I do not use this package, but a quick look at the code shows this.
if (!is.null(suggestions)) {
# [deleted]
suggestionCount = dim(suggestions)[1]
So 'suggestions' needs to have a dim argument (while the documentation
speaks of an 'optional list of suggested chromosomes'). You could try
Hi Tal,
Just another note, I recently joined the R2HTML team. I am still
slogging through the Sweave code trying to understand it better, but
in the coming months I will be working on implementing more of the
features in R's RweaveLatex() driver for HTML. This will not
precisely help a LaTeX to
Have you tried asciidoc (ascii package)? It seems like a good fit for
your needs.
baptiste
On 23 September 2011 11:09, Tal Galili wrote:
> Hello dear R help members,
> I have found several references on how to do this, my question is if anyone
> is actually using them - and if there are some s
Hi,
I'm interested in building a Cox PH model for survival modeling, using 2
covariates (x1 and x2). x1 represents a 'baseline' covariate, whereas x2
represents a 'new' covariate, and my goal is to figure out where x2 adds
significant predictive information over x1.
Ideally, I could get a p-val
Hi there,
I thought it would be useful to answer my own question for anybody
else searching Google.
An easy way to split a national map into smaller maps at lower levels
of aggregation is to use the function
mask()
in the package
raster
Alex
On 21 September 2011 19:20, Paul Hiemstra wrote:
>
> I have found several references on how to do this, my question is if anyone
> is actually using them - and if there are some strong points on what to use,
> and how well it is working out.
> My goal is to be able to easily create docs from R, but to be able to share
> it with other researchers (
Paul
I tested your suggestion of use the BIGLM package. With this package, model
run with out any problem.
regards
2011/9/22 David Winsemius
>
> On Sep 22, 2011, at 5:00 PM, Mario Montecinos Carvajal wrote:
>
> Michale and Paul
>>
>> Thanks for your quick response.
>>
>> Michael, I am runnin
On 11-09-22 8:38 PM, Abhijit Dasgupta wrote:
So, I was playing around a bit on my Mac
LyX can do Sweave (see http://wiki.lyx.org/LyX/LyxWithRThroughSweave), and will
actually output HTML or ODT. However, on a cursory pass, I couldn't get the
graphics to translate,
> since the Sweave driv
David
Thanks for the time that you spent in read and understand my mail, as well
as for your response and recomendations. I apologize if my attempt to put
comment in my code, not was enought.
I appreciate a lot your suggestion and I will take care of change the
variable name "length" for avoid co
I realize this may be more of a math question. I have the following optim:
optim(c(0.0,1.0),logis.op,x=d1_all$SOA,y=as.numeric(md1[,i]))
which uses the following function:
logis.op <- function(p,x,y) {
ypred <- 1.0 / (1.0 + exp((p[1] - x) / p[2]));
res <- sum((y-ypred)^2)
return(res)
}
Hello
I have a dataframe that looks like this:
Date Min Subj VAR1 VAR2 VAR3
1 8/30/2011 5min1 34.41042 126.08490 55.3548387
2 8/30/2011 10min1 34.53030 133.81343 61.600
3 8/30/2011 15min1 34.66297 118.38193 11.800
4 8/30/2011 20min1 34.82770 1
So, I was playing around a bit on my Mac
LyX can do Sweave (see http://wiki.lyx.org/LyX/LyxWithRThroughSweave), and will
actually output HTML or ODT. However, on a cursory pass, I couldn't get the
graphics to translate, since the Sweave driver translates the graphics as .ps
or .pdf files,
I don't see the problem. AFAICT, you want plots of quant vs. sampdate
by chemicals for each of the 37 streams. Essentially, you seem to want
two superimposed time plots in each panel. A time plot is a
scatterplot with a time-ordered (usually horizontal) axis.
If you use ggplot2 or lattice to gener
On Fri, 23 Sep 2011, Michael Sumner wrote:
Do you perhaps mean ?droplevels, as mentioned in See Also of subset help?
Yep. Mis-translation between the help page and the working page.
Mea culpa!
Rich
__
R-help@r-project.org mailing list
https://st
Hi, Michael & Ulisses:
ULISSES: If you haven't already, I suggest you look at the hexView
package including the R News article cited below and the readRaw
function in particular. I just used readRaw(filename, offset=4,
nbytes=8) to read bytes 5:12 in filename; in this case, filename was
*
Where is dropvalue(s) mentioned?
> ?subset
subset: logical expression indicating elements or rows to keep:
missing values are taken as false.
select: expression, indicating columns to select from a data frame.
drop: passed on to ‘[’ indexing operator.
...: further arg
Do you perhaps mean ?droplevels, as mentioned in See Also of subset help?
Otherwise, where exactly do you see 'dropvalues' referred to?
Cheers, Mike.
On Fri, Sep 23, 2011 at 9:08 AM, Rich Shepard wrote:
> While reading ?subset I'm referred to learn about dropvalues() as a
> following operation
1) I don't know about automated clipping using Audacity.
2) en.wiktionary.org/wiki/for_the_win
---
Jeff Newmiller The . . Go Live...
DCN: Basics: ##.#. ##.#. Live Go...
Live: OO#.. Dead: OO#.. Playing
Research Engineer
Hello dear R help members,
I have found several references on how to do this, my question is if anyone
is actually using them - and if there are some strong points on what to use,
and how well it is working out.
My goal is to be able to easily create docs from R, but to be able to share
it with ot
While reading ?subset I'm referred to learn about dropvalues() as a
following operation. Yet, when I issue ?dropvalue I see, "No documentation
for '?dropvalues' in specified packages and libraries:".
How do I identify the library/package that contains a specific function
such as, in this case
Hi, Carl:
1. I've used Audacity and it seemed fine -- though I haven't
used it much.
2. What's FTW? (None of the Wikipedia disambiguation entries
seemed to fit.)
Thanks,
Spencer
On 9/22/2011 2:41 PM, Carl Witthoft wrote:
With all due respect to those of us (i
On Thu, 22 Sep 2011, David Winsemius wrote:
Scatterplots are for two variables with continuous valued data. You are
asking about one such variable, apparently within some combination of
groups of discrete variables. Look at dotplot or bwplot examples.
David,
Good catch. Point noted.
Thank
On Thu, 22 Sep 2011, Dennis Murphy wrote:
Question: Do you want 37 different panels with plots of quant vs. date
by param, or two panels (one per chemical) with all 37 streams? If you
only want two of the eight chemicals,
Dennis,
I want only 2 chemicals per plot.
I'd suggest using subset(
On Sep 22, 2011, at 5:00 PM, Mario Montecinos Carvajal wrote:
Michale and Paul
Thanks for your quick response.
Michael, I am running a 32bit version of R
sessionInfo()
R version 2.11.1 (2010-05-31)
i386-pc-mingw32
Paul, the dimension of the Data Frame with I am workis is
dim(d)
[1] 7017
hello,
I want to know as mortality in different families of epiphytes after selective
logging in the forest
I want to make a survival analysis with left and right censored data. My study
begins in 2004 but I have many individuals who enter the study in 2007
I have tried this:
HI, Dennis,
Thanks for the helps! All roads to Rome, appreciated!
On Thu, Sep 22, 2011 at 2:54 PM, Dennis Murphy wrote:
> Hi:
>
> Here's one approach with package reshape2. I copied the same data
> frame 10 times to illustrate the idea, but as long as your data frames
> have the same structur
Michale and Paul
Thanks for your quick response.
Michael, I am running a 32bit version of R
> sessionInfo()
R version 2.11.1 (2010-05-31)
i386-pc-mingw32
Paul, the dimension of the Data Frame with I am workis is
dim(d)
> [1] 7017411
And the size of the file that contains the data is 2946
Hello everyone I am currently trying to conduct analysis of my graduate thesis
data using a mixed effects model and I have reached an impass. When I try to
conduct a multiple comparison, I get an error (See below): > fm3<-
lme(abovegroundbiomass.m.2~medium*amelioration*fertilizer*treatment,
ra
On Sep 22, 2011, at 6:03 PM, Rich Shepard wrote:
Data frame has this structure:
'data.frame': 11169 obs. of 4 variables:
$ stream : Factor w/ 37 levels "Burns","CIL",..: 1 1 1 1 1 1 1 1 1
1 ...
$ sampdate: Date, format: "1987-07-23" "1987-09-17" ...
$ param : Factor w/ 8 levels "As",
Hi:
Question: Do you want 37 different panels with plots of quant vs. date
by param, or two panels (one per chemical) with all 37 streams? If you
only want two of the eight chemicals, I'd suggest using subset() to
select out the pair you want and then redefine the param factor so
that the subset d
Data frame has this structure:
'data.frame': 11169 obs. of 4 variables:
$ stream : Factor w/ 37 levels "Burns","CIL",..: 1 1 1 1 1 1 1 1 1 1 ...
$ sampdate: Date, format: "1987-07-23" "1987-09-17" ...
$ param : Factor w/ 8 levels "As","Ca","Cl",..: 1 1 1 1 1 1 1 1 1 1 ...
$ quant :
Hi:
Here's one approach with package reshape2. I copied the same data
frame 10 times to illustrate the idea, but as long as your data frames
have the same structure (same variables, same dimension), this should
work.
library('plyr')
library('reshape2')
# Use your example data as the template:
ds
With all due respect to those of us (including me) who love R, when it
comes to audio processing w/ freeware,
Audacity FTW.
'nuff said
Carl
--
-
Sent from my Cray XK6
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo
Hello,
You can check ?model.frame.
I do not know however to extract only the right-hand of left-hand part
of a formula.
JC
2011/9/22 trekvana :
> Hello all,
>
> So I am using the (formula entry) method for randomForests:
>
> randomForest(y~x1+x2+...+x39+x40,data=xxx,...) but the issue is that som
Hello all,
So I am using the (formula entry) method for randomForests:
randomForest(y~x1+x2+...+x39+x40,data=xxx,...) but the issue is that some of
the items in that package dont take a formula entry - you have to explicitly
state the y and x vector:
randomForest(x=xxx[,c('x1','x2',...,'x40')],
Hi Bolker,
Sorry for the late reply and thank you very much. The code works fine.
I am indeed sorry for telling you it was a linear equation.
I am just trying to use the R code to perform the curve fitting problem for
the team of biologists. The data given to me was a sample data and they told
me
Hi Hadley,
Thank-you for your interest in the quelplot. I agree that Rand Wilcox only
published relplot code. I do not know of any other R or S implementations. I
wrote all of my code in HTBasic (Rocky Mountain BASIC) originally. I later
copied some of it to SAS proc iml, but I think that was j
Try this:
long.prop.table <- function(x) {
x <- as.factor(x)
p = tabulate(x)/length(x)
p[x]
}
Michael Weylandt
On Thu, Sep 22, 2011 at 3:41 PM, Jim Silverton wrote:
> >
> > Hi all,
> > I have a vector xm say: xm = c(1,2,3,4,5,5,5,6,6)
> >
> > I want to return a vector with the corr
If the values in xm are always going to be consecutive integers 1:n, then this:
> prob.xm[xm]
xm
1 2 3 4 5 5 5 6 6
0.111 0.111 0.111 0.111 0.333 0.333 0.333 0.222 0.222
otherwise:
> prob.xm[as.numeric(as.factor(xm))]
xm
1 2 3 4 5 5
>
> Hi all,
> I have a vector xm say: xm = c(1,2,3,4,5,5,5,6,6)
>
> I want to return a vector with the corresponding probabilities based on the
> amount of times the numbers occurred. For example, I should get the
> following vector for xm:
> prob.xm = c(1/9, 1/9, 1/9, 1/9, 3/9, 3/9, 3/9, 2/9, 2/9
On 9/21/2011 3:11 PM, Hadley Wickham wrote:
Hi all,
Does anyone have an R implementation of the queplot (K. M. Goldberg
and B. Iglewicz. Bivariate extensions of the boxplot. Technometrics,
34(3):pp. 307–320, 1992)? I'm struggling with the estimation of the
asymmetry parameters.
Do you have so
Would someone be so kind as to provide example code where they use the
suggestions argument in the rgba function
In genalg? I can't get it to work.
The following code works just fine:
GenFit <-rbga(Lower, Upper, evalFunc = evaluate)
Lower and Upper are each numeric vectors with 7 elements. Eva
On Sep 22, 2011, at 2:06 PM, Changbin Du wrote:
HI, Michael,
The following codes are great!
first.out <- do.call("cbind", list(first, result.fun))
Would this have been easier?
> dat[ , c(1:3, rep(4, 5))]
probe_name chr_id position array1 array1.1 array1.2 array1.3
1C-7SARK 1 8
HI, Michael,
The following codes are great!
first.out <- do.call("cbind", list(first, result.fun))
colnames(first.out) <- c(colnames(first), paste("array",
seq(length(result.fun)), sep=""))
> head(first.out)
probe_name chr_id position array1 array2 array3 array4 array5 array6
array7
1C-7S
Thank, Jean, appreciated your help!
On Thu, Sep 22, 2011 at 10:52 AM, Jean-Christophe BOUËTTÉ <
jcboue...@gmail.com> wrote:
> Hi,
> It's hard to provide you with working code when you don't provide a
> reproducible example, but do you really need to create variables? What
> about (untested):
>
>
Thanks Rich - unfortunately, as far as I can, tell Rand Wilcox only
developed relplot code.
Hadley
On Thu, Sep 22, 2011 at 12:52 PM, Richard M. Heiberger wrote:
> Hadley,
>
> I forwarded your request to Boris and Ken. Here is Boris' response.
>
> Rich
>
>
> Dear Richard:
>
> I looked a bit mo
Thanks so much, Michael!
head(first)
probe_name chr_id position array1
1C-7SARK 1 849467 10
2C-4WYLN 1 854278 10
3C-3BFNY 1 854471 10
4C-7ONNE 1 874460 10
5C-6HYCN 1 874571 10
6C-7SCGC 1 874609 10
for( i i
On how to use named vs. positional arguments, you can also have a look
at section 2.3 of "an introduction to R".
2011/9/22 Jean-Christophe BOUËTTÉ :
> Hi,
> It's hard to provide you with working code when you don't provide a
> reproducible example, but do you really need to create variables? What
Hi,
It's hard to provide you with working code when you don't provide a
reproducible example, but do you really need to create variables? What
about (untested):
for (i in 1:2) {
first <-cbind(first, result.fun[[i]])
}
you will then have to look at
names(first)
and change the last part of it to
Hadley,
I forwarded your request to Boris and Ken. Here is Boris' response.
Rich
Dear Richard:
I looked a bit more and found the second edition of book referenced, Rand
R Wilcox, "Introduction to Robust Estimation and Hypothesis Testing," Second
Edition, Academic Press, 2005. It has over 6
Hello,
I just upgraded to R version 2.13.1 and am running Rcmdr version 1.7-0.
Prior to the upgrade, Rcmdr returned descriptive error messages. However,
since the upgrade the only error message Rcmdr supplies is:
ERROR:
How can I convince Rcmdr to return useful error messages again?
Thanks,
Actually, I think you can make that even easier:
first.out <- cbind(first, result.fun)
Michael Weylandt
On Thu, Sep 22, 2011 at 1:37 PM, R. Michael Weylandt <
michael.weyla...@gmail.com> wrote:
> There are a few ways to proceed from here. If you are really committed to
> this loop + assign idea
There are a few ways to proceed from here. If you are really committed to
this loop + assign idea, I'd provide the following code:
for( i in 2:3) {
label <- paste("array", i, sep="")
assign(label, value = result.fun[[i-1]] )
first <- cbind(first, get(label))
}
However, this is general
For some time I have been looking for a convenient way of performing
post-hoc analysis to Repeated Measures ANOVA, that would be acceptable
if sphericity is violated (i.e. leaving aside post-hoc to lme models).
The best solution I found was John Fox's proposal to similar requests
in R-help:
http:/
HI, Michael,
I tried use x and got the following:
> for (i in 2:3) {
+
+ assign(x=paste("array", i, sep=""), value=result.fun[[i-1]])
+
+ first <-cbind(first, x)
+
+ }
*Error in cbind(first, x) : object 'x' not found
*
But I checked the
ls()
"array2" "array3"were created.
Can I
There is no "lab=" argument for assign() hence the error. Did someone
provide you with example code that suggested such a thing? remove lab=
entirely or replace it with x= to make your code work. More generally type
?assign or args(assign) to see what the arguments for a function are.
More general
HI, Dear R community,
I am trying to created new variables and put into a data frame through a
loop.
My original data set:
head(first)
probe_name chr_id position array1
1C-7SARK 1 849467 10
2C-4WYLN 1 854278 10
3C-3BFNY 1 854471 10
4C-7ONNE
Thank you very much! I'm using the first example.
For others: there are two simple typos in Henrik's email below: pretty sure
y <- this$.; should be y <- this$.y;
Thanks again...
Corrected below...
Ben
> Hello,
>
> I'd like to 'do work' on data members upon construction (i.e. without
> imple
On Sep 22, 2011, at 12:28 PM, John Kane wrote:
And I always have a problem with reshape().
Me too.
Mind you I often have similar problems with melt()
Many fewer, though.
Anyway with the data.frame xx, try
melt(xx, id=c("ID"))
Just
newdf <- melt(xx) # would have succeeded here.
And I always have a problem with reshape(). Mind you I often have similar
problems with melt()
Anyway with the data.frame xx, try
melt(xx, id=c("ID"))
--- On Thu, 9/22/11, Uwe Ligges wrote:
> From: Uwe Ligges
> Subject: Re: [R] need help on melt/cast
> To: "Eugene Kanshin"
> Cc: r-help@r
Dear Prof. Repley, may I know in details why ignoring intermediate lags are
sin? How the statistical properties will be worse than not ignoring them? If
I am correct then, ignoring some parameters means we know the population
values for them. Therefore in this case, my MSE estimate should be smalle
On Thu, Sep 22, 2011 at 9:06 AM, Ben qant wrote:
> Hello,
>
> I'd like to 'do work' on data members upon construction (i.e. without
> implementing it in a get method). Is this the best way to create data member
> 'z' upon construction? I'm thinking if .z=paste(x,y) below gets more complex
> I'll r
This should do the trick:
barplot(data, ylim=c(60,90), beside=TRUE, xpd = FALSE)
As usual, check ?barplot first for clues on how to customize the plot
to your specifications.
On Thu, Sep 22, 2011 at 11:49 AM, Benedikt Drosse wrote:
>
> Hello R-Users,
> it might be a rather simple problem I have
What timezone is this?
In America/Bogota there was no midnight that day, so the time would be
invalid. The Olson database has
# Colombia
# Rule NAMEFROMTO TYPEIN ON AT SAVELETTER/S
RuleCO 1992only- May 3 0:001:00S
R
Hi,
I am very new to R so I hope this is not stupid. Here a small example:
(I use R version 2.13.1)
library("fields")
## round pixel
x=matrix(1:100,ncol=10)
y=matrix(1:100,ncol=10)
for(i in 1:10){
x[i,] <- 1:10 + i
y[i,] <- 1:10 + i/20
}
#x=1:10
#y=1:10
z=matrix(1:
Hello R-Users,
it might be a rather simple problem I have, but I couldn't find any
solution online. Thus, here is my problem:
I would like to adjust the y-axis range in a barplot, since all my
values are >70. Therefore I would like to only visualize the y-axis from
60-100 (example 1).
The pro
Didn't Columbia switch to a year of daylight
savings time at what would have been midnight
May 3, 1992 (so midnight did not exist that day)?
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.o
Dear list, dear Cecilia and Daniel,
sorry for coming in ten days late, I've been very busy lately so I came
across this email only today.
This is just to make some points clearer re: fixed effects and r2 in
package 'plm', to both you and the list. In particular, to make you
aware of some addition
Hello,
I'd like to 'do work' on data members upon construction (i.e. without
implementing it in a get method). Is this the best way to create data member
'z' upon construction? I'm thinking if .z=paste(x,y) below gets more complex
I'll run into issues.
setConstructorS3("MyClass", function(x=NA,y=
Hi R users:
This is a very strange problem:
Why this instruction shows me NA?,
and any other date shows me that error!
as.POSIXct(strptime("1992-5-3",format="%Y-%m-%d"))
This is my R version on windows 7.
"R version 2.13.1 Patched (2011-08-25 r56794)"
Thank you for your help.
___
BFGS is actually Fletcher's (1970) variable metric code that I modified with
him in
January 1976 in Dundee and then modified very, very slightly (to insist that
termination
only occurred on a steepest descent search -- this messes up the approximated
inverse
Hessian, but I have an experimental R
Yes, I want to it with plm package for panel data in dataframes.
Thank you,
Cecília Carmo
De: R. Michael Weylandt [mailto:michael.weyla...@gmail.com]
Enviada: quinta-feira, 22 de Setembro de 2011 16:06
Para: Cecilia Carmo
Cc: r-help@r-project.org
Assunto: Re: [R] the opposite of lag()
Hi there,
I am having some trouble with NLS convergence for my function. I was
wondering if there is a way to check the value of the indicator function for
all the iterations to look at the surface of the likelihood function.
Any help would be most appreciated.
Thanks,
Diviya
[[alternat
gamm can't estimate the theta parameter for a negative binomial
automatically. It can only work with fixed user supplied values for
theta (i.e. negbin(2.3) should work, but negbin(c(1,10)) won't). Is
negative binomial the only thing you can use here (it doesn't seem like
the most natural choice
Is there perhaps a particular package you are interested in here? I'm not
aware of a "pdata.frame" function... This certainly works with the xts
class. If you just mean a regular data.frame() perhaps some of the ideas in
this old thread will work with a little tweaking:
http://www.mail-archive.com/
Hi R-helpers
I want a function that performs the opposite of lag() with panel data.
I have transformed my data before with pdata.frame(mydata,
index=c("groupindex", timeindex"))
And then Ive done lag(mydata, -1) but it doesnt work.
The error message was:
Error in rep(1, ak) : invalid
I can never remember what melt, cast and all that means, hence I simpy
use reshape() which does not even require any additional package:
reshape(dat, direction="long", idvar = "ID",
varying=list(2:4), v.names="Value", times=names(dat)[2:4])
Uwe Ligges
On 22.09.2011 15:54, Eugene Kanshin wro
If you explicitly convert your categorical covariates to factors before you
regress, you can use the dot notation (see help on lm) to refer to "the rest"
of the columns not otherwise specified in your formula.
---
Jeff Newmil
You can use function reshape(), e.g.,
DF <- data.frame(ID = LETTERS[1:3],
T0 = c(1,4,7), T1 = c(2,5,8), T2 = c(3,6,9))
DF.new <- reshape(DF, idvar = "ID", direction = "long",
varying = list(2:4), times = names(DF[-1]))
DF.new
DF.new[order(DF.new$ID), ]
I hope it helps.
Best,
Dimitris
On 22.09.2011 14:47, Andrey A wrote:
Dear R users
How does one completely uninstall R from their machine? Going to control
panel>programs does not do it for me. After installing the new version it
will still remember my previous workspace and all packages I've installed.
This seems to be Wind
?reshape
From: r-help-boun...@r-project.org [r-help-boun...@r-project.org] On Behalf Of
Eugene Kanshin [kanshin...@gmail.com]
Sent: Thursday, September 22, 2011 9:54 AM
To: r-help@r-project.org
Subject: [R] need help on melt/cast
Hello,
I need to convert d
You need to uninstall packages directly (they are kept independently of R,
which is actually quite helpful when updating so you don't have to get them
all anew): this can be done within R by combining remove.packages() and
installed.packages(). To delete the workspace you need to manually remove
th
Hello,
I am having some difficulty converting my gam code to a correct gamm code, and
I'm really hoping someone will be able to help me.
I was previously using this script for my overdispersed gam data:
M30 <-gam(efuscus~s(mic, k=7) +temp +s(date)+s(For3k, k=7) + pressure+
humidity, fam
Many thanks Gabor,
That is exactly what I needed.
Regards,
W.
>>> Gabor Grothendieck 22/09/2011 13:52 >>>
On Thu, Sep 22, 2011 at 6:48 AM, Wesley Roberts wrote:
> Dear R users,
>
>
> I am currently working in subsetting a zooreg() object using either window or
> subset. I have a solution but
Hello,
I need to convert dataframe from:
ID T0 T1 T2
A1 2 3
B4 5 6
C7 8 9
to:
ID Variable Value
A T0 1
A T1 2
A T2 3
B T0 4
B T1 5
B T2 6
C T0 7
C T1 8
C
Hi.
First, a little preliminary observation: in this thread, it is indeed a
(multiple linear) regression model, the real problem is but my opinion on
general questions about R assign.
So as I said, I want to do a regression analysis, however, for several
target variables or data tables. This ca
Dear R users
How does one completely uninstall R from their machine? Going to control
panel>programs does not do it for me. After installing the new version it
will still remember my previous workspace and all packages I've installed.
Thank you.
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On Sep 21, 2011, at 18:39 , Marc Schwartz wrote:
> Jeremy,
>
> Correlation alone is irrelevant when comparing two separate sets of
> measurements on the same specimen. Correlation does not mean good agreement,
> but good agreement tends to infer high correlation.
Marc,
I think Jeremy is well
Late, I know, but if method comparison id the interest, the methcomp package on
CRAN does Bland-Altman plots and passing-Bablock regression, both clinical
chemistry staples for method comparison.
S Ellison
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun.
Dear R users,
When running the program below I receive the following error message:
fit <- optim(parm, objective, yt = tyield, hessian = TRUE)
Error in as.vector(data) :
no method for coercing this S4 class to a vector
I can't figure out what the problem is exactly. I imagine that it has
someth
On Thu, 22 Sep 2011, Gabor Grothendieck wrote:
On Thu, Sep 22, 2011 at 6:48 AM, Wesley Roberts wrote:
Dear R users,
I am currently working in subsetting a zooreg() object using either window or
subset. I have a solution but it may be a bit cumbersome when I start working
with actual data.
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On 22/09/11 10:13, ESTEBAN ALFARO CORTES wrote:
> Thanks David,
>
> The crx.data is a different database and I would like to use both.
> I have contacted with the developer but he has not answered me.
I would suggest talk to folks using emacs, as ema
On Thu, Sep 22, 2011 at 6:48 AM, Wesley Roberts wrote:
> Dear R users,
>
>
> I am currently working in subsetting a zooreg() object using either window or
> subset. I have a solution but it may be a bit cumbersome when I start working
> with actual data. Your inputs would be greatly appreciated.
Hi
Interested in learning R programming via workshop/short course in India.
Request all to suggest any.
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the p
Dear R users,
I am currently working in subsetting a zooreg() object using either window or
subset. I have a solution but it may be a bit cumbersome when I start working
with actual data. Your inputs would be greatly appreciated.
Example: I have a zooreg() object that starts in 1997 and ends i
Thanks Cesar,
Any idea for this contents of the file?
;; positive examples represent people that were granted credit
(def-pred credit_screening :type (:person)
:pos
((s1) (s2) (s4) (s5) (s6) (s7) (s8) (s9) (s14) (s15) (s17) (s18) (s19)
(s21) (s22) (s24) (s28) (s29) (s31) (s32) (s3
Szeptember 12-től 26-ig irodán kívül vagyok, és az emailjeimet nem érem el.
Sürgős esetben kérem forduljon Kárpáti Edithez (karpati.e...@gyemszi.hu).
Üdvözlettel,
Mihalicza Péter
I will be out of the office from 12 till 26 September with no access to my
emails.
In urgent cases please contact
Thanks David,
The crx.data is a different database and I would like to use both. I have
contacted with the developer but he has not answered me.
Regards,
Esteban
De: David Winsemius [mailto:dwinsem...@comcast.net]
Enviado el: mié 21/09/2011 17:08
Para: ESTEBA
Hi Hadley,
have a look at:
http://www.riani.it/pub/zrc-csda98.pdf
and some Gauss code:
http://www.riani.it/Gauss/procedures/BOXPLOTB.G
Best regards,
Daniele
2011/9/21 Hadley Wickham :
> Hi all,
>
> Does anyone have an R implementation of the queplot (K. M. Goldberg
> and B. Iglewicz. Bivariate
Hi everybody,
If I am correct, you can compare a model with random effect with the same model
without the random effect by using the nlme function, like this:
no.random.model <- gls(Richness ~ NAP * fExp,
method = "REML", data = RIKZ)
random.model <- lme(Richness ~NAP * fExp, data
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