Hi,
I might write a little function that does different things depending
on the class of the variable. Along the lines of:
where i is a column index:
function(i) {
if (is.numeric(imputeddata[, i])) {
something
} else if (is.factor(imputeddata[, i])) {
something else
} etc.
then you can jus
A) There is a dedicated ggplot mailing list.
B) proper protocol here is to provide a reproducible example including sample
data that we can run. See the posting guide mentioned at the end of every
message.
C) create a factor (perhaps using the cut function) in your original data set,
before su
Hi all,
after using Amelia II to create 10 imputed data sets I need to average them
to have one unique data that includes the average for each cell of the
variables imputed, in addition to the values for the variables not imputed.
Such data has many variables (some numeric, other factors), and mor
Just to be precise in language, the use of:
age %in% 20:30
is only going to match exact integer values of age from 20 to 30:
> 20:30
[1] 20 21 22 23 24 25 26 27 28 29 30
That is not the same as matching any value between 20 and 30 as Michael
inferred and as our respective examples would do.
Thanks for the warning !
Better use Michael's or Marc's suggestion instead.
Stefan
-Original Message-
From: R. Michael Weylandt [mailto:michael.weyla...@gmail.com]
Sent: Thu 1/12/2012 9:05 PM
To: Schreiber, Stefan
Cc: Marc Schwartz; r-help@r-project.org; manu79
Subject: Re: [R] work wit
Almost certainly ok here -- I have just seen too many instances where
the non-standard evaluation of subset() tripped someone up in a
programming context and figured it was better to get going in the `[`
direction now rather than introducing subset() into the OP's workflow.
Best,
Michael
On Thu,
Be careful: I think that's only going to check exact equality: i.e.,
it won't find 20.5, but it also won't find 19.7 which you
might get when you mean 20 due to floating point error. If the OP has
non-integer data, this will cause trouble.
Michael
PS -- you also don't need the call to
Hi All,
If anyone is using wordcloud, do you know if it clusters word that are used
together. For example in a document if the words {bus, drive, eat, pizza}
appeared as the most frequent word, you would expect {bus, drive} to be
close to each other, whereas {eat,pizza} to be away from the other c
But better without calling your new data frame "subset" since it's a function
as well.
-Original Message-
From: r-help-boun...@r-project.org on behalf of Schreiber, Stefan
Sent: Thu 1/12/2012 8:50 PM
To: Marc Schwartz; R. Michael Weylandt
Cc: r-help@r-project.org; manu79
Subject: Re: [R]
Dear Michael,
Thank you for your clear explanation.
Best regards,
Jorge.-
On Thu, Jan 12, 2012 at 10:34 PM, R. Michael Weylandt <> wrote:
> As Jorge noted, the fix is to use "%in%": a fuller explanation of why
> `==` didn't work is that it implicitly used vector recycling: look at
>
> with(data,
Or with what I just learned:
subset<-[mydata$age %in% c(20:30),]
Thanks for explaining Michael!
Stefan
-Original Message-
From: r-help-boun...@r-project.org on behalf of Marc Schwartz
Sent: Thu 1/12/2012 8:38 PM
To: R. Michael Weylandt
Cc: r-help@r-project.org; manu79
Subject: Re: [R]
Presuming that 'DF' is the data frame, I am not sure what is wrong with
NewDF <- subset(DF, (age >= 20) & (age <= 30))
presuming that 20 and 30 are to be included.
?
Marc Schwartz
On Jan 12, 2012, at 9:26 PM, R. Michael Weylandt wrote:
> You can probably do it more easily with the subset()
As Jorge noted, the fix is to use "%in%": a fuller explanation of why
`==` didn't work is that it implicitly used vector recycling: look at
with(data, id == c("a", "c"))
implicitly, this expands to id == c("a","c", "a", "c") to get the
lengths to match. Obviously only the first elements work here
You can probably do it more easily with the subset() function but in
my experience that often leads to more problems than solutions:
perhaps try this.
idx <- with(DATA, which(age > 20 & age < 30))
DATA[idx, ]
Michael
On Thu, Jan 12, 2012 at 5:25 PM, manu79 wrote:
> Hello,
> I have a big dataset
Not sure it's doable entirely without a for-loop, but I'd suggest something like
df[which( (sapply(df, median) < 6) & (sapply(df, median) > 5))]
If your data frame has an enormous amount of rows, perhaps calculate
the sapply() call independently and reference the result twice.
You can probably d
Hi,
Use %in% instead of ==.
HTH,
Jorge.-
On Thu, Jan 12, 2012 at 9:36 PM, å欣 <> wrote:
> Hi all
> I have a question about "subset" function.
>
>
> > dat
> id x1 x2 x3
> 1 a 1 11 111
> 2 b 2 22 222
> 3 c 3 33 333
> 4 d 4 44 444
>
>
> > subset(dat,id==c("a","c"))
> id x1 x2 x3
>
Hi all
I have a question about "subset" function.
> dat
id x1 x2 x3
1 a 1 11 111
2 b 2 22 222
3 c 3 33 333
4 d 4 44 444
> subset(dat,id==c("a","c"))
id x1 x2 x3
1 a 1 11 111
> subset(dat,id==c("a","d"))
id x1 x2 x3
1 a 1 11 111
4 d 4 44 444
>From the above, if I choos
Hi all
New to R and GGplot2 but loving the potential. I am trying to plot four
separate point plots by looping over the data and plotting a different
subset each time.
When I plot the data as a point plot, the size of the points is determined
by the data values used as below
qplot(accum_rain, a
Thanks!
I read your "shoer term" solution and thanks to it was able to make stemming
working in R for Mac OS X.
I actually used Sys.setenv(NOAWT=TRUE) instead of Sys.setenv("NOAWT",
"true"), as the latter produces the following error message: Error in
Sys.setenv("NOAWT", "true") : all arguments mu
Hello,
I have a big dataset with many variables and I would like to consider
only the rows in which there is a specific value of a variable.
I make an example for explain what I mean:
I have 5 variables describing a person: age, sex, weight, colour of
hair, colour of eyes.
I have 1000 rows (10
-Tom Roche Thu, 12 Jan 2012 11:56:25 -0500>>>
> - Starting R from the resulting tramp buffer fails with either of two
> messages in buffer=*Messages*
...
> > Cannot read history file /scpc:t:/home/me/.Rhistory
This is normal. Not a problem.
> I'm
> also guessing I might have a configuration probl
Hello,
I have got a data frame df like this :
> df
e1 e2 e3 e4
1 1 11 1 21
2 2 12 2 22
3 3 13 3 23
4 4 14 4 24
5 5 15 5 25
6 6 16 6 26
7 7 17 7 27
8 8 18 8 28
9 9 19 9 29
10 10 20 10 30
where e1 ... e3 are vectors
I have to select columns which median is in the inter
Tom Roche Thu, 12 Jan 2012 11:56:25 -0500
>>> * I have access to the cluster [where I want to run R] configured
>>> [in my linux laptop's .ssh/config] such that I can `ssh t` from
>>> commandline.
Note also that I'm using keychain
http://www.cyberciti.biz/faq/ssh-passwordless-login-with-keyc
You could generate an R script using an RSP template 'main.R.rsp' containing:
<% DEBUG <- TRUE %>
<% if (!DEBUG) { %>
make_addition = function(a, b) {
<% } %>
<% if (DEBUG) { %>
a = 1
b = 2
<% } %>
c=a+b
plot(c)
<% if (!DEBUG) { %>
return(c)
}
<% } %>
which you can compile in
My best guess is that you are misunderstanding what the c() function does.
I'd suggest reading the help page for c, obtained by typing
?c
Note that if you supply c() with objects of different types (as you have),
the results will probably not be what you wanted.
Given what c() does, your output
Tom Roche Thu, 12 Jan 2012 11:56:25 -0500
>>> * I have access to the cluster [where I want to run R] configured
>>> [in .ssh/config] such that I can `ssh t` from commandline.
>>> 1 I can open an R file on the cluster with
>>> `C-x C-f /t:/home/me/onlyOrigDN2.r`
>>> from my laptop, and note
Hi,
On Thu, Jan 12, 2012 at 3:10 PM, dadrivr wrote:
> How do I subset data to only keep those rows of a dataframe where a
> variable's value matches one item of a vector. For example, how do I keep
> all of the rows (and all variables) where mydata$id equals one of the values
> in keepid? See b
How do I subset data to only keep those rows of a dataframe where a
variable's value matches one item of a vector. For example, how do I keep
all of the rows (and all variables) where mydata$id equals one of the values
in keepid? See below?
mydata <- NULL
mydata$id <- 1:30
mydata$value <- seq(fr
Peter,
The score test from the P.O. model for the global null hypothesis (k-1
degrees of freedom for comparing k groups) is almost exactly the
Kruskal-Wallis test statistic. For the case where k=2 (Wilcoxon test) the
numerator of the score test is exactly the numerator of the
Wilcoxon-Mann-Whitne
On Thu, Jan 12, 2012 at 12:12 PM, William Dunlap wrote:
> You could put your debug-only code into a function calls like
> ifDebug(diagnosticPlot(c))
> and
> ifDebug({
> tmp <- timeConsumingFunction(c)
> stopifnot(tmp < 1.0)
> })
> When you want debug output define ifDebug as
>
Uwe,
>
> The opposite: It implies it is extremely flexible in the sense a user can do
> anything the OS allows, e.g by installation of packages that reimplement
> functions you had prohibited before. I don't see why this is related to
> cloud services. In a cloud process, again, the user can do as
On 12/01/12 17:28, Hasan Diwan wrote:
I have a list of bounds for a series of polygons. I do understand the
formula to determine whether point i is within polygon X (X[x1]< i[x]
& X[x2]> i[x]& X[y1]< i[y]& X[y2]> i[y]), and I can apply this
throughout the dataset. However, this naive algor
Thank you, Thomas,
> More precisely, there are several packages that could provide separate
> sessions, such as rserve and RApache.
Thank you, we tried RServe. RApache is new for me. I've checked it: R
access through Apache server. I also found interesting blog
http://www.stat.ucla.edu/~jeroen/ w
how bout:
dat<-data.frame(val=rnorm(100,12,10),x=letters[1:4])
col.val<-ddply(dat,.(x),summarise,mean(val))
col.val$breaks<-cut(col.val$..1,c(0,9,15,Inf))
dat.merge<-merge(dat,col.val)
ggplot(dat.merge,aes(x=x,y=val,colour=breaks))+geom_boxplot()+scale_color_manual(values=c('green','yellow','red')
You are of course correct: I was trying to walk the line between using
"list" in the colloquial sense of "a set of things" that seems to have
motivated the formals of rm() and "list" in the sense of a VECSXP. In
retrospect, I probably shouldn't have relegated that important
distinction to a ill-phr
Dear R users,
I have some problems with the parLapply function from the "parallel"
package:
I use parLapply on a pretty big R object without changing the object
within the called function. If I execute parLapply alone, everything
works fine. It seems that the object resides only once in the memor
On Fri, Jan 13, 2012 at 6:12 AM, William Dunlap wrote:
> You could put your debug-only code into a function calls like
> ifDebug(diagnosticPlot(c))
> and
> ifDebug({
> tmp <- timeConsumingFunction(c)
> stopifnot(tmp < 1.0)
> })
> When you want debug output define ifDebug as
>
Additional question: the plyr package mentions that parallel computation can
be set up using the parallel computing backend from 'foreach'.
Is this limited to executing the following two lines on a UNIX machine
(source
http://cran.r-project.org/web/packages/doMC/.../gettingstartedMC.pdf
getting
The code below shows that
(1) the way to activate the parallel backend indeed is to use 'registerDoMC'
(2) the function d_ply does NOT accept the argument parallel, while the
function ddply does. Perhaps it is interesting to add this feature to d_ply,
l_ply and a_ply too? As a workaround one can of
ggplot(dat.melt,aes(x=width,y=value,fill=variable,colour=variable))+geom_density(stat='identity',alpha=0.5)
the fill and colour variables can be removed if you want.
or
ggplot(dat.melt,aes(x=width,y=value,fill=variable))+geom_density(stat='identity',alpha=0.5)+facet_wrap(~variable,ncol=1)
same
mun.ca> writes:
> I have a post I would like to put on the "95% confidence intercal with glm"
> thread. Thank-you so much!
Sending it where you did and titling it "Re: 95% confidence interval
with glm" might add it to the same thread, but even if not it will
be in roughly the right place.
On Jan 12, 2012, at 14:11 , Frank Harrell wrote:
> The Kruskal-Wallis test is a special case of the proportional odds ordinal
> logistic model.
Eh? Can you elaborate on that?
I would expect that at best it is equivalent to some _test_ in a polr-type
model. It is never really clear what the mod
On Jan 12, 2012, at 12:04 PM, R. Michael Weylandt wrote:
Nope - you misunderstand entirely. Both of those functions have an
argument named "list" and the code you quote is just the standard
way of using a named argument. It could just as well read
rm(salmon = ls())
but that would be absur
The usual way to pose questions about "unexpected behavior" is to look
up the package maintainer's name and email address in the DESCRIPTION
file of the package which is accessed with the help function:
help(package=coin)
You see:
Maintainer: Torsten Hothorn
--
David
On Jan 9, 2012, at 4:
Use a version from the archives available on the link you quoted.
If you really want the current version, you could try to change the dependency
before installation but I imagine the maintainer put it there for good reasons.
Of course, the real answer is to update R.
Michael
PS - If I remem
Hi this is exactly what i am looking for but I do not like to draw as
histogram instead I want two separate plot for this data. Something like
the ones shown in the following link. Please disregard the legends of the
following fig.
http://had.co.nz/ggplot2/graphics/55078149a733dd1a0b42a57faf8470
You missed the "Old Sources" link under "Downloads:" on that page (which most
CRAN packages have):
http://cran.r-project.org/src/contrib/Archive/fields/
You can then download the appropriate tarball version and install the package
locally.
HTH,
Marc Schwartz
On Jan 12, 2012, at 11:17 AM, M
http://cran.r-project.org/web/packages/fields/index.html
As you can see, it clearly stated that "> 2.13"...
I thought in Linux, we default to download and build from the source...
using "install.packages()" ...
How do I really build it for 2.12?
On Thu, Jan 12, 2012 at 11:12 AM, R. Michael W
On Thu 12 Jan 2012 09:02:27 AM PST, Mary Kindall wrote:
Hi
I have a data frame in the following form. There are two groups and for
each 'width' relative frequency for group1 and group2 is given. How to plot
this in R using ggplot or other package.
Width relativeFrequency1 relativeFreq
Hi Tom,
a few answers to your questions:
On Mon, Jan 9, 2012 at 3:54 PM, Tom Roche wrote:
>
> :-) I guess I should have explained: I need to copy most of a source
> file, modifying only part, and to write a target file. So my motivation
> for this thread is, first, to be sure I can do the copyi
I assume you mean it's not on CRAN. You'll have to build from source. The
easiest way to do so is with the "type" argument to install.packages()
Michael
On Jan 12, 2012, at 12:05 PM, Michael wrote:
> Hi all,
>
> I am installing a package called "fields" but it's for R version > 2.13...
>
> I
You could put your debug-only code into a function calls like
ifDebug(diagnosticPlot(c))
and
ifDebug({
tmp <- timeConsumingFunction(c)
stopifnot(tmp < 1.0)
})
When you want debug output define ifDebug as
ifDebug <- function(expr) force(expr)
and when you don't want it de
Oh, indeed. Thanks, Jim and Michael for clarifying, and making me aware of
my incorrect inference!
Adi
On Thu, Jan 12, 2012 at 6:04 PM, R. Michael Weylandt <
michael.weyla...@gmail.com> wrote:
> Nope - you misunderstand entirely. Both of those functions have an
> argument named "list" and the c
Hi all,
I am installing a package called "fields" but it's for R version > 2.13...
I only have R 2.12 on Linux.
How do I find the earlier version of "fields"?
Thanks a lot!
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing
Hi
I have a data frame in the following form. There are two groups and for
each 'width' relative frequency for group1 and group2 is given. How to plot
this in R using ggplot or other package.
Width relativeFrequency1 relativeFrequency2
1 100 0.0006388783 0.02265428
2 200 0.0022677303
Nope - you misunderstand entirely. Both of those functions have an argument
named "list" and the code you quote is just the standard way of using a named
argument. It could just as well read
rm(salmon = ls())
but that would be absurd. The list argument gets its name from the fact it
(usually)
Read the documentation for those two commands and you will see that
'list' is just a parameter to the function. It would have been called
'xyz' and worked the same. The is nothing special about 'list =' in
this context; it is just naming a parameter to the function.
On Thu, Jan 12, 2012 at 11:55
Dear all,
I have noticed that the expression 'list =' is sometimes used to tell R to
evaluate something before executing it.
Two examples:
rm(list=ls())
a = 3
myVarName = 'a'
save(list=myVarName, file=...)
I was wondering whether there is any documentation on this way of using
"list". Which i
I have a boxplot of Production run rates per 10 minute intervals and I would
like to color code them by the average (i.e. >15ppm = green, <9ppm = red,
everything else yellow).
Is there a way to do this?
http://r.789695.n4.nabble.com/file/n4289381/RunRateBoxWhisker.png
--
View this message in co
haplo.stats, version 1.5.2, is now available on CRAN.
Below I provide the description and link to our software page where you
can also find the updated user manual. The most notable updates for this
version were to make the haplo.glm fitted object work more like the glm
object; other changes are
Good day everyone, I am using the data below to fit Intervention Time Series
model for two policies introduced in 2002 (54th data point) and 2003 (55th data
point) respectively. Please can anyone give me a complete R code for modeling
the two step functions? I have already modeled the pre-interv
Hi,
I'd like to know if there is an equivalent for #ifdef (Clangage) in R. I 'd
like to do something like:
useDebug = defmacro(DEBUG, expr=(DEBUG==1))
if(useDebug(0)){
#Here I do not use debug mode
make_addition = function(a, b) {
c=a+b
plot(c)
return(c)
}
}e
Dear R Users,
How can I prevent solve.Qp from printing the solution progress ?
Thanks in advance,
Tolga
This email is confidential and subject to important disclaimers and
conditions including on offers for the purchase or sale of
securities, accuracy and completeness of information, viruses,
con
As a slight aside, Tibco/Spotfire originally planned to provide a capability
to load R packages into S-Plus. This always seemed to me to be a hard thing
to do, and if my understanding is correct, this proved to be too difficult
to do in S-Plus, at least for large packages such as mine.
Frank
Ter
Medimel gmail.com> writes:
>
> Dear Sir/ Madam,
>
> I'm having trouble de-bugging the following - which works perfectly
> well with optim or optimx - but not with mle2.
> I'd be really grateful if someone could show me what is wrong. Many
> thanks in advance. JSC:
>
mle2 is built on mle
Dear all,
I have a question regarding the possibility of parallel computation in plyr
version 1.7.
The help files of the following functions mention the argument '.parallel':
ddply, aaply, llply, daply, adply, dlply, alply, ldply, laply
However, the help files of the following functions do not
What is wrong is that you define and use parameters and global data
inconsistently in your functions.
v <- 6
f <- function( x ) { x^2 }
g <- function( x ) { v^3 }
f(v) # right answer
g(v) # right answer, accidentally
f(5) # works as expected
g(5) # surprise
You need to go through your functions
If you need the animation in a file outside of R (or possibly in R) then look
at the animation package. This allows you quite a few options on how to save
an animation, some of which depend on outside programs, but options mean that
if you don't have one of those programs there are other ways t
On Jan 12, 2012, at 9:54 AM, Manta wrote:
> It was already done, as I reduced the dataset at the minimum I could. I
> really need to solve this issue somehow.
What VM are you using on what underlying OS?
Perhaps the VM configuration is limiting memory allocation in some fashion for
applicat
Dear useRs,
Rook version 1.0-3 has been submitted to CRAN. In the mean time you
can get it here:
https://github.com/jeffreyhorner/rRack/blob/master/Rook_1.0-3.tar.gz
The latest release contains support for deployment with rApache. Please see
3.6.5 and 3.6.6 under section 'Configuring rApache' i
It was already done, as I reduced the dataset at the minimum I could. I
really need to solve this issue somehow.
--
View this message in context:
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Sent from the R help mailing list archive at Nabble.com.
___
On Wed 11 Jan 2012 08:28:03 PM PST, Hasan Diwan wrote:
I have a list of bounds for a series of polygons. I do understand the
formula to determine whether point i is within polygon X (X[x1]< i[x]
& X[x2]> i[x]& X[y1]< i[y]& X[y2]> i[y]), and I can apply this
throughout the dataset. However,
Because it uses regexp: use split='\\.' to split on "." char
and read help(strsplit) :)
Ryszard
--
Confidentiality Notice: This message is private and may contain confidential
and proprietary information. If you have receiv
Hi Ryszard,
Try
strsplit("a.b", "[.]")[[1]]
and see "Extended Regular Expressions" in ?regexp.
HTH,
Jorge,-
On Thu, Jan 12, 2012 at 10:15 AM, Czerminski, Ryszard <> wrote:
> Any ideas what is wrong?
>
> > strsplit("a.b", ".") # generates empty strings with split="."
> [[1]]
> [1] "" "" ""
>
Reread the help for strsplit:
## Note that 'split' is a regexp!
## If you really want to split on '.', use
unlist(strsplit("a.b.c", "\\."))
## [1] "a" "b" "c"
## or
unlist(strsplit("a.b.c", ".", fixed = TRUE))
For your example:
> strsplit("a.b", "\\.")
[[1]]
[1] "a"
On Thu, Jan 12, 2012 at 9:59 AM, Michael wrote:
> I usually display each 200x200 data as a heatmap...
>
> And now I only need to make a movie out of them...
That was the part I was querying: do you need to be able to upload
this to YouTube?
Embed in a presentation? Look at it by yourself on your
Any ideas what is wrong?
> strsplit("a.b", ".") # generates empty strings with split="."
[[1]]
[1] "" "" ""
> strsplit("a b", " ") # seems to work fine with split=" ", and other
characters...
[[1]]
[1] "a" "b"
>
> R.Version()
$platform
[1] "x86_64-unknown-linux-gnu"
$arch
[1] "x86_64"
$os
[1] "l
Dear all,
I would compare two means between cases and controls taking
into account that I have matched 1 case
to two controls. How i can do it with R.
Thanks in advance
Jan
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing
Many thanks! Never used lists before, but it’s a great solution! It works
very well!
Although, I have a next question concerning this.
I want to know for which value (column) I have the maximal Rsquared.
Therefore, I unlist the LIST so that it’s written like a vector.
The columns were always na
Dear Sir/ Madam,
I'm having trouble de-bugging the following - which works perfectly
well with optim or optimx - but not with mle2.
I'd be really grateful if someone could show me what is wrong. Many
thanks in advance. JSC:
gompertz<- function (x,t=data)
{
a3<-x[1]
b3<-x[2]
I just saw a little mistake in my last post: Totally in the end, last line of
the last loop, results$depth[,u] [t-1] should be results$newdepth[,u] [t-1].
My apologies.
for (u in 1:91)
{
results$newdepth [,u]<- results$depth [,u]
for (t in 2:60)
{
results$newdepth[,u][t] <- results$newdepth[,u] [t
Perhaps clearing unneeded objects our of your workspace with rm() might save a
little memory but it's hard to say if that actually helps.
Michael
On Jan 12, 2012, at 8:11 AM, Manta wrote:
> Dear Uwe,
>
> many thanks for your message. To reply to your questions, as you imagined I
> cannot pro
Dear everyone, I need R codes to fit an Intervention Time Series Model for two
separate policies for a single observed time series.
Please, I have prior knowledge of how to fit the impact parameter(omega) but I
no not the codes for the decay parameter(delta). Can someone help me?
[[altern
Basically I wanted to find an equivalent of the following Matlab command in
R:
http://www.mathworks.com/help/toolbox/images/ref/immovie.html
On Thu, Jan 12, 2012 at 8:46 AM, Sarah Goslee wrote:
> [deleted the annoying cross-posting]
>
> On Thu, Jan 12, 2012 at 9:38 AM, Michael wrote:
> > Hi
I usually display each 200x200 data as a heatmap...
And now I only need to make a movie out of them...
I don't have ImageMagick (not admin)...
Any more pointers?
Thanks a lot!
On Thu, Jan 12, 2012 at 8:46 AM, Sarah Goslee wrote:
> [deleted the annoying cross-posting]
>
> On Thu, Jan 12, 2012
[deleted the annoying cross-posting]
On Thu, Jan 12, 2012 at 9:38 AM, Michael wrote:
> Hi all,
>
> I have an array of 1 x 200 x 200 numbers... which is a time-series of
> 200x200 2D data...
>
> The 1st dimension is the time index.
>
> Is there a way to make a movie out of these data - i.e. pl
John,
Spotfire is a menu driven data exploration tool, very popular here
with biologists who found that their previous Excel based approach
doesn't cut it for large data sets. When TIBCO wanted to expand the
tool with further quantitative features they made (I think) a bright
decision to purchas
Michael,
Please don't cross post to both lists. If it doesn't have to do with
finance, don't send it it r-sig-finance.
Thanks,
Garrett
On Thu, Jan 12, 2012 at 8:38 AM, Michael wrote:
> Hi all,
>
> I have an array of 1 x 200 x 200 numbers... which is a time-series of
> 200x200 2D data...
>
Hi all,
I have an array of 1 x 200 x 200 numbers... which is a time-series of
200x200 2D data...
The 1st dimension is the time index.
Is there a way to make a movie out of these data - i.e. playback 1
frames(200x200) at a playback rate per second?
Thanks a lot!
[[alternative HT
You have to load the gtools package via library() or require() before
you can make use of the function.
Uwe Ligges
On 12.01.2012 12:18, ikuzar wrote:
Hi everybody,
I want to use macro in my R code. But defmacro was not in my libraries. So I
installed it :
install.packages("gtools")
Install
On 12.01.2012 13:21, gli wrote:
thanks for the help, Duncan. but when you said "study some geometry",
He meant basic school maths, I suppose.
Uwe
do you
mean the rgl package pdf reference mannual or other documents? please
clarify. i am a total beginner on rgl.
graham
--
View this messa
Works for me. Did you actually load the library or just install it?
Try this:
library(gtools)
example(defmacro)
Michael
On Thu, Jan 12, 2012 at 6:18 AM, ikuzar wrote:
> Hi everybody,
>
> I want to use macro in my R code. But defmacro was not in my libraries. So I
> installed it :
>
>> install.
thanks for the help, Duncan. but when you said "study some geometry", do you
mean the rgl package pdf reference mannual or other documents? please
clarify. i am a total beginner on rgl.
graham
--
View this message in context:
http://r.789695.n4.nabble.com/RGL-Drawing-Circle-tp4278717p4288776.ht
Hi there
I have a post I would like to put on the "95% confidence intercal with glm"
thread. Thank-you so much!
I am wondering first of all if anyone knows how to calculate confidence
intervals for a GLMM? I use the lme4 library.
Also, I am wondering how to predict a model mean and confidence
Hi,
i was working with this model
> mq<-glm(rojos~edadysexo*zona*estacion,quasipoisson)
and i get this minimal adequate model
> anova(mq5,test="F")
Df Deviance Resid. Df Resid. DevFPr(>F)
NULL518 64799
edadysex
Hi everybody,
I want to use macro in my R code. But defmacro was not in my libraries. So I
installed it :
> install.packages("gtools")
Installing package(s) into ‘C:/Program Files/R/R-2.13.2/library’
(as ‘lib’ is unspecified)
essai de l'URL
'http://cran.cict.fr/bin/windows/contrib/2.13/gtools_2.
Hi all,
I'm trying to do some data manipulation using R, but I'm a bit stuck. I have
to warn you, I'm a real R noob.
I have for example this file:
V1 V2 V3 V4
V5V6
1:156706559
The Kruskal-Wallis test is a special case of the proportional odds ordinal
logistic model. You can get any contrast you want by testing regression
coefficients. In a couple of weeks the rms package's contrast function
will allow for individual confidence intervals of effects that together have
a
Dear Uwe,
many thanks for your message. To reply to your questions, as you imagined I
cannot provide a reproducible example. In addition, I cannot expand the
memory, as I'm working on a virtual desktop. At any rate, the program is
really on 'standstill' as the memory usage is flat and does not mov
On Jan 12, 2012, at 13:38 , carol white wrote:
> The OS is fedora 10. It's also a 32-bit architecture.
>
10? Aren't they at 15 or 16 by now?
I guess you need
yum install readline-devel
or thereabouts.
> Best,
>
>
>
> - Original Message -
> From: peter dalgaard
> To: carol whit
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