On Tue, 17 Jan 2012, Bert Gunter wrote:
2012/1/17 Uwe Ligges :
I think the amount of people on this list who understand your question is
roughly zero.
A Fortunes candidate?
Included in the devel version now.
Thanks,
Z
Cheers,
Bert
We cannot see how the subject is related to the body of
Hi
> Hi,
>
> I have a list of unique patient IDs which I want to run against a
dataframe
> of unique patient IDs with dates. There are multiple date instances
against
> unique IDs. The end result I wish is that I have a list of IDs (which
are
> unique) with the latest date. I have begun with
On Tue, 17 Jan 2012, twarzin wrote:
This request is related to the following post from last year:
https://stat.ethz.ch/pipermail/r-help/2011-June/279752.html
Not very closely. The post linked above was asking about getting predicted
means vs. predicted probabilities. It is not related to mar
Hi
How to choose the variables that needs smoothing. Is there any criteria for
those
Please help me
-
Thanks in Advance
Arun
--
View this message in context:
http://r.789695.n4.nabble.com/How-to-choose-variabe-that-needs-to-be-smoothing-in-GAM-tp4305676p4305676.html
Sent from the R
Hi,
I have a list of unique patient IDs which I want to run against a dataframe
of unique patient IDs with dates. There are multiple date instances against
unique IDs. The end result I wish is that I have a list of IDs (which are
unique) with the latest date. I have begun with using test data (but
Hello,
Jonas, I've just seen your function 'sistring' code and it's different from
the code in
R-help, Ben.BigHair, Jan 06, 2012 reply to the thread "automatic SI prefixes
as ticklabels on axis".
The difference is that it's not "as.character(x)", it should be
"as.character(number)"
(The functio
On Tue, 17 Jan 2012, crimsonengineer87 wrote:
Thanks for the comments everyone. I was hoping to not have to find someone in
the stats department ... well, we'll see.
So in response to Z's comment ... I have tried breakpoints(Na ~ yield)
and I did expect to get something continuous.
You won't
Hi
addLine<- function(a=NULL, b=NULL, v = NULL, h = NULL, ..., once=F) {
tcL <- trellis.currentLayout()
k<-0
for(i in 1:nrow(tcL))
for(j in 1:ncol(tcL))
if (tcL[i,j] > 0) {
k<-k+1
trellis.focus("panel", j, i, highlight = FALSE)
if (once) panel.abline(a=a[k], b=b[k], v=v[k], h=h[k],
http://stackoverflow.com/questions/726690/who-killed-my-process-and-why
---
Jeff NewmillerThe . . Go Live...
DCN:Basics: ##.#. ##.#. Live Go...
Just install the updated library over the old one and start a new R session.
Devtools can be helpful for some things, but when I last looked at it I was
having more difficulty with getting documentation right than debugging code,
which I can do using normal function development processes, so I w
Try adding
LazyData: yes
to the DESCRIPTION file.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf Of Jonas Stein
> Sent: Tuesday, January 17, 2012 4:41 PM
> To: r-h...@st
Hi,
i create two constants kilo and milli in [1]. These should be available
after loading
library(sitools)
How should i export them and what have i done wrong?
(Other suggestions for improving the package are welcome too)
The ready to use .tar.gz and the source can be found on github [2,3]
kin
In respect of fitting piecewise linear regressions, have you looked at
the "segmented" package?
cheers,
Rolf Turner
On 18/01/12 04:30, crimsonengineer87 wrote:
Dear Forum,
I have been wracking my head over this problem for the past few days. I have
a dataset of (x,y). I have been
http://cran.r-project.org/web/packages/devtools/index.html
Michael
On Tue, Jan 17, 2012 at 6:51 PM, Jonas Stein wrote:
>> Look at Hadley Wickham's devtools package. It is designed with this
>> sort of thing. That said, it really is not too difficult to install
>> as long as you have a working
> I don't believe you can. However, you need not install it into a system-wide
> library directory... your personal library (e.g.
> /home/jonas/R/x86_64-pc-linux-gnu-library/2.14) should be sufficient.
Finally i created a new testuser to install the library locally as you wrote.
It works. Thank
> Look at Hadley Wickham's devtools package. It is designed with this
> sort of thing. That said, it really is not too difficult to install
> as long as you have a working tool chain (which you will need to test
> it anyway).
I cound not find it with google and found no "devtools" on this page
Thanks Hadley for your input.
The following code works fine now.
Thanks again
con = textConnection("inputs var1 var2 var3
100 10 5 2
1000 20 10 4
5000 30 15 8
1 40 20 16
3 50 25 32")
data = read.table(con, header=TRUE)
data
data = melt(data, id="inputs")
g <- ggplot(data,aes(x=inpu
Hi, I recently got a bizarre message when running arules. It just said
"Killed" and quit. Anyone know why this might have happened? I am running R
on an AWS quad xl ubuntu instance.
Here is some information, including dataset size and the parameters:
parameter specification:
confidence minval
This request is related to the following post from last year:
https://stat.ethz.ch/pipermail/r-help/2011-June/279752.html
After reading the thread, the idea is still not clear. I have fitted a model
using HURDLE from the PSCL package. I am trying to get marginal effects /
slopes by multiplying
Try using the function in the plyr package. E.g.,
> z <- data.frame( # your toy dataset
run = c(1, 2, 1, 2),
par = c(10, 10, 20, 20),
measured = c(12, 14, 20, 26))
> library(plyr)
> ddply(z, .(par), summarize, meanMeasured=mean(measured),
sdMeasured=sd(measured))
pa
On Jan 17, 2012, at 4:56 PM, Jean V Adams wrote:
Read the help file on how to extract from a data frame:
?"[.data.frame"
Then, try adding a comma inside the brackets.
data.station1 <- data[data$Station==1, ]
Before the comma, the data$Station==1 identifies what rows to select.
After the comma,
Thanks for the comments everyone. I was hoping to not have to find someone in
the stats department ... well, we'll see.
So in response to Z's comment ... I have tried breakpoints(Na ~ yield) and I
did expect to get something continuous. The idea was to get two or three
linear functions making up t
Thank you, Uwe, for your help! I have more measurements (m1, m2) and
more parameters (par1, par2). I can calculate the means of m1 and m2
this way:
aggregate(cbind(m1, m2) ~ par1 + par2, dat, mean)
However, I also need to calculate the standard error of the mean, and
the variance for the sa
Carlo Fezzi (ENV uea.ac.uk> writes:
>
> Dear all,
>
> I am writing an R code to fit a Bayesian mixed logit (BML) via MCMC / MH
algorithms following Train (2009, ch. 12).
>
> Unfortunately, after many draws the covariance matrix
> of the correlated random parameters tend to become
> a matrix w
Read the help file on how to extract from a data frame:
?"[.data.frame"
Then, try adding a comma inside the brackets.
data.station1 <- data[data$Station==1, ]
Before the comma, the data$Station==1 identifies what rows to select.
After the comma, the lack of specification indicates that all column
On Jan 17, 2012, at 2:21 PM, Ray Brownrigg wrote:
David:
That doesn't quite answer the question about Alaska and Hawaii.
Agreed. I misinterpreted the text of help(map) example to mean that HI
and AK boundaries could be found in "unemp". However, it was also
advice to Jeffrey that searchi
mukul purva wrote on 01/16/2012 01:35:00 AM:
> hello,
>i hav a prob in R lang. i want to do correlation of data frame
> 22810(gene) rows and 1436 colums(experiment) when i covert this file
> in csv or xls format it reads only 1024 cloumns. n when i do
> correlation of data mean 22810 *2281
Dan -
Try using "having Premie not null" instead of
"having !is.na(Premie)" .
- Phil Spector
Statistical Computing Facility
Department of Statistics
(As a noob to R, this is my first posting - yes yes, groans all around...)
I'm trying to extract certain rows from a data frame. I used the following to
import data from a CSV txt file.
data <- read.table(file="data.txt", header=TRUE)
when I do this, my attempt to extract the data rows
Did you try a where statement?
where Premie is not null
On Tue, Jan 17, 2012 at 3:03 PM, Dan Abner wrote:
> Hi everyone,
>
> I have the following:
>
> sqldf("select Premie,count(tpounds) N,avg(tpounds) Avg_Weight,
> stddev_samp(tpounds) StdDev
> from children
> group by Premie
> having !is.
Hi everyone,
I have the following:
sqldf("select Premie,count(tpounds) N,avg(tpounds) Avg_Weight,
stddev_samp(tpounds) StdDev
from children
group by Premie
having !is.na(Premie)")
sqldf() does not like the !is.na(Premie) specification. How does one
exclude a "missing" group in an aggrega
2012/1/17 Uwe Ligges :
> I think the amount of people on this list who understand your question is
> roughly zero.
A Fortunes candidate?
Cheers,
Bert
We cannot see how the subject is related to the body of your
> function nor do we see any incidence that you followed the posting guide.
>
> Uwe
Hello,
RNoob wrote
>
> Dear all,
>
> I am trying to apply the aggregate() function to calculate correlations
> for subsets of a dataframe. My argument x is supposed to consist of 2
> numerical vectors, which represent x and y for the cor() function.
>
> The following error results when callin
I think the amount of people on this list who understand your question
is roughly zero. We cannot see how the subject is related to the body of
your function nor do we see any incidence that ou followed the posting
guide.
Uwe Ligges
On 17.01.2012 17:06, Poul Kristensen wrote:
Hi !
I am n
Thanks! Both solutions work well for the problem that I described,
although I failed to mention that there are also pre-abbreviated names
in the list that I'm working with, and the second solution returns NA's
for these (but there are plenty of ways around this). Sample data might
be: State.P
David:
That doesn't quite answer the question about Alaska and Hawaii.
Jeffrey:
help(state, maps)
states "This database produces a map of the states of the United States
mainland ..."
so you have to use:
map("world", "USA")
map("state", add=T)
to get the whole lot (which I am willing to bet is
I have a question on generating multivariate time series surrogates
using the "surrogates" function in the RTisean library.
The surrogate data matrices are always much shorter than the input matrices.
FYI, I'm using R version 2.12.2 on Windows XP
RTisean library v 3.0.14
Tisean algorithms
Hello, R-List,
I'm getting error messages when adding geom_density2d() [package ggplot2]:
Fehler in pretty(range(data$z), 10) :
NA/NaN/Inf in externem Funktionsaufruf (arg 1)
Zusätzlich: Warnmeldungen:
1: Removed 1
On Jan 17, 2012, at 1:52 PM, Doran, Harold wrote:
It does indeed produce what I'm expecting. The input to panel.number
seems to require a character string, but here the function is called
with no argument. I am not entirely clear _why_ it works, but it
does seem to.
?panel.numer
Says th
It does indeed produce what I'm expecting. The input to panel.number seems to
require a character string, but here the function is called with no argument. I
am not entirely clear _why_ it works, but it does seem to.
> -Original Message-
> From: David Winsemius [mailto:dwinsem...@comcas
On Jan 17, 2012, at 1:34 PM, Doran, Harold wrote:
Thank you, Bert. The help page doesn't have a usage example and I
can't seem to find one via google. Do you, or anyone else, have
sample code?
It did not seem particularly daring or complex when I tried this
(which does appear to produce
Dear all,
I am writing an R code to fit a Bayesian mixed logit (BML) via MCMC / MH
algorithms following Train (2009, ch. 12).
Unfortunately, after many draws the covariance matrix of the correlated random
parameters tend to become a matrix with almost perfect correlation, so I think
there is a
Sarah Jervis medschl.cam.ac.uk> writes:
>
> I am having problems using the /lme /command to fit mixed models. I have
> a data set similar to longitudinal data, except the hypothesised
> correlation is between observations taken from different individuals in
> the same family rather than from
Thank you, Bert. The help page doesn't have a usage example and I can't seem to
find one via google. Do you, or anyone else, have sample code?
> -Original Message-
> From: Bert Gunter [mailto:gunter.ber...@gene.com]
> Sent: Tuesday, January 17, 2012 1:07 PM
> To: Doran, Harold
> Cc: r-hel
On Tue, 17 Jan 2012, Bert Gunter wrote:
On Tue, Jan 17, 2012 at 8:06 AM, Kenneth Frost wrote:
Sorry, that wasn't to helpful...I see that the intervals and se.fit argument
are currently ignored.
Yes, because the fitted values are nonlinear in the parameters, which
makes finding exact confide
On 17.01.2012 18:10, RNoob wrote:
Dear all,
I am trying to apply the aggregate() function to calculate correlations for
subsets of a dataframe. My argument x is supposed to consist of 2 numerical
vectors, which represent x and y for the cor() function.
The following error results when calling
On Tue, 17 Jan 2012, crimsonengineer87 wrote:
Dear Forum,
I have been wracking my head over this problem for the past few days. I have
a dataset of (x,y). I have been able to obtain a nonlinear regression line
using nls. However, we would like to do some statistical analysis. I would
like to ob
?panel.number
This tells you what panel you're in and you can use that to determine
which line to draw.
-- Bert
On Tue, Jan 17, 2012 at 9:59 AM, Doran, Harold wrote:
> Searched archives and found some old email threads on the topic. But mot
> exactly what I think I need. Suppose I have a dataf
> Note that although ddply does a lot for you, it doesn't reproduce all of
> your calculations on all of the data columns like summaryBy does... you have
> to explicitly create every calculated column in your function.
Well, ddply doesn't, but colwise will.
Hadley
--
Assistant Professor / Dobel
Searched archives and found some old email threads on the topic. But mot
exactly what I think I need. Suppose I have a datafile such as tmp.
tmp <- data.frame(var1 = c(rnorm(1000), rnorm(1000, 1, 1)), var2 = gl(2, 1000))
I'd like a plot similar to the one below, but with an abline of v=0 in the
"R offers a bewildering array of options when it comes to representing
dates and times"
Yes & no: read www.r-project.org/doc/Rnews/Rnews_2004-1.pdf (the help
desk section)
Brief summary: 3 major ways to deal with dates/times in R:
i ) the Date class from the base distribution -- no time support,
On 17/01/2012 12:14 PM, Jake Beaulieu wrote:
R offers a bewildering array of options when it comes to representing
dates and times (e.g, as.Date, chron, strptime, zoo, etc). Can anybody
recommend a document that compares the relative merit of each method? I'm
not looking for help with any one m
Dear all,
I am trying to apply the aggregate() function to calculate correlations for
subsets of a dataframe. My argument x is supposed to consist of 2 numerical
vectors, which represent x and y for the cor() function.
The following error results when calling the aggregate function: Error in
FUN
Replying to old messages without including context (particularly old ones)
is rather bad netiquette.
Thank you for at least providing a reproducible example. Now if you can
figure out how to read the documentation we will really make some
progress.
Further responses below.
On Tue, 17 Jan 20
On 01/17/2012 11:55 AM, Essers, Jonah wrote:
Actually, I don't think I made myself clear and I wrote this late last
nightSorry. More the issue is that the raw model predictions (from 0
to 1) have no inherent clinical value to them. I.e. They aren't "risk of
disease" or "risk of outcome". They
R offers a bewildering array of options when it comes to representing
dates and times (e.g, as.Date, chron, strptime, zoo, etc). Can anybody
recommend a document that compares the relative merit of each method? I'm
not looking for help with any one method, but rather a guide that
describes wh
Actually, I don't think I made myself clear and I wrote this late last
nightSorry. More the issue is that the raw model predictions (from 0
to 1) have no inherent clinical value to them. I.e. They aren't "risk of
disease" or "risk of outcome". They are raw scores that are specific to
each model
On 01/17/2012 07:16 AM, Essers, Jonah wrote:
Thanks for the reply. I think more the issue is whether it can be applied
to cross-sectional data. This I'm not sure. This method is heavily cited
in the New England Journal of Medicine, but thus far I've only seen it
used with longitudinal data.
As
On Mon, Jan 16, 2012 at 1:13 AM, Paul wrote:
> On 16/01/12 02:08, J Toll wrote:
>> Hi,
>>
>> I'm trying to create a stacked bar plot using ggplot2. Rather than
>> plotting the count of each of the 13 "Bar" factors on the Y axis, I
>> would like to represent the sum of the Values associated with ea
Robin Lock at St Lawrence has done this for hockey, see
http://it.stlawu.edu/~chodr/faq.html
As I recall, he has a poisson regression model with parameters for
offense and defense, and perhaps home 'field' advantage.
I confess I am skeptical that this is the right approach for football
- te
On Jan 17, 2012, at 10:55 AM, kerry1912 wrote:
I am working on predicitng the scores for a days worth of matches of
team
sports. I have already collected data for the teams for the season
we are
concentrating on.
I have been fitting poisson models for football games and have
worked out
On Tue, Jan 17, 2012 at 8:06 AM, Kenneth Frost wrote:
> Sorry, that wasn't to helpful...I see that the intervals and se.fit argument
> are currently ignored.
Yes, because the fitted values are nonlinear in the parameters, which
makes finding exact confidence regions impossible. I think the "usua
I am having problems using the /lme /command to fit mixed models. I have
a data set similar to longitudinal data, except the hypothesised
correlation is between observations taken from different individuals in
the same family rather than from the same individual at different times.
As soon as I
I am working on predicitng the scores for a days worth of matches of team
sports. I have already collected data for the teams for the season we are
concentrating on.
I have been fitting poisson models for football games and have worked out
what model is best and which predictor variables are most
Hi Ken,
Thx for that advice. I took a brief look at it. I already have my curve by
just using the curve() function using the parameters a and b given by the
nls. Would se.fit and interval have computed the CI?
Maybe where I'm confused is at how I can break up my curve into pieces of
linear regres
On Jan 17, 2012, at 10:48 AM, Matthias Gondan wrote:
Dear R team, dear Prof. Therneau,
library(survival)
data(colon)
?colon
gives me only a very rudimentary source (only a name). Is there a
possibility to get a reference to the clinical trial these data
are taken from?
Wouldn't this seem to
Hi !
I am new to R and I am using Rstudio on Linux.
Have I missed some library() ?
and if so does anyone have the time to write which?
I am trying to create some PostqreSQL tables from comma separated files.
I am a bit surpriced that character is a problem. The missing value
could be NULL.
T
On Jan 17, 2012, at 10:22 AM, csrabak wrote:
Em 16/1/2012 08:07, David martin escreveu:
Hi,
I haven't found in R a possibility to draw a boxplot with a diamond
shape (means and CI).
David,
Perhaps, even prejudicially, as I cannot see any advantage on the
diamond shape for displaying just t
Sorry, that wasn't to helpful...I see that the intervals and se.fit argument
are currently ignored.
On 01/17/12, crimsonengineer87 wrote:
> Dear Forum,
>
> I have been wracking my head over this problem for the past few days. I have
> a dataset of (x,y). I have been able to obtain a nonlinear
Hi, Julian-
I'm not sure if this will be what you want but you could start by taking a look
at:
?predict.nls
Ken
On 01/17/12, crimsonengineer87 wrote:
> Dear Forum,
>
> I have been wracking my head over this problem for the past few days. I have
> a dataset of (x,y). I have been able to obtain
Dear Forum,
I have been wracking my head over this problem for the past few days. I have
a dataset of (x,y). I have been able to obtain a nonlinear regression line
using nls. However, we would like to do some statistical analysis. I would
like to obtain a confidence interval for the curve. We thou
Dear R team, dear Prof. Therneau,
library(survival)
data(colon)
?colon
gives me only a very rudimentary source (only a name). Is there a
possibility to get a reference to the clinical trial these data
are taken from?
Many thanks in advance. With best wishes,
Matthias Gondan
--
___
Inline:
Michael
On Jan 16, 2012, at 10:26 PM, Hélène Genet wrote:
> Dear all,
>
> I need to do the same procedure on several files. But I don't know how to
> refer to the file name.
> Here is an example of what I am trying to do.
>
> List of files: file1(A,B,C, D1...Dn), file2(A,B,C,E1,...
Em 16/1/2012 08:07, David martin escreveu:
Hi,
I haven't found in R a possibility to draw a boxplot with a diamond
shape (means and CI).
David,
Perhaps, even prejudicially, as I cannot see any advantage on the
diamond shape for displaying just two dimensions, I would recommend you
check if pl
You mean the process of clustering (the algorithm)? Have you looked at
kmeans.ani() in the animation package?
Regards,
Yihui
--
Yihui Xie
Phone: 515-294-2465 Web: http://yihui.name
Department of Statistics, Iowa State University
2215 Snedecor Hall, Ames, IA
On Tue, Jan 17, 2012 at 2:48 AM, muk
Perhaps I misunderstand you, but it sounds like all you need to do is change
weibull to the name of another distribution
Michael
On Jan 17, 2012, at 8:11 AM, chrisr34000 wrote:
> Hi!
>
> I want to plot the probability density function and the cumulative
> distribution function for the gamma,
Will depend heavily on the structure of your data (you haven't even told use te
number of dimensions or the metric in question), but I'd suggest something like
a scatterplot color coded by cluster with an additional marker for cluster
means.
Michael Weylandt
On Jan 17, 2012, at 3:48 AM, mukul
On Mon, Jan 16, 2012 at 6:05 PM, Mary Kindall wrote:
> Thanks for reply
> I wanted to have legend name with spaces. Right now I am using the
> following code but it produce two legends. I have to use Gimp to cut the
> redundant legend.
Your basic problem is that you're using the fill and colour
a
On Tue, Jan 17, 2012 at 6:06 AM, Scott Raynaud wrote:
> I'm setting up an Ubuntu virtual machine that will use 4-Intel Xeon CPU x5650.
> I'd like to compile R with a BLAS but the question is whcih one. Seems
> like the only free ones are GotoBLAS which I'm not sure is being maintained
> for newer
On Jan 17, 2012, at 8:02 AM, Thomas Mang wrote:
On 1/11/2012 11:07 PM, Paul Miller wrote:
Hello Everyone,
I have a question about how best to check dates for entry errors.
Try using regular expression matching and the functions grep,
strsplit, regexpr etc.
If you are not familiar with reg
Hi
>
> Hi,
>
> I am creating a function and ran into the problem of selecting a column
> from a dataset. It seems as though the $ function (as in
data$columnname)
> does not apply in the function. In simplified version:
>
> This works:
> testf2<-function(data,columnnumber){print(data[,columnn
On Jan 17, 2012, at 5:37 AM, Jeffrey Joh wrote:
I have a text file with states and numbers. I would like to display
each number that corresponds to a state on a map.
I am trying to use the maps package, but it doesn't show Alaska or
Hawaii. Do you have suggestions on how to do this?
Hi
>
> Hello all,
>
> It might be a simple question, but I cannot find the solution, as I do
not
> know which subjects I should search on. So, much thanks for he/she we
can
> help me.
> I am creating a function and would like to place a formula in the
function,
> without it being executed imme
On 17-01-2012, at 13:36, Julia Burggraaf wrote:
> Hello all,
>
> It might be a simple question, but I cannot find the solution, as I do not
> know which subjects I should search on. So, much thanks for he/she we can
> help me.
> I am creating a function and would like to place a formula in the f
On 17-01-2012, at 11:35, Nerak wrote:
> Dear all,
> I have a question about the knowing for which row I have the max value of
> one of my variables.
> I calculated the Rsquared for different columns and made a list to gather
> them. I unlisted this list to create a vector with this values. I want
On 17/01/2012 5:35 AM, Nerak wrote:
Dear all,
I have a question about the knowing for which row I have the max value of
one of my variables.
I calculated the Rsquared for different columns and made a list to gather
them. I unlisted this list to create a vector with this values. I want to
know for
On 17.01.2012 14:54, Riccardo Romoli wrote:
Hi, I use the lda function from the MASS package to classify some
samples according to some chemical properties. If I run lda without
cross validation all is ok but, if I run lda with cross validation, the
R consol say:
resLDA <- ldaRedOx <- lda(Acti
On 17.01.2012 12:31, Irek Szczesniak wrote:
Hi,
I have the simulation results of the following structure:
run par measured
1 1012
2 1014
1 2020
2 2026
Where "run" is the simulation run number, "par" is the parameter of
the simulation, and "measured" is the value mea
Hi!
I want to plot the probability density function and the cumulative
distribution function for the gamma, lognormal, exponential and Pareto
distribution. I want to vary the parameters and and have a plot with 2-3
different parameters in the same figure. It should look like this (example
weibull
I'm setting up an Ubuntu virtual machine that will use 4-Intel Xeon CPU x5650.
I'd like to compile R with a BLAS but the question is whcih one. Seems
like the only free ones are GotoBLAS which I'm not sure is being maintained
for newer CPUs and OpenBLAS for Loongson CPUs. I saw a favorable re
Hello all,
It might be a simple question, but I cannot find the solution, as I do not
know which subjects I should search on. So, much thanks for he/she we can
help me.
I am creating a function and would like to place a formula in the function,
without it being executed immediately. Like saving it
Thanks for the reply. I think more the issue is whether it can be applied
to cross-sectional data. This I'm not sure. This method is heavily cited
in the New England Journal of Medicine, but thus far I've only seen it
used with longitudinal data.
On 1/16/12 10:23 PM, "Kevin E. Thorpe" wrote:
>On
On 16.01.2012 18:00, chaps31 wrote:
Hi
"The log file (not as .odc and as .txt file) is in R'd tempdir() after
WinBUGS returns to R."
Was this my statement?
I actually meant to write *both* rather than "not" above.
Best,
Uwe
Is there any way to save the .odc file?
Ruth
--
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Dear Hélène Genet,
Re:
> Dear all,
>
> I need to do the same procedure on several files. But I don't know how to
> refer to the file name.
> Here is an example of what I am trying to do.
>
> List of files: file1(A,B,C, D1...Dn), file2(A,B,C,E1,...,En),
> file3(A,B,C,F1,...,Fn)
>
> Procedure
Dear Members,
I required to score probability of survival before specified time using
fitted cox model on scoring dataset.
On the training sample data I am able to get the probability of a survival
before time point(t), but on the scoring dataset, which will have only
predictor information I am fac
hello,
i want a visualization of the k-mean clustering.which one method
will be best for visualization??
thnkx
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Dear all,
I have a question about the knowing for which row I have the max value of
one of my variables.
I calculated the Rsquared for different columns and made a list to gather
them. I unlisted this list to create a vector with this values. I want to
know for which column I have the max value of
df<-data.frame(
group=rep(c("a","b"), c(7,6)),
sales=c(3,4,6,5,1,30,8,4,6,9,10,27,9),
turn_over=c(1.5, 2.9, 1.9,20.5, 2.3, 1.65, 0.06, 3.4, 3.5, 2.23, 0.1,
9.8,1.4)
)
Hello all,
In this data set ı need to replace the outliers with 1.5IQR for each group
and for each variable so the final data s
Hi,
I have the simulation results of the following structure:
run par measured
1 1012
2 1014
1 2020
2 2026
Where "run" is the simulation run number, "par" is the parameter of
the simulation, and "measured" is the value measured in the
simulation. This is only a simple
Hi, I use the lda function from the MASS package to classify some
samples according to some chemical properties. If I run lda without
cross validation all is ok but, if I run lda with cross validation,
the R consol say:
resLDA <- ldaRedOx <- lda(Activity ~ TRedOx[,1:6], CV=TRUE,
data=dfD
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