I think I have it and my apologies for spamming the list. I should
not work this late on Sunday :-)
I think that it should be
as.integer(regexpr("$$", my.text.vector)
2011/10/16 Henri-Paul Indiogine :
>
> I tried the following
>
> as.integer(regexpr("??", my.text.vector)
--
Henri-Paul Indio
Hi!
I need to find the position of the last character (could be empty
space) of a vector of text files (my.text.vector) that I have read
into R. I tried Google, but all I have found needs a pattern.
I tried the following
as.integer(regexpr("??", my.text.vector)
but it returns 1 or even the cor
Hi,
You could also pad the text labels with phantom 0s,
ghostrighter <- function(x, ...){
n <- sapply(x, nchar)
nmax <- max(n)
padaone <- function(ii){
si <- paste(rep("0", length= nmax - n[ii]), collapse="")
as.expression(bquote(phantom(.(si)) * .(x[ii]) ))
}
sapply(seq_along(
It is good to provide the code but please make sure it is
reproducible? e.g. XZ is not defined in mgram(XY,XZ)?
Weidong Gu
On Sun, Oct 16, 2011 at 7:10 PM, Nevil Amos wrote:
> I would like to put confidence intervals on a mantel corellogram
> they are already calculated in the pmgram object but
On 17/10/11 12:12, Matt Curcio wrote:
Greetings All,
What is the procedure to make the open screen for R silent. I would
to have my opening screen in Ubuntu 10.04 linux open to an empty
terminal. Instead of the list of licenses and version of R that is
being run. By the way, I am using RStudio
Hello,
I have a log likelihood function that I was able to optimize using
mle2. I have two years of the data used to fit the function and I would
like to fit both years simultaneously to test if the model parameter
estimates differ between years, using likelihood ratio tests and AIC.
Can an
Hi all,
I consider myself a somewhat experienced user of R, but have struggled with
this for a while now. to the point where I just end up pulling the entire graph
together in powerpoint and fixing it up from there.
How does one adjust the horizontal/vertical positions of axis titles? I've
tried
Well don't I feel silly now.
Thanks for the help!
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_
Hello
I'm wanting to understand more about ptrend (a statistical explanation via an
internet website if possible) and also to know what package in R would produce
a ptrend.
Appreciate any help I can get on this as I'm trying to read and understand an
epidemiological paper and data and rep
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf Of David Winsemius
> Sent: Sunday, October 16, 2011 1:59 PM
> To: Jeff Newmiller
> Cc: r-help@r-project.org; syrvn
> Subject: Re: [R] Which function to use: grep, replace, substr etc
Thanks for the clarification. I stand corrected.
Dennis
On Sun, Oct 16, 2011 at 5:48 PM, gj wrote:
> David is right. I am looking for the ecfd for fs$numstudents. The
> other column is just an id.
>
> I guess I don't know how to read the R documentation when it comes to
> functions.
>
> looking
Hi,
On Sun, Oct 16, 2011 at 8:48 PM, gj wrote:
> David is right. I am looking for the ecfd for fs$numstudents. The
> other column is just an id.
>
> I guess I don't know how to read the R documentation when it comes to
> functions.
>
> looking at the documentation, i now notice that it says "Com
David is right. I am looking for the ecfd for fs$numstudents. The
other column is just an id.
I guess I don't know how to read the R documentation when it comes to functions.
looking at the documentation, i now notice that it says "Compute an
empirical cummulative distribution function and not a
Hi,
I have spent a few hours on the R-exts manual and the documentation of
parse_Rd() (as well as the PDF document in the references), but I
still have not figured out what results=rd means. I thought I could
use an R code fragment to create an Rd fragment dynamically. Here is
an example, in which
[cc'ed back to r-help]
I've started to take a look, and there's nothing immediately obvious
about the problem with the fit (the warnings and errors are about a
"non-positive-definite Hessian", which usually means an
overfitted/poorly identified model) -- still working on whether there's
a way to
Hi
On 16/10/2011 6:17 p.m., Richard M. Heiberger wrote:
How can I right justify the right-axis tick values? They appear in the
example below as left-justified.
I have tried several different ways and all fail in different ways.
The example below creates the right axis tick value with no attem
Hi,
The x value you want is lag from my.mgram$mgram
You can use lines() to add them to the plot.
Sarah
On Sun, Oct 16, 2011 at 7:10 PM, Nevil Amos wrote:
> I would like to put confidence intervals on a mantel corellogram
> they are already calculated in the pmgram object but I am unsure how I
I would like to put confidence intervals on a mantel corellogram
they are already calculated in the pmgram object but I am unsure how I
get the x value in order to plot them?
package(ecodist)
X<-1:100
Y<-rnorm(1:100)
Z<-rnorm(1:100)
XY<-dist(data.frame(X,Y))
YX<-dist(data.frame(Y,X))
my.mgram<-
On Oct 16, 2011, at 3:55 PM, Cliff Clive wrote:
It's easy to run a linear regression on a simple model without an
intercept
just by doing this:
lm(y ~ x1 + x2 -1)
Is there a similar trick to suppress the intercept when your model
is in a
large dataframe and you don't want to write out th
On Oct 16, 2011, at 3:08 PM, Jonas Stein wrote:
Hi,
how can i set the position of the first and last tick to the
borderline of a plot?
The plot should look like this one made in Gnuplot [1].
Gnu-R adds some space between the ticks and the end of plot.
do you mean like this?
plot(rnorm(25),
On Oct 16, 2011, at 3:53 PM, Dennis Murphy wrote:
Hi:
I don't understand what you're attempting to do. Wouldn't courseid be
a categorical variable with a numeric label? If that is so, why are
you trying to compute an EDF? An EDF computes cumulative relative
frequency of a random variable, whic
On Oct 16, 2011, at 1:32 PM, Jeff Newmiller wrote:
Note that "male" comes before "female" in your data frame.
---
Jeff Newmiller The . . Go Live...
syrvn wrote:
Hi,
thanks for the tip! I do it as follows now
On Sun, Oct 16, 2011 at 12:55 PM, Cliff Clive wrote:
> It's easy to run a linear regression on a simple model without an intercept
> just by doing this:
>
> lm(y ~ x1 + x2 -1)
>
>
> Is there a similar trick to suppress the intercept when your model is in a
> large dataframe and you don't want to w
Hi,
how can i set the position of the first and last tick to the
borderline of a plot?
The plot should look like this one made in Gnuplot [1].
Gnu-R adds some space between the ticks and the end of plot.
[1] http://commons.wikimedia.org/wiki/File:Atmospheric_radiocarbon_1954-1993.svg
kind rega
It's easy to run a linear regression on a simple model without an intercept
just by doing this:
lm(y ~ x1 + x2 -1)
Is there a similar trick to suppress the intercept when your model is in a
large dataframe and you don't want to write out the names of individual
columns?
--
View this message in
Hi,
no, don't use kmeans with factors.
The kmeans algorithm does, besides other things, calculate the mean of the k
clusters.
But you don't get a useful mean from factors, because the internally used
integers are arbitrary. In this case its 1,2 and 3. But it could be 42, 7
and 10 as well, whi
On Sun, Oct 16, 2011 at 7:20 AM, Duncan Murdoch
wrote:
> On 11-10-16 8:57 AM, Bogaso Christofer wrote:
>>
>> Dear all, can somebody please update me on what could be the best editor
>> to
>> write and edit the RD files? I need to something with syntax highlighter,
>> auto-completion etc (like Note
Hi:
I don't understand what you're attempting to do. Wouldn't courseid be
a categorical variable with a numeric label? If that is so, why are
you trying to compute an EDF? An EDF computes cumulative relative
frequency of a random variable, which by definition is numeric. If we
were talking about E
Hi:
Try this:
ratok <- data.frame(Id = rep(1:3, 3:1), value = c(2, 3, 4, 2, 1, 5))
aggregate(value ~ Id, data = ratok, FUN = mean)
Id value
1 1 3.0
2 2 1.5
3 3 5.0
aggregate() returns a data frame with the Id variable and mean(value).
HTH,
Dennis
On Sun, Oct 16, 2011 at 6:53 AM, Hel
Hi,
Thank you .. The information was very helpful.
Yes.It was meant to be centers=3.Even with that , kmeans gives error if we
give the index of Species columns.
So, *is it ok to use kmeans for String data by using cbind*.But,
kmeans*works even if we give a column which contains distinct String
Hi,
I suspect your column Species is of class "factor" (as it is in R's built in
iris dataset).
This means that in your case Species is an integer vector with the
additional information of the levels names. kmeans is internally calling
as.matrix(), which creates a character matrix of your datafram
On Sun, 16-Oct-2011 at 09:08AM -0700, M3Mph15 wrote:
|> Hey, I'm new to R. I wrote a script for doing several statistic tests and
|> plot. is there any way to add a kind of pause function which halts script
|> execution until a key is pressed. Please help fast if you can
?browser
|>
|> --
|> V
In addition to Michael's suggestion, if what you want to pause is the
creation of graphs, set:
par(ask = TRUE)
see ?par for details. It makes it so that user input is required
between each graph plotting.
Cheers,
Josh
On Sun, Oct 16, 2011 at 9:08 AM, M3Mph15 wrote:
> Hey, I'm new to R. I wro
Perhaps something like this (stolen from the demo() code):
readline("\nType \t to start : ") # If you don't want the
auto-print "" and are running it interactively, a call to invisible()
might help.
Michael Weylandt
On Sun, Oct 16, 2011 at 12:08 PM, M3Mph15 wrote:
> Hey, I'm new to R. I wrote
Perfect. Thank you David.
Since I almost always want right-axis numeric ticks to be right justified,
I will include this function as part of the next version of the HH package
(any day now), listing you as author.
Would you consider sending this as a proposed patch to lattice? As a patch
it migh
Note that "male" comes before "female" in your data frame.
---
Jeff Newmiller The . . Go Live...
DCN: Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playing
Research Engineer (Solar/Batteries O.O#. #.O#. with
/S
Hi,
thanks for the tip! I do it as follows now but I still have a problem I do
not understand:
abbrvs <- data.frame(c("peter", "name", "male", "female"),
c("P", "N", "m", "f"))
colnames(abbrvs) <- c("pattern", "replac
Hey, I'm new to R. I wrote a script for doing several statistic tests and
plot. is there any way to add a kind of pause function which halts script
execution until a key is pressed. Please help fast if you can
--
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http://r.789695.n4.nabble.com/need-help-in-pausing-a-s
On Oct 16, 2011, at 12:35 PM, syrvn wrote:
Hello,
I have a simple question but I don't know which method is best to
use for my
problem.
I have the following strings:
str1 <- "My_name_is_peter"
str2 <- "what_is_your_surname_peter"
I would like to apply predefined abbreviations for peter=p
Hello,
I have a simple question but I don't know which method is best to use for my
problem.
I have the following strings:
str1 <- "My_name_is_peter"
str2 <- "what_is_your_surname_peter"
I would like to apply predefined abbreviations for peter=p and name=n to
both strings
so that the new string
The model _is_ linear in parameters, after the log transformation of
the response, so
you don't need nlrq. If you really want something like:
y = exp(a + b x) + u
then you need to make a token effort to look at the documentation.
Here is another
example:
x <- exp(rnorm(50))
y
On Oct 16, 2011, at 11:31 AM, gj wrote:
Hi,
Newbie here. I read the R for Beginners but i still don't get this.
I have the following data (this is just an example) in a CSV file:
courseid numstudents
101 209
141 13
246 140
263
Hi,
Newbie here. I read the R for Beginners but i still don't get this.
I have the following data (this is just an example) in a CSV file:
courseid numstudents
101 209
141 13
246 140
263 8
321 10
361
chchjames windowslive.com> writes:
>
> Thanks for the reply Ben. I tried it with verbose=TRUE, and got about 7 pages
> of a word doc as an output, that ended with the error "Error in
> glmmadmb(stainp ~ beetle.ev + Caged * Section/SegmentT + (1 | :
> The function maximizer failed".
>
> I am
Hi All,
For executing kmeans for Iris, we found that there were 2 different ways.
dataFrame <- read.csv("c:/Iris.csv",header=T)
1. kmeans_model<-kmeans(dataFrame[1:5],size=3)
*This gave an error as it had Species which is a String column as one of
the inputs*
2.attach(dataFrame)
kmeans_mo
Hi,
i was looking into the documentation for the rma() function in affy()
package, and was trying to figure out how exactly the background
normalization is done. I read all three papers cited in the rma()
documentation, but the most detailed explanation i could find was in Irizary
et al., 2003, w
if you set parameter simplify=TRUE, it returns a vector of the ragged
mean. In your case,
mean_rating <- tapply(ratok$value, ratok$project_id , mean,simplify = TRUE)
df<-data.frame(ID=dimnames(mean_rating)[[1]], mean=mean_rating)
Weidong Gu
On Sun, Oct 16, 2011 at 9:53 AM, Helene Schreyer
wrot
On 11-10-16 8:57 AM, Bogaso Christofer wrote:
Dear all, can somebody please update me on what could be the best editor to
write and edit the RD files? I need to something with syntax highlighter,
auto-completion etc (like Notepad++ for R etc.). Currently I am using plain
Notepad however expect so
As usual, try reading the Help files!
?panel.lmline
-- Bert
On Sun, Oct 16, 2011 at 6:50 AM, Weidong Gu wrote:
> If you want to draw the global regression line in each panel, you can try
>
> xyplot(T~A|speaker,data=spk0,layout=c(4,5),type='p',groups=fns),
> panel=function(x,y,...){
> panel.xy
Hello,
I have a big problem which Im just not able to solve.
I created the following mean value from the following dataset structure:
Id |value
1 | 2
1 | 3
1 | 4
2 | 2
2 | 1
3 | 5
4 | 3
etc.|etc.
with the command:
mean_rating <- tapply(ratok$value, ratok$project_id , mean
If you want to draw the global regression line in each panel, you can try
xyplot(T~A|speaker,data=spk0,layout=c(4,5),type='p',groups=fns),
panel=function(x,y,...){
panel.xyplot(x,y,...)
panel.abline(lm(y~x,data=spk0))})
Weidong Gu
2011/10/16 조혜선 :
> I'd like to draw a lattice plot with groups.
On Oct 16, 2011, at 1:44 AM, Noah Silverman wrote:
> Hi,
>
> I'm looking at the "cocktail party" classic problem.
>
> I can see how to use ICA to separate the components. But, How do I then
> create new wav files of the separated sounds so that they can be played?
>
FWIW you can play sounds
Dear all, can somebody please update me on what could be the best editor to
write and edit the RD files? I need to something with syntax highlighter,
auto-completion etc (like Notepad++ for R etc.). Currently I am using plain
Notepad however expect something which could be more professional.
T
Just thought I'd let you know the following: In the gRbase package there is a
function called combnPrim which does the same as combn but it is implemented in
C - and is quite a bit faster than combn().
Regards
Søren
Fra: r-help-boun...@r-project.org [r-
On 16.10.2011 07:44, Noah Silverman wrote:
Hi,
I'm looking at the "cocktail party" classic problem.
I can see how to use ICA to separate the components. But, How do I then create
new wav files of the separated sounds so that they can be played?
Others suggested tuneR already for a former
Here is another solution that gets the order you posted:
> myArray <- c('AFP9','AFR9','TLQP7','AFS9','AFR8','AFP8','AFS7','TLQS8')
> # create a sort key
> key <- sub("^(.*)(.)(.)$", "\\3\\2\\1", myArray)
> key
[1] "9PAF" "9RAF" "7PTLQ" "9SAF" "8RAF" "8PAF" "7SAF" "8STLQ"
> # sort, but don't
Try this, but I get a different order especially based on the last digit
> myArray <- c('AFP9','AFR9','TLQP7','AFS9','AFR8','AFP8','AFS7','TLQS8')
> # create a sort key
> key <- sub("^(.*)(.)(.)$", "\\3\\2\\1", myArray)
> key
[1] "9PAF" "9RAF" "7PTLQ" "9SAF" "8RAF" "8PAF" "7SAF" "8STLQ"
> #
On 16.10.2011 13:08, Laura wrote:
Dear all,
I am a little bit confused because of the returned p-value by summary.lm and
also summary.rq
I thought if the pvalue is<= 0.05 the difference is significant. But the R
help says it is a two-sided pvalue. So does that mean the pvalue has to be
<= 0.0
No worries for the brevity. That worked exactly like I wanted. Thank you.
--
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Sent from the R help mailing list archive at Nabble.com.
___
Dear all,
I am a little bit confused because of the returned p-value by summary.lm and
also summary.rq
I thought if the pvalue is <= 0.05 the difference is significant. But the R
help says it is a two-sided pvalue. So does that mean the pvalue has to be
<= 0.025 and >= 0.975?
Best, Laura
--
Vi
I"m trying to do a custom sort in this order:
1) Numeric digit furthest right;
2) Alphabetical second furthest to the right;
3) Alphabetical the rest of the string beginning with the first character;
The example code I'm using is an array that follows:
/myArray <- c('AFP9','AFR9','TLQP7','AFS9
You are too good! Thanks a lot !
Have a nice weekend
B.R
Alexs
From: Jim Lemon
Cc: "R-help@r-project.org"
Sent: Sunday, October 16, 2011 9:10 AM
Subject: Re: [R] function for handling time
On 10/16/2011 04:13 AM, Alaios wrote:
> Dear all
> I have the followi
Thank you for your help. It works now.
2011/10/13 Jean V Adams
>
> Kristian Lind wrote on 10/13/2011 04:52:16 AM:
>
> >
> > Dear R-users,
> >
> > I'm writing a program that constructs a dataset. I wish to save the
> dataset
> > to a file.
> >
> > Here's a very simple example of what I'm trying t
Dear all,
I sent an email on Friday asking about nlrq {quantreg}, but I haven't received
any answer.
I need to estimate the quantile regression estimators of a model as: y =
exp(b0+x'b1+u). The model is nonlinear in parameters, although I can linearise
it by using log.When I write:
fitnl <- nlr
I'd like to draw a lattice plot with groups. The groups (the grouping
condition, fns) are successfully marked with separate symbols, using the
following code:
xyplot(T~A|speaker,groups=fns,pch=1:3,key=list(space="right",points=list(pch=1:3)),type=c("g","p","r"))
Here's a hard part. This draws reg
This is a 'rather than re-invent the wheel' post. Has anyone out there
re-written combn so that it can be parallelized - with multicore, snow, or
otherwise? I have a job that requires large numbers of combinations, and
rather than get all of the index values, then crank it through mclapply, I
was
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