Hi
without other details it is probably impossible to give you any reasonable
advice. Do you have your data already in R? What is their form? Are they
in 2 columns in data frame? How did you get them paired?
So without some more information probably nobody will invest his time as
it seems no t
Thanks a lot for the nice explanation. however, you mention that it will be
nicer if there is data. yes you are right it be very kind of you if you
include a simple example. where my data are:
x1<-c(11.5,9.38,9.3,9.8,9,9.06,9.42,8.8,9.05,8.14,8.2,7.59,6.92,6.47,7.12,
7.47,6.81,8.41,9.64,9.62,9.2,
Hi,
I would like to emphasize ("zoom") the zone of a nomogram where the
probability are > 0.01
(nomogram built with nomogram, Design).
As a consequence, I don't need to draw the part of the "Total points"
axis with score < 60 equivalent in my case to a linear predictor < 4.5
- As far as I know, th
Rhelpers:
I'm trying to make a barchart of a 2-group dataset
(barchart(x~y,data=data,groups=z,horizontal=FALSE)). My problem is
that I can't, for the life of me, seem to get rid of the inter-bar
space -- box.ratio set to 1 doesn't do much. Any ideas? I'd
ideally want zero space between the
I'm in the process of converting some S3 methods to S4 methods.
I have this function :
setGeneric("enrichmentCalc", function(rs, organism, seqLen,
...){standardGeneric("enrichmentCalc")})
setMethod("enrichmentCalc", c("GenomeDataList", "BSgenome"), function(rs,
organism, seqLen, ...) {
Thanks Josh and Karl. function dnrm() works well for my purpose.
--
View this message in context:
http://r.789695.n4.nabble.com/How-to-remove-all-objects-except-a-few-specified-objects-tp2335651p2337398.html
Sent from the R help mailing list archive at Nabble.com.
_
Hello,
I want to know how do R calculates the number of intervals between
tick-marks in the y axis in a plot.
I'm making a three y-axes plot and this information would help me a lot.
Thanks in advance.
Antonio Olinto
Webmai
Many thanks to you both. I have now filed away for future reference the 2
factor tapply as well as the extremely useful looking plyr library. And the
code worked beautifully :-)
On 24 Aug 2010, at 19:47, "Abhijit Dasgupta, PhD"
wrote:
> The paste-y argument is my usual trick in these situat
Thanks for the advice, problem solved.
-daisy
On Wed, Aug 25, 2010 at 1:35 PM, David Winsemius wrote:
>
> On Aug 24, 2010, at 10:45 PM, Daisy Englert Duursma wrote:
>
>> Hello help,
>>
>> I have changed around some graphing code and made it into a function.
>> Previously they y label of the axi
On Aug 24, 2010, at 11:37 PM, Tim Elwell-Sutton wrote:
Hi Jim
Thanks for this. The staxlab function seems very useful.
Unfortunately, the
rotation option doesn't seem to work for me when the y-axis is on a
log
scale.
What part of:
"If srt is not NA, the labels will be rotated srt degree
Hi Jim
Thanks for this. The staxlab function seems very useful. Unfortunately, the
rotation option doesn't seem to work for me when the y-axis is on a log
scale. It will stagger the labels but not rotate them. There's no error
message. On a linear axis the rotation works nicely. Any ideas?
The exam
On Aug 24, 2010, at 10:45 PM, Daisy Englert Duursma wrote:
Hello help,
I have changed around some graphing code and made it into a function.
Previously they y label of the axis was inserted as text in its own
layout box.
text(1,1, expression(~degree~C),cex=1)
This worked great and resulted i
xmlDoc() is not the function to use to parse a file.
Use
doc = xmlParse("Malaria_Grave.xml")
xmlDoc() is for programmatically creating a new XML within R.
It could be more robust to being called with a string, but
the key thing here is that it is not the appropriate function for what
you wa
On Tue, Aug 24, 2010 at 10:45 PM, Daisy Englert Duursma
wrote:
> Hello help,
>
> I have changed around some graphing code and made it into a function.
> Previously they y label of the axis was inserted as text in its own
> layout box.
>
> text(1,1, expression(~degree~C),cex=1)
>
> This worked grea
Hi Daisy,
Try it without paste():
> plot(1, col = 'white')
> text(1,1, b_unit,cex=1)
HTH,
Jorge
On Tue, Aug 24, 2010 at 10:45 PM, Daisy Englert Duursma <> wrote:
> Hello help,
>
> I have changed around some graphing code and made it into a function.
> Previously they y label of the axis was i
Hello help,
I have changed around some graphing code and made it into a function.
Previously they y label of the axis was inserted as text in its own
layout box.
text(1,1, expression(~degree~C),cex=1)
This worked great and resulted in the symbol for degree.
In the function, I have changed it so
--
Daisy Englert Duursma
Room E8C156
Dept. Biological Sciences
Macquarie University NSW 2109
Australia
Tel +61 2 9850 9256
10A Carrington Rd
Hornsby, NSW 2077
Mobile: 0421858456
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/l
Tena korua
ls()[!(ls() %in% c('keepThis','andThis'))]
will give the elements excluding 'keepThis' and 'andThis'. Thus
rm(list= ls()[!(ls() %in% c('keepThis','andThis'))])
will remove everything except these two objects, and hidden objects. It you
want to remove the hidden objects as be use ls
How about this approach, using aggregate():
> DF
StandID PlotNum HerbNum Woody
1 001 1 1low
2 001 2 2 medium
3 001 3 1low
4 001 4 3low
5 001 5 1 high
6 001 6 2 medium
7 002
Tena koe Randy
If your dataframe is called randy, then the following seems to work:
aggregate(randy[,-(1:2)], list(randy[,1]), function(x) {tt <- table(x);
names(tt)[which.max(tt)]})
HTH
Peter Alspach
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun.
Do you expect this to be easy? It may be, but I can't see a particularly
graceful way to do it. Here is one possible solution.
> dat
StandID PlotNum HerbNum Woody
1 001 1 1low
2 001 2 2 medium
3 001 3 1low
4 001 4 3
Thanks
a lot, Charles and Yihui,
Your
ideas are great! Both worked, although Yihui's solutions are a lot more
comprehensive.
BTW
as a comment on Charles idea, parse function works for loosen statement lines,
for not for the code blocks of a function. For example, the following code for
vennC
R users,
I am trying to find some way to find the value of a column that is repeated
the most for each StandID of a dataframe. I have research methods online
and the help page, but have had no success in finding a solution. I have
tried using the table function but it returns items for the whole
If your specified objects have a certain pattern, you can use the
parameter "pattern" in ls() to remove or keep it.
rm(list=ls(..., pattern="your_pattern"))
If not, possibly you have to manually specify them.
On 2010-8-24 3:00, Cheng Peng wrote:
How to remove all R objects in the RAM except for
On Tue, Aug 24, 2010 at 11:25 AM, Martin Morgan wrote:
> On 08/24/2010 07:27 AM, Doran, Harold wrote:
>> There is the stringMatch function in the MiscPsycho package.
>>
>>> stringMatch('Hadley', 'Hadley Wickham', normalize = 'no')
>> [1] 8
>>> stringMatch('Hadley', 'Hadley Wickham', normalize = 'y
On Aug 24, 2010, at 7:12 PM, elaine kuo wrote:
Dear List,
I have a richness data distributing across 20 N to 20 S latitude.
(120 E-140
E longitude).
I would like to draw the richness in the north hemisphere and a
regression
line in the plot
(x-axis: latitude, y-axis: richness in the no
Actually I've implemented Charles' idea in the function tidy.source()
in package 'animation' years ago. An example can be found here:
http://animation.yihui.name/animation:misc#tidy_up_r_source
BTW, you might be interested in the 'formatR' package if you are
somehow addicted to GUI:
http://yihui.n
Dear List,
I have a richness data distributing across 20 N to 20 S latitude. (120 E-140
E longitude).
I would like to draw the richness in the north hemisphere and a regression
line in the plot
(x-axis: latitude, y-axis: richness in the north hemisphere).
The above demand is done using plot.
Th
David,
I am not sure I completely understand your problem. However, you can take a
look at a couple of packages in R that can handle (smooth) nonlinear
optimization with general (smooth) constraints:
library(alabama)
?constrOptim.nl
and
library(Rsolnp)
?solnp
Best,
Ravi.
__
My system is an Ubuntu 9.10 32bit:
#uname -a
Linux cavemanpc 2.6.31-22-generic #63-Ubuntu SMP Wed Aug 18 22:54:26 UTC
2010 i686 GNU/Linux
# free -m
total used free sharedbuffers cached
Mem: 3000 1847 1152 0120961
-/
It seems to be a bug on the XML package.
This is what I run (and it is not the only file):
> library("XML")
> doc <- xmlDoc("Malaria_Grave.xml")
*** caught segfault ***
address 0x9, cause 'memory not mapped'
Traceback:
1: .Call("RS_XML_createDocFromNode", node, PACKAGE = "XML")
2: xmlDoc("Mal
Liviu, thanks again for the suggestion. Do you have a customized style file
that you wouldn't mind sharing?
I like the default output but I'm curious about others.
Thanks!
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-hel
Marianne -
The function you're looking for is mapply:
mapply(function(one,two)one[two],x,y)
[[1]]
[1] "one"
[[2]]
[1] "four" "five"
- Phil Spector
Statistical Computing Facility
On Tue, 2010-08-24 at 23:35 +0200, Orvalho Augusto wrote:
> I have one XML file with 30MB that I need to read the data.
>
> I try this;
> library(XML)
> doc <- xmlDoc("Malaria_Grave.xml")
>
> And R answers like this
> *** caught segfault ***
> address 0x5, cause 'memory not mapped'
This is most
That is great Liviu, thanks for letting me know. My LaTeX documents have been
looking like this, however I have been doing all the cosmetics through LaTeX.
Thanks for letting me know about this!
On Aug 24, 2010, at 2:34 PM, Liviu Andronic wrote:
On Tue, Aug 24, 2010 at 10:40 PM, r.ookie wrote:
On Aug 24, 2010, at 5:15 PM, Michel Lutz wrote:
> Thank you David for your answer.
>
> To be honest, I didn't read those posting guide, because I don't
> know where to find it - I just get this email from N. Gunther.
> So here the txt file, and sorry for having sent a wrong format.
>
> I checke
I have two lists of the same shape, like this:
x <- list()
x[[1]] <- c("one","two")
x[[2]] <- c("three","four","five")
y <- list()
y[[1]] <- c(TRUE,FALSE)
y[[2]] <- c(FALSE,TRUE,TRUE)
I would like to index x "by" y, that is, the result in this case
should be:
z
[[1]]
[1] "one"
[[2]]
[1] "four
I have one XML file with 30MB that I need to read the data.
I try this;
library(XML)
doc <- xmlDoc("Malaria_Grave.xml")
And R answers like this
*** caught segfault ***
address 0x5, cause 'memory not mapped'
Traceback:
1: .Call("RS_XML_createDocFromNode", node, PACKAGE = "XML")
2: xmlDoc("Mala
On Tue, Aug 24, 2010 at 10:40 PM, r.ookie wrote:
> Does anyone know where I can download the latest version of Sweave.sty? I
> have looked all over the site http://www.stat.umn.edu/~charlie/Sweave/ with
> no luck.
>
Not exactly an answer, Frank Harrell once published a fork of Sweave,
Sweavel [1
Hi:
This is pretty straightforward to do in ggplot2, but it would be nice to
have some data to work with (hint). The job requires processing the two
input series and dates with melt() from the reshape package, a couple of
opts() to change, proper rotation of the dates, etc. It's easier to show how
This is easier if you simply link to the ACML BLAS as an alternative
to Rblas.so -- see the R-admin manual.
If you need further help, please ask on the R-devel list (see the
posting guide). It seems likely that you missed the comment in the
R-admin manual about ensuring that the ACML lib dire
On Tue, 24 Aug 2010, heyi xiao wrote:
Dear
all,
I have
written some R source program with many thousands of lines. I didn???t insert
line breaks automatically or manually for the long lines. But now I would like
to edit the source code in Emacs/ESS to make it more formal as a package. One o
R-sig-mac is the right list for Mac-specific questions. But
Command-line R on Snow Leopard is 64-bit
R.app is 32-bit.
So either use R32 CMD INSTALL or use R64.app.
(And as 'R' is 32-bit on Leopard, it is rather easy to get confused.)
On Tue, 24 Aug 2010, Marie-Hélène Ouellette wrote:
Dear
On Tue, 24 Aug 2010, Daniel Malter wrote:
Hi, has there been a solution to this issue? I am encountering the same
Yes, please look in the R-sig-mac archives (the place to ask
Mac-specific questsions!). My notes say July 28,
https://stat.ethz.ch/pipermail/r-sig-mac/2010-July/007601.html
Hi Dennis, thanks! No, this looks good to me, with equal-sized panels. I didn't
realize there was such a similar post before - all my queries had retrieved
questions about dropping categories in panels... but this is great - thank
you.All the best!Stephen
Date: Tue, 24 Aug 2010 12:58:20 -0700
On Aug 24, 2010, at 2:56 PM, Michel Lutz wrote:
Hello,
As recommended by N. Gunther, I'm writing you because I have some
difficulties to create a script to track computer performance, as
done in
Holtman, 2005 (Visualization techniques for analysing patterns in
system
performance).
I woul
Hi:
A reasonable place to start would be the Optimization task view at CRAN:
http://cran.r-project.org/web/views/
HTH,
Dennis
On Tue, Aug 24, 2010 at 10:47 AM, David Beacham
wrote:
> I'm relatively new to R, but I'm attempting to do a non-linear maximum
> likelihood estimation (mle) in R, with
On Aug 24, 2010, at 3:16 PM, Daniel Yarlett wrote:
Hello,
I am using R to train a logistic regression model and save the
resulting
model to disk. I am then subsequently reloading these saved objects,
and
using predict.glm on them in order to make predictions about single-
row data
frames
On Mon, Aug 23, 2010 at 1:02 PM, Alison Macalady wrote:
> Hi,
>
> I have a 5-paneled figure that i made using the facet function in qplot
> (ggplot). I've managed to arrange the panels into two rows/three columns,
> but for the sake of easy visual comparisons between panels in my particular
> dat
I am trying to get R to use the ACML BLAS, specifically the 'mp' version for
multithreading.
I have installed acml-4-4-0-gfortran-64bit
I added /opt/acml4.4.0/gfortran64_mp/lib to $LD_LIBRARY_PATH.
I ran: sudo ./configure --with-blas="-L/opt/acml4.4.0/gfortran64_mp/lib
-lacml_mp"
At the end
Dear R users,
I'm building linear models that use poly and has a lot of product terms. My
model summaries look messy. I know that the summary could use aliases for
the variable names, but I don't know how to get it to do that. Please help
Thanks,
--
View this message in context:
http://r.789695.
Hello,
As recommended by N. Gunther, I'm writing you because I have some
difficulties to create a script to track computer performance, as done in
Holtman, 2005 (Visualization techniques for analysing patterns in system
performance).
I would like to do a leveplot, with the kind of file here enclo
Hello,
I am using R to train a logistic regression model and save the resulting
model to disk. I am then subsequently reloading these saved objects, and
using predict.glm on them in order to make predictions about single-row data
frames that are generated in real-time from requests arriving at an
Dear
all,
I have
written some R source program with many thousands of lines. I didnât insert
line breaks automatically or manually for the long lines. But now I would like
to edit the source code in Emacs/ESS to make it more formal as a package. One of
the major problems here is how to break
On Tue, 2010-08-24 at 12:40 -0700, r.ookie wrote:
> Does anyone know where I can download the latest version of
> Sweave.sty? I have looked all over the site
> http://www.stat.umn.edu/~charlie/Sweave/ with no luck.
It is provided in the R sources as Sweave is an integrated part of R.
You can get i
Hi:
This looks to be a step in the right direction, but the resulting
panels are all the same size. Perhaps you can build on it...
# Solution based on an R-help post by Deepayan Sarkar:
# http://tolstoy.newcastle.edu.au/R/e2/help/06/09/1579.html
dotplot(A ~ B | C, data=dfr, scales=list(y=list(re
On 08/24/2010 09:40 PM, r.ookie wrote:
> Does anyone know where I can download the latest version of
> Sweave.sty? I have looked all over the site
> http://www.stat.umn.edu/~charlie/Sweave/ with no luck.
I don't think there is anything newer than what is inside the latest
version of R. Look under
Here is one:
http://svn.r-project.org/R/trunk/share/texmf/tex/latex/Sweave.sty
-Matt
On Tue, 2010-08-24 at 15:40 -0400, r.ookie wrote:
> Does anyone know where I can download the latest version of Sweave.sty? I
> have looked all over the site http://www.stat.umn.edu/~charlie/Sweave/ with
> no
Does anyone know where I can download the latest version of Sweave.sty? I have
looked all over the site http://www.stat.umn.edu/~charlie/Sweave/ with no luck.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do rea
On 08/24/2010 09:01 PM, Marie-Hélène Ouellette wrote:
> Dear all,
>
> I'm trying to compile FORTRAN code to be used in R, failing miserably. I got
> a simple code function to try to figure out what is going wrong. Here is the
> code (available on the web) :
>
>
>
> subroutine bar(n, x)
>
> -Original Message-
> From: r.ookie [mailto:r.oo...@live.com]
> Sent: Tuesday, August 24, 2010 12:25 PM
> To: William Dunlap
> Cc: r-help@r-project.org
> Subject: Re: [R] How to obtain seed after generating random number?
>
> Thanks for your solution, however, which values would I then
Hello,
I am using R to train a logistic regression model and save the resulting
model to disk. I am then subsequently reloading these saved objects, and
using predict.glm on them in order to make predictions about single-row data
frames that are generated in real-time from requests arriving at an
You can certainly use apply()
#make up some data
x <- 10; y <- 10; g <- 5
set.seed(1969)
dat <- matrix(rnorm((x + y) * g), ncol = x + y)
# apply() the t.test function to each row fo the matrix and extract
just the p value
results <- apply(dat, 1, function(dat) {
t.test(x = dat[1:x], y = d
Thanks for your solution, however, which values would I then provide someone
else so that they can produce the same results?
On Aug 24, 2010, at 12:06 PM, William Dunlap wrote:
The following will attach (as an attribute) the current global value
of .Random.seed to the value of the evaluated 'exp
On Aug 24, 2010, at 3:13 PM, Daniel Malter wrote:
Hi, has there been a solution to this issue? I am encountering the
same
problem on a Mac with OSX 10.6.4. The problem persists when I try to
install
lme4 from the source (see below), and my R version is up to date
according
to R's update
On Aug 24, 2010, at 1:40 PM, abotaha wrote:
Hello guys,
I would to plot a bar line between to curves like in excel as shown
in the
following image. but i do not know how I can do that in R.
http://r.789695.n4.nabble.com/file/n2337089/excel_Plot.png
any help would appreciate.
?segments
Hi, has there been a solution to this issue? I am encountering the same
problem on a Mac with OSX 10.6.4. The problem persists when I try to install
lme4 from the source (see below), and my R version is up to date according
to R's update check.
Thanks for any help,
Daniel
--
session
Hi,
the actual thread on "multiple assignments ?" made up an interesting point for
me.
If I have a matrix with g rows and x + y columns where columns 1 - x contain
values of group1 and columns x+1 to y contain the values of group2.
Now I want to compute a vector of length g that holds the p-valu
The following will attach (as an attribute) the current global value
of .Random.seed to the value of the evaluated 'expr' argument. If you
supply
the initial.Random.seed argument then it will use that when evaluating
the expression (and also attach it to the result) so you can repeat the
'unusual'
Dear all,
I'm trying to compile FORTRAN code to be used in R, failing miserably. I got
a simple code function to try to figure out what is going wrong. Here is the
code (available on the web) :
subroutine bar(n, x)
integer n
double precision x(n)
integer i
do
> On Aug 24, 2010, at 10:11 AM, Bogaso Christofer wrote:
>
> Dear all, I was doing an experiment to disprove some theory therefore
> performing lot of random simulation. Goal is to show the audience that
> although something has very rare chance to occur but it doesn't mean that
> event would be
Hello guys,
I would to plot a bar line between to curves like in excel as shown in the
following image. but i do not know how I can do that in R.
http://r.789695.n4.nabble.com/file/n2337089/excel_Plot.png
any help would appreciate.
--
View this message in context:
http://r.789695.n4.nabble
Dear R Helpers,
I am a newbie and recently got introduced to R. I have a large database
containing the names of bank branch offices along-with other details. I am into
Operational Risk as envisaged by BASEL II Accord.
I am trying to express my problem and I am using only an indicative da
I have wondered this in the past too so thanks for the question.
On Aug 24, 2010, at 10:11 AM, Bogaso Christofer wrote:
Dear all, I was doing an experiment to disprove some theory therefore
performing lot of random simulation. Goal is to show the audience that
although something has very rare cha
The paste-y argument is my usual trick in these situations. I forget
that tapply can take multiple ordering arguments :)
Abhijit
On 08/24/2010 02:17 PM, David Winsemius wrote:
On Aug 24, 2010, at 1:59 PM, Abhijit Dasgupta, PhD wrote:
The only problem with this is that Chris's unique individu
Dear expeRts,
I would like to have four plots appearing in one figure. The minimal example
shows this. However, the four figures are not properly aligned. Why? If I
comment out the scales=... arguments, then it works, but I would like to use
this... :-)
Cheers,
Marius
library(lattice)
set.
On Aug 24, 2010, at 1:59 PM, Abhijit Dasgupta, PhD wrote:
The only problem with this is that Chris's unique individuals are a
combination of Type and ID, as I understand it. So Type=A, ID=1 is a
different individual from Type=B,ID=1. So we need to create a unique
identifier per person, sim
The only problem with this is that Chris's unique individuals are a
combination of Type and ID, as I understand it. So Type=A, ID=1 is a
different individual from Type=B,ID=1. So we need to create a unique
identifier per person, simplistically by uniqueID=paste(Type, ID,
sep=''). Then, using th
An answer to 1)
> x = data.frame(Type=c('A','A','B','B'), ID=c(1,1,3,1), Date =
c('16/09/2010','23/09/2010','18/8/2010','13/5/2010'), Value=c(8,9,7,6))
> x
Type ID Date Value
1A 1 16/09/2010 8
2A 1 23/09/2010 9
3B 3 18/8/2010 7
4B 1 13/5/2010 6
> x$
On Aug 24, 2010, at 1:19 PM, Chris Beeley wrote:
Hello-
A basic question which has nonetheless floored me entirely. I have a
dataset which looks like this:
Type ID DateValue
A 116/09/2020 8
A 1 23/09/2010 9
B 3 18/8/20107
B
On 2010-08-24 11:06, Mike Williamson wrote:
Hello All,
Using the standard "summary" function in 'R', I ran across some odd
behavior that I cannot understand. Easy to reproduce:
Typing:
summary(c(6,207936))
Yields::
Min. *1st Qu. MedianMean 3rd Qu.Max.*
6 *5199
I'm relatively new to R, but I'm attempting to do a non-linear maximum
likelihood estimation (mle) in R, with the added problem that I have a
non-linear constraint.
The basic problem is linear in the parameters (a_i) and has only one
non-linear component, b, with the problem being linear when
summary.default uses the signif function to round for display purposes.
In ?summary, we can see the digits argument is used to control
the value passed to signif.
> lapply(1:6, function(x) summary(c(6, 207936), digits = x))
[[1]]
Min. 1st Qu. MedianMean 3rd Qu.Max.
6e+00 5e+04
Hello J.R.M. Hosking,
charToRaw() works perfectly, thank you:
> charToRaw(as.character(moose[1, "V3"]))
[1] 24 38 38 30 2c 33 37 30 c2 a0
gsub("[[:space:]]", "", ...) did not remove them, but now I know what they
are (hex: c2 a0) I can remove them with gsub() by:
> gsub("[$,\xc2\xa0]", "", as.
I'm currently running into a little trouble with the kfilter method,
and would love some clarification if you are able to offer it. When
trying to run kfilter, I've been running into errors that seem to
result from having mismatched dimensions. Specifically, the dimension
of my observations is 2,
Hello-
A basic question which has nonetheless floored me entirely. I have a
dataset which looks like this:
Type ID DateValue
A 116/09/2020 8
A 1 23/09/2010 9
B 3 18/8/20107
B 1 13/5/20106
There are two Types, whi
On Tue, Aug 24, 2010 at 8:45 AM, Maas James Dr (MED) wrote:
> Thanks Bert, will have a look. I'm originally a Fortran programmer so tend
> to think in loops ... so yes expect it may be job for loops, just tried to
> avoid it
because several references say not to use loops in R.
-- Yes, an un
On Aug 24, 2010, at 1:06 PM, Mike Williamson wrote:
Hello All,
Using the standard "summary" function in 'R', I ran across some odd
behavior that I cannot understand. Easy to reproduce:
Typing:
summary(c(6,207936))
Yields::
Min. *1st Qu. MedianMean 3rd Qu.Max.*
6 *51
BTW, can you recommend a book on statistical simulations? I want to know
more on how to generate random numbers from distributions, how to generate
the theoretical models,...
Thanks a lot.
2010/8/24 Michael Dewey
> At 02:40 24/08/2010, rusers.sh wrote:
>
>> Hi all,
>> rmvnorm()can be used to ge
On Aug 24, 2010, at 12:39 PM, Jennifer Hains wrote:
Dear r-help,
I'm having trouble formatting xy labels for plot in r. I want to
make the following y-label
"benzene (mug-3)"
where mu is greek and -3 is superscript and benzene is held in an
array.
I tried this,
myname = c("benzene", "etc
In addition to the other suggestions you may also want to look at the subplot
function in the TeachingDemos package (the version in Hmisc is a copy of a
prior version of this one) as well as the my.symbols or panel.my.symbols
functions in the same package.
--
Gregory (Greg) L. Snow Ph.D.
Stati
Hi R-help,
I am trying to use 'samr' for 10 pre and post paired samples to test
whether
post is different from pre (i.e., the location shift for the delta of
(post-pre)).
However, I got an error message saying
> samr.obj<-samr(d, resp.type="Two class paired", nperms=100,
random.seed=100)
pe
Hello All,
Using the standard "summary" function in 'R', I ran across some odd
behavior that I cannot understand. Easy to reproduce:
Typing:
summary(c(6,207936))
Yields::
Min. *1st Qu. MedianMean 3rd Qu.Max.*
6 *51990 104000 104000 156000 207900*
None of t
Great. It is more clearer for me. Thanks all.
2010/8/24 Michael Dewey
> At 02:40 24/08/2010, rusers.sh wrote:
>
>> Hi all,
>> rmvnorm()can be used to generate the random numbers from a multivariate
>> normal distribution with specified means and covariance matrix, but i want
>> to specify the c
Dear all, I was doing an experiment to disprove some theory therefore
performing lot of random simulation. Goal is to show the audience that
although something has very rare chance to occur but it doesn't mean that
event would be impossible.
In this case after getting that rare event I need to
Dear r-help,
I'm having trouble formatting xy labels for plot in r. I want to make the
following y-label
"benzene (mug-3)"
where mu is greek and -3 is superscript and benzene is held in an array.
I tried this,
myname = c("benzene", "etc")
plot (c(0:10), ylab = bquote(.(myname[1])~~(mu~g ~m^-3)))
On 08/24/2010 07:27 AM, Doran, Harold wrote:
> There is the stringMatch function in the MiscPsycho package.
>
>> stringMatch('Hadley', 'Hadley Wickham', normalize = 'no')
> [1] 8
>> stringMatch('Hadley', 'Hadley Wickham', normalize = 'yes')
> [1] 0.4285714
>
> It uses Levenshtein distance to tel
Hello there,
I am using the Tps function to fit a spline to my data which is measurements
of a sedimentary layer on an xy plane to see how the thickness of the layer
changes. I was wondering if it was possible to change the Tps code so that
no minus values are calculated by the spline as these a
None of this would work if the list is long. Isn't this an obvious
task for a loop, explicit or implicit?
e.g.
for(i in 1:100)assign(paste("vec",i,sep=""), vector("integer",5))
or probably better because it creates a list structure:
## warning, untested. You may have to fool with the syntax a b
Hi Cheng,
Check out the keep() function in package:gdata.
And to be sure the "removed" objects are really removed from system
memory i think you need to run gc().
hth,
Karl
On 8/23/2010 9:00 PM, Cheng Peng wrote:
How to remove all R objects in the RAM except for a few specified ones?
rm(l
1 - 100 of 149 matches
Mail list logo