FreeType versions have broken index support,
With these toy data, how can I remove unused empty space between the bars?
#Toy data
x1 <- as.data.frame(rep(1:3, c(10,2,6)))
colnames(x1) <- c("name")
x2 <- as.data.frame(rep(5:7, c(14,5,8)))
colnames(x2) <- c("name")
x3 <- as.data.frame(rep(10:12, c(5,5, 8)))
colnames(x3) <- c("name")
x4 <-
You could compare the outputs of
z1 <- with(dd, dd$EVYEAR==2012 & dd$EVMONTH=='02')
(which is like subset()) and that of
z2 <- dd$EVYEAR==2012 & dd$EVMONTH=='02'
(evaluated from within the same context) with
table(z1, z2, exclude=NULL)
That may show something useful.
Bill Dunlap
Spotf
On 01/06/2014 11:14 AM, Sarah Goslee wrote:
Hi Walter,
I can't reproduce your results. Please provide some data that
demonstrates the problem.
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
subset() and [ differ in their handling of NA values, and you don
For decomposing a time series into seasonal components, you need at least 2
seasons worth of data. If you have even one data point less, you will see
this error message.
blockLength <- 52
ts1 <- ts(rnorm(2*blockLength-1), frequency=blockLength)
decompose(ts1) # error
ts2 <- ts(rnorm(2*blockL
blockLength <- 37 # can be anything you like
ts1 <- ts(rnorm(2*blockLength-1, 0,2), frequency=blockLength)
de <- decompose(ts1) # error
ts2 <- ts(rnorm(2*blockLength, 0,2), frequency=blockLength)
de <- decompose(ts2)
plot(de)
So the trick is to have at least two periods in your time series. Ev
R 3.0.2
OS X
Colleagues,
I know little about encoding so please be patient with this question. I have a
CSV file created from a SAS7BDAT dataset (using Shotwell's SAS7BDAT package).
In the CSV file, when opened with XL, one entry reads as:
¸æçñàºmol/L
When I read this into R, that en
Hi Walter,
I can't reproduce your results. Please provide some data that
demonstrates the problem.
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
subset() and [ differ in their handling of NA values, and you don't
need the dd$ in the arguments to subset().
I have a data frame that I am extracting some records from and noticed
the following issue
I originally used tmp <- subset(dd, dd$EVYEAR==2012 & dd$EVMONTH=='02')
and noticed that I wasn't ending up with all of the records I should
have; however, when I used
tmp <- dd[dd$EVYEAR==2012 & dd$EV
Capitalize your column name "pr(...)" - printCoefmat is looking for "Pr(...)".
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf
> Of ???
> Sent: Monday, January 06, 2014 5:5
Hin-Tak Leung wrote:
...
Somewhat related, I have finally gotten round to make two small bundles,
which replace the small cairo.dll/cairo.so' in the official
windows or Mac R binaries, to fix quite a few problems with them,
the first of which was reported almost a year ago. Just move the two
smal
My question is about the "Signif. codes" , the output when I run
matcoef =cbind(fit$par, se.coef,tval,2*(1-pnorm(abs(tval
dimnames(matcoef)=list(names(tval),c("Estimate","Std.Error","t
value","pr(>|t|)"))
cat("\nCoefficient(s):\n")
printCoefmat(matcoef, digits=4, signif.stars = TRUE)
Co
Dear Sir,
Thanks a lot for your wonderful guidance. It gave me a new vision to look at
teh equations. Really appreciate.
Thanks a lot once again.
Katherine
On Monday, 6 January 2014 5:31 PM, Frede Aakmann Tøgersen
wrote:
Hi
Reading the error message carefully you can see that f() is not
Because we get a lot of questions on regex here:
http://xkcd.com/1313/
Anybody want to write a regex golf package for R?
Sarah
--
Sarah Goslee
http://www.functionaldiversity.org
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listi
I have a regression line, called "mean". X-axis is called "week"
Now, I want to draw vertical and horizontal lines, from each point of the
regression line, to x-axis and y-axis.
Here is my code:
ggplot()+
geom_linerange(data=df2,x=df2$week, ymin=0, ymax=df2$mean,
colour="#00",size=0.1)+
ge
Hi Arun & Jim & Marc,
Thank you!
The solution worked well!
It seems I am using too many unnecessary loops to solve my problems. I
have tried using is.na() before posting:
for(i in 1:3){
for(j in 1:3){
if(is.na(test[j,i])){
test[j,i]=""
}
}
} # but here the factors were creating problems.
Thanks
Hi
can you be more specific? In what aspect those packages does not comply with
your data? What did you do for testing it?
I am not an expert in neural networks but I do not see anything which prevents
using your data in nnet.
Petr
> -Original Message-
> From: r-help-boun...@r-projec
Hi,
Try:
test[test=="" & !is.na(test)] <- NA
A.K.
On Monday, January 6, 2014 7:51 AM, vikram ranga wrote:
Dear All,
I am bit stuck to a problem of replacing "" to NA.
I have big data set but here is the toy example:-
test<-data.frame(
test1=c("","Hi","Hello"),
test2=c("Hi","","Bye"),
test3
Dear Petr;
I saw the nnet and neuralnet packag, and I cant find some thing relating
with my data based on neural network.
On Mon, Jan 6, 2014 at 10:55 AM, PIKAL Petr wrote:
> Hi
>
> Why you did not use dput for sending data? It is far better than picture,
> which can not be used without retypin
try this:
> test<-data.frame(
+ test1=c("","Hi","Hello"),
+ test2=c("Hi",NA,"Bye"),
+ test3=c("Hello","",""))
> test
test1 test2 test3
1 Hi Hello
2Hi
3 Hello Bye
>
> test[] <- lapply(test, function(x){
+ x[!is.na(x) & x == ''] <- NA
+ x
+ })
> test
test1 test2 test3
1
On Jan 6, 2014, at 5:57 AM, vikram ranga wrote:
> Dear All,
>
> I am bit stuck to a problem of replacing "" to NA.
> I have big data set but here is the toy example:-
>
> test<-data.frame(
> test1=c("","Hi","Hello"),
> test2=c("Hi","","Bye"),
> test3=c("Hello","",""))
>
> If the data as in ab
On Jan 6, 2014, at 6:36 AM, Sarah King wrote:
Hi
I tried to install R on my laptop which has Office 2013 on it. The
download didn't work, is this because R is not compatible with Office
2013?
In a word, no. It's more likely that some corporate security barrier
is preventing installation.
Hi
Reading the error message carefully you can see that f() is not defined at 0:
> uniroot(f, c(0, 1))
Error in uniroot(f, c(0, 1)) : f.lower = f(lower) is NA
> f(0)
[1] NaN
If you plot f() in the interval (0,1) then you'll see there is two solutions:
> uniroot(f, c(0.0001, 1))
Error in uniroo
Dear Saha thank you to reminding me. Here is the text file.
On Mon, Jan 6, 2014 at 10:33 AM, Koushik Saha wrote:
> please don't send images . paste your data in a text file with .text
> extension and attach it
>
>
> On Mon, Jan 6, 2014 at 12:06 PM, javad bayat wrote:
>
>> Dear all;
>> many than
Dear All,
I am bit stuck to a problem of replacing "" to NA.
I have big data set but here is the toy example:-
test<-data.frame(
test1=c("","Hi","Hello"),
test2=c("Hi","","Bye"),
test3=c("Hello","",""))
If the data as in above, I could change all "" to NA by this code:-
for(i in 1:3){
for(j in
Hi
I tried to install R on my laptop which has Office 2013 on it. The
download didn't work, is this because R is not compatible with Office
2013?
Thanks
Sarah
Notice of Confidentiality
This transmission contains information that may be confidential and that may
also be privileged. Unless yo
On 06-01-2014, at 12:41, Katherine Gobin wrote:
> Dear R forum
>
> I have following variables -
>
> EAD = 1
> LGD = 0.45
> PD = 0.47
> M = 3
>
> # Equation 1
>
> R = 0.12*(1-exp(-50*PD))/(1-exp(-50)) + 0.24*(1-(1-exp(-50*PD))/(1-exp(-50)))
>
> b = (0.11852 - 0.05478 * log(PD))^2
>
> K
Dear R forum
I have following variables -
EAD = 1
LGD = 0.45
PD = 0.47
M = 3
# Equation 1
R = 0.12*(1-exp(-50*PD))/(1-exp(-50)) + 0.24*(1-(1-exp(-50*PD))/(1-exp(-50)))
b = (0.11852 - 0.05478 * log(PD))^2
K = (LGD * pnorm((1 - R)^(-0.5) * qnorm(PD) + (R / (1 - R))^0.5 * qnorm(0.999))
- PD
Thanks Michael.
I have read the original article and I guess whether the following formula
could resolve my question?
*for adjusted HR of each BMI category,*
fit<-coxph(Surv~factor(BMI-category)+..+covariates)
*for trend, *
fit<-coxph(Surv~as.numeric(BMI-category)+..+covariates)
*# p trend may be
Dear Users,
Is there way to avoid the useless title (Rattle, date-time and user
imformation) at the bottom of the fancyRpartPlot. We already referencing it why
should it be there?
Thanks,
Levent.
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