The error seems to be a BioC problem[*] and associated with having a
package installed with an empty DESCRIPTION file. So please take a
look at your installed packages and remove any such.
The following R code may help:
for(lib in .libPaths()) {
descs <- Sys.glob(file.path(lib, "*", "DESC
Hello Cesar,
Thank you for the reply.
Another question I have is if it is possible to detect the library path of
an old R install, from the terminal of the new R install.
Cheers,
Tal
Contact
Details:---
Contact me: tal.gal...@g
Hi list,
I have been trying to create a legend for a plot that includes polygons,
lines, and points. I've included an example below.
I have two problems with this legend.
1. I can't seem to change the colour of the box that represents the polygon
in the legend.
2. The boxes and points in the lege
Hi:
See inline.
On Mon, Nov 15, 2010 at 4:26 PM, Nate Miller wrote:
> Hi All!
>
> I have some experience with R, but less experience writing scripts using
> R and have run into a challenge that I hope someone can help me with.
>
> I have multiple .csv files of data each with the same 3 columns
Hi Anthony,
On Mon, Nov 15, 2010 at 7:07 AM, Anthony Damico wrote:
> Hi, I'm working in R 2.11.1 x64 on Windows x86_64-pc-mingw32. I'm trying to
> insert a very large CSV file into a SQLite database. I'm pretty new to
> working with databases in R, so I apologize if I'm overlooking something
>
Hi everyone,
I'm having a little trouble with working out what formula is better to use
for a repeated measures two way anova. I have two factors, L (five levels)
and T (two levels). L and T are both crossed factors (all participants do
all combinations). So, I do:
summary(aov(dat~L*T+Error(
Hi,
I'm using R-2.12 on a linux 64bit machine.
When I run a chunk of code inside a foreach() %do% { ...} or %dopar%
{...} (with doMC backend) I keep getting a segfault. Running the
*same* code within lapply(something, function(x) ... ) doesn't result
in any segfaults. I'll paste the output below,
Hi:
Perhaps this post from earlier today will be useful:
http://r.789695.n4.nabble.com/Re-interpretation-of-coefficients-in-survreg-AND-obtaining-the-hazard-function-td3043160.html#a3043160
HTH,
Dennis
2010/11/15 Lorena Avendaño
> Dear R-users,
>
> I would like to fit a fully parametric propor
On Nov 15, 2010, at 7:58 PM, Chris Carleton wrote:
Thanks for the suggestions, but 'cat' is not causing name space
conflicts for me
install.packages(
library(fortunes)
fortune("dog")
and since I'm not packaging the code for anyone else to use, I'm
less than concerned about potential confl
Hello,
Is this what you want ?
sampleX <- function(X, nGrp1, nsamples)
# X is matrix or data.frame with cols for two groups of variables
# with grp1 in cols 2:5 and grp2 in cols 6:9
#
# nGrp1 <- number of variables to sample from group 1
#
# nsamples <- number of rows in output matrix
if (nGrp
Thanks for the suggestions, but 'cat' is not causing name space conflicts
for me and since I'm not packaging the code for anyone else to use, I'm less
than concerned about potential conflicts. I did type that too quickly, and I
have resolved my problem using a workaround that does not involve findi
Thanks! Seems to work just fine!
Best regards,
Eduardo Horta
On Mon, Nov 15, 2010 at 10:37 PM, David Winsemius wrote:
>
> On Nov 15, 2010, at 7:18 PM, Eduardo de Oliveira Horta wrote:
>
> Hello,
>>
>> I was trying to build some functions which I would like to integrate over
>> an
>> interval u
On Nov 15, 2010, at 7:18 PM, Eduardo de Oliveira Horta wrote:
Hello,
I was trying to build some functions which I would like to integrate
over an
interval using the function 'integrate' from the 'stats' package. As
an
example, please consider the function
h(u)=sin(pi*u) + sqrt(2)*sin(pi*
Hi All!
I have some experience with R, but less experience writing scripts using
R and have run into a challenge that I hope someone can help me with.
I have multiple .csv files of data each with the same 3 columns of
data, but potentially of varying lengths (some data files are from short
m
Hello R community,
I need to do some aggregation based on the test data below. The below
code works ok, but when its applied to my real data which includes over
9,000 records the process runs for over an hour. I know there is a more
efficient way of doing this. I want to Sum the below data'
Hey everybody.
I found the solution to the problem - at least for univariate statistics. In
order to use the bootstrap method for an arbitrary statistic, the syntax for
the function has to be in the form:
Given a univariate formula with argument 'x':
myfunction <- function(x,p){formula(x[p])}
Em 14/11/2010 20:42, csrabak escreveu:
Em 14/11/2010 18:24, Tal Galili escreveu:
Hi John, thank you for that input.
It could be that the code I wrote here:
http://www.r-statistics.com/2010/04/changing-your-r-upgrading-strategy-and-the-r-code-to-do-it-on-windows/
Should be updated so every time
Hello,
I was trying to build some functions which I would like to integrate over an
interval using the function 'integrate' from the 'stats' package. As an
example, please consider the function
h(u)=sin(pi*u) + sqrt(2)*sin(pi*2*u) + sqrt(3)*sin(pi*3*u) + 2*sin(pi*4*u)
Two alternative ways to 'bu
julien martin gmail.com> writes:
> (2) The second part of the script calls WinBUGS and run the binomial
> mixture models on the count data. In this case the count matrix y was
> converted to a vector C1 before being passed over to BUGS
> Any idea how to create a zero truncated Poisson for paramet
On Nov 15, 2010, at 5:33 PM, daniel carawan wrote:
Hi,
I need to convert general numbers to percentages in R to create a
boxplot for purposes of comparison.
Can you please tell me how I can do that? My data is attached as a
csv file.
No, it's not. Please read the Posting Guide. (.csv is
Ben Raymond rhul.ac.uk> writes:
>
> Dear R community,
>
> I would like to compare the degree of aggregation (or dispersion) of
> bacteria isolated from plant material. My data are discrete counts
> from leaf washes. While I do have xy coordinates for each plant, it
> is aggregation in t
... and/or perhaps ?coplot in base R graphics or ?xyplot in trellis.
-- Bert Gunter
On Mon, Nov 15, 2010 at 2:25 PM, Greg Snow wrote:
> Look at Predict.Plot (and TkPredict) from the TeachingDemos package.
>
> --
> Gregory (Greg) L. Snow Ph.D.
> Statistical Data Center
> Intermountain Healthcare
On Nov 15, 2010, at 5:07 PM, Chris Carleton wrote:
Thanks for the suggestions. The issue for me is that the top level
index is
also like a database key so it might be a bit annoying to coerce it to
char() so that I can reference it with a $ and then I would have to
still be
able to find out
On Mon, Nov 15, 2010 at 1:28 PM, Anthony Damico wrote:
> Hi Gabor,
>
> Thank you for your willingness to help me through this. The code you sent
> works on my machine exactly the same way as it does on yours.
> Unfortunately, when I run the same code on the 1.3GB file, it creates the
> table stru
On Mon, Nov 15, 2010 at 2:19 PM, Reshmi Chowdhury
wrote:
> Here is the code I am using:
>
> m <- read.csv("data_unsorted.csv",header=TRUE)
> m <- na.omit(m)
> cs <- hclust(dist(t(m),method="euclidean"),method="complete")
> ds <- as.dendrogram(cs)
As Christian said, you may want to plot the cs tre
Hi,
I need to convert general numbers to percentages in R to create a boxplot for
purposes of comparison.
Can you please tell me how I can do that? My data is attached as a csv file.
Thanks.
Daniel
__
R-help@r-project.org mailing list
https://stat.e
Thanks for the suggestions. The issue for me is that the top level index is
also like a database key so it might be a bit annoying to coerce it to
char() so that I can reference it with a $ and then I would have to still be
able to find out what the name was automatically. I've got a function right
Dear R-users,
I would like to fit a fully parametric proportional hazard model with a
weibull baseline hazard and a logit link function. This is, the hazard
function is: lambda_i (t) = lambda_0 (t) psi (x_i* beta)
where lambda_0 is a weibull distribution and psi a logistic distribution.
Does some
Hey,
I am hoping someone can help me with a sampling question.
I have a data frame of 8 variables (the first column is the subjects' id):
SubIDCSE1 CSE2 CSE3 CSE4 WSE1 WSE2 WSE3 WSE4
1 6 5 6 2 6 22 4
2 6 4
Look at Predict.Plot (and TkPredict) from the TeachingDemos package.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Be
You could display the matrix as an image then add column names (rotated used
srt) if you really want them.
x <- cor(matrix(rnorm(600), 60, 100))
# set margins with extra space at top and xpd=TRUE to write outside plot
region
op<-par(mar=c(1,1,5,1), xpd=TRUE)
# display image without the 90 de
Here is the code I am using:
m <- read.csv("data_unsorted.csv",header=TRUE)
m <- na.omit(m)
cs <- hclust(dist(t(m),method="euclidean"),method="complete")
ds <- as.dendrogram(cs)
In this case, m is a 106x40 matrix of doubles. When I change the order of
the columns, I get different results...
Tha
I don't know how the hclust function is implemented, but generally in
hierarchical clustering the result can be ambiguous if there are several
distances of identical value in the dataset (or identical between-cluster
distances occur when aggregating clusters). The role of the order of the
data
Hi Mark,
If the cumbersome part is that you have to create new data to use
predict, then I think the answer is "no", there is not an easier way.
However, we can consider easy ways to make new data that fit with
certain constraints (e.g., variables = their mean). Here's an
example:
## original d
On Mon, Nov 15, 2010 at 2:07 PM, rchowdhury wrote:
>
> Hello,
>
> I am using the hclust function to cluster some data. I have two separate
> files with the same data. The only difference is the order of the data in
> the file. For some reason, when I run the two files through the hclust
> funct
Hi,
I am unable to install packages on my R 2.12.0 Windows 7 machine. Here are the
relevant lines:
sessionInfo()
R version 2.12.0 (2010-10-15)
Platform: x86_64-pc-mingw32/x64 (64-bit)
locale:
[1] LC_COLLATE=English_United States.1252 LC_CTYPE=English_United States.1252
LC_MONETARY=English_
On Nov 15, 2010, at 4:43 PM, patze003 wrote:
Hello Everyone -
I want to print a number of results from lme function objects out to
a txt
file. How could I do this more efficiently than what you see here:
out2 <- capture.output(summary(mod2a))
out3 <- capture.output(summary(mod3))
out4 <-
Sorry folks, I keep forgetting to switch to my r-help email to send the
replies so they get unintentionally sent to a moderator (particularly sorry
for that moderators...)
C
-- Forwarded message --
From: Chris Carleton
Date: 15 November 2010 17:07
Subject: Re: [R] indexing lists
On Mon, 15 Nov 2010 13:28:40 -0500, Anthony Damico wrote:
> Do you have any other ideas as to how I might diagnose what's going on
> here? Or, alternatively, is there some workaround that would get this giant
> CSV into a database? If you think there's a reasonable way to use the
> IMPORT comman
Hello,
I am using the hclust function to cluster some data. I have two separate
files with the same data. The only difference is the order of the data in
the file. For some reason, when I run the two files through the hclust
function, I get two completely different results.
Does anyone know w
On Nov 15, 2010, at 4:24 PM, Chris Carleton wrote:
Hi List,
I'm trying to work out how to use which(), or another function, to
find the
top-level index of a list item based on a condition. An example will
clarify
my question.
a <- list(c(1,2),c(3,4))
a
[[1]]
[1] 1 2
[[2]]
[1] 3 4
I wan
Hello Everyone -
I want to print a number of results from lme function objects out to a txt
file. How could I do this more efficiently than what you see here:
out2 <- capture.output(summary(mod2a))
out3 <- capture.output(summary(mod3))
out4 <- capture.output(summary(mod5))
out5 <- capture.outp
Hello R-helpers,
Please see a self-contained example below, in which I attempt to plot
the effect of x1 on y, while controlling for x2.
Is there a function that does the same thing, without having to
specify that x2 should be held at its mean value? It works fine for
this simple example, but migh
On 15/11/2010 4:10 PM, William Dunlap wrote:
You could make f[[i]] be function(t)t^2+i for i in 1:10
with
f<- lapply(1:10, function(i)local({ force(i) ; function(x)x^2+i}))
After that we get the correct results
> f[[7]](100:103)
[1] 10007 10208 10411 10616
but looking at the func
Hi Chris,
Does this do what you're after? It just compares each element of a
(i.e., a[[1]] and a[[2]]) to c(1, 2) and determines if they are
identical or not.
which(sapply(a, identical, y = c(1, 2)))
There were too many 1s floating around for me to figure out if you
wanted to find elements of a
Chris,
Well, the 'answer' could be:
which(sapply(a, function(x) all(x == c(1,2
But I wonder how these elements of 'a' in your
actual application are coming to be? If you're
constructing them, you can give the elements of
the list names, and then it doesn't matter what
numerical index they
Thanks a lot for your readiness! Problem (apparently) solved!
Best regards,
Eduardo Horta
On Mon, Nov 15, 2010 at 7:10 PM, William Dunlap wrote:
> You could make f[[i]] be function(t)t^2+i for i in 1:10
> with
> f <- lapply(1:10, function(i)local({ force(i) ; function(x)x^2+i}))
> After th
Hi List,
I'm trying to work out how to use which(), or another function, to find the
top-level index of a list item based on a condition. An example will clarify
my question.
a <- list(c(1,2),c(3,4))
a
[[1]]
[1] 1 2
[[2]]
[1] 3 4
I want to find the top level index of c(1,2), which should return
Hi Craig,
As Greg pointed out, choose optimal locations for labels is tricky
(side note for anyone reading pointLabel() comes from the maptools
package). Inferring from your code, the labels you are plotting are
the "Category" each point belongs to which suggests there may not be a
huge amount of
Hi Ivan / Dieter
Thanks for your assistance, I will try the suggestions.
The plotrix solution seems like the more elegant solution, except that
unless I missing something I will land up with a value based graph
rather than a density based one, which is what I really wanted.
It seems like the
You could make f[[i]] be function(t)t^2+i for i in 1:10
with
f <- lapply(1:10, function(i)local({ force(i) ; function(x)x^2+i}))
After that we get the correct results
> f[[7]](100:103)
[1] 10007 10208 10411 10616
but looking at the function doesn't immdiately tell you
what 'i' is in th
Sorry, pointLabel() is in the package "maptools":
http://rgm2.lab.nig.ac.jp/RGM2/R_man-2.9.0/library/maptools/man/pointLabel.html
Thank you for the tips on the other packages, I will give it a try.
-C
On Mon, Nov 15, 2010 at 3:54 PM, Greg Snow wrote:
> What package is pointLabel (or is it p
This is a side effect of the lazy evaluation done in functions. Look at the
help page for the force function for more details and how to force evaluation
and solve your problem.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
What made you think that a cross-covariance matrix should be positive
definite? Id does not even need to be a square matrix, or symmetric.
Giovanni Petris
On Mon, 2010-11-15 at 12:58 -0500, Jeff Bassett wrote:
> I am creating covariance matrices from sets of points, and I am having
> frequent pro
What package is pointLabel (or is it pointLabels) in? giving a reproducible
example includes stating packages other than the standard ones.
What you are trying to do is not simple for general cases, some tools work
better on some datasets, but others work better on other datasets.
Some other t
Hello,
I was trying to define a set of functions inside a loop, with the loop index
working as a parameter for each function. Below I post a simpler example, as
to illustrate what I was intending:
f<-list()
for (i in 1:10){
f[[i]]<-function(t){
f[[i]]<-t^2+i
}
}
rm(i)
With that, I was ex
On 16 November 2010 02:40, Feng Mai wrote:
>
> I also have the problem trying to start rattle
>
> Windows 7 32-bit R 2.12.0
>
> When I try library(rattle) I get an error message
> "The procedure entry point deflateSetHeader could not be located in the
> dynamic link library zilb1.dll"
> I hit OK
RE: the folloing original question:
> I'm using the randomForest package and would like to generate partial
> dependence plots, one after another, for a variety of variables:
>
> m <- randomForest( s, ... )
> varnames <- c( "var1", "var2", "var3", "var4" ) # var1..4 are all in
> data frame s
>
Dear Prof Therneau,
thank yo for this information: this is going to be most useful for what I want
to do. I will look into the ACF model.
Yours,
David Biau.
De : Terry Therneau
Cc : r-help@r-project.org
Envoyé le : Lun 15 novembre 2010, 15h 33min 23s
Obje
I've solved the condition problem, but have come across another one with the
gcmrec function and was wondering if anyone could point me in the right
direction again? After running the code below, I get this error message:
Error in gcmrec(Survr(id, time, event) ~ var, data = dataOK, s = 1096) :
N
Hello,
in my doctoral thesis i try to model time series crash count data with
an inar(1)-process, but i have a few problems in writing the r-code.
is there someone, who works with inar-processes. i would be very
grateful, if someone gives me some ideas in writing the code.
nazli
Hello R-list,
I am plotting a weighted linear regression in R. The points on my chart are
also scaled to sample size, so some points are large, some are small. I have
figured out everything I need using the plot() function: how to plot the
points, scale them by sample size, weight the linear regre
> From: ajdam...@gmail.com
> Date: Mon, 15 Nov 2010 13:28:40 -0500
> To: ggrothendi...@gmail.com; r-help@r-project.org
> Subject: Re: [R] How to Read a Large CSV into a Database with R
>
> Hi Gabor,
>
> Thank you for your willingness to help me throu
On Fri, 12-Nov-2010 at 03:29PM -0500, Ralf B wrote:
|> I know such programs, however, for my specific problem I have an R
|> script that creates a report (which I have to create many times)
|> and I would like to append about 100 single paged post scripts at
|> the end as appendix. File names are
Hi Lara,
Hmm, I've never seen column names rotated in R (certainly you could in
graphics, etc. and this should do it in that case:
lapply(strsplit(colnames(x), ''), paste, collapse = "\n") ). You
could transpose the matrix so the columns become the rows and then
just have numbers (1:1600) as the
On 15/11/2010 12:38 PM, Ralf B wrote:
Thank you for all your comment. In result of own research I found this
method that seems to do what I want in addition to your suggestions:
tools::texi2dvi("myfile.tex", pdf=TRUE)
Sure, but this doesn't quite answer your original question: you can't
pass
Hi Gabor,
Thank you for your willingness to help me through this. The code you sent
works on my machine exactly the same way as it does on yours.
Unfortunately, when I run the same code on the 1.3GB file, it creates the
table structure but doesn't read in a single line [confirmed with
sqldf("sele
Hi Ralf,
I first create (or not) the figure as a separate file(s) and then use
conditional LaTeX to display the existing file(s) (exactely where I want
it/them to appear). This also works with png etc, but you'll have to specify
the extensions. Just be careful if you change paths ...
This will
I am creating covariance matrices from sets of points, and I am having
frequent problems where I create matrices that are non-positive
definite. I've started using the corpcor package, which was
specifically designed to address these types of problems. It has
solved many of my problems, but I sti
I have a code junk that produces a figure. In my special case,
however, data does not always exist. In cases where data exists, the
code chunk is of course trival (case #1), however, what do I do for
case # 2 where the data does not exist?
I can obviously prevent the code from being executed by che
Dear List,
I have a large (1600*1600) matrix generated with symnum, that I am using to
eyeball the structure of a dataset.
I have abbreviated the column names with the abbr.colnames option. One way
to get an even more compact view of the matrix would be to display the
column names rotated by 90
Thank you for all your comment. In result of own research I found this
method that seems to do what I want in addition to your suggestions:
tools::texi2dvi("myfile.tex", pdf=TRUE)
Thanks again,
Ralf
On Mon, Nov 15, 2010 at 6:42 AM, Duncan Murdoch
wrote:
> On 15/11/2010 6:22 AM, Dieter Menne wro
Hello,
Is it possible to remove those extra margins on the "sample" axis from
plot.dendrogram:
par(oma=c(0,0,0,0),mar=c(0,0,0,0))
ddr<-as.dendrogram(hclust(dist(matrix(sample(1:1000,200),nrow=100
stats:::plot.dendrogram(ddr,horiz=F,axes=F,yaxs="i",leaflab="none")
vs.
stats:::plot.dendrogram
On Mon, Nov 15, 2010 at 11:46 AM, Anthony Damico wrote:
> Hi Gabor,
>
> Thank you for the prompt reply. I definitely looked over all of the
> examples on the code.google.com sqldf page before sending, which is why I
> wrote the code
>
> read.csv.sql("ss09pusa.csv" , sql="create table ss09pusa as
Thanks, Duncan. Finally getting a chance to follow up on this...
I tried again, changing and resetting my password, and trying to specify my
login and password manually in the getGoogleDocsConnection argument list. I
also tried removing either or both of the service and error options. No luck
in a
Thank you, Doug. I am still missing something here. Should this simply be
sum(f(x_i) * w_i) where x_i is node i and w_i is the weight at node i? So, my
function f(x) = (1/(s*sqrt(2*pi))) * exp(-((qq$nodes-mu)^2/(2*s^2))) would
then be multiplied only by the weights, qq$weights
Here is some rep
I am always trying but i could not do it. Are there any example about this
--
View this message in context:
http://r.789695.n4.nabble.com/Re-jackknife-after-bootstrap-tp3043213p3043398.html
Sent from the R help mailing list archive at Nabble.com.
__
R
Hi Gabor,
Thank you for the prompt reply. I definitely looked over all of the
examples on the code.google.com sqldf page before sending, which is why I
wrote the code
read.csv.sql("ss09pusa.csv" , sql="create table ss09pusa as select * from
file" , dbname="sqlite")
directly pulled from their co
Well, another possibility would be to edit the plot so that you cut the
empty part (between 300 and 2000).
There might be some function that can do it, maybe the
plotrix::gap.barplot() that Dieter already told you about.
Le 11/15/2010 16:22, sbsid...@mweb.co.za a écrit :
Thanks
What you have
On Mon, Nov 15, 2010 at 3:46 PM, Feng Mai wrote:
>
> IMO it is not possible. The code behind aspx page queries data from a
> database server and display it on the webpage.
That doesn't make it possible. Your web browser is sending a request
to the web server, and whatever happens behind the scen
Thanks for all of your help. It works to me.
Kate
On Mon, Nov 15, 2010 at 10:06 AM, David Winsemius wrote:
>
> On Nov 15, 2010, at 10:42 AM, Kate Hsu wrote:
>
> Hi r users,
>>
>> I have two data sets (X1, X2). For example,
>> time1<-c( 0, 8, 15, 22, 43, 64, 85, 106, 127, 148, 169, 190 ,21
On Mon, Nov 15, 2010 at 10:42 AM, Kate Hsu wrote:
> Hi r users,
>
> I have two data sets (X1, X2). For example,
> time1<-c( 0, 8, 15, 22, 43, 64, 85, 106, 127, 148, 169, 190 ,211 )
> outpue1<-c(171 ,164 ,150 ,141 ,109 , 73 , 47 ,26 ,15 ,12 ,6 ,2 ,1 )
> X1<-cbind(time1,outpue1)
>
>
We distribute several R applications using the tcltk package on different
servers or PC (Windows XP). On some machines and in a not reproducible
way, all the R windows disappear when using functions like tkgetSaveFile
or tkchooseDirectory. The R application remains open (the Rgui.exe
processus
On Mon, Nov 15, 2010 at 10:49 AM, Matthieu Stigler
wrote:
> I have limited understanding of Duncan's points but will follow your advice
> not to do it like this. If I am nervertheless quit keen to use foo2
> externally, is the use of either assign() in foo1, or mget() in foo2 more
> indicated? Or
On Nov 15, 2010, at 10:42 AM, Kate Hsu wrote:
Hi r users,
I have two data sets (X1, X2). For example,
time1<-c( 0, 8, 15, 22, 43, 64, 85, 106, 127, 148, 169, 190 ,
211 )
outpue1<-c(171 ,164 ,150 ,141 ,109 , 73 , 47 ,26 ,15 ,12 ,6 ,
2 ,1 )
X1<-cbind(time1,outpue1)
time2<-c(
See ?merge with argument all=TRUE and replace by 0 afterwards.
Uwe Ligges
On 15.11.2010 16:42, Kate Hsu wrote:
Hi r users,
I have two data sets (X1, X2). For example,
time1<-c( 0, 8, 15, 22, 43, 64, 85, 106, 127, 148, 169, 190 ,211 )
outpue1<-c(171 ,164 ,150 ,141 ,109 , 73 , 47 ,26
On 15.11.2010 15:52, Jonathan Williams wrote:
Dear Helpers,
I was trying to find a repository of earlier Windows versions of R packages. However,
while I can find the Archives for Linux versions (in the "Old Sources" section
of each package's Downloads) , I cannot find one for Windows versio
Ok to follow up my post, I finally got rattle and RGtk2 to work. The trick is
when R prompts me to install Gtk2+ I still hit yes but after the download,
once the installation process starts I close the R Gui window. After Gtk2+
installation is complete I start R again and it worked.
--
View this
Try the most excellent package dlm written by Giovanni Petris for your all
your Kalman filter needs. Also buy the accompanying book - it really
integrates the dlm package with the theory behind it.
Best,
John
On Mon, Nov 15, 2010 at 8:39 AM, Garten Stuhl
wrote:
> Hello,
>
>
>
> thanks for answ
IMO it is not possible. The code behind aspx page queries data from a
database server and display it on the webpage.
Maithula Chandrashekhar wrote:
>
> Dear all R users, I am wondering is there any procedure exists on R to
> fetch
> data directly from "http://www.ncdex.com/Market_Data/Spot_pric
Hi r users,
I have two data sets (X1, X2). For example,
time1<-c( 0, 8, 15, 22, 43, 64, 85, 106, 127, 148, 169, 190 ,211 )
outpue1<-c(171 ,164 ,150 ,141 ,109 , 73 , 47 ,26 ,15 ,12 ,6 ,2 ,1 )
X1<-cbind(time1,outpue1)
time2<-c( 0 ,8 ,15 , 22 ,43 , 64 ,85 ,106 ,148)
output2<-c(
On Mon, Nov 15, 2010 at 10:07 AM, Anthony Damico wrote:
> Hi, I'm working in R 2.11.1 x64 on Windows x86_64-pc-mingw32. I'm trying to
> insert a very large CSV file into a SQLite database. I'm pretty new to
> working with databases in R, so I apologize if I'm overlooking something
> obvious here
Le 15. 11. 10 14:14, Duncan Murdoch a écrit :
On 15/11/2010 7:48 AM, Matthieu Stigler wrote:
Hi
I have within a quite big function foo1, an internal function foo2. Now,
in order to have a cleaner code, I wish to have the internal foo2 as
"external". This foo2 was using arguments within the foo1
I also have the problem trying to start rattle
Windows 7 32-bit R 2.12.0
When I try library(rattle) I get an error message
"The procedure entry point deflateSetHeader could not be located in the
dynamic link library zilb1.dll"
I hit OK and it prompts me to install GTK+ again. I tried to uninstal
Hello,
thanks for answer my Question. I prefer use KalmanLike(y, mod, nit = 0,
fast=TRUE). For parameter estimating I have a given time series. In these
are several components: Season and noise; furthermore it gives a mean
reversion process. The season is modelled as a fourierpolynom. From the
g
Dear Helpers,
I was trying to find a repository of earlier Windows versions of R packages.
However, while I can find the Archives for Linux versions (in the "Old Sources"
section of each package's Downloads) , I cannot find one for Windows versions.
Does such a repository exist? If so, where ca
Tal
My main use of R now is on Windows 7. As explained I always retain at
least one previous version on windows 7 PCs. My upgrade is done as
follows -
1) Download and install the binary install program for R and install.
2) Rename the library directory (default - C:\Program
Files\R\R-2.12.0patc
Thanks
What you have suggested of course works but I am trying to reduce the
'ugliness'.
Anybody got any other ideas?
Regards
Steve
Sent from my BlackBerry® wireless device
-Original Message-
From: Ivan Calandra
Sender: r-help-boun...@r-project.org
Date: Mon, 15 Nov 2010 16:08:47
To
Steve Sidney mweb.co.za> writes:
> I am trying to re-scale a histogram and using hist() but can not seem to
> create a reduced scale where the upper values are not plotted.
>
> What I have is about 100 of which 80 or so are between a value of 0 and
> 40 , one or two in the hundreds and an outl
Anthony-107 wrote:
>
> Hi, I'm working in R 2.11.1 x64 on Windows x86_64-pc-mingw32. I'm trying
> to
> insert a very large CSV file into a SQLite database.
>
Better use an external utility if this is a one-time import for this job:
http://sqlitebrowser.sourceforge.net/
Dieter
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