Dear R users,
I have a dataset with two variables: $esan - a grouping factor with 8
levels and $reus. I'd like to do wilcox.test on this dataset as
sugested Weiwei here:
https://stat.ethz.ch/pipermail/r-help/2007-July/136627.html. I tried
to adapt his recommendation but no succes. Can anyone help
> Liaw, Andy
> on Mon, 16 Aug 2010 08:22:33 -0400 writes:
> From: Stephen Liu
>>
>> Hi JesperHybel,
>>
>> Thanks for your advice.
>>
>> >If you're trying to follow the youtube video you have a
>> typing mistake here:
>>
>> >InsectSprays.aov
Hi Rookie,
You're running RedR on Linux OR on Windows?
If on Windows whether you download it on its official website? Or on R ran;
> install.packages("RedR")
?
If on Linux whether you install RedR on repo?
B.R.
Stephen L
- Original Message
From: Rookie
To: Stephen Liu
Cc: r-h
Hi folds,
RedR - visual programming for R
http://www.red-r.org/
Has any folk used RedR before? What will be the difference compared with;
RKWard - GUI for R
http://sourceforge.net/apps/mediawiki/rkward/index.php?title=Main_Page
Screen Short
http://sourceforge.net/apps/mediawiki/rkward/index.php
Tena koe Sadz
One way:
tt <- c('122:45:45','-69:38:27')
tt <- lapply(strsplit(tt,':'), as.numeric)
lapply(tt, function(x) x[1]+((x[1]>0)-0.5)*(x[2]+x[3]/60)/30)
To understand how this work you might need to break up the bits.
HTH
Peter Alspach
> -Original Message-
> From: r-help-b
On Mon, Aug 16, 2010 at 7:27 PM, Sadz A wrote:
> Hi All,
>
> I have location data set up as degrees: minutes: seconds (for example,
> 122:45:45) I need to get this data into decimal degree form (122.7625).
>
> I know that I need to use the formula
>
> Decimal degrees = Degrees + (Minutes/60) + (Se
I take it you have the data in character form. If the DMS data is already in a
data frame it is probably in factor form, so you will need to coerce it to
character first. Here is how you could do it with the DMS data in a data frame:
> m ## an example with 3 entries
DMS
1 122:45:45
2
On 2010-08-16 03:49, Tonja Krueger wrote:
Hi List!
I’m using regsimq() from the “lmomRFA”-package to calculate error bounds for
diverse distributions. For example:
regsimq(gumfit$qfunc, nrec = lmom.data$n, f = lcdfgum, boundprob = c(0.025,
0.975))
Several times I got this error massage:
Fehl
On Aug 16, 2010, at 11:05 PM, hen chao Chang wrote:
>
> My R_version is 2.11.1.
> I can’t install R packages.
> The error massages are following:
>
> package 'DBI' successfully unpacked and MD5 sums checked
> error in normalizePath(path) :
> path[1]="E:\R-2.11.1\library/DBI"……
... and were yo
I am absolutely new to R and I am aware of only a few basic command lines. I
was running a robust regression in R, using the following command line
library (MASS)
rfmodel2 <- rlm (TotalEmployment_2005 ~ ALABAMA + MISSISSIPPI + LOUISIANA +
TotalEmployment_2000 + PCWhitePop_2005 + UnemploymentRate_
Hi All,
I have location data set up as degrees: minutes: seconds (for example,
122:45:45) I need to get this data into decimal degree form (eg, 122.7625).
I know that I need to use the formula:
Decimal degrees = Degrees + (Minutes/60) + (Seconds/3600)
Does anyone know how I can get R to do t
Hi All:
I had a basic question to ask. I am running R2WinBUGS so that I could
automate the running of my model using 1000 simulated datasets. Below is the
code I am using. The only problem I am having is the bugs output that comes
out shows my parameters as nos with 1 decimal place after. I would
Hi All,
I have location data set up as degrees: minutes: seconds (for example,
122:45:45) I need to get this data into decimal degree form (122.7625).
I know that I need to use the formula
Decimal degrees = Degrees + (Minutes/60) + (Seconds/3600)
Does anyone know how I can get R to do this?
Hello,
I am trying to iteratively build a build a panel of variables to
discriminate between two groups.
My starting position is a matrix of experimental data and I have a function
that will work through all pairs of variables and produce sensitivities,
specificities and p-values for each pair an
On Aug 16, 2010, at 11:05 PM, hen chao Chang wrote:
My R_version is 2.11.1.
I can’t install R packages.
The error massages are following:
package 'DBI' successfully unpacked and MD5 sums checked
error in normalizePath(path) :
path[1]="E:\R-2.11.1\library/DBI"……
... and were you running as
sorry I forget the attachments
Dear List,
>
>
>
> Some independent variable were missing in calculation using lm and glm
> (gaussian).
>
> (X= Y1+Y2+…..+Y16, Independent number: 16 variable)
>
> However, those variables did work well in cor(X, Y) respectively.
>
> str(dataframe) was also run to en
On Aug 16, 2010, at 11:05 PM, hen chao Chang wrote:
My R_version is 2.11.1.
I can’t install R packages.
The error massages are following:
package 'DBI' successfully unpacked and MD5 sums checked
error in normalizePath(path) :
path[1]="E:\R-2.11.1\library/DBI"……
In Windoze all back-slashes
My R_version is 2.11.1.
I can’t install R packages.
The error massages are following:
package 'DBI' successfully unpacked and MD5 sums checked
error in normalizePath(path) :
path[1]="E:\R-2.11.1\library/DBI"……
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Dear List,
Some independent variable were missing in calculation using lm and glm
(gaussian).
(X= Y1+Y2+
..+Y16, Independent number: 16 variable)
However, those variables did work well in cor(X, Y) respectively.
str(dataframe) was also run to ensure that the variables were all numbers.
Mor
That's really too big a question to do justice to in a mailing list
reply. If possible, consult a local expert.
To keep it very short, I would say:
(1) when you are interested in maximizing expected predictive accuracy
(rather than testing hypotheses);
(2) when the parameters in the mode
- Original Message
From: Robert Baer
To: Stephen Liu ; r-help@r-project.org
Sent: Tue, August 17, 2010 12:35:07 AM
Subject: Re: [R] Learning ANOVA
>>> modelfn(count ~ spray, data=test01)
>> Error: could not find function "modelfn"
>>
>> What will be +var3 ?
>I think the general advice
You may want to check out examples in lattice and ggplot2. Both of
these make plotting subsets much easier. I can't remember the lattice
syntax off the top of my head, but if you post some example data –
either by creating it or using dput – people will be able to help out
easier. Here is some exa
On Mon, Aug 16, 2010 at 8:07 PM, Gabor Grothendieck
wrote:
> On Mon, Aug 16, 2010 at 8:00 PM, skan wrote:
>>
>> I've just seen that sep sep cannot be "," because there are not commas in
>> the file.
>> but I want it to take the first and second columns (date and time) as a
>> whole, the index.
>
On Mon, Aug 16, 2010 at 8:50 PM, skan wrote:
>
> Oh, I got it with these code:
>
> tmp <- read.table("file.txt")
> mydata <- zoo(z$V3, as.chron(paste(z$V1,z$V2)))
>
> but that way I cannot specify the format of the date
>
The default method of as.chron has a format= argument which uses the %
code
- Original Message
From: Michael Dewey
To: Duncan Murdoch ; Stephen Liu
Cc: r-help@r-project.org
Sent: Tue, August 17, 2010 12:50:51 AM
Subject: Re: [R] About .RData
- snip -
>>You probably set the startup directory in the shortcut when you did
>>the install. (I believe that's the d
Oh, I got it with these code:
tmp <- read.table("file.txt")
mydata <- zoo(z$V3, as.chron(paste(z$V1,z$V2)))
but that way I cannot specify the format of the date
cheers
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Sent from t
On Mon, Aug 16, 2010 at 8:36 PM, skan wrote:
>
> Error in .subset(x, j) : invalid subscript type 'list'
>
>
> Maybe is because I'm using Revolution Analytics and is based on an older
> version of R.
> I use it because I need to manage very big files and the common version of R
> shows me an out of
Error in .subset(x, j) : invalid subscript type 'list'
Maybe is because I'm using Revolution Analytics and is based on an older
version of R.
I use it because I need to manage very big files and the common version of R
shows me an out of memory error.
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http://r.
On Mon, Aug 16, 2010 at 8:00 PM, skan wrote:
>
> I've just seen that sep sep cannot be "," because there are not commas in
> the file.
> but I want it to take the first and second columns (date and time) as a
> whole, the index.
>
In the latest version of zoo index.column= can be a list.
index.c
I've just seen that sep sep cannot be "," because there are not commas in
the file.
but I want it to take the first and second columns (date and time) as a
whole, the index.
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Sent fr
Thanks for Ben.
Model selection by AIC is feasible by the code below.
One more question, when is it appropriate to carry out model averaging and
parameter averaging?
code
library(MuMIn)
data(Cement)
lm1 <- lm(y ~ ., data = Cement)
dd <- dredge(lm1, beta = TRUE, eval = TRUE, rank =
Gabor Grothendieck wrote:
>
>
> Note that zoo does have the read.zoo function which can read a file
> returning a zoo object. See help(read.zoo) .
>
>
I know, but there are many different ways to read and I wanted to know
what's the proper in my case.
For example I've seen these ones, what
Marc, this works perfectly!
Thanks
John
- Original Message
From: Marc Schwartz
To: William Dunlap
Cc: array chip ; r-help@r-project.org
Sent: Mon, August 16, 2010 3:23:33 PM
Subject: Re: [R] print numbers
Bill et al,
See ?axTicks
plot(3^(0:5), 0:5, log="x",axes=FALSE)
> axTicks
Bill et al,
See ?axTicks
plot(3^(0:5), 0:5, log="x",axes=FALSE)
> axTicks(1)
[1] 1 2 5 10 20 50 100 200
> axTicks(2)
[1] 0 1 2 3 4 5
HTH,
Marc Schwartz
On Aug 16, 2010, at 5:17 PM, William Dunlap wrote:
>
>> -Original Message-
>> From: r-help-boun...@r-project.org
>>
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of array chip
> Sent: Monday, August 16, 2010 2:54 PM
> To: Wu Gong; r-help@r-project.org
> Subject: Re: [R] print numbers
>
> Thank you all for the suggestions. They all worked. N
Hi,
Take a look at this:
> identical(a,b)
[1] FALSE
> all.equal(a,b)
[1] "Attributes: < Component 2: 4 string mismatches >"
> rownames(a) <- rownames(b) <- NULL
> identical(a,b)
[1] TRUE
> all.equal(a,b)
[1] TRUE
HTH,
Jorge
On Mon, Aug 16, 2010 at 5:47 PM, array chip <> wrote:
> Hi, I am real
Hi John,
They are different as Erik said.
> identical(a,b)
[1] FALSE
> row.names(a)
[1] "2" "4" "6" "8"
> row.names(b)
[1] "1" "3" "5" "7"
> row.names(a) <- NULL
> row.names(b) <- NULL
> identical(a,b)
[1] TRUE
Regards,
Wu
array chip wrote:
>
>> a
> a b
> 2 10011048 L
> 4 100110
Oops, I overlooked the row names. Sorry for my carelessness.
Thanks
- Original Message
From: Erik Iverson
To: array chip
Cc: r-h...@stat.math.ethz.ch
Sent: Mon, August 16, 2010 2:53:37 PM
Subject: Re: [R] identical()
Hello,
array chip wrote:
> Hi, I am really puzzled by this. hop
On Mon, Aug 16, 2010 at 5:47 PM, array chip wrote:
> Hi, I am really puzzled by this. hope someone can help me
>
> I have a 2 small data frames "a" and "b" derived from a larger data frames.
> They
> look exactly the same to me, but identical() always returns FALSE.
>
>> a
> a b
> 2 10011
Hello,
array chip wrote:
Hi, I am really puzzled by this. hope someone can help me
I have a 2 small data frames "a" and "b" derived from a larger data frames. They
look exactly the same to me, but identical() always returns FALSE.
a
a b
2 10011048 L
4 10011048 R
6 10011049 L
8 10
Thank you all for the suggestions. They all worked. Now, those numbers on the
ticks are produced by default plot function "bxp()", i.e. they are different in
each plot, is there any functions I can retrieve them so I can use formatC() or
prettyNum() etc?
Thanks again,
John
- Original Me
Katayoon Kasaian wrote:
Hello,
I've been trying to use R-2.11.1 but I get the following error when trying to
run R on linux:
"error while loading shared libraries: libRblas.so: cannot open shared object file:
No such file or directory"
How can I solve this problem?
Did you install this ve
Hi, I am really puzzled by this. hope someone can help me
I have a 2 small data frames "a" and "b" derived from a larger data frames.
They
look exactly the same to me, but identical() always returns FALSE.
> a
a b
2 10011048 L
4 10011048 R
6 10011049 L
8 10011049 R
> b
a b
1 1
Hi John,
formatC will do your work. Hope it helps.
x <- y <- c(50.00,25.00,10.00,1.00,0.05,0.01)
plot(x,y,log = "xy",axes = F)
axis(1, x, formatC(x))
axis(2, y, formatC(y))
Regards,
Wu
-
A R learner.
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Hello,
I've been trying to use R-2.11.1 but I get the following error when trying to
run R on linux:
"error while loading shared libraries: libRblas.so: cannot open shared object
file: No such file or directory"
How can I solve this problem?
Best,
Katy
___
On Mon, Aug 16, 2010 at 1:40 PM, skan wrote:
>
> OK, thanks
>
> Some time ago I asked in the forum how to read data from a file in order to
> use it with zoo.
> Someone suggested to use textConnection
> That's why I'm a little bit confused.
> I guess I don't need to use textConnection in order to
On Sat, 2010-08-14 at 21:17 +0800, elaine kuo wrote:
> Thanks
>
> I wanna to add the species labels in a cca biplot
> based on species and environment conditions (maybe sites are of less
> relevance here).
0. It would help your learning if you actually read the help pages for
the functions I used
Try this:
x <- c(50,25,5,1,.1,.05)
prettyNum(x)
On Mon, Aug 16, 2010 at 4:53 PM, array chip wrote:
> Hi,
>
> When I plot, the axis ticks are printed as "50.00 25.00 10.00 1.00 0.05
> 0.01", is there any way to print them as "50 25 10 1 0.05 0.01"
> instead?
>
> Thanks
>
> John
>
> _
How about this:
> x <- c(50,25,5,1,.1,.05)
> ifelse(x >= 1, sprintf("%.0f", x), sprintf("%.2f", x))
[1] "50" "25" "5""1""0.10" "0.05"
>
On Mon, Aug 16, 2010 at 4:33 PM, array chip wrote:
> sorry that I didn't give more details, thought it's going to be the same for
> all
> plots. I
On Aug 16, 2010, at 4:33 PM, array chip wrote:
sorry that I didn't give more details, thought it's going to be the
same for all
plots. It's the bxp() for boxplot. I have about couple of 10 such
plots in a
for() loop, so would like to automate the process. Using "labels= "
certainly
works,
sorry that I didn't give more details, thought it's going to be the same for
all
plots. It's the bxp() for boxplot. I have about couple of 10 such plots in a
for() loop, so would like to automate the process. Using "labels= " certainly
works, but it's manual work - plot by plot. Any other sugge
On Aug 16, 2010, at 3:53 PM, array chip wrote:
Hi,
When I plot, the axis ticks are printed as "50.00 25.00 10.00
1.00 0.05
0.01", is there any way to print them as "50 25 10 1 0.05 0.01"
instead?
No example, so we don't even know which of the three plotting
paradigms you might
Hi,
If you should decide to pursue the LaTeX approach, you would want to install
MacTeX on your Mac. More information here:
http://www.tug.org/mactex/2009/
MacTeX is a self contained distribution of TeX Live 2009. It also provides an
easy to use GUI based maintenance tool to add packages and
Hi,
When I plot, the axis ticks are printed as "50.00 25.00 10.00 1.00 0.05
0.01", is there any way to print them as "50 25 10 1 0.05 0.01" instead?
Thanks
John
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-hel
The R Journal article by Paul Murrell may be of interest:
http://journal.r-project.org/2009-1/RJournal_2009-1_Murrell.pdf
The documentation for the Diagram Package may also be of interest:
http://cran.r-project.org/web/packages/diagram/diagram.pdf
http://cran.r-project.org/web/packages/di
Thanks! My LaTeX knowledge is quite limited, I don't even know which
one of these
http://www.ucc.ie/cgi-bin/uncgi/ctan?term=PSTricks
I should install to get PSTricks working. I have used TeXShop once or
twice on my Mac. So, I maybe prefer plain R solution.
-J
2010/8/16 Marc Schwartz :
>
> On Au
Negate is in the base package, although apparently not in the
prehistoric version of R you're using here! Updating to the
latest R should work.
Jock Currie wrote:
Dear All
I'm having problem with some script which worked a few months ago (on a
different computer that might well have had a diff
Dear All
I'm having problem with some script which worked a few months ago (on a
different computer that might well have had a different version of R
installed, so perhaps it has to do with the old version of R?):
library(reshape)
Loading required package: plyr
> tble.data <- melt.array(interp, v
Dear Grzesiek
Only pch 21 to 25 can be filled. Pairing fill with plot characters 1:20
will be ignored. You could try overlaying points to increase the number
of unique colour/shape combinations.
Cheers
Chris
Hadley Wickham, Creator of ggplot2 - teaching in the UK. 1st - 2nd
November 2010.
To
You have a lot of different way
a<-c(1,2,3,NA,3,4,3)
is.na(a)
[1] FALSE FALSE FALSE TRUE FALSE FALSE FALSE
a==2
[1] FALSE TRUE FALSENA FALSE FALSE FALSE
Look at here:
http://cran.r-project.org/doc/manuals/R-intro.html
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Hello
On Mon, 16 Aug 2010 11:17:41 -0700
Dennis Fisher wrote:
> Colleagues,
>
> R 2.11.1, OS X. Please forgive my ignorance of some issues related
> to ANOVA.
>
This has already been discussed at length on this list. You might try
searching the archives and using Rseek. There are two pointe
On Aug 16, 2010, at 12:59 PM, johannes rara wrote:
> I have a large dataset and I would like to make some kind of flowchart
> from this dataset. The idea is to show rowcounts from data subsets:
>
> data1
> rows= 10
> |
>/ \
http://cran.r-project.org/web/packages/diagram/vignettes/diagram.pdf
It might be difficult to include very large amounts of data, but names and
counts should be fine.
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Sent from the R
Colleagues,
R 2.11.1, OS X. Please forgive my ignorance of some issues related to ANOVA.
I am trying to replicate some SAS analyses that use type 3 sum of squares. The
model that I am using is:
lm(YVAR ~ DATA$SEQ + DATA$SEQ %in% DATA$ID + DATA$PERIOD +
FRAME$FORMULATION)
The intent i
I have a large dataset and I would like to make some kind of flowchart
from this dataset. The idea is to show rowcounts from data subsets:
data1
rows= 10
|
/ \
/ \
males females,
rows=
OK, thanks
Some time ago I asked in the forum how to read data from a file in order to
use it with zoo.
Someone suggested to use textConnection
That's why I'm a little bit confused.
I guess I don't need to use textConnection in order to read from files, it's
just for text copied from other sourc
Also, many R functions are designed to operate on R connections, to
input and output text. Alternatively, we may wish to provide the input
text as an R character vector, or output text to a character vector. The
textConnection makes a character vector look like a connection, so R
routines that oper
Hi,
One useful case is when data is sent in an email. For instance:
T1 T2 T3
-0.24 -0.26 -0.67
-1.58 0.04 0.14
-1.21 1.55 -0.45
0.31 0.48 -1.39
One could read it in via
con <- textConnection("
T1 T2 T3
-0.24 -0.26 -0.67
-1.58 0.04 0.14
-1.21 1.55 -0.45
0.31 0.48 -1.39")
re
At 21:20 15/08/2010, Duncan Murdoch wrote:
On 15/08/2010 10:24 AM, Stephen Liu wrote:
- Original Message
From: Michael Bedward
To: Stephen Liu
Cc: r-help@r-project.org
Sent: Sun, August 15, 2010 3:43:55 PM
Subject: Re: [R] About .RData
Furthermore can I run following command on R?
r
Thanks Chuck,
I was trying to implement something more complicated than what I had to and
after finding the reduce() function in bioconductor, everything went
smoothly.
Thanks again
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Sent
Hello.
I don't uderstant when to use textConnection and when not.
Some examples do it, some not.
I've even seen something like
con <- textConnection(rev(rev(ReadLines('data.txt'))[-(1:2]))
data <- read.table(con)
close(con)
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modelfn(count ~ spray, data=test01)
Error: could not find function "modelfn"
What will be +var3 ?
I think the general advice applied to your specific situation was meant to
suggest using the construct:
InsectSprays.aov <- aov(count ~ spray, data=InsectSprays)
rather than:
InsectSprays.aov <-
Hello R-list!
I'm developing a prognostic model for a medical problem (event yes/no).
So I used the patrty package and did a Random Forest:
ctrl <- cforest_unbiased(ntree=1000, mtry=3, minsplit=100)
set.seed(675)
rf <- cforest( ph ~. , data=train, controls=ctrl)
print(rf)
and calculated the ind
- Original Message
From: Erik Iverson
To: Stephen Liu
Cc: r-help@r-project.org
Sent: Mon, August 16, 2010 11:41:34 PM
Subject: Re: [R] Learning ANOVA
>> modelfn(count ~ spray, data=test01)
> Error: could not find function "modelfn"
>
> What will be +var3 ?
>
> This is just a generic
The set runs fine without the fixed effects. However, once I add the
"+factor(HostCode)"-part, it throws out two variables. The africa-dummy
thrown out certainly does not exhibit perfect multicollinearity, I checked
that. The litrate variable is continuous and therefore cannot be perfectly
related
Stephen Liu wrote:
- Original Message
From: "Liaw, Andy"
To: Stephen Liu ; r-help@r-project.org
Sent: Mon, August 16, 2010 8:22:33 PM
Subject: RE: [R] Learning ANOVA
- snip -
Well-written model fitting functions should be called like this:
modelfn(var1 ~ var2 + var3, data=df,
- Original Message
From: "Liaw, Andy"
To: Stephen Liu ; r-help@r-project.org
Sent: Mon, August 16, 2010 8:22:33 PM
Subject: RE: [R] Learning ANOVA
- snip -
> Well-written model fitting functions should be called like this:
> modelfn(var1 ~ var2 + var3, data=df, ...)
Hi Andy,
Than
1. Bootstrap will do poorly for small sample sizes (less than 25 or
so). Parametric methods (t) have the advantage of working down to a
sample size of less than 5.
2. You need to have the number of resamples reasonably large, say
10,000, for poorly behaved distributions. Otherwise extreme
per
Do not worry, I found the solution.
I had a list, as follows :
x <- list()
x$i <- 5
x$j <- 9
x$k <- 15
names(x$i) <- "a"
names(x$j) <- "b"
names(x$k) <- "b"
And I wanted to obtain a list, as follows :
$a
i
5
$b
j k
9 15
My solution :
n <- sapply(x, names)
m <- sapply(x, c, use.names = FALS
Thanks a lot, Dimitris!
I see - data should be defined precisely as data.frame.
On Mon, Aug 16, 2010 at 2:47 PM, Dimitris Rizopoulos <
d.rizopou...@erasmusmc.nl> wrote:
> better try it this way:
>
> DF <- data.frame(y = rnorm(100), x = rchisq(100, df = 3))
> m <- lm(y ~ x, DF)
> predict(m, data
http://rwiki.sciviews.org/doku.php?id=developers:projects:gsoc2010:nosql_interface
http://github.com/wactbprot/R4CouchDB
On Mon, Aug 16, 2010 at 7:40 AM, David Mitchell wrote:
> Hello all,
>
> I'm kind of surprised that searching the archives and Googling haven't given
> me a result for this...
On Mon, Aug 16, 2010 at 12:40 PM, David Mitchell wrote:
> What's the best way to go about extracting data from CouchDB databases, so
> that I can process it using R? There don't seem to be any specific R
> modules for CouchDB, but I find it hard to believe that I'd be the first one
> to want to
On 16 August 2010 at 21:40, David Mitchell wrote:
| Hello all,
|
| I'm kind of surprised that searching the archives and Googling haven't given
| me a result for this...
There is a project called 'R4CouchDB' on github:
http://github.com/wactbprot/R4CouchDB
Hth, Dirk
|
| I've got a lar
On 16.08.2010 15:07, McEachron, Luke wrote:
I am running R 2.10.1 on Windows Server 03 in an effort to increase my memory
limit. The memory limit on my machine is 4 gb and 8 gb on our server. However,
when I run R within the server and try to increase my memory R still says I am
limited to
elaine kuo gmail.com> writes:
[re: MuMIn package]
> However, the criteria in this package for model selection are AICc
> (second-order AIC) and QAIC (quasi-AIC).
> Please kindly share if it is possible to carry AIC rather than the metrics
> above using this package.
> Thank you.
I think you'r
On Mon, Aug 16, 2010 at 2:06 PM, Hyunchul Kim
wrote:
> Hi all,
>
> How to convert following simple python script to R
>
>
> if x in a_list:
> print x
>
> OR
>
> simply, how to test if a vector contain a value?
if(any(a_list == x)){
print(x)
}
Or use %in%:
> a_list=c(1,2,3,4)
> b_list=c(1
Just based on my limited understanding of bootstrapping and statistics in
general, bootstrapping is effective but not magical - you can't reasonably
expect any reliable inference to be drawn about the population based on a
sample of 10, without any distributional assumptions. Your t interval looks
> mylist = c(1,2,3)
> if (any(mylist == 3)) { print(3) }
[1] 3
>
On 08/16/2010 03:06 PM, Hyunchul Kim wrote:
Hi all,
How to convert following simple python script to R
if x in a_list:
print x
OR
simply, how to test if a vector contain a value?
Thank you in advance,
Hyunchul
Try this:
is.element(2, c(1, 2, 4))
On Mon, Aug 16, 2010 at 10:06 AM, Hyunchul Kim
wrote:
> Hi all,
>
> How to convert following simple python script to R
>
>
> if x in a_list:
>print x
>
> OR
>
> simply, how to test if a vector contain a value?
>
>
> Thank you in advance,
>
> Hyunchul
>
>
Hi Hyunchul,
See ?match
-Ista
On Mon, Aug 16, 2010 at 1:06 PM, Hyunchul Kim
wrote:
> Hi all,
>
> How to convert following simple python script to R
>
>
> if x in a_list:
> print x
>
> OR
>
> simply, how to test if a vector contain a value?
>
>
> Thank you in advance,
>
> Hyunchul
>
> [
Hi,
Anybody can tell me why I don't have colors in my picture?
library(lattice)
my.pch<-c(17,16,15,18,20,9,10,12)
my.fill<-c('yellow','black','green','red','blue','cyan','magenta','pink')
wzorzec1<- c(1,3,2,4,6,4,2,3)
wzorzec2<- c(5,3,6,6,2,3,4,1)
a<-factor(wzorzec1)
b<-factor(wzorzec2)
n1<-c
I am running R 2.10.1 on Windows Server 03 in an effort to increase my memory
limit. The memory limit on my machine is 4 gb and 8 gb on our server. However,
when I run R within the server and try to increase my memory R still says I am
limited to 4 gb. Any thoughts?
Thank you in advance for th
Hello all,
I'm kind of surprised that searching the archives and Googling haven't given
me a result for this...
I've got a large amount of data that is a good fit for CouchDB; it's
reasonably unstructured, and such structure that exists is quite fluid. I
want to slice the data in many different
Sorry for chiming in a tad late (I was incommunicado for two weeks)
Le lundi 02 août 2010 à 18:50 +, Ben Bolker a écrit :
> Prof Brian Ripley stats.ox.ac.uk> writes:
>
> >
> > Here is how I do it:
> >
> > write("
> > model {
> >for (year in 1:N) {
> > D[year] ~ dpois(mu[year])
You can also write
x[match(z,x[,2]),].
Leila
on 2010/08/16 06:36 AM RICHARD M. HEIBERGER said the following:
Yes,
x[order(order(z)),]
Two uses of order are needed, as shown.
Rich
On Sun, Aug 15, 2010 at 11:47 PM, Leon Yee wrote:
Dear all,
I have a data frame with several columns,
Hi all,
How to convert following simple python script to R
if x in a_list:
print x
OR
simply, how to test if a vector contain a value?
Thank you in advance,
Hyunchul
[[alternative HTML version deleted]]
__
R-help@r-project.org mailin
better try it this way:
DF <- data.frame(y = rnorm(100), x = rchisq(100, df = 3))
m <- lm(y ~ x, DF)
predict(m, data.frame(x = seq(-13, 13, 0.5)))
I hope it helps.
Best,
Dimitris
On 8/16/2010 2:37 PM, Trafim Vanishek wrote:
Dear all,
I have an error in the simple prediction function for lm
Dear all,
I have an error in the simple prediction function for lm().
Maybe someone experienced the same?
xma <- matrix(data = 0, nrow = 100, ncol = 2)
xma[, 1] <- rnorm(100)
xma[, 2] <- rchisq(100, df = 3)
m1 <- lm(xma[, 1] ~ xma[, 2])
predict(m1, as.data.frame(seq(-13, 13, 0.5)))
Thanks a lo
From: Stephen Liu
>
> Hi JesperHybel,
>
> Thanks for your advice.
>
> >If you're trying to follow the youtube video you have a
> typing mistake here:
>
> >InsectSprays.aov <-(test01$count ~ test01$spray)
>
> >I think this should be:
>
> >InsectSprays.aov <-aov(test01$count ~ test01$spray)
>
Thanks for the answer!
However, if I would have scal.fn() like below, how would I apply
uniroot() or optimize() or the like?
Best,
PM
On 16/08/10 13:24, Adaikalavan Ramasamy wrote:
You probably need to look up on how to write functions.
Try
scal.fn <- function(P, R, T){
out <- ( 1/R - T
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