Hi,
I'm having trouble with quantmod's addTA plotting functions. They seem to
work fine when run from the command line. But when run inside a function,
only the last one run is visible. Here's an example.
test.addTA <- function(from = "2010-06-01") {
getSymbols("^GSPC", from = from)
GS
On Wed, May 4, 2011 at 9:47 AM, FMH wrote:
> Dear All,
>
> Could someone please give some advice the way to do linear modelling via best
> subset regression in R?...
Yes. Don't do it.
-- Bert
(Very Brief Explanation: Best subset regression was a questionable
approach to parsimonious modeling
The one that gives results that you trust and uses algorithms that you
understand!
Cheers
Andrew
On Wed, May 04, 2011 at 12:52:03PM +, Halldór Björnsson wrote:
> Hi,
>
> I have three matrices (X,Y,P) with the same dimension. The X,Y grid is
> regular and I want to
> perform linear interpola
Hi
r-help-boun...@r-project.org napsal dne 04.05.2011 22:26:59:
> Erik Iverson
> Odeslal: r-help-boun...@r-project.org
>
> 04.05.2011 22:26
>
> Komu
>
> Dan Abner
>
>
> > Ultimately, I would like for this to be 1 conponent in a larger
function
> > that will produce PROC CONTENTS style ou
I can't honestly say that I grasp what you're trying to do, but that
said, I wonder if the curve() function will help you?
Cheers
Andrew
On Wed, May 04, 2011 at 07:30:20AM -0700, blutack wrote:
> I have a vector with lots of different numbers. I need to make a graph
> showing the Uniform Distri
A hack would be to use gsub() to prepend e.g. XXX to the keywords that
you want, perform a strsplit() to break the lines into component
strings, and then substr() to extract the pieces that you want from
those strings.
Cheers
Andrew
On Wed, May 04, 2011 at 04:08:40PM -0700, sunny wrote:
> Hi. I
I hope not!
Facetiousness aside, the model that you have fit contains C, and,
indeed, an interaction between A and C. So, the effect of A upon the
response variable depends on the level of C. The summary you want
must marginalize C somehow, probably by a weighted or unweighted
average across its
Hi Paul,
I suggest that you should send us commented, minimal, self-contained,
reproducible code.
That means, in essence, developing the simplest possible
representation of your problem. In the process of developing the
simplest possible representation, you may learn more about the
problem. May
On 05/05/11 11:16, Dan Abner wrote:
Hello everyone,
How does one write a function to return the name of an input object (that is
assumed to be a data frame) as a character string? I tired using the get(),
but this does not work as I had hoped. For example:
myfn<-function(x){
output<-data.frame
Yes, thank you.
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Hi. I have a character vector that looks like this:
> temp <- c("Company name: The first company General Manager: John Doe I
> Managers: John Doe II, John Doe III","Company name: The second company
> General Manager: Jane Doe I","Company name: The third company Managers:
> Jane Doe II, Jane Doe II
Hello everyone,
How does one write a function to return the name of an input object (that is
assumed to be a data frame) as a character string? I tired using the get(),
but this does not work as I had hoped. For example:
myfn<-function(x){
output<-data.frame(Attribute="Data Set Name",Value=as.ch
Hi Cristina,
you can probably hack your own solution using the index.cond argument.
Cheers
Andrew
On Wed, May 04, 2011 at 04:50:53PM +0100, Cristina Silva wrote:
> Hi all,
>
> In lattice graphs, panels are drawn from left to right and bottom to
> top. The flag "as.table=TRUE" changes to left
I wonder if this question should be directed to the package
maintainer?
Best wishes,
Andrew
On Wed, May 04, 2011 at 02:31:51PM +0100, Jannis wrote:
> Just did some more testing.May the problem be due to the fact that I am
> using a windows machine? I just ran the same code on a Linux machin
Hi Rohit,
actually, the request for simple reproducible code means that you have
to find the simplest possible representation of the problem.
What happens if you simplify the observation level gradient and the
likelihood function? Eg to trivial examples? If you still get the
error, then simpl
Hi:
If it's doable, you'll probably need the gridBase package.
Fortunately, it has a nice vignette to get you started, which tells
you at the end that there are limitations in compatibility between
base and grid graphics (lattice is built on the latter).
HTH,
Dennis
2011/5/4 Lucia Cañas :
> Dear
Hi:
> x1 <- 1:5
> x2 <- 6:10
> x3 <- c(1, 2, 5)
> x4 <- 3
> x5 <- 4
> x2[x1 %in% x3]
[1] 6 7 10
> x2[x1 %in% x4]
[1] 8
> x2[x1 %in% x5]
[1] 9
HTH,
Dennis
On Wed, May 4, 2011 at 2:20 PM, blue100 wrote:
> dear all,
>
> Im a complete R newby with the following question.
>
> I have a dataset whe
Hi:
Is this what you're after?
> z=c(1,3,0.5,6,8,10,2,2,3,4,7,3)
> which(z > 2)
[1] 2 4 5 6 9 10 11 12
HTH,
Dennis
On Wed, May 4, 2011 at 1:02 PM, derek wrote:
> Dear R,
>
> Here is a code:
> z=c(1,3,0.5,6,8,10,2,2,3,4,7,3)
> z[z>2]
>
> I dont want print the elements, but theirs placings
Beware - this approach is a statistical train wreck. Been there, done that.
If all you want is "an" answer it will save you a lot of time thinking,
however.
Frank
FMH-4 wrote:
>
> Dear All,
>
> Could someone please give some advice the way to do linear modelling via
> best subset regression
Hi:
Start here:
library(sos)# Install first if necessary
findFn('Box-Cox')
This search finds 131 matches; the basic Box-Cox transformations for
regression are found in the MASS and car packages. For other
situations, consult the packages and functions identified from the sos
search.
HTH,
De
Hi,
All of the components in the grid.arrange statement are from ggplot2 and
lattice, which are both in turn based on the grid package. What
grid.arrange is able to do is use the grid framework to arrange the
individual plots on a page. The base graphics are not based on grid, and
so won't wor
dear all,
Im a complete R newby with the following question.
I have a dataset where my variable values are incorrectly numbered. it has
to be something like this
Where x is variable name, y=actual value which must become corresponding
z-value
x3 x4 x5
Hi,
I am attempting to fit a ARMA/GARCH regression model without success.
### ARIMA-GARCH model with regressor ###
### Time series data: A multivariate data set.
cov.ts.dq = cov.ts[1:4,"dq1"][!is.na(cov.ts[,"dq1"])]
cov.ts.day = ts.intersect(dq = diff(q.ts), day = lag(q.t
Dear R,
Here is a code:
z=c(1,3,0.5,6,8,10,2,2,3,4,7,3)
z[z>2]
I dont want print the elements, but theirs placings in vector.
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And I responded as follows:
Hi,
Thanks for your advice. I tried using table() to check for missing
data. Here are the results:
> table(Combined.Plot)
Combined.Plot
60m A1 B1 B3 B4 C5 C9 D2 D9 F60m F8 Q7
34 34 3434 343434 3434 34 34 34
>
merge(dat, pheno, by.x = "sid", by.y = "sen")
Scott
On Wednesday, May 4, 2011 at 12:53 PM, 1Rnwb wrote:
> Hello,
>
> I have data in a dataframe with 139104 rows which is multiple of 96x1449. i
> have a phenotype file which contains the phenotype information for the 96
> samples. the snp name i
This response went to my email:
Without your data it's hard to say, but one possibility is that your
plots are nested within treatments instead of crossed, or that you have
something rather more cunning going on involving the Days. For example
if you had 8 days for six of your plots and another 8
How can I apply feature selection with caret and support vector regression.
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___
Perfect Erik! Thank you!
On Wed, May 4, 2011 at 4:22 PM, Erik Iverson wrote:
> Dan,
>
>
>
> I am attempting to write a function to count the number of non-missing
>> values of each column in a data frame using the sapply function. I have
>> the
>> following code which is receiving the error me
Hi Andrew, Ravi and Arne,
Thank you so much for your prompt replies. I see that all of you mention the
need for simple, reproducible code. I had thought of doing this, but the
functions I was using for the observation level gradient and likelihood
function were very long. I will paste them below h
Thanks all, this is very helpful.
--Andrew Steen
> -Original Message-
> From: David Winsemius [mailto:dwinsem...@comcast.net]
> Sent: Wednesday, May 04, 2011 4:35 PM
> To: Andrew D. Steen
> Cc: r-help@r-project.org
> Subject: Re: [R] what happens when I store linear models in an array?
>
Thank you all!
2011/5/4 David Wolfskill :
> On Wed, May 04, 2011 at 10:41:36PM +0300, johannes rara wrote:
>> I have a string like this
>>
>> st <- "SELECT COUNT(empid), COUNT(mgrid), COUNT(empname),
>> COUNT(salary), FROM Employees"
>>
>> How can I remove the last comma before the FROM statement?
On 05/04/2011 12:53 PM, FMH wrote:
Hi,
Could any one please help how I can transform data based on Box-Cox
Transformations in R.
Any helps will be much appreciated.
thanks,
Kagba
[[alternative HTML version deleted]]
See the boxcox function in the MASS package.
On Wed, May 04, 2011 at 10:41:36PM +0300, johannes rara wrote:
> I have a string like this
>
> st <- "SELECT COUNT(empid), COUNT(mgrid), COUNT(empname),
> COUNT(salary), FROM Employees"
>
> How can I remove the last comma before the FROM statement?
This doesn't use a regex, per se, but:
> st <-
It looks from str(SA) that Response IPS1 is a data.frame of class "anova",
which probably cannot be coerced to vector.
Maybe you can use unlist() instead of as.vector()
Or something like
SA[["Response IPS1"]]["as.factor(WSD)",] ## to select the first row only, even
maybe with unlist()
Without
On 4 May 2011 09:47, FMH wrote:
> Dear All,
>
> Could someone please give some advice the way to do linear modelling via best
> subset regression in R? I'd really appreciate for your kindness.
>
Google is your friend here:
http://www.google.com/search?q=best+subsets+regression+R , and sends
me
Ultimately, I would like for this to be 1 conponent in a larger function
that will produce PROC CONTENTS style output. Something like...
data1.contents<-data.frame(Variable=names(data1),
Class=sapply(data1,class),
n.valid=sapply(data1,sum(!is.na)),
n.miss=sapply(data1,sum(is.na)))
data1.cont
On Wed, 2011-05-04 at 22:41 +0300, johannes rara wrote:
> I have a string like this
>
> st <- "SELECT COUNT(empid), COUNT(mgrid), COUNT(empname),
> COUNT(salary), FROM Employees"
>
> How can I remove the last comma before the FROM statement?
gsub(",[^,]*FROM ", " FROM ", st)
HTH,
Jerome
__
Dan,
I am attempting to write a function to count the number of non-missing
values of each column in a data frame using the sapply function. I have the
following code which is receiving the error message below.
n.valid<-sapply(data1,sum(!is.na))
Error in !is.na : invalid argument type
Tha
Hi,
On Wed, May 4, 2011 at 10:32 AM, Roccato Alfredo (UniCredit)
wrote:
> I'd to match-merge 2 tables in such a manner that I keep all the rows in
> table 1, but not the rows that are in both table 1 and 2.
> Thank you for your help,
> Alfredo
>
>> master <- data.frame(ID=2001:2011)
>> train <
Try this:
gsub(",\\s+FROM", " FROM", st)
On Wed, May 4, 2011 at 4:41 PM, johannes rara wrote:
> I have a string like this
>
> st <- "SELECT COUNT(empid), COUNT(mgrid), COUNT(empname),
> COUNT(salary), FROM Employees"
>
> How can I remove the last comma before the FROM statement?
>
> -J
>
> _
On Wed, May 04, 2011 at 04:32:14PM +0200, Roccato Alfredo (UniCredit) wrote:
> I'd to match-merge 2 tables in such a manner that I keep all the rows in
> table 1, but not the rows that are in both table 1 and 2.
> Thank you for your help,
> Alfredo
>
> > master <- data.frame(ID=2001:2011)
> > tra
Hi,
On Wed, May 4, 2011 at 10:19 AM, blutack wrote:
> Hi,
> I have a created a function, but now I need to call it about a hundred times
> and store the results as a vector.
> I think doing a for loop would work, but I cant work out how to save the
> values generated from the function as a vector
Look at the merge command
?merge
Steve Friedman Ph. D.
Ecologist / Spatial Statistical Analyst
Everglades and Dry Tortugas National Park
950 N Krome Ave (3rd Floor)
Homestead, Florida 33034
steve_fried...@nps.gov
Office (305) 224 - 4282
Fax (305) 224 - 4147
Hello everyone,
I am attempting to write a function to count the number of non-missing
values of each column in a data frame using the sapply function. I have the
following code which is receiving the error message below.
> n.valid<-sapply(data1,sum(!is.na))
Error in !is.na : invalid argument ty
Hi,
Could any one please help how I can transform data based on Box-Cox
Transformations in R.
Any helps will be much appreciated.
thanks,
Kagba
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.c
Dear All,
Could someone please give some advice the way to do linear modelling via best
subset regression in R? I'd really appreciate for your kindness.
Thanks,
Kagba
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Hi,
I am currently analysis Raman spectroscopic data with the hyperSpec package.
I consulted the documentation on this package and I found an example
work-flow dedicated to Raman spectroscopy (see the address :
http://hyperspec.r-forge.r-project.org/chondro.pdf)
I am currently trying to remove ou
I'm fitting a regression model for censored data with three categorical
predictors, say A, B, C. My final model based on the survreg function is
Surv(..) ~ A*(B+C).
I know the three-way group mean estimates can be computed using the predict
function. But is there any way to obtain two-way group
Sorry I had typo in previous email,
this typo corrected version:
Dear R experts
I have simple question, please execuse me:
#example data, the real data consists of 2 pairs of variables
K1 <- c(1,2,1, 1, 1,1); K2 <- c(1, 1,2,2, 1,2); K3 <- c(3, 1, 3, 3, 1, 3)
M1a <- rep( K1, 100); M1b <- re
I figured out that attributes is the command that I was trying to find. It
allowed me to find out that I was needing to use "stats" not "Df" or
"Pillai" etc. Following command worked.
> S1<-as.vector(S$stats[1,])
However when I try the same thing with summary.aov it is not working.
>SA<-summary.
SA gives the output:
Response IPS1 :
Df Sum Sq Mean Sq F value Pr(>F)
as.factor(WSD) 3 3.3136 1.10455 23.047 5.19e-12 ***
Residuals 129 6.1823 0.04793
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
.
.
.
There are 11 more just
Yes thats it :-)
Thank you very much!
Janine
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I have a vector with lots of different numbers. I need to make a graph
showing the Uniform Distribution of the figures. I have created a graph
showing all the different values, but now want individual Gaussian Kernel
round each point. This is what I have but each time it comes up with an
error as I
Hi,
First- I am relatively new to R and would therefore greatly appreciate any
kind of help from you !
I am currently trying to use R to make a heatmap using the Pheatmap package.
My question: I want to include a different distance measure than the ones
given by the implemented hclust function
Dear all,
I would like to implement a spatial quantile regression using instrumental
variable estimation (according to Su and Yang (2007), Instrumental variable
quantile estimation of spatial autoregressive models, SMU economics & statistis
working paper series, 2007, 05-2007, p.35 ).
I am app
Hi,
I have a created a function, but now I need to call it about a hundred times
and store the results as a vector.
I think doing a for loop would work, but I cant work out how to save the
values generated from the function as a vector. Any ideas?
Thanks.
--
View this message in context:
http:/
> Date: Wed, 4 May 2011 07:07:44 -0700
> From: sterles...@hotmail.com
> To: r-help@r-project.org
> Subject: Re: [R] nls problem with R
>
> Thanks Andrew.
> I am sorry for some typos that I omit some numbers of T2.
> Based on your suggestion,I think the problem is in the initial values.
> And I w
I'd to match-merge 2 tables in such a manner that I keep all the rows in table
1, but not the rows that are in both table 1 and 2.
Thank you for your help,
Alfredo
> master <- data.frame(ID=2001:2011)
> train <- data.frame(ID=2004:2006)
> valid <- ???
in this example table valid should have th
Hello,
I have data in a dataframe with 139104 rows which is multiple of 96x1449. i
have a phenotype file which contains the phenotype information for the 96
samples. the snp name is repeated 1449X96 samples. I haveto merge the two
dataframes based on sid and sen. this is how my two dataframes loo
I have a string like this
st <- "SELECT COUNT(empid), COUNT(mgrid), COUNT(empname),
COUNT(salary), FROM Employees"
How can I remove the last comma before the FROM statement?
-J
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo
What about the example in gridExtra package:
require(ggplot2); require(lattice); require(gridExtra)
grid.arrange(qplot(1:10), xyplot(1:10~1:10), tableGrob(head(iris)), nrow=2,
as.table=TRUE, main="test main", sub=textGrob("test sub", gp=gpar(font=2)))
On Wednesday, May 4, 2011 at 1:44 PM, Jonatha
If you read the help documentation, lattice is not really compatible
with standard graphics.
library("lattice")
?lattice
2011/5/4 Lucia Cañas :
> Dear R users,
>
> I would like to combine lattice plot (xyplot) and standard R plot (plot and
> plotCI) in an unique figure.
>
> I use the function "p
Dear R users,
I would like to combine lattice plot (xyplot) and standard R plot (plot and
plotCI) in an unique figure.
I use the function "par()" to combine plot and plotCI and I use the function
"print()" to combine xyplot. I tried to use these functions to combine xyplot
and plotCI and plots
Beautiful Prof.
This worked:
for (i in seq(along = tbl$key)) {
if (inherits(try(sqlSave(pg, tbl[i, ], "tbl", append = TRUE,
rownames = FALSE), silent = TRUE), "try-error", TRUE))
sqlUpdate(pg, tbl[i, ], index = "key1")
)
}
--- On Wed, 5/4/11, Prof Brian Ripley wrote:
On May 4, 2011, at 8:34 AM, Joshua Wiley wrote:
Hi Ondrej,
What documentation have you looked at? Does this help at all?
require(splines)
?ns
## one example
summary(lm(y ~ ns(x, df = 3),
data = data.frame(y = runif(100), x = rbinom(100, 9, .25)^2)))
## built in examples
example(ns)
Also,
On May 4, 2011, at 8:43 AM, Richard M. Heiberger wrote:
> David,
>
> That is not clear from the original request. The request was for
> {}^18*O
I see your point. The use of the phantom would also allow a pre-
superscript with no preceding "delta". Thanks for bearing with my
obtuseness.
--
On 04.05.2011 19:22, Matías Ramírez Salgado wrote:
The package is called: "adapt" (adapt_1.0-4.tgz is the version of
package for mac, search it in google)
is not in all CRAN servers, because is an old package.
Yes, there is a reason why the package was archived (which I said
already!): It does
The package is called: "adapt" (adapt_1.0-4.tgz is the version of package
for mac, search it in google)
is not in all CRAN servers, because is an old package.
I tried to install it from package manager as CRAN (binaries), Other
repositorys, and as a local source packages, and allways returns this
Start with try(): you may find it easier to understand.
if(inherits(try(), "try-error"))
so in your case
if(inherits(try(sqlSave(pg, tbl[i, ], "tbl", append = TRUE,
rownames = FALSE
sqlUpdate(pg, tbl[i, ], index = "key")
or some such.
On Wed, 4 May 2011, Mikke
On Wed, May 04, 2011 at 08:52:07AM -0700, William Dunlap wrote:
> > -Original Message-
> > From: r-help-boun...@r-project.org
> > [mailto:r-help-boun...@r-project.org] On Behalf Of Petr Savicky
> > Sent: Wednesday, May 04, 2011 12:51 AM
> > To: r-help@r-project.org
> > Subject: Re: [R] Sim
I would like to do inserts into a database table, but do updates in the fairly
rare cases in which the inserts fail. I thought tryCatch might be the way to do
it, but I honestly do not understand the help file for tryCatch at all.
I thought something like this might work:
for (i in seq(along = t
Thanks a lot Duncan,
I have removed the system variable incorrectly setup and it works now.
Have a nice day
Xavier
From: Duncan Murdoch
Cc: r-help@r-project.org
Sent: Wed, 4 May, 2011 17:37:55
Subject: Re: [R] Error Rscript: No such file or directory
On 04/05
On 04/05/2011 11:49 AM, xavier abulker wrote:
Hello,
I'm trying to build a simple cpp file using the R CMD SHLIB command and I always
receive the same error message:
cygwin warning:
MS-DOS style path detected: C:/PROGRA~1/R/R-212~1.1/etc/i386/Makeconf
Preferred POSIX equivalent is:
/cygdri
I would like to create a table of my points and identify which
'quadrant' of a plot they are in with the 'origin' at the means. the
kicker is i would like to display it right next to or below a ggplot
of the data. Maybe xtable isnt the right thing to use, but its the
only thing i can think of. A
Hi all,
In lattice graphs, panels are drawn from left to right and bottom to
top. The flag "as.table=TRUE" changes to left to right and top to
bottom. Is there any way to change to first top to bottom and then left
to right? didn´t find anything neither in Help pages nor Lattice book.
Cristi
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Petr Savicky
> Sent: Wednesday, May 04, 2011 12:51 AM
> To: r-help@r-project.org
> Subject: Re: [R] Simple loop
>
> On Tue, May 03, 2011 at 12:04:47PM -0700, William Dunlap wrote
David,
That is not clear from the original request. The request was for {}^18*O
It wasn't for delta^18
Therefore I put the space there to be sure that the 18 was seen as
pre-superscript of O,
not as a post-superscript of delta. I probably should also have used ~ as
plot(1:10, xlab=expression(d
Hello,
I'm trying to build a simple cpp file using the R CMD SHLIB command and I
always
receive the same error message:
cygwin warning:
MS-DOS style path detected: C:/PROGRA~1/R/R-212~1.1/etc/i386/Makeconf
Preferred POSIX equivalent is:
/cygdrive/c/PROGRA~1/R/R-212~1.1/etc/i386/Makeconf
Hi Ondrej,
What documentation have you looked at? Does this help at all?
require(splines)
?ns
## one example
summary(lm(y ~ ns(x, df = 3),
data = data.frame(y = runif(100), x = rbinom(100, 9, .25)^2)))
## built in examples
example(ns)
Also, I am very fond of the book, Modern Applied Statisti
Dear R-helpers,
I need to fit natural cubic spline with specified number of knots. I
expected 'splines' package will be helpful, but I am confused by its
help. Is more detailed documentation available for it or could you
recommend another R function?
Best regards
Ondrej Mikula
Hi all--
We are planning an intervention study for adolescent alcohol use, and I
am planning to use simulations based on a hurdle model (using the
hurdle() function in package pscl) for sample size estimation.
The simulation code and power code are below -- note that at the moment
the "powe
Please read the comments in the help about umask (and in the posting
guide about the 'at a minimum' information required in postings, for
the details do depend on the version of R and it seems yours is not
current).
In R 2.13.0:
‘dir.create’ creates the last element of the path, unless
On May 4, 2011, at 3:44 AM, TheSavageSam wrote:
Hello!
I have had some problems lately with use of R at home and school. At
my home
laptop (Ubuntu linux 64bit & R-2.12.0) R works just fine. But when I
take my
codes to school(Windows XP 32bit & R-2.10.1 I think) and run those
there
those
On May 4, 2011, at 7:28 AM, Richard M. Heiberger wrote:
Dos this do what you want?
plot(1:10, xlab=expression(delta*{}^18*"O" * " VSMOW [‰]"))
The specific is to put an empty item there to hold the superscript.
I do not think that is necessary:
plot(1:10, xlab=expression(delta^18*O~VSMOW["
Hi,
I would suggest you to check the structure of your summary object with
str(), like this:
S <- summary(M, test="Pillai")
str(S)
You will then see how to access each element of it.
If you cannot manage to do it yourself, then provide an example, or at
least the output from str(s).
By the wa
On May 4, 2011, at 5:57 AM, Ben Bolker wrote:
smoff boku.ac.at> writes:
My problem is that I have a table containing dates in the first
column of 10
years. These dates have the format ddmm at least in the csv-
file. After
importing the file using read.table() R deletes the first charac
On May 4, 2011, at 4:49 AM, Andrew D. Steen wrote:
I've got a bunch of similar datasets, all of which I've fit to linear
models. I'd like to easily create arrays of a specific parameter
from each
linear model (e.g., all of the intercepts in one array). I figured
I'd put
the model objects
On May 4, 2011, at 5:57 AM, Ben Bolker wrote:
smoff boku.ac.at> writes:
My problem is that I have a table containing dates in the first
column of 10
years. These dates have the format ddmm at least in the csv-
file. After
importing the file using read.table() R deletes the first charac
Linux systems have a user mask that limits the file mode creation
possibilities of any processes launched from that shell. If you check
your /etc/profile file, you will see the line
umask 022
This prevents you by default from creating files with write access for
everyone except the user. In
On May 4, 2011, at 15:11 , JP wrote:
> Peter thanks for the fantastically simple and understandable explanation...
>
> To sum it up... to find the z values of a number of pairwise wilcox
> tests do the following:
>
> # pairwise tests with bonferroni correction
> x <- pairwise.wilcox.test(a, b,
Hi
r-help-boun...@r-project.org napsal dne 04.05.2011 12:44:04:
> TheSavageSam
> Odeslal: r-help-boun...@r-project.org
>
>
> Hello!
>
> I have had some problems lately with use of R at home and school. At my
home
> laptop (Ubuntu linux 64bit & R-2.12.0) R works just fine. But when I
take m
Dos this do what you want?
plot(1:10, xlab=expression(delta*{}^18*"O" * " VSMOW [â°]"))
The specific is to put an empty item there to hold the superscript.
On Wed, May 4, 2011 at 9:37 AM, Janhal wrote:
> Salut,
> I have been struggling to superscript the 18 before the O without ^ visible
> an
In addition to the suggestion about finding a good initial value, you should
also scale your response V2 (and, of course, V0). Divide V2 by 10^4, for
example. Now your V0 should also be scaled by this factor. This would likely
help with convergence.
Ravi.
---
On Wed, May 4, 2011 at 9:28 AM, Robert Baer wrote:
>>> I have a erdos-renyi game with 6000 nodes and probability 0.003.
>>>
>>> g1 = erdos.renyi.game(6000, 0.003)
>>>
>>> How to create a Watts Strogatz game with the same probability.
>>>
>>> g1 = watts.strogatz.game(1, 6000, ?, ?)
>>> What should
Thanks Andrew.
I am sorry for some typos that I omit some numbers of T2.
Based on your suggestion,I think the problem is in the initial values.
And I will read more theory about the non-linear regression.
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On Wed, May 4, 2011 at 2:18 PM, Mike Harwood wrote:
> Thank you, Goran. Please see the package details below:
Thanks, I have uploaded a corrected version of eha to CRAN. Should be
available soon.
Göran
[...]
__
R-help@r-project.org mailing list
http
Thanks Ruben.
Your suggestion about more deeper analysis about the model itself is really
helpful.
I am trying out some new initial values based on the analysis of the special
T2 in the model.
--
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Dear list,
I am trying to create a folder structure, say 'test/sub', and set the
folder and sub folder to be writable to everyone.
By default
dir.create('test/sub', recursive=TRUE, mode='0777')
creates folders with mode: drwxr-xr-x
After
Sys.chmod('test/sub',mode='0777')
The folder 'test' is
Thanks, that clears things up quite a bit. Now I'm left wondering why there
is so much bias, but that's a separate issue.
--
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