Hi Harold,
I thought of one way to do this, but maybe (probably) there is a faster way:
tmp <- data.frame(index = gl(3,20), foo = rnorm(60))
subset.first.x.elements <- function(INDEX, num.of.elements = 5)
{
t.INDEX <- table(factor(INDEX, levels = unique(INDEX)))
running.indexes <- unlist(sapply(t.INDEX, seq_len))
ss <- running.indexes %in% 1:num.of.elements
return(ss)
}
ss <- subset.first.x.elements(tmp[,1])
tmp[ss,]
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On Mon, Sep 20, 2010 at 7:16 PM, Doran, Harold <hdo...@air.org> wrote:
> Suppose I have a data frame, such as the one below:
>
> tmp <- data.frame(index = gl(2,20), foo = rnorm(40))
>
> And further assume it is sorted by index and then by the variable foo.
>
> tmp <- tmp[order(tmp$index, tmp$foo) , ]
>
> Now, I want to grab the first N rows of tmp for each index. In the end,
> what I want is the data frame 'result'
>
> tmp1 <- subset(tmp, index == 1)
> tmp2 <- subset(tmp, index == 2)
>
> tmp1 <- tmp1[1:5,]
> tmp2 <- tmp2[1:5,]
> result <- rbind(tmp1, tmp2)
>
> Does anyone see a way to subset and subsequently bind without a loop?
>
> Harold
>
>
>
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>
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