Hi there,
I cannot find a detailed explanation to the following error message:
> colnames(matrix(1:10, ncol = 2)) <- c("X", "Y")
Error in colnames(matrix(1:10, ncol = 2)) <- c("X", "Y") :
target of assignment expands to non-language object
However, when I do the following things, the error me
Hi:
This should get you most of the way there; I'll let you figure out how to
assign the BLOCK and RUN numbers.
tx <- "Subject ID,ExperimentName,2010-04-23,32:34:23,Version 0.4, 640 by
960 pixels, On Device M, M, 3.2.4,
zz_373_462_488_...@9z.svg,592,820,3.35,zz_032_288_436_...@9z.svg
,332,878,3.
Does this seems like a good stand in for now:
require(ggplot2)
x <- runif(100,1,2)
y <- runif(100,50,60)
z <- runif(100,99,100)
xyz <- melt(data.frame(x,y,z))
ggplot(xyz, aes(value)) +
geom_histogram() +
facet_grid(~ variable, scale="free")
On Sunday, March 6, 2011 at 9:25 PM, cassie jones wr
Try
t.test(buzz$var1, conf.level=.98)$conf.int[1:2]
Cheers,
Simon.
From: r-help-boun...@r-project.org [r-help-boun...@r-project.org] On Behalf Of
Erin Hodgess [erinm.hodg...@gmail.com]
Sent: Monday, March 07, 2011 3:11 PM
To: R help
Subject: [R] attr q
Dear R People:
When I want to produce a small sample confidence interval using
t.test, I get the following:
> t.test(buzz$var1, conf.level=.98)$conf.int
[1] 2.239337 4.260663
attr(,"conf.level")
[1] 0.98
How do I keep the attr statement from printing, please? I'm sure it's
something really simp
"count.fields" is a very nice hint for a clean solution - thank you!
Joh
On Sunday 06 March 2011 21:48:32 David Winsemius wrote:
> On Mar 6, 2011, at 12:47 PM, Johannes Graumann wrote:
> > Thank you for pointing this out. This is really inconvenient as I do
> > not
> > know a priori how many and
On 6-Mar-11, at 7:13 PM, Eric Fail wrote:
Dear R-list,
I have a partly comma separated partly underscore separated string
that I am trying to parse into R.
Furthermore I have a bunch of them, and they are quite long. I have
now spent most of my Sunday trying to figure this out and thought
Dear R-list,
I have a partly comma separated partly underscore separated string that I am
trying to parse into R.
Furthermore I have a bunch of them, and they are quite long. I have now spent
most of my Sunday trying to figure this out and thought I would try the list to
see if someone here wo
> Date: Sun, 6 Mar 2011 15:42:11 -0800
> From: ksa...@gmail.com
> To: r-help@r-project.org
> Subject: [R] Monte carlo help
>
> Hello, I am currently doing my project and I need some help.
> I am trying to schedule tutors for a study room where stu
Hi Bert and Lattice experts
Thank you for suggestion and I am still reading your suggestions (Deepayan's
book) and help guide. So far no silverlining in horizon. Here is my outline,
that keep changing:
require(lattice)
pvals <- which (dataf$p < 0.05)
xyplot(p ~ xvar|chr, data=dataf, pvals = pva
On Mar 6, 2011, at 6:05 PM, Liviu Andronic wrote:
On Sun, Mar 6, 2011 at 11:53 PM, Liviu Andronic > wrote:
On Sun, Mar 6, 2011 at 11:49 PM, Liviu Andronic > wrote:
Dear all
This may be obvious, but I cannot get it working. I'm trying to
subset
& sort a data frame in one go.
x <- iris
x$Speci
Dear all,
I am trying to plot 3 histograms on the same graph using the following
command.
hist(x,xlim=c(0,100))
hist(y,add=TRUE)
hist(z,add=TRUE)
The xlim of y is c(20,21) and that of z is c(99,99.5) , whereas the variable
x has xlim at c(0.5,2). Apparently, the graph end of displaying a line on
Dear Sebastian,
Yes. The problem is that the most recent
version of psych 1-.0-94 was released before the
most recent version of lavaan (0.4-7)
I have updated the lavaan.diagram function in psych and will release it soon.
In the meantime, you can get the update by sourcing it at
http://
Hi everyone,
I get the following message when I try to get a diagram of a CFA:
Error in lavaan.diagram(fit) :
no slot of name "GLIST" for this object of class "Fit"
Does anyone know what the problem is?
Regards.
--
Sebastián Daza
sebastian.d...@gmail.com
_
Hi
On 5/03/2011 9:37 a.m., Sébastien Bihorel wrote:
Dear R-users,
As far as I understand, when one defines the width of a rectGrob call using
a 'npc' unit, the width of the object is proportional to the width of the
current viewport. Is there a way to refer to the height (or width) of the
viewp
On 03/06/2011 04:34 PM, Janko Thyson wrote:
> Dear list,
>
> a while ago I posted this at r-devel but got no answers. Hope it’s okay to
> give it a shot again by cross-posting it here.
Hi Janko --
>
> TIA for any comments,
> Janko
>
> Von: Janko Thyson [mailto:janko.thyson.rst...@googlemail.com
Hi David,
On Sat, Mar 5, 2011 at 11:00 PM, David Winsemius wrote:
>
> On Mar 5, 2011, at 11:28 AM, Joshua Ulrich wrote:
>
>> Hi Chris,
>>
>> Perhaps something like this?
>>
>> require(xts)
>> ds <- options(digits.secs=6) # so we can see sub-seconds
>> x <- xts(1:10, as.POSIXct("2011-01-21") + c(1
Hello, I am currently doing my project and I need some help.
I am trying to schedule tutors for a study room where students come in and
out for helps. My goal is to schedule the tutors to maximally accomodate to
the flow of students that need help with math so that each tutor is given an
appropriat
Dear list,
a while ago I posted this at r-devel but got no answers. Hope its okay to
give it a shot again by cross-posting it here.
TIA for any comments,
Janko
Von: Janko Thyson [mailto:janko.thyson.rst...@googlemail.com]
Gesendet: Montag, 21. Februar 2011 00:58
An: r-devel@r-project. org (r-d
Hi:
One approach is through the data.table package:
library(data.table)
df <- as.data.frame(data.table(iris, key = 'Species')[Sepal.Length == 6.7])
str(df)
Using Species as a key variable automatically sorts by Species; the
bracketing allows you to subset on Sepal.Length == 6.7.
ddply() in the
So there are a couple parts to this question. I am trying to implement the
rpart/random forest algorithms on a transaction lists. That is to say i am
trying to train models in order to deduce what are the most predictive
transactions within a customers history in order apply this model to future
te
On Mar 6, 2011, at 5:49 PM, Liviu Andronic wrote:
Dear all
This may be obvious, but I cannot get it working. I'm trying to subset
& sort a data frame in one go.
x <- iris
x$Species1 <- as.character(x$Species)
##subsetting alone works fine
with(x, x[Sepal.Length==6.7,])
##sorting alone works fin
On Sun, Mar 6, 2011 at 11:53 PM, Liviu Andronic wrote:
> On Sun, Mar 6, 2011 at 11:49 PM, Liviu Andronic
> wrote:
>> Dear all
>> This may be obvious, but I cannot get it working. I'm trying to subset
>> & sort a data frame in one go.
>> x <- iris
>> x$Species1 <- as.character(x$Species)
>> ##sub
On Sun, Mar 6, 2011 at 11:49 PM, Liviu Andronic wrote:
> Dear all
> This may be obvious, but I cannot get it working. I'm trying to subset
> & sort a data frame in one go.
> x <- iris
> x$Species1 <- as.character(x$Species)
> ##subsetting alone works fine
> with(x, x[Sepal.Length==6.7,])
> ##sorti
Dear all
This may be obvious, but I cannot get it working. I'm trying to subset
& sort a data frame in one go.
x <- iris
x$Species1 <- as.character(x$Species)
##subsetting alone works fine
with(x, x[Sepal.Length==6.7,])
##sorting alone works fine
with(x, x[order(Sepal.Length, rev(sort(Species1))),]
On Mar 6, 2011, at 1:52 PM, Ashish Kumar wrote:
In the boot package,consider a scalar function to boot.
estimator <- function(x, d) {
+ mean(x[d])
+ }
data <- city$u
b <- boot(data, estimator, R=1000)
b$t0
[1] 64
ci <- boot.ci(b, type=c("bca"), conf=.95)
ci$bca
conf
[1,] 0.95 49.44
In the boot package,consider a scalar function to boot.
> estimator <- function(x, d) {
+ mean(x[d])
+ }
>
> data <- city$u
> b <- boot(data, estimator, R=1000)
> b$t0
[1] 64
> ci <- boot.ci(b, type=c("bca"), conf=.95)
> ci$bca
conf
[1,] 0.95 49.44 991.39 36.78807 110.0254
Now if I want est
On Sun, 2011-03-06 at 08:06 -0500, Mike Marchywka wrote:
>
>
>
>
>
>
> > Date: Thu, 3 Mar 2011 13:04:11 -0600
> > From: matt.shotw...@vanderbilt.edu
> > To: r-help@r-project.org
> > Subject: Re: [R] Developing a web crawler / R "webkit" or something
>
On Mar 6, 2011, at 12:47 PM, Johannes Graumann wrote:
Thank you for pointing this out. This is really inconvenient as I do
not
know a priori how many and where those darn cases containing an
additional
(or more) ":" might be ...
There is a count.fields function that might assist with this
Opted for a solution with 100 column names, which is unlikely to be met ...
Thanks for your guidance.
Joh
On Sunday 06 March 2011 20:57:11 Sarah Goslee wrote:
> You could pre-process your data into a more sensible format.
> Or you could use scan to read each line of the file, count the number of
Em 5/3/2011 21:29, Umesh Rosyara escreveu:
Dear All
I am reposting because I my problem is real issue and I have been working on
this. I know this might be simple to those who know it ! Anyway I need help
!
Let me clear my point. I have huge number of datapoints plotted using either
base plot f
On Mar 6, 2011, at 9:50 AM, tsvi sabo wrote:
Hi!,i would really appreciate any help on that matter.I am currently
programming a procedure on RI have few functions,1. Choose Excel
file function2. Choose Excel sheet function.3.Choose columns for
variables function4.Few plots functions and an
You could pre-process your data into a more sensible format.
Or you could use scan to read each line of the file, count the number of colons,
then use read.table with ncolons + 1 columns.
Or you could use read.table with many more columns than are ever going to be
in the data, then delete the empty
Thank you for pointing this out. This is really inconvenient as I do not
know a priori how many and where those darn cases containing an additional
(or more) ":" might be ...
The seems to work, but will fail if there's a "1:sdfjhlfkh:2:adlkjf"
somewhere (1 & 2 both integerable).
na.exclude(as
Hi Nipesh,
Try "\cr". See section 2.2 of the "Writing R Extensions" document for more
information.
HTH,
- Francisco
On Sun, Mar 6, 2011 at 2:03 PM, Nipesh Bajaj wrote:
> Hi all, I have created a package and now into writing it's help files.
> However I am having problem on, how to put a 'new
Hi!,i would really appreciate any help on that matter.I am currently
programming a procedure on RI have few functions,1. Choose Excel file
function2. Choose Excel sheet function.3.Choose columns for variables
function4.Few plots functions and analisys5.Main function that runs these
functions on
On Mar 6, 2011, at 10:19 AM, Sarah Goslee wrote:
Not so much a mystery. read.table() only looks at the first 5 lines
when
decided how many columns your file has (as described in the Details
section of the help).
The easiest solution is to add a col.names argument to read.table()
with
the
If you want to identify the coordinates of points within a region, you
might want to look at the ImageJ application.
http://rsbweb.nih.gov/ij/
IIRC it has some macros to find and classify spots.
__
R-help@r-project.org mailing list
https://stat.ethz.
This is easy to do by specifying xyplot's panel function. Assuming
only one panel -- otherwise you need to pass the subscripts arguments
to choose the values belonging to the panel -- somethings like:
xyplot(y~x, pvals = pvals,..., ## pvals is your vector of small p
values with e.g. NA's elsewher
Not so much a mystery. read.table() only looks at the first 5 lines when
decided how many columns your file has (as described in the Details
section of the help).
The easiest solution is to add a col.names argument to read.table() with
the correct number of names.
You may want to also include as.
On 6 March 2011 at 12:37, Paul Smith wrote:
| Dear All,
|
| I would like to use
|
| - plot,
| - curve
|
| inside a C++ program. What R package do you recommend? Rcpp?
You can use base R, embedding R is explained in the 'Writing R Extensions'
manual. That said, the material is a little on the
Dear Jorge, Dennis, Sarah and R-experts.
Thank for helping me. As you mentioned it is difficult apply in lattice in
this situation.
Unless, there is a possibility, I would try to use lattice. The major reason
toward this is- my ultimate solution might be better of in lattice as I have
a cla
> Date: Thu, 3 Mar 2011 13:04:11 -0600
> From: matt.shotw...@vanderbilt.edu
> To: r-help@r-project.org
> Subject: Re: [R] Developing a web crawler / R "webkit" or something similar?
> [off topic]
>
> On 03/03/2011 08:07 AM, Mike Marchywka wrote:
> >
>
Hello,
Please have a look at the code below, which I use to read in the attached
file. As line 18 of the file reads "1065:>sp|Q9V3T9|ADRO_DROME
NADPH:adrenodoxin oxidoreductase, mitochondrial OS=Drosophila melanogaster
GN=dare PE=2 SV=1", I expect the code below to produce a 3 column data frame
Dear all, I am having problem to create a package when this package is
supposed to have some newly created s4 class. Here is my workout:
> #rm(list = ls())
> setClass("aClass", sealed=T, representation(slot1 = "vector", slot2 =
> "character"))
[1] "aClass"
> fn1 <- function(x, y, z) {
+ x <- x[1
Hi all, I have created a package and now into writing it's help files.
However I am having problem on, how to put a 'new line' in any
statement of the help file? For example please consider following:
\title{
This is a new function and this function will calculate the mean.
}
However I want to wr
> From: uwe.wolf...@uni-ulm.de
> To: andy_l...@merck.com
> Date: Sat, 5 Mar 2011 17:14:12 +0100
> CC: r-help@r-project.org; gunter.ber...@gene.com
> Subject: Re: [R] Coefficient of Determination for nonlinear function
>
> Dear Bert, dear Andy,
>
> th
I think you've made your problem too complicated.
Given your example below (and THANK YOU for including a workable
example), is this not what you need?
sigdata <- dataf[dataf$p < 0.01,]
plot(dataf$xvar, dataf$p)
text(sigdata$xvar, sigdata$p, sigdata$name)
text() will take vectors of arguments.
Dear All,
I would like to use
- plot,
- curve
inside a C++ program. What R package do you recommend? Rcpp?
Thanks in advance,
Paul
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide htt
On 05.03.2011 18:40, djbirdnerd wrote:
not yet, but i have only just started programming in r...
I don't know if i will able to...
Without quoting the former thread and without replying to a particular
person (rather than the mailing list only): Do you expect anybody on the
mailing list kn
On 11-03-05 8:20 PM, Kingsley G. Morse Jr. wrote:
Is my understanding correct that the body()
function currently can't return a function's body
intact, in order, and as characters ready for
editing?
Yes, that's not what body() returns. You can get what you want by
printing the result of body(
On Mar 6, 2011, at 09:34 , array chip wrote:
> Hi, I am encountering a confusing problem when I tried to use read.ssd to
> read
> SAS datasets. For one SAS dataset "a.sas7bdat", it did not work; while for
> another SAS dataset "b.sas7bdat" it worked:
>
>> tmp<-read.ssd("C:\\SASdata", "a",sasc
I came across the same thing, doing multinomial cross validation with
cv.glmnet but also doing it with a for loop with subsets on the X matrix and
y response categories. I've tested it out various ways and I think the
problem occurs because in one of the folds there are no codes for at least
on
Hi, I am encountering a confusing problem when I tried to use read.ssd to read
SAS datasets. For one SAS dataset "a.sas7bdat", it did not work; while for
another SAS dataset "b.sas7bdat" it worked:
> tmp<-read.ssd("C:\\SASdata", "a",sascmd="C:/Program
>Files/SAS/SASFoundation/9.2/sas.exe")
SAS
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