Hello,
yes, thanks!
Also,how do I get the cutoff similarity value which was used for
clustering when I cut the tree at a specific heigt?
Best regards,
Madeleine
On Tue, 2011-09-13 at 09:39 -0700, Mikkel Grum wrote:
> plot(clust)
> rect.hclust(clust, h = 0.65)
>
>
>
> - Original Message
On 14/09/11 17:49, anand m t wrote:
Hi all,
I'm analyzing micro array data.. it has produced a file (to be specific
matrix) withdimension of 35556 2.
first few lines of the matrix are as below..
probe_name control.fdr.pvals.present
10338001 0.000440001
10338002 0.000583093
10338003 0.000528449
Hi all,
I'm analyzing micro array data.. it has produced a file (to be specific
matrix) withdimension of 35556 2.
first few lines of the matrix are as below..
probe_name control.fdr.pvals.present
10338001 0.000440001
10338002 0.000583093
10338003 0.000528449
10338004 0.000610362
10338005 0.000151
Current systems
OS: RedHat SE Linux 5.7, fully patched
R: R-2.13.1
I am a new R user.
The R installation needs to be very tight because I plan to use it after I am
employed on Internet facing systems to analyse firewall and filesystem log
data. Everything to my knowledge regarding
On 09/13/2011 10:54 AM, Joseph Park wrote:
Hi, I'm looking for some guidance on whether to use
S4 or Reference Classes for an analysis application
I'm developing.
I'm a C++/Python developer, and like to 'think' in OOD.
I started my app with S4, thinking that was the best
Well, I've bee reading the R Manual, Nathan Yau's book on Flowing Data, and a
few others like this to my kids to get them to go to sleep. I started off
doing it the *wrong* way, just to keep it boring but slipped into doing it
the *correct* way for my own sanity. It puts the kids to sleep in no tim
varunshivashankar gmail.com> writes:
>
> I have a dataset
>
> X Y1
> 1200 1.375
> 4000 0.464
> 1333.33 0.148
> 444.440.047
> 148.148 0.014
> 49.3830.005
> 16.4610.004
>
> I have to find a curve fit for the above dataset based on a 4-parameter
> logist
I've been having trouble making sense of the drc results for my binomial
response toxicity data. Firstly, the standard errors are far too large for
how well the data fit the log-logistic model, particularly compared to other
methods of LC50 estimation (e.g. probit and trimmed spearman-karber).
Seco
Thank you, it helped me clear some confusions.
Jamie
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Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-pro
I have a dataset
X Y1
12001.375
40000.464
1333.33 0.148
444.44 0.047
148.148 0.014
49.383 0.005
16.461 0.004
I have to find a curve fit for the above dataset based on a 4-parameter
logistic equation viz.
Y1 = d + ((a-d)/(1+(X/cc)^b)), where X and Y1 are the values above.
I nee
On Tue, 13 Sep 2011, Gabor Grothendieck wrote:
In the example data there were no duplicate dates for a given param value.
Gabor,
There are duplicate dates for a given param value, but each is on a
different stream. It is the triplet (stream, sampdate, param) that is
associated with each val
On Tue, Sep 13, 2011 at 7:36 PM, Rich Shepard wrote:
> On Tue, 13 Sep 2011, Gabor Grothendieck wrote:
>
>> As in ?zoo a zoo object is a numeric matrix, numeric vector or factor
>> together with an ordered time index which is unique. Its not clear that
>> that is what you have; however, if we can a
``The only stupid question is the one that is not asked.''
--- Anon. (???)
The reason that there is no value for level "A" of treatment is
that level "A" is the reference level, under the default ``treatment''
contrasts.
See ?contr.treatment.
Some insight may be obtained by doing:
obviously not. thank you, henrik. going back to square 101. (I just
googled, because I usually find stuff faster by googling. cmyk and R
brought up nothing.)
apologies for the bandwidth, everyone.
Ivo Welch (ivo.we...@gmail.com)
On Tue, Sep 13, 2011 at 4:24 PM, Henrik Bengtsson wrote:
On Tue, 13 Sep 2011, Gabor Grothendieck wrote:
As in ?zoo a zoo object is a numeric matrix, numeric vector or factor
together with an ordered time index which is unique. Its not clear that
that is what you have; however, if we can assume that for each value of
param we have a unique set of dates
Did you ask your question being aware of the following from
help("pdf") in R v2.13.1:
pdf(file = ifelse(onefile, "Rplots.pdf", "Rplot%03d.pdf"),
width, height, onefile, family, title, fonts, version,
paper, encoding, bg, fg, pointsize, pagecentre, colormodel,
useDingbats, useKerning,
On Tue, Sep 13, 2011 at 2:07 PM, Rich Shepard wrote:
> I have read ?zoo but am not sure how to relate the parameters (x,
> order.by, frequency, and style) to my data.frame. The structure of the
> data.frame is
>
> 'data.frame': 11169 obs. of 4 variables:
> $ stream : Factor w/ 37 levels "Bur
On Sep 13, 2011, at 4:51 PM, Tianchan Niu wrote:
Thank you David for your reply. But I am still confusing.
I am using Wilcoxon test to compare two samples to assess whether
their means differ because neither of them is normally distributed.
Is it possible to compute the power of the Wilcoxon
Hi Igors
On 13 September 2011 13:27, Igors wrote:
> Any success in finding possible solutions for my problem?
Somewhat. The calculation of the log-likelihood values is numerically
much more robust/stable now. The log-likelihood contributions of some
individuals became minus infinity in your mode
dear R experts---I am struggling with the requirements to prepare my files
for my printers. I am printing in 2/2 format, which means cyan and black
for me, which they take from my color-separated pdf files. R comes into
play, because it produces all the figures that are embedded in my book
(pdfla
I feel bad even asking, but:
Rgames> data(OrchardSprays)
Rgames> model<-lm(decrease~.,data=OrchardSprays)
Rgames> model
Call:
lm(formula = decrease ~ ., data = OrchardSprays)
Coefficients:
(Intercept) rowpos colpos treatmentB treatmentC
22.705 -2.784 -1.234
I often use the following function
is.true <- function(x) !is.na(x) & x
and, less often,
is.false <- function(x) !is.na(x) & !x
to report if elements of a logical vector are TRUE (not
FALSE or NA) or FALSE (not TRUE or NA), respectively.
Do your complicated logical expression and apply is.true
On 11-09-13 5:17 PM, Timothy Bates wrote:
Dear Duncan and Hadley,
I stumbled across the NA behavior of subset a little while ago and thought it
might do the trick. But my common usage case is not getting a subsetting sans
NAs, but setting values in the whole dataframe.
So I need T/F at each r
On Tue, Sep 13, 2011 at 4:11 PM, Steve Lianoglou
wrote:
> Hi,
>
> On Tue, Sep 13, 2011 at 1:54 PM, Joseph Park wrote:
>>
>> Hi, I'm looking for some guidance on whether to use
>> S4 or Reference Classes for an analysis application
>> I'm developing.
>> I'm a C++/Python developer, and like
On Tue, Sep 13, 2011 at 12:54 PM, Joseph Park wrote:
> Hi, I'm looking for some guidance on whether to use
> S4 or Reference Classes for an analysis application
> I'm developing.
> I'm a C++/Python developer, and like to 'think' in OOD.
> I started my app with S4, thinking that was the
Dear Duncan and Hadley,
I stumbled across the NA behavior of subset a little while ago and thought it
might do the trick. But my common usage case is not getting a subsetting sans
NAs, but setting values in the whole dataframe.
So I need T/F at each row, not just the list of rows that match th
Hi,
On Tue, Sep 13, 2011 at 1:54 PM, Joseph Park wrote:
>
> Hi, I'm looking for some guidance on whether to use
> S4 or Reference Classes for an analysis application
> I'm developing.
> I'm a C++/Python developer, and like to 'think' in OOD.
> I started my app with S4, thinking that was
Thank you David for your reply. But I am still confusing.
I am using Wilcoxon test to compare two samples to assess whether their means
differ because neither of them is normally distributed.
Is it possible to compute the power of the Wilcoxon test similar to that of t
test? Or is it just a wron
Dearfolks--
I have been told by an experienced R programmer and teacher whom I trust
that it is easier to understand R code if you read it aloud, as the language
that it is. However, she was clear that reading it aloud was not simply
reading the marks on the screen: you read A.df[5,] as "the fift
On Tue, 13 Sep 2011, jekang wrote:
Hello,
It might be more of a statistical question than an R question.
I was reading
http://cran.r-project.org/web/packages/pscl/vignettes/countreg.pdf, and I
was wondering why the following functions were used to compare zero counts
(observed and predicted),
And a final word of advice: be lazy, and use
file.choose()
to get the string that R expects as a filename. This will help avoid such typos!
JC
2011/9/13 Mikkel Grum :
> You are missing \\ between Documents and settings and Administrator.
>
>
> - Original Message -
> From: dbonneau
> To:
On Sep 13, 2011, at 12:58 PM, Greg Snow wrote:
It would appear that your file is not a csv file, but we cannot tell
for sure without seeing an example of the data that you are reading
in, can you cut and paste the first few lines of the file? Or post a
link to a copy of the file. If the d
Hi All,
theoretically, I should be able (with proper proxy setting and IP
address) to connect and perform literature database searches, such as in
the ISI Web of Science, with R. I can imagine this working nicely with
the RCurl package.
I am pestering the list to ask if I missed a certain pa
On Sep 13, 2011, at 11:56 AM, David Winsemius wrote:
On Sep 13, 2011, at 11:44 AM, David Winsemius wrote:
On Sep 13, 2011, at 9:43 AM, RCulloch wrote:
Dear John,
Thank you for that, and for explaining why the abline() command
wont/dosen't
work. The approach is based on reviewers commen
On Sep 13, 2011, at 3:34 PM, tn85 wrote:
Hello All,
I perform a Wilcoxon signed rank test for two sets of data to test
whether
they two have significantly different means. I would also like to
know the
power of this test.
Given that none of the various "Wilcoxon tests" are for differen
Hello,
It might be more of a statistical question than an R question.
I was reading
http://cran.r-project.org/web/packages/pscl/vignettes/countreg.pdf, and I
was wondering why the following functions were used to compare zero counts
(observed and predicted), instead of just using
hist(fitted(fm_
Hi, I'm looking for some guidance on whether to use
S4 or Reference Classes for an analysis application
I'm developing.
I'm a C++/Python developer, and like to 'think' in OOD.
I started my app with S4, thinking that was the best
set of OO features in R. However, it appears that o
You are missing \\ between Documents and settings and Administrator.
- Original Message -
From: dbonneau
To: r-help@r-project.org
Cc:
Sent: Tuesday, September 13, 2011 10:59 AM
Subject: [R] space in directory name
Hi, I am trying to read a text file located in following paths. I am get
On Sep 13, 2011, at 10:26 AM, travellina wrote:
Hi there,
I am looking for some help with a loop which uses three list()-
objects:
"sequence" has got numbers, "start" and "end" have got the begin/end
time
points which should be applied to the numbers in "sequence".
length() of all
three o
I decided to go with circles instead of rectangles. Thank you for your help.
Here is the new code:
dev.new(width=2.5, height=3,mar=c(0,0,0,0))
par(mfrow=c(1,1),mar=c(0,0,0,0))
x=c(-1,1,1,-1,-3,-3,5)
y=c(1.2,0.6,-.7,-1.3,-.7,0.6,5)
plot(0,xlim=c(-4,2),ylim=c(-2,2),type="n",axes=FALSE,xlab="",ylab="
On Wed, 14 Sep 2011, Patrick Connolly wrote:
The objects will be available already. See what you have with the
ls() command. They are stored in .RData so the fact that you can't
read .RData directly matters not.
Patrick,
I'm aware of .Rdata and use ls() regularly outside of R. What I did n
On Tue, 13-Sep-2011 at 06:53AM -0700, Rich Shepard wrote:
|> I use ESS and have no problems invoking it when I fire up emacs. When it
|> loads it tells me, [Previously saved workspace restored]. However, I do not
|> know how to view that history of commands so I can continue what I was
|> doing.
On Tue, 2011-09-13 at 05:18 -0700, Briony wrote:
> It *really* does help to read the documentation for functions. Like most
> of the functions in vegan that extract information from ordinations,
> ordilabel() extracts information for "axes" 1 and 2 only, by default.
It also helps if I read the doc
> Because in coding, I often end up with big chunks looking like this:
>
> ((mydataframeName$myvariableName > 2 &
> !is.na(mydataframeName$myvariableName)) &
> (mydataframeName$myotherVariableName == "male" &
> !is.na(mydataframeName$myotherVariableName)))
>
> Which is much less readable/maintai
Hello All,
I perform a Wilcoxon signed rank test for two sets of data to test whether
they two have significantly different means. I would also like to know the
power of this test.
The third part of this tutorial is similar to what I want except the t
distribution. http://www.cyclismo.org/tutori
FYI,
by using
library("R.utils");
pathname <- "C:\\Documents and Settings Administrator\\My
Documents\\My Dropbox\\data.txt";
pathname <- Arguments$getReadablePathname(pathname);
data1 <- read.table(pathname, sep="\t", header=TRUE);
you would get an explanation what is wrong and helps you troubl
Jean-Christophe BOUËTTÉ gmail.com> writes:
>
> I suggest changing
> Documents and Settings Administrator
> to
> Documents and Settings\\Administrator
>
Please don't cross-post to R-help and Stack Overflow.
People in both places will gladly answer well-posed questions,
but it turns into a was
On Sep 13, 2011, at 1:17 PM, bradford wrote:
With the help of Andrie on StackOverflow.com, I was able to learn
about
ddply. I have another question that is more trivial and cannot seem
to find
help on IRC and do not want to bother Andrie again.
It's doubtful that he would have considered
On 13/09/2011 2:28 PM, Henri Mone wrote:
Dear R users and experts,
I need to modify an exisiting R function from a package. The function/
variable is inside a namespace and I have problems accessing it.
I only need to get access to to corresponding sourcecode. I localised
the "RDX" and "RDB" fil
On Sep 13, 2011, at 12:31 PM, Rawlins, Barry G. wrote:
Hello
I wish to extract the row indices from a data.frame in which a
column contains numeric data by calculating the minimum value, but
grouped on another column factor:
An example data.frame:
Codeabsdiff
NY14/3070
Hi henri,
R is open source, so you should be able to download the source code of
the package from CRAN.
JC
2011/9/13 Henri Mone :
> Dear R users and experts,
>
> I need to modify an exisiting R function from a package. The function/
> variable is inside a namespace and I have problems accessing i
The current "classwt" option in the randomForest package has been there since
the beginning, and is different from how the official Fortran code (version 4
and later) implements class weights. It simply account for the class weights
in the Gini index calculation when splitting nodes, exactly as
Dear R users and experts,
I need to modify an exisiting R function from a package. The function/
variable is inside a namespace and I have problems accessing it.
I only need to get access to to corresponding sourcecode. I localised
the "RDX" and "RDB" files. But it seems to be a binary format.
How
I have read ?zoo but am not sure how to relate the parameters (x,
order.by, frequency, and style) to my data.frame. The structure of the
data.frame is
'data.frame': 11169 obs. of 4 variables:
$ stream : Factor w/ 37 levels "Burns","CIL",..: 1 1 1 1 1 1 1 1 1 1 ...
$ sampdate: Date, format
I suggest changing
Documents and Settings Administrator
to
Documents and Settings\\Administrator
...
JC
2011/9/13 dbonneau :
> Hi, I am trying to read a text file located in following paths. I am getting
> error if I try to read from long directory.. But if I place the file right
> under C, It r
With the help of Andrie on StackOverflow.com, I was able to learn about
ddply. I have another question that is more trivial and cannot seem to find
help on IRC and do not want to bother Andrie again. I can't seem to figure
out what to google for, so I thought I'd ask here.
I have:
library(plyr)
Code <- c(rep("NY14/3070", 3), rep("NY14/5459", 2))
Code <- as.factor(Code)
absdiff <- c(2, 4, 1, 5, 7)
df <- data.frame(Code, absdiff)
which(
paste(df$Code, df$absdiff) ==
paste(
aggregate(df$absdiff, by = list(df$Code), min)$Group.1,
aggregate(df$absdiff, by = list(df$Cod
On 13/09/2011 12:42 PM, Timothy Bates wrote:
Dear R cognoscenti,
While having NA as a native type is nifty, it is annoying when making binary
choices.
Question: Is there anything bad about writing comparison functions that
behavior like %in% (which I love) and ignore NAs?
"%>%"<- function(ta
i responded offline the first time, but:
google is your friend: search for R maps and you'll find what I mention
below.
In the future make sure to perform a thorough search of google and the help
forums before you post
That said... you're looking for the maps package
install.packages('maps')
It would appear that your file is not a csv file, but we cannot tell for sure
without seeing an example of the data that you are reading in, can you cut and
paste the first few lines of the file? Or post a link to a copy of the file.
If the data is not able to be shared, then create a new (smal
The following will get you the first stock in each week. Is that useful?
install.packages("surveillance")
library(surveillance)
alldat$year <- isoWeekYear(alldat$mydate)$ISOYear
alldat$week <- isoWeekYear(alldat$mydate)$ISOWeek
alldat <- alldat[order(alldat$year, alldat$week), ]
alldat[!duplicated
Hi Michael,
First of all thanks for your response.
I do know that if I make my stimation on a single data the regression has no
sense but it will be getting sense in the growing next estimations.
I change my asking doubt.
I want to use this regressions as a first filter. Only this.
Can anyone
Dear R cognoscenti,
While having NA as a native type is nifty, it is annoying when making binary
choices.
Question: Is there anything bad about writing comparison functions that
behavior like %in% (which I love) and ignore NAs?
"%>%" <- function(table, x) {
return(which(table > x))
}
If I create an aggregation like this:
aggregate(lastYear[,8:10],list(Stadium=lastYear$STAD),mean)
I'll get a new data frame, which I can order if I assign it like this:
newFrame <- aggregate(lastYear[,8:10],list(Stadium=lastYear$STAD),mean)
newFrame[order(newFrame$TEMP),]
But.. if I just want t
Hi, I am trying to read a text file located in following paths. I am getting
error if I try to read from long directory.. But if I place the file right
under C, It runs fine. Could anyone tell me how to read table from following
directory path ?
data1 <-read.table("C:\\Documents and Settings Adm
Adding to the previous question, I would like to map central Asia along with
those five countries (Kazakhstan, Kyrgyzstan, Uzbekstan, Tajikstan and
Turkmenstan). Please tell us the right data base!!! Thanks a lot!!!
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View this message in context:
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Dear R users,
we are trying to build a R package that includes a precompiled shared
library, let's say mylib.so. We created the skeleton of the package
and we moved the mylib.so file into the libs folder that we created at
the same level of the folders man and R. Moreover we created the file
NAMES
Hello
I wish to extract the row indices from a data.frame in which a column contains
numeric data by calculating the minimum value, but grouped on another column
factor:
An example data.frame:
Codeabsdiff
NY14/3070 2
NY14/3070 4
NY14/3070 1
NY14/5459
Hi, I used read.csv(file name, header=T, sep=",") to bring in a csv file I
saved in MS Excel. The strange thing is all the data ended up in one big
column. The number of rows match with the number of observations, but all
the variables got squeezed into one column. Also the first row where the
head
plot(clust)
rect.hclust(clust, h = 0.65)
Is that what you wanted?
- Original Message -
From: Madeleine Seeland
To: r-help@r-project.org
Cc:
Sent: Tuesday, September 13, 2011 9:25 AM
Subject: [R] help with hclust and cutree
Hello,
I would like to cut a hclust tree into several groups
On Sep 13, 2011, at 11:44 AM, David Winsemius wrote:
On Sep 13, 2011, at 9:43 AM, RCulloch wrote:
Dear John,
Thank you for that, and for explaining why the abline() command
wont/dosen't
work. The approach is based on reviewers comments that I am a tad
sceptical
about myself but yet curi
On Sep 13, 2011, at 9:43 AM, RCulloch wrote:
Dear John,
Thank you for that, and for explaining why the abline() command wont/
dosen't
work. The approach is based on reviewers comments that I am a tad
sceptical
about myself but yet curious enough to test their suggestion..I
don't
think
Hi there,
I am looking for some help with a loop which uses three list()-objects:
"sequence" has got numbers, "start" and "end" have got the begin/end time
points which should be applied to the numbers in "sequence". length() of all
three objects is identical, length() of vectors stored in "sequen
David & JC,
Excellent point, of course it does - and of course that is (should have
been) obvious!!! That is what I get for taking a reviewers
comment/suggestion as gospel without applying a bit of thought!
I'm off to go and kick myself.
Cheers,
Ross
--
View this message in context:
htt
I use ESS and have no problems invoking it when I fire up emacs. When it
loads it tells me, [Previously saved workspace restored]. However, I do not
know how to view that history of commands so I can continue what I was
doing.
Since the buffer begins with ESS, what do I do to view that restor
Dear John,
Thank you for that, and for explaining why the abline() command wont/dosen't
work. The approach is based on reviewers comments that I am a tad sceptical
about myself but yet curious enough to test their suggestion..I don't
think it is very straightforward to explain; however, it in
Hi Ben,
Your suggestions about the offset worked. Thank you!!
Lizzy
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Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-pr
Hello,
I am trying to use SVM from e1071 package for doing binary classification
and I am having problems in prediction using SVM. I ran a SVM for
X~as.factor(X1)+as.factor(X2)+as.factor(X3),data=data1,cross=10.
str(data1) gives me
data.frame':5040 obs. of 5 variables:
$ X4: int 1 2 3
Hi!I'm trying to plot the italian map with provincial administration but I
don't find the right database and packages to do so.Does anyone help me and
tell me how to do???Thanks for your attention
[[alternative HTML version deleted]]
__
R-help
John, you were right.
After I checked: I had MORE predictors that entered the model than
predictors that were left in and that show up in in
summary(myreg)$coeff). That means, some of the predictors were kicked
out from the results.
I have rerun my lm with all the predictors left in and then vif wo
Hello,
how can I get the similarity value (i.e., the inner cluster similarity) that
was used to cut a hierarchical tree at a specific height?
I would appreciate your help!
Best regards,
Madeleine
__
R-help@r-project.org mailing list
https://stat.ethz
Hi JC and Bill,
Thanks a lot for your help.
I found that Office 2007 and 2010 both have this problem when I choose to save
as PDF file in Word program. If I copy a graph as bitmap file, then everything
is ok, but not look as nice as metafile. I have tried to use other two tools
(CutePDF and
Dear Dimitri,
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Dimitri Liakhovitski
> Sent: September-13-11 10:29 AM
> To: r-help
> Subject: [R] using vif from package "car" - "aliased coefficients in
> the model"
>
> Hello!
>
The error msg is telling you that R cannot evaluate the loss function, so you
should not
expect answers.
You might try examining the data -- Are there NA or Inf entries?
Or prepare a dataframe with just X and Y, sort by X and graph.
Then check the nls computations by sampling, say, every 100 X'
Hello!
I have run a simple regression - lm and created a regression object "myreg".
I can see all the coefficients when I print(myreg).
Then I tried to run vif(myreg) from the package "car".
However, it's giving me an error: in vif.lm(regr.f) : there are
aliased coefficients in the model
Very sorr
Hello,
I would like to cut a hclust tree into several groups at a specific
similarity. I assume this can be achieved by specifying the "h" argument
with the specified similarity, e.g.:
clust<-hclust(dist,"average")
cut<-cutree(clust,h=0.65)
Now, I would like to draw rectangles around the branche
Dear Ross,
But the residuals are just y - x.
Best,
John
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of RCulloch
> Sent: September-13-11 9:19 AM
> To: r-help@r-project.org
> Subject: Re: [R] Force regression line to a 1:1
Dear JC,
> -Original Message-
> From: Jean-Christophe BOUËTTÉ [mailto:jcboue...@gmail.com]
> Sent: September-13-11 9:35 AM
> To: John Fox
> Cc: RCulloch; r-help@r-project.org
> Subject: Re: [R] Force regression line to a 1:1 relationship
>
> And you can easily get these predictions using
Hi All!
I have been messing around with this problem for about a week but to no
avail! The following data has been cut down in order to make my question
reproducible. The alldat data frame includes 2 columns: 1 date column and 1
factor column (equity names)).
mydate<-as.Date(c("2001-07-02","2001
Jim,
I have seen this outcome as well with graphs from time to time and
agree with Jean-Christophe that the bug seems to creep in at the
Windows / Office level. You do not mention your version of Word, but
I have seen this with Word 2000 and Word 2007 (doc and docx) software
and formats, for examp
On Sep 13, 2011, at 9:34 AM, Jean-Christophe BOUËTTÉ wrote:
And you can easily get these predictions using the following code :
A <- B
I had a similar thought in that: resA_B <- A - B would give the
"residuals" from a line through the origin with a slope of 1. No
regression needed
On Sep 13, 2011, at 9:30 AM, David Winsemius wrote:
On Sep 13, 2011, at 8:30 AM, Timo Schmid wrote:
Hi,
I am working with the lattice package and I want to label to groups
in the xyplots with mathematical expressions.
I short example for this
library(lattice)
Case<-factor(rep(1:2,each
And you can easily get these predictions using the following code :
A <- B
;-)
JC
2011/9/13 John Fox :
> Dear Ross,
>
> lm(y ~ 0 + offset(x)) will do the trick, but the resulting model has no
> coefficient estimates and thus can't be used with abline(). You can, e.g.,
> get predictions from the m
Ben Bolker vas escriure el dia dt, 13 set 2011:
> You mentioned that you had compiled R yourself.
> Can you replicate this with a stock R binary, i.e. from a
> Red Hat or Ubuntu repository? If not, can you give details of
> your compilation setup, especially if you are using a specialized
> or
yes, that is correct. The idea being that I want to know the residuals of the
data points compared to a 1:1 line (as shown in the plot), if that makes
sense? I appreciate that this might not be considered a typical approach,
and it would probably take a while to explain (defend) why I am doing it!
On Sep 13, 2011, at 8:30 AM, Timo Schmid wrote:
Hi,
I am working with the lattice package and I want to label to groups
in the xyplots with mathematical expressions.
I short example for this
library(lattice)
Case<-factor(rep(1:2,each=300))
xx<-rnorm(600,0,1)
yy<-rnorm(600,0,1)
xyplot(yy~
Hi there,
did you try saving your graph directly as pdf with R, using ?pdf
What you're describing seems more a Word problem.
JC
2011/9/13 Jin Minming :
> Hi all,
>
> I copy metafile boxplot from R to Word. Then save as Pdf file. But I found
> there are some unexpected black lines in some plots wit
Dear Ross,
lm(y ~ 0 + offset(x)) will do the trick, but the resulting model has no
coefficient estimates and thus can't be used with abline(). You can, e.g.,
get predictions from the model, but I'm not sure what real use it will be to
you.
I hope this helps,
John
---
On Sep 13, 2011, at 4:11 AM, drflxms wrote:
Dear R colleagues,
as result of a function a huge list is generated. From this result
list
I'd like to extract information.
Think of the list i.e. as an object named "listResult" with the
following form:
[[a]]
[1] [2] [3] [4] [5]
[[b]]
[1] [2]
On 09/13/2011 05:21 AM, Sandeep Amberkar wrote:
Dear All,
I need to fetch GO ontologies for Homo sapiens with their mappings to
corresponding Uniprot identifiers. I would be using this information to
compare result from a clustering algorithm with existing protein complexes.
This would be a test
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