Unless you have a subdirectory called "dir" below the directory returned by
getwd(), the command you gave would be expected to fail. Perhaps you should use
an absolute directory specification?
---
Jeff Newmiller The . ...
Hello, I got some of the R source code and not being able to Run it in
RStudio.
I get the error:
Error in setwd("dir") :
cannot change working directory
I have gone through forums but nothing seemed relevant to my issue.
What bugs me the most is the ("dir") that the error shows, is of those w
Hi guys,
I have a data-set that fits well into a Weibull model y = a-b*exp(-c*x^d).
I want to estimate the parameters of the coefficients a, b, c and d, given x
and y.
Can you guys help me?
Just as an example, I fit the data
y <- c(1,2,3,4,10,20)
and
x <- c(1,7,14,25,29,30)
According to this mod
On Aug 30, 2011, at 10:00 PM, Markus Weisner wrote:
snipped long preamble:
Now I have a more complicated
problem and I need help. Assuming the following factor:
B = as.factor(c("Engine 1", "Engine 10", "Ladder 3", "Engine 3",
"Ladder 10",
"Engine 10"))
levels(B)
I would like the fa
Tena koe Markus
I think you'll have to tailor a solution specific to your case. However, the
following might give you some ideas:
B <- as.factor(c("Engine 1", "Engine 10", "Ladder 3", "Engine 3", "Ladder 10",
"Engine 10"))
summary(B)
Engine 1 Engine 10 Engine 3 Ladder 10 Ladder 3
1
djmuseR
Sorry about that! I am using the mvtnorm package.
I forgot that R has (so) many packages as it is has been a while since I
last used R.
Meddee
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On Aug 30, 2011, at 10:13 PM, . . wrote:
By way of follow-up, here is some data and code that generates the
output with headings out of alignment:
Looks perfectly acceptable to me. I attached what I got when saved as
a PDF which is exactly how it looks in my dvi viewer.
filed0e744c.pdf
get a 'traceback' at the point of the error to see how deep the stack is and
what is being called. Also look at the help page for 'options' to see how to
get the browser when an error ocurs; this is under 'error' on the help page.
also lookup debugging under R so that you can do this yourself.
use readLines to read in the entire file, find your pattern of where your data
starts and then write the data starting there using writeLines to a temporary
file and now you can just read in that file using read.table; you will have
'skipped' the extra header data.
Sent from my iPad
On Aug 30,
Hi all,
I've been using the wdTable() function from R2wd package and it's been
working great.
However I just tried to do the following:
> table.2
WasteRebate code Chargeable (fin_map) Quantity (qty)
Total
[1,] "Waste" "Rebate code" "CHG"
Hello All,
I have a data frame called train.data which has 100 columns. I am using an
statistical package to learn a model and the format of using that package is as
follows:
ex5 <- stepFlexmix(cbind(y,1-y)~x|id2, data=NPreg, k=2,
model=FLXMRglm(family="binomial"), nrep=5)
the
By way of follow-up, here is some data and code that generates the
output with headings out of alignment:
> dput(mytab)
structure(c(1.3878, -0.7194, 0.3235, 1.6316, -0.4356, 1.8148,
2.1689, -1.3665, -0.2746, -0.5798, 0.7115, -0.1848, -0.2882,
-1.2555, 1.0218, -1.0525, 0.0228, -0.412
I am trying to reorder a factor data type so that when I plot stats
associated with the factor, the ordering makes sense.
For instance, if I have a factor entered as follows ...
A = as.factor(c("1", "10", "3", "3", "10", "10"))
levels(A)
... the ordering does not really make sense (assuming I
optimx uses exactly the same code as optim for BFGS. However, the call to optim
in optimx
is preceded by a check of the gradient at the starting values supplied using
numDeriv.
That is, we evaluate the gradient with gr=(user's function for gradient) and
then with
the grad() function from numDer
Dear All,
I have many files with a lot of headers and text at the beginning of the file.
The headers are not uniform though and they contain different sizes Is there a
way where I can read a table and skip all of the headers/text on top of it
until I encounter a certain text pattern? Here is a
Hi all,
Why I am getting,
Error: evaluation nested too deeply: infinite recursion / options(expressions=)?
Thanks in advance!
func <- Vectorize(function(x, a, sad, trunc=0, ...) {
result <- function(x) {
f1 <- function(n) {
dcom <- paste("d", deparse(substitute(sad)), sep="")
Hi:
It's polite to mention from which package you extract certain
functions. For example, the function dmvnorm() exists in at least the
following packages (following a search from the sos package):
mixtools, emdbook, klaR and mvtnorm, not to mention related functions
in three other packages. Since
Dear R users:
When I create a table without Major Column headings, my *regular* column
headings appear correct in the typeset latex file. The major row heading and
row groups are as they should.
w <- latex(mytab,title="",file="tab/my.tex",ctable=TRUE,caption="Descriptive
statistics by
Covar
Hi Jing
recommenderlab is still under heavy development and quite far away from
version 1.0-0. Here is some code to create a binaryRatingMatrix from a
0-1 matrix:
library(recommenderlab)
## create a 10x10 0-1 matrix
m <- matrix(sample(c(0,1),100, replace=TRUE), nrow=10, ncol=10)
m
## coerce
Hi Rich,
I do not know what u really want, because it seems to me, u want to calculate
the mean of all rows, where the chemical is Arsenic??
But try this to get a little more inside:
mean(chemdata$quant[chemdata$param=="Arsenic"])
The vector chemdata[chemdata$param=="Arsenic",] is a logical ve
I have the following function, a MSE calc based on some Multivariate normals:
MV.MSE<-function(n,EP,X,S){
(dmvnorm(X,mean=rep(0,2),I+S+EP)-dmvnorm(X,mean=rep(0,2),I+S))^2
+
1/n*(dmvnorm(X,mean=rep(0,2),1+S+EP/2)*det(4*pi*EP)^-.5-
(dmvnorm(X,mean=rep(0,2),I+S+EP
Solved!
xe <- paste("\\end{verbatim}\n",sep="")
> cat(xe)
\end{verbatim}
>
On Tue, Aug 30, 2011 at 5:31 PM, Erin Hodgess wrote:
> Dear R People:
>
> Here is a question which probably has a very simple answer. I want to
> print "\end{verbatim}" in the output of a sink file. If I put in
>
>
I've got a sparse term list of the form
term1 doc1
term2 doc1
term3 doc2
etc.
I'd like to load this into a Corpus, as defined in the tm package. I was
thinking that one way to do this is to iterate over the list building up the i,
j, v vectors for a simple_triplet_matrix, and then to use that as
There are 10 overlaps in the data:
> df1<-data.frame(start=as.POSIXct(paste('2011-06-01 ',1:20,':00',sep='')),
+ end=as.POSIXct(paste('2011-06-01 ',1:20,':30',sep='')))
> df2<-data.frame(start=as.POSIXct(paste('2011-06-01
+ ',rep(seq(1,20,2),2),':',sample(1:19,20,replace=T),sep='')),
+ end=as.POSI
Thanks to both Weidong and David for the help! By implementing both of your
suggestions I was able to make this work. I did end up putting header=TRUE for
both read operations.
--Kelly
From: David Winsemius [dwinsem...@comcast.net]
Sent: Tuesday, August
On 08/30/2011 04:19 PM, Debs Majumdar wrote:
Here's the plik code I ran:
plink --bfile olr_try1 --pheno p3.txt --pheno-name dnum --covar p3.txt
--covar-name a4 --missing-phenotype -9 --R olr2.R
The below function is contained in the olr2.R script.
The data which I input is contained in the bi
Here's the plik code I ran:
plink --bfile olr_try1 --pheno p3.txt --pheno-name dnum --covar p3.txt
--covar-name a4 --missing-phenotype -9 --R olr2.R
The below function is contained in the olr2.R script.
The data which I input is contained in the binary file named olr_try1.
The response variable
On Tue, 30 Aug 2011, David Winsemius wrote:
That does look more workable. You might consider changing the dates with:
chemadata$samp_date <- as.Date(as.character(chemdata$sample_date) )
David,
I was thinking that I needed to do this. Thank you. It's now done.
Good progress for the first
On Aug 30, 2011, at 6:49 PM, Debs Majumdar wrote:
Hi,
I am very new to R. So, pardon my dumb question. I was trying to
write my own function to run a different model (perform an ordered
logistic regression) using the example in website http://pngu.mgh.harvard.edu/~purcell/plink/rfunc.sh
Hi,
I am very new to R. So, pardon my dumb question. I was trying to write my own
function to run a different model (perform an ordered logistic regression)
using the example in website
http://pngu.mgh.harvard.edu/~purcell/plink/rfunc.shtml
But R returns a error `R Error in eval(expr, envi
Dear R People:
Here is a question which probably has a very simple answer. I want to
print "\end{verbatim}" in the output of a sink file. If I put in
\end{verbatim}
I get an unrecognized escape sequence. If I put in \\end{verbatim},
it runs fine, but the output is "\\end{verbatim}"
How do I g
On Aug 30, 2011, at 5:38 PM, Rich Shepard wrote:
On Tue, 30 Aug 2011, David Winsemius wrote:
I think you need to go back and do your input operations again with
sep="|"
David,
Yes, that's better. I did not know of the sep option. The new
results:
str(chemdata)
'data.frame': 14886
On Tue, 30 Aug 2011, David Winsemius wrote:
I think you need to go back and do your input operations again with
sep="|"
David,
Yes, that's better. I did not know of the sep option. The new results:
str(chemdata)
'data.frame': 14886 obs. of 4 variables:
$ site_id: Factor w/ 148 le
On Aug 30, 2011, at 5:30 PM, Rich Shepard wrote:
On Tue, 30 Aug 2011, David Winsemius wrote:
It appears that your original file was delimited by "|" and your
used something else, perhaps the default white-space setting?
David,
Yes, the csv file separator is the pipe.
It is _not_ a csv
On Tue, 30 Aug 2011, David Winsemius wrote:
It appears that your original file was delimited by "|" and your used
something else, perhaps the default white-space setting?
David,
Yes, the csv file separator is the pipe.
I think you need to go back and do your input operations again with
se
On Wed, 31 Aug 2011, Tal Galili wrote:
It is a bit hard to read the "summary" you are using. Consider please
pasting the output of:
ls.str(chemdata)
Tal,
Yes, summary() is inappropriate. I do want str() instead. And what that
shows is:
str(chemdata)
'data.frame': 14886 obs. of 1 vari
On Aug 30, 2011, at 5:00 PM, Rich Shepard wrote:
I don't find how to do what I need to do in Dalgaard or 'R
Cookbook', so
I'm asking here.
I have a data frame with water chemistry data and I want to start
exploring these data. There are three factors (site, date, chemical)
associated with
Hi Rich,
It is a bit hard to read the "summary" you are using. Consider please
pasting the output of:
ls.str(chemdata)
Regarding your question, please start and see if this work (I'm not sure,
since it seems you have made some changes to the summary output, and I am
only guessing how things look
I don't find how to do what I need to do in Dalgaard or 'R Cookbook', so
I'm asking here.
I have a data frame with water chemistry data and I want to start
exploring these data. There are three factors (site, date, chemical)
associated with each measurement. The data frame looks like this:
-- Forwarded message --
From: John C Frain
Date: 30 August 2011 21:52
Subject: Re: [R] ARMA show different result between eview and R
To: Young Gyu Park
If you check your manuals you will find that R uses full maximum
likelihood while Eviews uses an alternative non-linear method
On Tue, Aug 30, 2011 at 4:43 PM, Gabor Grothendieck
wrote:
> On Tue, Aug 30, 2011 at 1:36 PM, Christopher W Ryan
> wrote:
>> Running R 2.13.1 on Windows XP.
>> I would like to get week of the year (1-52) for each date.
>>
>> library(chron)
>> dts <- dates(c("02/27/92", "02/27/92", "01/14/92","02/
On 08/30/2011 10:53 AM, Rich Shepard wrote:
> Error in dyn.load(file, DLLpath = DLLpath, ...) :
> unable to load shared object
> '/home/rshepard/R/i486-slackware-linux-gnu-library/2.13/RPostgreSQL/libs/RPostgreSQL.so':
>
> libR.so: cannot open shared object file: No such file or directory
> Er
On Tue, Aug 30, 2011 at 1:36 PM, Christopher W Ryan
wrote:
> Running R 2.13.1 on Windows XP.
> I would like to get week of the year (1-52) for each date.
>
> library(chron)
> dts <- dates(c("02/27/92", "02/27/92", "01/14/92","02/28/92", "02/01/92"))
Try this:
as.numeric(cut(dts, "weeks"))
--
You did read jannis' reply didn't you?
--
David.
On Aug 30, 2011, at 2:34 PM, Christopher W Ryan wrote:
Here it is with the output:
library(chron)
dts <- dates(c("02/27/92", "02/27/92", "01/14/92","02/28/92",
"02/01/92"))
dts
[1] 02/27/92 02/27/92 01/14/92 02/28/92 02/01/92
dts.chron
Hi Meddee,
Try this:
dmat <- lapply(1:100, function(d) diag(d, 2))
That will give you a list of all 100 matrices.
Cheers,
Josh
On Tue, Aug 30, 2011 at 1:00 PM, meddee wrote:
> I am trying to generate a sequence of diagonal matrices.
>
> In the scalar case I would use something like, seq(0,10
On Tue, 30 Aug 2011, Joe Conway wrote:
Just a guess, but possibly because libpq.so (the postgres client
library) is not being found.
Joe,
My initial thought, too. But, that's not it.
1) Do you have libpq.so installed on your system?
2) If so, where?
3) If it is not in a standard system lo
On Aug 30, 2011, at 3:46 PM, Vining, Kelly wrote:
Thanks much for your help! This almost works. However, now I am
getting the following error:
for(i in all.files) {
+ if (i==all.files[1]) new.data <- read.table(i,header=TRUE) else {
+ new.data <- rbind(new.data, read.table(i))}}
Error in m
I am trying to generate a sequence of diagonal matrices.
In the scalar case I would use something like, seq(0,100,by=1).
How do I generalise the above for , say a 2 dimensional diagonal matrix. In
other words how do I produce the series of diagonal matrices {
diag(0,2),diag(1,2), diag(2,2),...,di
Thanks very much for the help.
I ended up getting it to work with one small change:
by(foo, foo$V2, function(foo) mean(foo$trust, na.rm=T))
thanks again,
Ari
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Hi,
In my package CatDyn, which uses optimx, I included the gradients of 20 version
of the model involved.
I estimate model parameters with numerical gradients, and at the final
estimates I calculate the analytical gradients.
In the simplest version of the model the analytical gradients computed
If the pattern is characterized by capital letters as your sample
suggests. The following code may help
df<-list()
names(d) = c("A.x", "B.x", "C.x", "A.y", "B.y", "C.y")
group.v<-matrix(NA,nrow=3,ncol=2) ### you may need to modify nrow and ncol
for (i in 1:3) {
group.v[i,]<-names(d)[grep(LETTERS[i
Thanks much for your help! This almost works. However, now I am getting the
following error:
> for(i in all.files) {
+ if (i==all.files[1]) new.data <- read.table(i,header=TRUE) else {
+ new.data <- rbind(new.data, read.table(i))}}
Error in match.names(clabs, names(xi)) :
names do not match pr
Thank you for the help. My focus was to split data frame for a different
function, not lm. I could provide detail of that lengthy function instead I
provided the lm function.
The comment were very helpful.
Thanks;
NIL
On Mon, Aug 29, 2011 at 3:37 PM, Dimitris Rizopoulos <
d.rizopou...@erasmusmc
Hi Ian,
There is currently no support for the mTSP in tsp.
The paper
Tolga Bektas, The multiple traveling salesman problem: an overview of
formulations and solution procedures, Omega, 34(3), June 2006, Pages 209-219
describes some methods to reformulate a mTSP as a regular TSP. However,
I ha
Hi I need some help with ploting the ROC for K-nearest neighbors. Since KNN
is a non-parametric classification methods, the predicted value will be
either 0 or 1.
It will not be able to test for different cutoff to plot ROC. What is the
package or functions I should use to plot ROC for KNN?
Thanks
How about to add a conditional statement to get the header from 1st file
for(i in all.files) {
if (i==all.files[1]) new.data <- read.table(i,header=TRUE) else {
new.data <- rbind(new.data, read.table(i))}}
Weidong Gu
On Tue, Aug 30, 2011 at 1:42 PM, Vining, Kelly
wrote:
> Hello R users.
>
>
It worked fabulously. Thank you so much for help and time.
--
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R-help@r-project.org
On 30.08.2011 14:31, . . wrote:
Hi all,
I am getting the erro showed in the subject. I was strange the this
becomes to happen after a computer restar. I think after the restart
another function f2 was in memory and it scape from me.
func<- Vectorize(FUN=
function(y, frac, rate, sad, samp="
Hi.
On Tue, Aug 30, 2011 at 3:59 AM, Janko Thyson
wrote:
> Dear list,
>
> I make use of cached objects extensively for time consuming computations and
> yesterday I happened to notice some very strange behavior in that respect:
> When I execute a given computation whose result I'd like to cache (
Here it is with the output:
> library(chron)
> dts <- dates(c("02/27/92", "02/27/92", "01/14/92","02/28/92", "02/01/92"))
> dts
[1] 02/27/92 02/27/92 01/14/92 02/28/92 02/01/92
> dts.chron <- as.chron(dts)
> dts.chron
[1] 02/27/92 02/27/92 01/14/92 02/28/92 02/01/92
> class(dts.chron)
[1] "dates"
Hi All,
I have a data frame, whose colnames like "A.x, B.x, C.x, A.y,
B.y, C.y". There could be many columns like this pattern. I want to compare
data in columns A.x with A.y, B.x with B.y and C.x with C.y etc.
Suppose my data frame is d,
names(d) = c("A.x", "B.x", "C.x", "A.y",
Jay het geskryf
When I have made a decision tree with rpart, is it possible to "apply"
this tree to a new set of data in order to find out the distribution
of observations? Ideally I would like to plot my original tree, with
the counts (at each node) of the new data.
Sadly, neither plot.rpart
Hi Ian,
I checked your example again and found the problem in tsp. fix(x) seems
to create column names but not row names which exposes a bug in as.ATSP
in tsp.
This code replicates your error message:
library(TSP)
x <- rbind(c(1,2,3,4), c(1,0,11,5), c(2,4,0,6), c(3,5,6,0))
colnames(x) <- 1:4
David,
Yes, I understand that cat() won't do what I want, but that is the only way
I can illustrate what I am after. Note the phrasing in my question:
'...cat() like...'
Regarding assigning the paste to a variable: it produces the same error.
I've already tried that.
Thanks for your suggestion!
Hiya,
maybe there is a native R function for this and if so please let me know!
I have 2 data.frames with start and end dates, they read in as strings and I
am converting to POSIXct. How can I check for overlap?
The end result ideally will be a single data.frame containing all the
columns of th
I'm starting to seriously use R and have tried to solve this issue using
my reference books but I'm missing something simple. Running R-2.13.1 on
Slackware-13.1.
Trying to invoke RPostgreSQL so I can copy data from a postgres table to
an R data-frame. I installed RPostgreSQL and the library()
On Aug 30, 2011, at 1:36 PM, Christopher W Ryan wrote:
Running R 2.13.1 on Windows XP.
I would like to get week of the year (1-52) for each date.
library(chron)
dts <- dates(c("02/27/92", "02/27/92", "01/14/92","02/28/92",
"02/01/92"))
dts
dts.chron <- as.chron(dts)
dts.chron
class(dts.chro
Well, there is no function called "weeks" in chron. Funny that the help
mentions it.
You can, however, use normal POSIXct objects and extract the week with:
dts <- dates(c("02/27/92", "02/27/92"))
dts.posx <- as.POSIXct(dts)
result <- as.integer(format(dts.posx,format="%W"))
HTH
Jannis
Hi Kathie,
The gradient check in "optimx" checks if the user specified gradient (at
starting parameters) is within roughly 1.e-05 * (1 + fval) of the numerically
computed gradient. It is likely that you have correctly coded up the gradient,
but still there can be significant differences b/w num
Hello R users.
This is a fairly basic question:
I am concatenating data from sets of files in a directory using a loop. The
column names in all files are exactly the same. My understanding is that rbind
takes column names from the first file it reads. However, my output is showing
that the co
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of DimmestLemming
> Sent: Tuesday, August 30, 2011 10:20 AM
> To: r-help@r-project.org
> Subject: Re: [R] "Negative length vector" error in simple merge
>
> Thanks! I'd just never h
Running R 2.13.1 on Windows XP.
I would like to get week of the year (1-52) for each date.
library(chron)
dts <- dates(c("02/27/92", "02/27/92", "01/14/92","02/28/92", "02/01/92"))
dts
dts.chron <- as.chron(dts)
dts.chron
class(dts.chron)
# all of these component extractions work:
months(dts.chron
On Aug 30, 2011, at 1:09 PM, Ben qant wrote:
Hello,
(Sorry if this is a dup post...)
I need to clarify, Henrique's suggestion worked great for getting
the text
that I needed via cat(), but I haven't sorted out how to get cat()
like
output into a variable so I can pass it into the message
Thanks! I'd just never heard of cbind or rbind... bit new.
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__
R-
Hello,
(Sorry if this is a dup post...)
I need to clarify, Henrique's suggestion worked great for getting the text
that I needed via cat(), but I haven't sorted out how to get cat() like
output into a variable so I can pass it into the message body variable I am
using.
Here is what I mean:
x
[1
On 30/08/2011 11:05 AM, Pitt, Joel wrote:
Hi All,
My attempts to build an R package on my Windows 7 computer using R V13.0 ir R
V13.1 using
R CMD build --binary
have been failing at the penultimate step with the error message "running 'zip'
failed" coming after the procedure has completed t
Hi,
I have the following, rather unorthodox problem:
I have a matrix that looks like this:
m1 <- matrix(c('a','b','d',NA,'c','c'), 2,3, byrow=TRUE)
[,1] [,2] [,3]
[1,] "a" "b" "d"
[2,] NA "c" "c"
now I would like to transform this matrix into this matrix:
[,1] [,2]
On Aug 30, 2011, at 11:08 AM, DimmestLemming wrote:
Hi,
I'm trying to take a vector (length almost 2,000,000) and merge it
with a
data frame of the same length. I'm trying to do it solely based on
index,
and not any other factors.
The vector is called "offense", and the data frame is jus
Dear users,
By running the script below, R crashes systematically at the last
command, namely dev.off(), on Windows 7, but not on Windows XP.
I therefore don't provide a reproducible example and do not really
extract the relevant parts of the script because it has most likely
nothing to do wit
Hi Jay,
first: thank u very much for your comments! U made some very important points
clear. I tried immediately to write directly the sample function from
trade<-as.big.matrix(matrix(sample(c(1,-1), (N+1)*K, replace=TRUE),ncol=K),
backingpath=backingpath, backingfile="trade.bin",descriptorfil
Hi everyone,
I´m starting with GMM estimator for panel data in R. In fact Im starting
with GMM estimation with panel data, my research area is accounting and
finance, so Ive been reading many «econometric» books but I have some
difficulties in applying GMM estimation.
Ive also read the
On Tue, Aug 30, 2011 at 7:42 AM, Filipe Leme Botelho
wrote:
> Hi all,
>
> I am reading previous posts and guidance on the 'reshape' package in order to
> solve the simple problem below. Thinking that this might be very trivial for
> most of you, I thought there could be a fast solution coming fr
Please ignore this message.
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Hi,
I'm trying to take a vector (length almost 2,000,000) and merge it with a
data frame of the same length. I'm trying to do it solely based on index,
and not any other factors.
The vector is called "offense", and the data frame is just called "data". I
went with the simplest option:
merge(data
Hello,
I need to clarify, Henrique's suggestion worked great for getting the text
that I needed via cat(), but I haven't sorted out how to get cat() like
output into a variable so I can pass it into the message body variable I am
using.
Here is what I mean:
x
[1] "a" "b" "c" "d"
paste(x,collaps
Dear list,
I performed a multivariate analysis on freshwater invertebrates data. So
I obtained coordinates of my samples on the axes defining the first
factorial plane (F1 and F2).
I would like to see if the positions on my factorial plan could be
linked to levels of impairment ('low' vs 'signifi
Duncan, Thanks. Combined with what Brian Ripley wrote it all works. For
future thread searchers this worked: oldstring <- readline()
C:\Users\Rinker\Desktop\Research& Law\Data\School Data 09-10
chartr("\\", "/",oldstring) Thank you both,Tyler
#> Dat
On Aug 30, 2011, at 11:29 AM, Simon Zehnder wrote:
Hi David,
thank you very much for your advice! I updated R and all my
packages. Regrettably it doesn't work yet. But, I think, that the
parallel processing (using 32bit) does improve time, especially when
it comes to higher dimensions:
Hi All,
My attempts to build an R package on my Windows 7 computer using R V13.0 ir R
V13.1 using
R CMD build --binary
have been failing at the penultimate step with the error message "running
'zip' failed" coming after the procedure has completed the MD5 sums step.The
same build comma
Dr. Hahsler,
Thank you so much for looking at my code. I made sure that I had TSP_1.0-3
install and ran the code again (this time with "<-" instead of "=" for my
assignments). I received the same response. I checked my sessionInfo and
did not see anything out of the ordinary. Does anything loo
Petr, many thanks. It´s very straightforward to to deal with the package, I had
different sources of revenues for same company, same month, like below, and
just by adding "sum" at the end of the function it collapsed values from all
sources. Very useful! Cheers
cast(dta, Data~Company, value="Re
Thanks Peter & Petr,
It was indeed an issue of having some character variables in there. Now it
works just fine.
Cheers,
Luca
Il giorno 30/ago/2011, alle ore 10.15, peter dalgaard ha scritto:
>
> On Aug 30, 2011, at 10:04 , Luca Meyer wrote:
>
>> Hi,
>>
>> Does anyone know how to show zero
Brian Ripley told you how to do the translation, but there's another
problem:
On 30/08/2011 8:14 AM, Tyler Rinker wrote:
[ much deleted ]
When I try
the function the backslash gets me again:
>
readyPath("C:\Users\Rinker\Desktop\Research& Law\Data\School Data
09-10")
The problem is that you
On 30/08/2011 3:48 AM, behave wrote:
That was my first guess as well, but unfortunately this doesn't solve the
problem.
I is remarkably that IE requires authentification for every new instance I
open (even if another instance is already open)...
Any other hints?
You can read about how WinINet
Thank you Brian. When I wrote the email I typed url into the subject line by
accident. I mean path. Thank you,Tyler
> Date: Tue, 30 Aug 2011 14:00:22 +0100
> From: rip...@stats.ox.ac.uk
> To: tyler_rin...@hotmail.com
> CC: r-help@r-project.org
> Subject: Re: [R] url prep function (backslash
Hi Ian,
Your example runs for me without problems. It seems that you are using
an older version of TSP. Please upgrade to the latest version TSP
(update to TSP_1.0-3). I am using:
> sessionInfo()
R version 2.13.1 (2011-07-08)
Platform: i686-pc-linux-gnu (32-bit)
locale:
[1] LC_CTYPE=en_US.U
Dear Julien
It is exactly what I need.
Thanks a lot.
-
Bc.Sc.Agri. Alessandro Samuel-Rosa
Postgraduate Program in Soil Science
Federal University of Santa Maria
Av. Roraima, nº 1000, Bairro Camobi, CEP 97105-970
Santa Maria, Rio Grande do Sul, Brazil
--
View this message in context:
http://
Chang Cheng,
this question has been asked on this list for several times. I would suggest
you search the list archive (http://r.789695.n4.nabble.com/R-help-f789696.html
or www.rseek.com) prior to posting in the future. "graph size many points pdf"
would give you at least 10 threads with detail
You seem to be looking for chartr("\\", "/", path) (and FAQ Q7.8)
What does any of this have to do with 'url prep': URLs are never
written with backslashes?
On Tue, 30 Aug 2011, Tyler Rinker wrote:
Greeting R
Community,
I am a
windows user so this problem may be specific to windows. I of
Hi all,
I am getting the erro showed in the subject. I was strange the this
becomes to happen after a computer restar. I think after the restart
another function f2 was in memory and it scape from me.
func <- Vectorize(FUN=
function(y, frac, rate, sad, samp="Poisson", trunc=0, ...){
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