On 09/21/2010 05:02 AM, Gregory Ryslik wrote:
> Hi,
>
> I think I've found away around that issue. The following works. If
this method is inefficient and one has something faster, I'll appreciate
it though!
>
> lapply(mylist, function(x) as.numeric(as.character(x)))
You could avoid making them f
I don't see a data frame name in the rlm call...
Dennis
On Mon, Sep 20, 2010 at 7:08 PM, uttara_n wrote:
>
> I am absolutely new to R and I am aware of only a few basic command lines.
> I
> was running a robust regression in R, using the following command line
>
> library (MASS)
> rfdmodel1 <-
Error originates in the customized function ode. When IN!=0, You did
not assign a value to dIN which is required in list(c(dP1,dP2,dIN)).
On 2010-9-21 2:30, Tianchan Niu wrote:
Dear All,
I am trying to use ode solver "rk4" to solve an ODE system, however, it
keeps saying: Error in eval(expr
Hi,
in order to save space for a publication, it would be nice to have a
combined scatter and density plot similar to what is shows on
http://addictedtor.free.fr/graphiques/RGraphGallery.php?graph=78
I wonder if anybody perhaps has already developed code for this and is
willing to share. This is
library(help = survival)
help("survreg", package = "survival")
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Halabi, Anan
Sent: Tuesday, 21 September 2010 3:12 PM
To: r-help@r-project.org
Subject: [R] Estimating Weibull paramete
Below my code:
sampleSize <- 20
shape.true <- 1.82
scale.true <- 987
sampWB <- rweibull(sampleSize, shape=shape.true, scale=scale.true)
print(sampWB)
censidx <- sample(1:length(sampWB), length(sampWB)*0.3)
Censored.data <- sampWB[censidx]
print(Censored.data)
NonCensored.data <- sampWB[-censidx]
p
It took me several rounds of failed efforts before I came up with a
perspective that was successful. One of the most informative exercises
was to look at lattice plot objects with str(). It taught me to always
try "packaging" arguments in nested list structures. I highly
recommend examining
Hi Joshua,
thanks, I came up with that solution myself after a bit of thinking.
Normally I wouldn't worry about NULL components of lists, but dimnames
is a list and often some components are null and is therefore a bit
tricky to manipulate...
Peter
On Mon, Sep 20, 2010 at 7:39 PM, Joshua Wiley
Hello,
I know I am supposed to get 'it' when I "?bwplot" but your example really
made things clearer for me.
Thanks,
Cheers,
Michael
On Mon, Sep 20, 2010 at 12:50 AM, David Winsemius wrote:
>
> On Sep 20, 2010, at 12:43 AM, Michael Just wrote:
>
> Hello,
>> If you run the following code with la
Hi,
I think I've found away around that issue. The following works. If this method
is inefficient and one has something faster, I'll appreciate it though!
lapply(mylist, function(x) as.numeric(as.character(x)))
Cheers,
Greg
On Sep 20, 2010, at 10:48 PM, David Winsemius wrote:
>
> On Sep 20,
On Sep 20, 2010, at 10:28 PM, David Winsemius wrote:
On Sep 20, 2010, at 10:12 PM, Gregory Ryslik wrote:
Hi,
I have a list of 5 main elements where each main element has 247
atomic entries either 0 or 1. I need to get this into a 247x5
matrix so I do "do.call(cbind, mylist)". However,
Hi Gregory,
May be this?
# some data
set.seed(123)
x <- factor(sample(0:1, 20, TRUE))
x
# [1] 0 1 0 1 1 0 1 1 1 0 1 0 1 1 0 1 0 0 0 1
# Levels: 0 1
as.numeric(as.factor(x))
# [1] 1 2 1 2 2 1 2 2 2 1 2 1 2 2 1 2 1 1 1 2
as.numeric(as.character(x))
[1] 0 1 0 1 1 0 1 1 1 0 1 0 1 1 0 1 0 0 0 1
HT
Hm,
Now that you mention it, I believe they are factors. They just appeared as 0 or
1 so I treated them as numbers.
Once I found out they were factors I tried using the as.numeric() but that
makes it 1 or 2 as before. How do I actually make it keep the factor number?
Thanks,
Greg
On Sep 20, 2
Sorry, that was a really half-hearted reply. This will create a new
list that is the old list shifted down (and should be much faster than
the for loop too).
lst <- list(NULL,2)
lst2 <- vector("list", length(lst) + 1)
lst2[2:length(lst2)] <- lst
lst
lst2
If you really need to use a for loop, may
On Sep 20, 2010, at 10:12 PM, Gregory Ryslik wrote:
Hi,
I have a list of 5 main elements where each main element has 247
atomic entries either 0 or 1. I need to get this into a 247x5 matrix
so I do "do.call(cbind, mylist)". However, it renumbers 0 to a 1
and the 1 to a 2 so that my matr
Hello Peter,
This is because assigning a value of NULL removes that element of the
list. I am not quite sure what the reference for that is. I remember
reading it in the documentation once though. I looked through ?list
to no avail. At any rate, to avoid it, you would have to assign
something
I am absolutely new to R and I am aware of only a few basic command lines. I
was running a robust regression in R, using the following command line
library (MASS)
rfdmodel1 <- rlm (TotalEmployment_2004 ~ MISSISSIPPI + LOUISIANA +
TotalEmployment_2000 + PCWhitePop_2004 + UnemploymentRate_2004 +
P
Hi,
I have a list of 5 main elements where each main element has 247 atomic entries
either 0 or 1. I need to get this into a 247x5 matrix so I do "do.call(cbind,
mylist)". However, it renumbers 0 to a 1 and the 1 to a 2 so that my matrix is
filled with 1's and 2's.
I understand I can fix it
Hello,
I encountered a weird problem. Consider the following code that takes
a list "lst" and shifts all elements one index up (for example, to
make space for a new first element):
lst = list(1,2)
ll = length(lst);
for (i in ll:1)
lst[[i+1]] = lst[[i]];
lst
If you run it, you get the expected
I have been looking for R package for audio manipulation in order to
extend RQDA's (http://rqda.r-forge.r-project.org/) capacity of
handling audio files.
The functions I need includes play, pause, get position information
(where it is paused), and seek according to a position. However, such
a pack
That's if the variables are visible. If they are only in the data frame it's
not much more difficult
d <- data.frame(group = rep(1:5, each=5),
variable = rnorm(25))
with(d, tapply(variable, group, max))
(Tip: avoid using attach().)
Bill Venables.
-Original Message-
Not sure why you think tapply is "awkward". Your example would be...
group <- rep(1:5, each=5)
variable <- rnorm(25)
tapply(variable, group, max)
...which looks quite elegant to me :)
Meanwhile, the reason your expression doesn't work is that you are
asking mistakenly for elements 1:5 repeatedly
Hi everyone:
I would like to know if there is a way of applying this kind of
transformation in R (i mean aligned ranks).
I read that this was a good
way of analyzing interactions in data with outliers and a not normal
distribution. The rank transformation is useful analyzing principal
effects, b
I'm writing an expression that requires searching a vector according to
group. As an example, I want to find the maximum value in each of 5
groups.
group=rep(1:5, each=5) # create grouping variable
variable=rnorm(25) # generate data
d <-
Hey, R Users
my windows is 64 bit windows 7. I am trying to install the package ucminf into
my 64 bit version R but cannot. the package I downloaded is from
http://cran.r-project.org/web/packages/ucminf/index.html and I installed it
with
the "install from local zip files", due to I did not co
Not sure exactly what capabilities you're looking for.
Just thought I'd put in a plug for a pretty decent, and free open
source, app for generating the sheet music pages themselves.
http://lilypond.org/
Carl
__
R-help@r-project.org mailing list
http
Thanks all. I have also been able to get things to work on an Ubuntu
system. I'll talk with the system guys for our server and see if I can get
them excited about finding and installing the proper Slavic fonts.
Cheers!
2010/9/20 Thomas Lumley
> On Mon, 20 Sep 2010, Jonathan Callahan wrote:
>
On Mon, 20 Sep 2010, Jonathan Callahan wrote:
Awesome! Can you tell me what version of R you are using and what operating
system? R does use system fonts, doesn't it? Perhaps I
just don't have the correct fonts installed -- I'm on CentOS.
Yes, R uses the system fonts. I'm using Mac OS and
Awesome! Can you tell me what version of R you are using and what operating
system? R does use system fonts, doesn't it? Perhaps I just don't have the
correct fonts installed -- I'm on CentOS.
Jon
2010/9/20 Thomas Lumley
> On Mon, 20 Sep 2010, Jonathan Callahan wrote:
>
> Can you -- or anyo
On Mon, 20 Sep 2010, Jonathan Callahan wrote:
Can you -- or anyone else -- point me to some plots in R that have
Czech, Slovak or Polish text on them? That would be the proof that it is
possible. Then I would still need to figure out why my version fails to
print this text properly.
I have c
VojtÄch,
Thanks for responding. I should be clear that the web pages and server all
support UTF-8 quite well.
I am asking about using slavic letters with the caron/hacek symbol in R *
plots*. Reading old messages I see that this has been a problem in past
years. Can you -- or anyone else -- p
You could do most of this with the function lmList in the nlme package, but
since you want both plots and summaries, you might as well do it in a more
flexible loop.
How about something like this:
Code:
## This makes a single factor to define your groups
BCI <- within(BCI,
Sp_ind
From: Oyomoare Osazuwa-Peters
Subject: Re: [R] Help!
To: "Erich Neuwirth"
Date: Monday, September 20, 2010, 5:16 PM
Thanks for responding to my request for help.
I understand what you mean about the repeated measurements methods for the two
cores. The thing though is to answer my research ques
If you assume that the variance is the same in all your subsets,
you can do an lm analysis with your subset classification as a factor.
You could also analyze the interaction between factors
and between factors and your numeric independent variable.
You also should consider repeated measurement met
Base graphics, ggplot2 or lattice? You need to be more specific. A
reproducible example to illustrate your problem would be helpful.
Dennis
On Mon, Sep 20, 2010 at 1:07 PM, Mestat wrote:
>
> Hello,
> Which would be the command to change the size of the legend.
> I checked at the help and I foun
Please I need some help using R to
analyze my data. What I
would like to do is to repeat the same basic process (e.g. linear regression
between wood density and distance from pith) for at least 240 data
subsets
within the main data-frame. Within the main data-frame, these data subsets will
be de
Anan -
If you actually want the indices, you can use
seq_along(sampWB)[-censidx]
If you want the values themselves, then use
sampWB[-censidx]
- Phil Spector
Statistical Computing Facility
sampleSize <- 20
shape.true <- 1.82
scale.true <- 987
sampWB <- rweibull(sampleSize, shape=shape.true, scale=scale.true)
print(sampWB)
censidx <- sample(1:length(sampWB), length(sampWB)*0.3)
Censored.data <- sampWB[censidx]
noncensidx <- defines the rest values of the vector which is not include
Thank you all
On Mon, Sep 20, 2010 at 12:53 PM, Zoppoli, Gabriele (NIH/NCI) [G]
wrote:
> see help(round)
>
> Gabriele Zoppoli, MD
> Ph.D. Fellow, Experimental and Clinical Oncology and Hematology, University
> of Genova, Genova, Italy
> Guest Researcher, LMP, NCI, NIH, Bethesda MD
>
> Work: 301-
Clearly inferior treatments are unethical.
Donald Berry at MD Anderson in Houston TX and Jay Kadane at Carnegie
Mellon have been working on more ethical designs within the Bayesian
framework. In particular, response adaptive designs reduce the assignment
to and continuation of patients on in
On 20/09/2010 3:07 PM, Tianchan Niu wrote:
Dear All,
I am trying to use ode solver "rk4" to solve an ODE system, however, it
keeps saying: Error in eval(expr, envir, enclos) : object "dIN" not found.
The sample codes are enclosed as follows, please help me. Thank you very
much!
rm(list=ls(
Hello,
Which would be the command to change the size of the legend.
I checked at the help and I found out something about TEXT.WIDTH, but I am
not sure if is what I want.
Any help!
Thanks in advance,
Marcio
--
View this message in context:
http://r.789695.n4.nabble.com/Size-of-the-legend-tp25476
Thank you Peter and Ben for your comments.
John
- Original Message
From: Peter Dalgaard
To: array chip
Cc: r-help@r-project.org; r-sig-mixed-mod...@r-project.org
Sent: Mon, September 20, 2010 12:28:43 PM
Subject: Re: [R] lmer() vs. lme() gave different variance component estimates
On
On 09/20/2010 08:01 PM, David Winsemius wrote:
> indexfoo
> 1.6 1 -3.0267759
> 1.7 1 -1.3725536
> 1.19 1 -1.1476048
> 1.16 1 -1.0963967
> 1.2 1 -1.0684793
> 2.29 2 -1.6601486
> 2.21 2 -1.2633632
> 2.22 2 -0.9875626
> 2.38 2 -0.9515301
> 2.30
On 09/20/2010 08:09 PM, array chip wrote:
> Thank you Peter for your explanation of relationship between aov and lme. It
> makes perfect sense.
>
>
> When you said "you might have computed the average of all 8
> measurements on each animal and computed a 1-way ANOVA" for treatment effect,
> wo
I was just reading about the merge sort algorithm last night (BTW, here
is a fun link http://www.youtube.com/watch?v=t8g-iYGHpEA). There are
some interesting similarities in this context. Here's a recursive method
for bisection:
bisectMatt <- function(fn, lo, hi, tol = 1e-7, ...) {
flo <- fn(
On Sep 20, 2010, at 2:28 PM, Charles C. Berry wrote:
On Mon, 20 Sep 2010, Bert Gunter wrote:
Hi Folks:
**Off Topic**
Those interested in clinical trials may find the following of
interest:
http://www.nytimes.com/2010/09/19/health/research/19trial.html
It concerns the ethicality of rand
Dear All,
I am trying to use ode solver "rk4" to solve an ODE system, however, it
keeps saying: Error in eval(expr, envir, enclos) : object "dIN" not found.
The sample codes are enclosed as follows, please help me. Thank you very
much!
rm(list=ls())
library(odesolve)
# The ODE syste
Hi Soyeon,
Here are a few options:
## Use get() to find the predictor
r <- rep(0, 13)
for(i in 1: 13) {
r[i] <- summary(lm(MEDV ~ get(name[i]), data = boston))$r.squared
}
## Use as.formula(paste()) to construction the model
for(i in 1: 13) {
r[i] <- summary(lm(as.formula(paste("MEDV ~ ", name[
Try this:
lapply(names(boston), function(x)summary(update(lm(MEDV ~ 1, boston), ~
get(x
On Mon, Sep 20, 2010 at 2:03 PM, Soyeon Kim wrote:
> Dear All,
>
> I have data which contains 14 variables. And I have to regress one of
> variables on each variable (simple 13 linear regressions)
>
> I
On Mon, Sep 20, 2010 at 11:15 AM, David Winsemius
wrote:
>
> On Sep 20, 2010, at 2:01 PM, David Winsemius wrote:
>
>>
>> On Sep 20, 2010, at 1:40 PM, Joshua Wiley wrote:
>>
>>> On Mon, Sep 20, 2010 at 10:27 AM, Phil Spector
>>> wrote:
Harold -
Two ways that come to mind:
On Mon, 20 Sep 2010, Bert Gunter wrote:
Hi Folks:
**Off Topic**
Those interested in clinical trials may find the following of interest:
http://www.nytimes.com/2010/09/19/health/research/19trial.html
It concerns the ethicality of randomizing those with life-threatening
disease to relatively i
Dear All,
I am trying to use ode solver "rk4" to solve an ODE system, however, it
keeps saying: Error in eval(expr, envir, enclos) : object "dIN" not found.
The sample codes are enclosed as follows, please help me. Thank you very
much!
rm(list=ls())
library(odesolve)
# The ODE syste
Dear All,
I have data which contains 14 variables. And I have to regress one of
variables on each variable (simple 13 linear regressions)
I try to make a loop and store only R-squared
colnames(boston)
[1] "CRIM""ZN" "INDUS" "CHAS""NOX" "RM" "AGE"
[8] "DIS" "RAD"
Richard Tan asked a very similar question last week
('get top n rows group by a column from a dataframe').
You could use ave() to make a sequence-number-within-group
vector and choose rows with a small enough value there:
tmp[ave(integer(nrow(tmp)), tmp$index, FUN=seq_along)<=N, ]
If there are f
On Sep 20, 2010, at 2:01 PM, David Winsemius wrote:
On Sep 20, 2010, at 1:40 PM, Joshua Wiley wrote:
On Mon, Sep 20, 2010 at 10:27 AM, Phil Spector
wrote:
Harold -
Two ways that come to mind:
1) do.call(rbind,lapply(split(tmp,tmp$index),function(x)x[1:5,]))
2) subset(tmp,unlist(tapply(fo
Thank you Peter for your explanation of relationship between aov and lme. It
makes perfect sense.
When you said "you might have computed the average of all 8
measurements on each animal and computed a 1-way ANOVA" for treatment effect,
would this be the case for balanced design, or it is also
On Sep 20, 2010, at 1:40 PM, Joshua Wiley wrote:
On Mon, Sep 20, 2010 at 10:27 AM, Phil Spector
wrote:
Harold -
Two ways that come to mind:
1) do.call(rbind,lapply(split(tmp,tmp$index),function(x)x[1:5,]))
2) subset(tmp,unlist(tapply(foo,index,seq))<=5)
3) do.call(rbind, by(tmp, tmp$index
On 9/17/2010 4:39 PM, Phil Spector wrote:
Soyeon -
I think scan() (combined with matrix and data.frame) is the easiest way.
Suppose your text file is called "data.txt". Then
data.frame(matrix(scan('data.txt'),byrow=TRUE,ncol=14))
should give you what you want.
- Phil Spector
Statistical Computi
On 09/20/2010 07:16 PM, Doran, Harold wrote:
> tmp1 <- tmp1[1:5,]
> tmp2 <- tmp2[1:5,]
> result <- rbind(tmp1, tmp2)
>
> Does anyone see a way to subset and subsequently bind without a loop?
>
> do.call(rbind,lapply(split(tmp,tmp$index),head,5))
indexfoo
1.11 1 -1.5124909
1.10
Dear All,
Does anyone know if there is any R implementation of the Lempel-Ziv
entropy estimator?
I searched for it in the entropy contributed package, but unsuccessfully.
Cheers
Lorenzo
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailma
On Mon, Sep 20, 2010 at 10:27 AM, Phil Spector
wrote:
> Harold -
> Two ways that come to mind:
>
> 1) do.call(rbind,lapply(split(tmp,tmp$index),function(x)x[1:5,]))
> 2) subset(tmp,unlist(tapply(foo,index,seq))<=5)
3) do.call(rbind, by(tmp, tmp$index, .Primitive("["), 1:5, 1:2))
Josh
>
>
Hi Harold,
I thought of one way to do this, but maybe (probably) there is a faster way:
tmp <- data.frame(index = gl(3,20), foo = rnorm(60))
subset.first.x.elements <- function(INDEX, num.of.elements = 5)
{
t.INDEX <- table(factor(INDEX, levels = unique(INDEX)))
running.indexes <- unlist(sappl
Hi Folks:
**Off Topic**
Those interested in clinical trials may find the following of interest:
http://www.nytimes.com/2010/09/19/health/research/19trial.html
It concerns the ethicality of randomizing those with life-threatening
disease to relatively ineffective SOC when new "biologically targe
Very nice, Phil. Thank you.
-Original Message-
From: Phil Spector [mailto:spec...@stat.berkeley.edu]
Sent: Monday, September 20, 2010 1:28 PM
To: Doran, Harold
Cc: R-help
Subject: Re: [R] Sorting and subsetting
Harold -
Two ways that come to mind:
1) do.call(rbind,lapply(split(tmp,t
Harold -
Two ways that come to mind:
1) do.call(rbind,lapply(split(tmp,tmp$index),function(x)x[1:5,]))
2) subset(tmp,unlist(tapply(foo,index,seq))<=5)
- Phil Spector
Statistical Computing Facility
Suppose I have a data frame, such as the one below:
tmp <- data.frame(index = gl(2,20), foo = rnorm(40))
And further assume it is sorted by index and then by the variable foo.
tmp <- tmp[order(tmp$index, tmp$foo) , ]
Now, I want to grab the first N rows of tmp for each index. In the end, what I
I am glad, Greg, you did this. Peter is one of the backbones behind R, and
has made enormous contributions to it. He deserves to be treated with
respect.
More to the point, Peter's comments are perfectly reasonable. People are
motivated by different factors to go to extra lengths to help s
Look at the clip function for one approach. You specify the clipping region,
then do abline and it only shows up in the region specified.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> From: r-he
Fair enough. I didn't intend to offend anyone. Please accept my apologies.
Greg
--- On Mon, 9/20/10, peter dalgaard wrote:
From: peter dalgaard
Subject: Re: [R] Is there a bisection method in R?
To: "Gregory Gentlemen"
Cc: "Ravi Varadhan" , r-help@r-project.org
Received: Monday, September 20,
On Sep 20, 2010, at 18:15 , Gregory Gentlemen wrote:
> Now that is a more useful reply than "Why do you assume there is one?".
> Thanks a lot Ravi!
>
Well, maybe, but you can NOT expect that someone will go out of THEIR way to
solve YOUR problem every time. Sometimes they will and sometimes t
On Sep 20, 2010, at 12:25 PM, Joshua Wiley wrote:
Hi Raphael,
mat <- matrix(rnorm(100), ncol = 2)
round(mat, 2)
for documentation see ?round
Thanks, Josh. I was having trouble a couple of minutes ago remembering
this. Getting old, I guess. In constructing my thanks to Josh I tested:
pr
Call for Papers:
R/Finance 2011: Applied Finance with R
April 29 and 30, 2011
Chicago, IL, USA
The third annual R/Finance conference for applied finance using R will
be held this spring in Chicago, IL, USA on April 29 and 30, 2011. The
two-day conference will cover topics including portfolio ma
Hi Raphael,
mat <- matrix(rnorm(100), ncol = 2)
round(mat, 2)
for documentation see ?round
Cheers,
Josh
On Mon, Sep 20, 2010 at 9:21 AM, Raphael Fraser
wrote:
> I have a 2x50 matrix and would like to round all the elements to 2
> decimal places. Can any one help?
>
> Thanks,
> Raphael
>
> ___
Look at the functions dummy.coef, model.tables, and se.contrasts, they may help
with what you want. You can also look at the multcomp package for another
approach.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Origina
I have a 2x50 matrix and would like to round all the elements to 2
decimal places. Can any one help?
Thanks,
Raphael
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.
Now that is a more useful reply than "Why do you assume there is one?". Thanks
a lot Ravi!
--- On Fri, 9/17/10, Ravi Varadhan wrote:
From: Ravi Varadhan
Subject: RE: [R] Is there a bisection method in R?
To: "'Peter Dalgaard'" , "'Gregory Gentlemen'"
Cc: r-help@r-project.org
Received: Frid
On Mon, 20 Sep 2010, Jabez Wilson wrote:
Hi, I am trying to reconcile anova table in R (summary(lm)) with individual
t.test.
datafilename="http://personality-project.org/R/datasets/R.appendix1.data";
data.ex1=read.table(datafilename,header=T) #read the data into a table
summary(lm(Alertness~D
On Sep 20, 2010, at 11:53 AM, Jabez Wilson wrote:
Hi, I am trying to reconcile anova table in R (summary(lm)) with
individual t.test.
datafilename="http://personality-project.org/R/datasets/R.appendix1.data
"
data.ex1=read.table(datafilename,header=T) #read the data into a
table
summary(
Hello
Dne Po 20. září 2010 10:28:54 Jonathan Callahan napsal(a):
> I am creating a Slovak translation of an interactive website (
> http://mazamascience.com/OilExport/index_sk.html ) and am running into
> problems with R's lack of support for the caron found in the following
> letters: Ä/Ä, Å /
Hi, I am trying to reconcile anova table in R (summary(lm)) with individual
t.test.
datafilename="http://personality-project.org/R/datasets/R.appendix1.data";
data.ex1=read.table(datafilename,header=T) #read the data into a table
summary(lm(Alertness~Dosage,data=data.ex1))
gives:
Call:
lm(form
I am creating a Slovak translation of an interactive website (
http://mazamascience.com/OilExport/index_sk.html ) and am running into
problems with R's lack of support for the caron found in the following
letters: Ä/Ä, Å /Å¡ and Ž/ž.
I am using R 2.6.1 running on a recent version of CentOS.
Thanks Peter. I think you're right.
Frank
-
Frank Harrell
Department of Biostatistics, Vanderbilt University
--
View this message in context:
http://r.789695.n4.nabble.com/predict-lrm-Design-package-tp2546894p2547146.html
Sent from the R help mailing list archive at Nabble.com.
__
On Mon, 20 Sep 2010, Duncan Murdoch wrote:
On 20/09/2010 9:54 AM, A wrote:
Dear all,
I'm performing a t-test on two normal distributions with identical mean&
standard deviation, and repeating this tests a very large number of times
to
describe an representative p value distribution in a null
Mango Solutions announce a public training course in ADVANCED R on the 6th and
7th October 2010 in London.
This 2 day course is suitable for people with a working knowledge of R who
want to extend their knowledge to take advantage of the fuller capabilities of
R. Ideally, attendees should have
A few comments; sorry I don't have time for any more.
- Combining categories is almost always a bad idea
- It can be harder to discriminate more categories but that's only because the
task is more difficult
- Split-sample validation is not reliable unless you have say 10,000 samples to
begin wit
On 20-Sep-10 13:54:56, A wrote:
> Dear all,
> I'm performing a t-test on two normal distributions with identical
> mean & standard deviation, and repeating this tests a very large
> number of times to describe an representative p value distribution
> in a null case. As a part of this, the program b
A gmail.com> writes:
>
> Dear all,
[snip]
> Here are two key parts of my code to show what functions I'm working with:
>
> #Calculating the p values
> while(i Group1<-rnorm(6,-0.0065,0.0837)
> Group2<-rnorm(6,-0.0065,0.0837)
> PV<-t.test(Group1,Group2)$p.value
> pscoresvector<-c(PV,pscoresve
C.H. gmail.com> writes:
> http://r-forge.r-project.org/projects/tuner/
>
> On Mon, Sep 20, 2010 at 8:35 AM, Deb Midya yahoo.com> wrote:
[snip]
> > 1. Is there any R-package or if any to compose music?
> > 2. Is there any R-package or if any to analyse music?
Also
RSiteSearch("mu
On Sep 20, 2010, at 15:50 , Frank Harrell wrote:
>
> You sent a private note about this which I just took the time to answer.
> Please send only one note, and please post my reply to you to r-help.
I have been annoyed by this at times as well. However, I have come to suspect
that it is actual
On 20/09/2010 9:54 AM, A wrote:
Dear all,
I'm performing a t-test on two normal distributions with identical mean&
standard deviation, and repeating this tests a very large number of times to
describe an representative p value distribution in a null case. As a part of
this, the program bins the
A few comments; sorry I don't have time for any more.
- Combining categories is almost always a bad idea
- It can be harder to discriminate more categories but that's only because the
task is more difficult
- Split-sample validation is not reliable unless you have say 10,000 samples to
begin w
Dear all,
I'm performing a t-test on two normal distributions with identical mean &
standard deviation, and repeating this tests a very large number of times to
describe an representative p value distribution in a null case. As a part of
this, the program bins these values in 10 evenly distributed
Duncan Murdoch gmail.com> writes:
>
> On 20/09/2010 9:44 AM, elaine kuo wrote:
> > Dear List,
> >
> > I am using plot for homework.
>
> You should ask your instructor or teaching assistant for help on homework.
>
> Duncan Murdoch
>
> > The x-axis covered from 0 to 80, with 4 intervals.
> >
You sent a private note about this which I just took the time to answer.
Please send only one note, and please post my reply to you to r-help.
Frank
-
Frank Harrell
Department of Biostatistics, Vanderbilt University
--
View this message in context:
http://r.789695.n4.nabble.com/predict-lr
Have a look at ?axis
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek
team Biometrie & Kwaliteitszorg
Gaverstraat 4
9500 Geraardsbergen
Belgium
Research Institute for Nature and Forest
team Biometrics & Quali
On 20/09/2010 9:44 AM, elaine kuo wrote:
Dear List,
I am using plot for homework.
You should ask your instructor or teaching assistant for help on homework.
Duncan Murdoch
The x-axis covered from 0 to 80, with 4 intervals.
However, the plot only showed 0, 40, 80.
20 and 60 disappeared.
Pl
Hi,
The list is not made for helping students with their homeworks.
I will just tell you this: there are graphic parameters for every single
detail on a plot. Take a look at ?par
Ivan
Le 9/20/2010 15:44, elaine kuo a écrit :
> Dear List,
>
> I am using plot for homework.
>
> The x-axis covere
Dear List,
I am using plot for homework.
The x-axis covered from 0 to 80, with 4 intervals.
However, the plot only showed 0, 40, 80.
20 and 60 disappeared.
Please kindly advise how to show 0, 20, 40, 60, 80 for the axis interval.
Thank you.
Elaine
[[alternative HTML version deleted]]
Hi!
I'm trying to read individual files from a ZIP archive, using the unz()
function. Some of the files contain non-ASCII characters and I'd like to avoid
unpacking them in a temporary directory.
My problem is that unz() seems to ignore the encoding="latin1" option I need to
read the non-ASCI
1 - 100 of 128 matches
Mail list logo
