You seem to be looking for chartr("\\", "/", path) (and FAQ Q7.8)
What does any of this have to do with 'url prep': URLs are never
written with backslashes?
On Tue, 30 Aug 2011, Tyler Rinker wrote:
Greeting R
Community,
I am a
windows user so this problem may be specific to windows. I often want to source
files from within R
such as:
C:\Users\Rinker\Desktop\Research & Law\Data\School Data 09-10. To source
this file I need to go
through the
path and replace all the backslashes (\) with forward slashes (/). I usually do
this in MS Word
using the
replace option, however, I'd like to do this in R. Attempting to write a
function to do this runs into
problems:
When I
enter the following:
readyPath
<- function(path){
z <- gsub("\", "/", path)
return(z)
}
I get:
readyPath <- function(path){
+ z <- gsub("\", "/", path)
+ return(z)
+ }
+
...meaning
R can't close the sequence (presumably because of the backslash which has
special meaning).
So I tried
(\\):
readyPath <- function(path){
z <- gsub("\\", "/", path)
return(z)
}This allows
the function to be stored as an object but I'm not sure if this is correct.
It isn't: please do read the help for gsub (\ is a metacharacter).
When I try
the function the backslash gets me again:
readyPath("C:\Users\Rinker\Desktop\Research & Law\Data\School Data
09-10")
Error: '\U' used without hex digits in character string starting
"C:\U"
You cannot do that: you have to scan a file or escape \
This is
what I'd like the function to return:
[1]
"C:/Users/Rinker/Desktop/Research & Law/Data/School Data 09-10"
I want a
function in which I enter a path and it returns the path with backslashes
replaced
with forward slashes. Is there a way to make a function to do this?
?normalizePath
chartr("\\", "/", path)
Windows 7
user
R version
2.14 beta
Thank you,
Tyler
Rinker
[[alternative HTML version deleted]]
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Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
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