if you set parameter simplify=TRUE, it returns a vector of the ragged
mean. In your case,
mean_rating <- tapply(ratok$value, ratok$project_id , mean,simplify = TRUE)
df<-data.frame(ID=dimnames(mean_rating)[[1]], mean=mean_rating)
Weidong Gu
On Sun, Oct 16, 2011 at 9:53 AM, Helene Schreyer
<helene.schre...@gmail.com> wrote:
> Hello,
>
>
> I have a big problem which I’m just not able to solve.
>
>
>
> I created the following mean value from the following dataset structure:
>
>
> Id |value
>
> 1 | 2
>
> 1 | 3
>
> 1 | 4
>
> 2 | 2
>
> 2 | 1
>
> 3 | 5
>
> 4 | 3
>
> etc.|etc.
>
>
>
> with the command:
>
> mean_rating <- tapply(ratok$value, ratok$project_id , mean,simplify = FALSE)
>
>
>
> this gives me a ragged array:
>
>> mean_rating [1]
>
> $`14` ###########==project_id
>
> [1] 3.933333 #######==mean value
>
>
>
>
>
>> dim (mean_rating)
>
> [1] 2214
>
>
>
> I want to separate now the project_id from the mean value. So that I have
> two separate columns (2 dimension).
>
>
>
> How can I separate a ragged array into two variables?
>
>
>
>
>
>
>
> *Additional information:*
>
> I need this information to put the mean value into another dataset
> (“projok”) at the correct project_id.
>
>
>
> I would do that as follow:
>
> k=projok[,1]
>
>
>
> for(i in 1:2442) {
>
> projLineNb = which(mean_rating$project_id==k[i])
>
> projok$mean[i] = mean_rating$value[projLineNb]
>
> }
>
>
>
> But with a ragged array I can not refer to project_id. Or is there a
> possibility that I can refer to the project_id in a ragged array?
>
>
>
>> mean_rating [[1]]
>
> [1] 3.933333 ==I can refer to the value only
>
>
>
> Thank you very much
>
> Best,
>
> Helene
>
> [[alternative HTML version deleted]]
>
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
>
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