On 01/07/10 05:43, Pablo Cerdeira wrote:
[...]
*My doubt is: what it means with see the package index?
It is cryptic statistician speak for
help(package = "maps")
Should I find a
Brazilian map on the index?*
No.
*
*If not, can someone help me to find some brazilian map (with state
On 30/06/10 22:14, Carlo Tambuatco wrote:
[...]
Also, references to /usr/lib/libfontconfig.so.1, : undefined symbol:
FT_Select_Size. No idea what this is or how to fix it. But it is the
reason that R_X11.so is not being loaded. There's obviously something
missing that I need to compile and insta
Hi there,
The following code can produce the correct type face, however, the Latin
character are displayed in GB1 font.
pdf("test_1.pdf", family = c("GB1"))
plot(1:10)
text(5,1, "\u4F60\u597D", font = 1)
text(5,2, "\u4F60\u597D", font = 2)
text(5,3, "\u4F60\u597D", font = 3)
text(5,4, "\u4F60\
Dear all,
I'm trying to plot some data over a geographic map.
I'm reading the documentation (?map)... The problem is here:
*map(database = "world", regions = ".", exact = FALSE, boundary = TRUE,*
* interior = TRUE, projection = "", parameters = NULL, orientation = NULL,*
* fill = FALSE, col =
Dear R Gurus,
I have spent some time in the R mail archive and only found one thread that
mentions key binding (http://tolstoy.newcastle.edu.au/R/help/06/03/22481.html).
I use R (2.9.2) from the command line using OS X's (10.6.4) Terminal.app. I
have spent a fair amount of time trying to unders
See if you can track down Thurstone's box problem dataset. It comes (I
believe) on a CD with Loehlin's book 'latent variable models', but I'd
be surprised if you couldn't find it elsewhere. Thurstone measured
boxes, and using EFA (rather than PCA, but they might be similar
enough to start off with
On Jun 30, 2010, at 10:48 PM, harsh yadav wrote:
Hi,
I am a newbie to R and this may be too simple to ask.
I am trying to find out a string function in R that returns the
index of a
character.
For e.g. indexOf("Test1234", '4') would return 8.
?grep
?strsplit
> grep("4", strsplit("Test1
On Jun 30, 2010, at 10:48 PM, harsh yadav wrote:
Hi,
I am a newbie to R and this may be too simple to ask.
I am trying to find out a string function in R that returns the
index of a
character.
For e.g. indexOf("Test1234", '4') would return 8.
Is there a similar function in R.
I tried sea
I noticed this running a few graphics demos the other day.
In particular the plotmath and the persp graphics demos, certain fonts
don't seem to render on the demos.
The plotmath demo displays certain math equations on a quartz window
that don't render properly, and the persp demo displays a 3D mo
Hello,
This does what you are looking for:
> regexpr("4", "Test1234")
[1] 8
attr(,"match.length")
[1] 1
see ?regexpr also ?regexp for more details on regular expressions in R.
HTH,
Josh
On Wed, Jun 30, 2010 at 7:48 PM, harsh yadav wrote:
> Hi,
>
> I am a newbie to R and this may be too simp
harsh yadav wrote:
Hi,
I am a newbie to R and this may be too simple to ask.
I am trying to find out a string function in R that returns the index of a
character.
For e.g. indexOf("Test1234", '4') would return 8.
> regexpr("4", "Test1234")
[1] 8
attr(,"match.length")
[1] 1
_
Christofer Bogaso wrote:
> Dear all, I am looking for some interactive study materials on Principal
> component analysis. Basically I would like to know what we are actually
> doing with PCA?
Having in mind the eigenvalue decomposition and a bivariate data set, the sum-
it-all in a few sentences I
Hi,
I am a newbie to R and this may be too simple to ask.
I am trying to find out a string function in R that returns the index of a
character.
For e.g. indexOf("Test1234", '4') would return 8.
Is there a similar function in R.
I tried searching the documentation and could find other useful str
On Jun 30, 2010, at 7:38 PM, Andrew Liu wrote:
Hello,
I am trying to color particular labels on my lattice xyplot.
For example:
library(lattice)
z = data.frame(x = 1:5)
xyplot(x~x, z)
Is there any way for me to make the "4" on the y-axis blue?
xyplot(x~x, z, scales=list(x=list(col=c("bla
Thanks Henrique, that appeared to work, but now I have another issue.
If I add a ylim to the plot then when I plot another line it gets plotted on
the wrong scale.
#this works as expected
plot(iris[,1],col="red",ylim=c(-10,10)) #plot1
lines(iris[,4],col="black")
#this does not
par(mfrow=c(2,1
Oh thanks Thierry, the ggplot produces very nice graphics. Really amazing.
I'll read more about it.
Thanks,
best regards
On Wed, Jun 30, 2010 at 8:56 AM, ONKELINX, Thierry wrote:
> Or you could use ggplot2
>
> library(ggplot2)
> Dataset <- read.csv("file.csv", header=TRUE)
> ggplot(Dataset, ae
On Wednesday 30 of June 2010 23:02:09 afso...@unisinos.br wrote:
> Hi all,
>
>I am using the vegan package to run a prcincipal components analysis
> on forest structural variables (tree density, basal area, average
> height, regeneration density) in R.
>
>However, I could not find out ho
Gavin,
Thank you for your clear explanation. I'm just learning R, hence my not knowing
how to dummy code a variable using R. Your example was very useful!
Thank you again.
Lidia
> Subject: Re: [R] Interpretation of gam intercept parameter
> From: gavin
Hi there,
According to ?par, 'font' is an integer which specifies which font to
use for text, that 1 corresponds to plain text (the default), 2 to bold
face, 3 to italic and 4 to bold italic.
When I test Chinese character in pdf(), I found that 1 to bold face, 2
to italic, 3 to bold italic, 4 t
For 1 you can just reverse one of the y ranges, e.g.:
updateusr(1:2, range(0,y1), 1:2, rev(range(y2)) )
on my computer for some reason the axis command needs you to explicitly set the
at points, but then it works properly.
For 2, are the axes on all the plots the same? If so you can put all th
Good day R-users,
So if the question may seem easy to many of you but this present a
serious issue for me . I'm currently running a panel data analysis
i've used the plm package to perform the Tests of poolability as
results intercepts and coefficients are assumed different. so my
question is sho
Use "Rprof" to determine where time is being spent. This might point
out some problems in the code.
On Wed, Jun 30, 2010 at 7:53 PM, Mike Williamson wrote:
> Hi all,
>
> I am using the package "random forest" for random forest predictions. I
> like the package. However, I have fairly large
Good day R-users,
So if the question may seem easy to many of you but this present a
serious issue for me . I'm currently running a panel data analysis
i've used the plm package to perform the Tests of poolability as
results intercepts and coefficients are assumed different. so my
question is sho
Hi all,
I am using the package "random forest" for random forest predictions. I
like the package. However, I have fairly large data sets, and it can often
take *hours* just to go through the "na.roughfix" call, which simply goes
through and cleans up any NA values to either the median (numer
Hello,
I am trying to color particular labels on my lattice xyplot.
For example:
library(lattice)
z = data.frame(x = 1:5)
xyplot(x~x, z)
Is there any way for me to make the "4" on the y-axis blue?
Thanks,
Andy
__
R-help@r-project.org mailing list
h
On 30 Jun 2010, at 22:55, Allan Engelhardt wrote:
>> > a$z=z
> You are (kind of) assigning *two* columns from the data frame "z" to
> the name 'z' in "a" which is probably not going to work as you
> expect. R tries to be clever which may or may not be a Good Thing.
> Try
>
> a$z1 <- z[,1]
I nominate the below for a Fortune.
-- Bert
Bert Gunter
Genentech Nonclinical Biostatistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of R. A. Bilonick
Sent: Wednesday, June 30, 2010 3:16 PM
To: r-help@r-project.org
Subject:
On 2010-06-30 15:56, Cable, Samuel B Civ USAF AFMC AFRL/RVBXI wrote:
Okay, here is a reproducible example of a possible solution (actually
it
probably does not do what you want but it's a start for discussion.
Note it is actual code and data which is what is needed.
=
On Mon, 2010-06-28 at 10:48 -0400, Robert Baer wrote:
> y=rnorm(100)
> x=abs(y)
> plot(x, y, axes=FALSE)
> axis(1, pos=0)
> axis(2)
> box()
It's nice to know that R tends to make nice graphics by default. But you
can have R do not so great graphics (like Excel and other programs that
make really
> Okay, here is a reproducible example of a possible solution (actually
> it
> probably does not do what you want but it's a start for discussion.
> Note it is actual code and data which is what is needed.
> ===
> str1 <- "abc"
> str2 <- "abcd"
>
On Wed, Jun 30, 2010 at 4:32 PM, Manussawee Sukunta
wrote:
> Hi,
>
> I'm having especially hard time today and couldn't find any
> clue/answer through the internet. I hope you can help.
>
> I'm in a process of writing a script to estimate error correction
> model, and I was following an example i
Try this:
par(mfg = c(1, 1))
lines(iris[,4],col="black")
On Wed, Jun 30, 2010 at 7:26 AM, pdb wrote:
>
> I am doing calculations in a loop and then plotting the results by adding a
> point to each of 2 charts at the end of the loop. Its very informative as
> you can see the progression through
I would generally write a function to create the entire first plot, then the
entire 2nd plot based on data or other arguments passed in, then in your loop
or whatever call the function with the different steps. This will recreate the
plots from scratch at each step rather than adding to the exis
OK, I have managed to use some of the basic processes of getting data from
my DB, passing it as a whole to something like fitdistr, &c. I know I can
implement most of what I need using a brute force algorithm based on a
series of nested loops. I also know I can handle some of this logic in a
brut
Sorry - I actually thought about it after I'd sent out the first message.
When I did
>attributes(series)
I saw that series$class is 'xts' 'zoo'.
I just want to keep some sort of indexing so that I can keep track of
what is going on... a sanity check. My database can get quite large.
I will try
I think this has reached the point where it is absolutely necessary
for Asha Sharma to state *exactly* what is meant by a "linear lower
envelope" of a set of points. There are too many possibilities for
the problem as stated so far. For instance (possibilities which have
not been considered so far)
You can try noquote also:
noquote(paste('abc', '"xyz"', sep = ""))
On Wed, Jun 30, 2010 at 3:31 PM, Paul Evans wrote:
> Hi,
>
> How can I get double quotes embedded in the string?
>
> Example:
>
> --
> str1 <- '"xyz"'
>
> ## desired output
> # abc"xyz"
>
> qr2 <- paste('abc',str1,s
Dear All,
I tried to build a distance matrix. The following example is using dis fucntion:
a<- 1:100
grid <- as.matrix(expand.grid(a,a))
dis<-as.matrix(dist(grid))
This can create a 1 x 1 distance matrix, and the object size is about
764Mb. However, the actual usage of this operation is
Yes.
I've got the R-core, and R-devel packages both installed and updated.
Also have tcl and tcl-devel installed and updated and also
fontconfig-devel.
For some reason, though the reason that Rcmdr fails to compile and be
stored in the library is because its dependencies fail to compile and
be lo
On 2010-06-30 14:32, Manussawee Sukunta wrote:
Hi,
I'm having especially hard time today and couldn't find any
clue/answer through the internet. I hope you can help.
I'm in a process of writing a script to estimate error correction
model, and I was following an example in Bernhard Pfaff's Anal
Hi all,
I am using the vegan package to run a prcincipal components analysis
on forest structural variables (tree density, basal area, average
height, regeneration density) in R.
However, I could not find out how to extract factor loadings
(correlations of each variable with each pca axis)
cat() is probably what you want, but note that print()
has a 'quote=' argument that you could set to FALSE:
print(qr2, quote = FALSE)
See ?print.default
-Peter Ehlers
On 2010-06-30 13:16, Phil Spector wrote:
Paul -
When you print a string, it escapes the quotes with a backslash. That's
a
Hi all,
I am using the vegan package to run a prcincipal components analysis
on forest structural variables (tree density, basal area, average
height, regeneration density) in R.
However, I could not find out how to extract factor loadings
(correlations of each variable with each pca axis)
On Wed, Jun 30, 2010 at 4:02 PM, skan wrote:
>
> Hello
>
> I have two series (that can have with different frequencies or with missing
> values).
> I merge them and use na.locf, getting a zoo objet with a common index and
> two core columns.
> How can I add this columns getting a new zoo series?
>
On Jun 30, 2010, at 4:02 PM, Asha Sharma wrote:
Hi,
Thanks to both of you for taking the time to answer my question. I
was maybe not very clear in the way I framed my question. By plot, I
meant an x-y plot with a cloud of points which should have a linear
lower envelope. Is there a way t
Hi,
your problem is called "string matching". Search for that term on
rseek.org, there are a couple of functions and packages. And Wikipedia
can tell you everything you ever wanted to know about string matching
(and more).
HTH,
Stephan
Cable, Samuel B Civ USAF AFMC AFRL/RVBXI schrieb:
A
On 30/06/10 20:46, Michael Lachmann wrote:
It took me some time to find this bug in my code. Is this a feature of
R? Am I doing something wrong?
> a=data.frame(x=1:10,y=1:10)
> b=data.frame(x=11:20,y=11:20)
> z=data.frame(1:10,11:20)
> a$z=z
You are (kind of) assigning *two* columns from the d
Manussawee,
What type of object is series? We could help you better if we could
reproduce exactly what you are trying to do, which requires more information
(you made a good start by including data and code, though).
The output of diff is a vector (time series, ...) with length one less than
the
If I just add them (without merging) I get only the common elements.
rowsum doesn't work for me
--
View this message in context:
http://r.789695.n4.nabble.com/merging-and-adding-time-series-tp2274125p2274131.html
Sent from the R help mailing list archive at Nabble.com.
_
Hi,
Thanks to both of you for taking the time to answer my question. I was
maybe not very clear in the way I framed my question. By plot, I meant
an x-y plot with a cloud of points which should have a linear lower
envelope. Is there a way to both plot as well as get the parameters of
the lowe
Hello
I have two series (that can have with different frequencies or with missing
values).
I merge them and use na.locf, getting a zoo objet with a common index and
two core columns.
How can I add this columns getting a new zoo series?
Any other way of adding two asynchronou series?
regards
--
I did a standard install of R on Fedora 13 using yum as root, which I
assumed installed both the base packages and the devel packages needed
to install R Commander (there weren't any optional packages listed on
the yum info page). My version of R is updated to the latest 2.11
version.
But, running
Have you changed the values in b.df? My reading of the original b.df in Erin's
post was that there were no common values in PATIENT_ID and ID.
--- On Tue, 6/29/10, jim holtman wrote:
> From: jim holtman
> Subject: Re: [R] merging/intersecting 2 data frames
> To: "Erin Hodgess"
> Cc: "R help
Dear Martin,
Thank you very much for the (reassuring and helpful) response.
Best regards,
Costas
On Jun 30, 2010, at 3:58 PM, Martin Maechler wrote:
>> "CA" == Constantinos Antoniou
>>on Wed, 30 Jun 2010 12:07:16 +0300 writes:
>> "CA" == Constantinos Antoniou
>>on Wed
On 2010-06-30 14:28, Erik Iverson wrote:
Cable, Samuel B Civ USAF AFMC AFRL/RVBXI wrote:
Anyway, I still wouldn't mind some advice on character
matching.
Thanks.
If so we need a reproducible example of what you are doing.
OK, let's say I have three strings. Str1="abc". Str2="abcd".
Str3
Peter Dalgaard wrote:
> The first issue of the second volume of The R Journal will shortly be
> available at jour...@r-project.org/current.html. Thanks to everyone
As no less than 16 people has informed me, that of course wants to be
http://journal.r-project.org/current.html
(That's what you get
Okay, here is a reproducible example of a possible solution (actually it
probably does not do what you want but it's a start for discussion. Note it is
actual code and data which is what is needed.
===
str1 <- "abc"
str2 <- "abcd"
str3 <- "ef
Hi,
I am trying to model a score over time. This score shows a ceiling effect. I
was
willing to use a longitudinal tobit model, such as the one described by Twisk
et
al. (Twisk_Longitudinal tobit regression: A new approach to analyze outcome
variables with floor or ceiling effects_JCE_2009) b
Hi,
I'm having especially hard time today and couldn't find any
clue/answer through the internet. I hope you can help.
I'm in a process of writing a script to estimate error correction
model, and I was following an example in Bernhard Pfaff's Analysis of
Integrated and Cointegrated Time Series w
Try this:
lapply(list(Str2, Str3), grepl, pattern = Str1)
On Wed, Jun 30, 2010 at 5:22 PM, Cable, Samuel B Civ USAF AFMC AFRL/RVBXI <
samuel.ca...@hanscom.af.mil> wrote:
>
>
> > > Anyway, I still wouldn't mind some advice on character
> > > matching.
> > > Thanks.
> > >
> > If so we need a repr
Cable, Samuel B Civ USAF AFMC AFRL/RVBXI wrote:
Anyway, I still wouldn't mind some advice on character
matching.
Thanks.
If so we need a reproducible example of what you are doing.
OK, let's say I have three strings. Str1="abc". Str2="abcd".
Str3="efgh".
I want to compare Str1 and Str2
> > Anyway, I still wouldn't mind some advice on character
> > matching.
> > Thanks.
> >
> If so we need a reproducible example of what you are doing.
OK, let's say I have three strings. Str1="abc". Str2="abcd".
Str3="efgh".
I want to compare Str1 and Str2 in such a way that R detects that St
Hi,
To be honest, what you mean by "a (linear) lower envelope" becomes less
and less clear to me. Take any cloud of 2-d points. The convex hull
consists of a number of these points - or alternatively, of a number of
line segments between successive ones of these points. Thus, every one
of the
Karl,
dev2bitmap runs its output through Ghostscript, and I assume that the
difference is somehow due to that. I can't say whether Ghostscript is
decreasing the file quality or just doing something clever, though.
Jonathan
On Wed, Jun 30, 2010 at 10:30 AM, Karl Brand wrote:
> Thank you Erik!
--- On Wed, 6/30/10, Cable, Samuel B Civ USAF AFMC AFRL/RVBXI
wrote:
> From: Cable, Samuel B Civ USAF AFMC AFRL/RVBXI
> Subject: Re: [R] What is wrong with this code?
> To: r-help@r-project.org
> Received: Wednesday, June 30, 2010, 3:41 PM
> OK, let me wipe the egg off of my
> face The p
Matthew,
The ggplot documentation pages (http://had.co.nz/ggplot2) have the following
to say under geom_bar:
"A bar chart maps the height of the bar to a variable, and so the base of
the bar must always been shown to produce a valid visual comparison."
Thus, I suspect what you are trying to do m
There is a Fedora mailing list for R which might be better, but some
suggestions:
On 30/06/10 20:18, Carlo Tambuatco wrote:
I did a standard install of R on Fedora 13 using yum as root, which I
assumed installed both the base packages and the devel packages needed
If you want the developer
Hi,
one possibility would be to calculate the convex hull using chull(). I
believe that the hull points are returned by chull() in a clockwise
order (?), so the points between the rightmost and the leftmost point in
the chull() result are the lower half of the convex hull. Remove these
points
It took me some time to find this bug in my code. Is this a feature of
R? Am I doing something wrong?
> a=data.frame(x=1:10,y=1:10)
> b=data.frame(x=11:20,y=11:20)
> z=data.frame(1:10,11:20)
> a$z=z
> b$z=z
> rbind(a,b)
Error in `row.names<-.data.frame`(`*tmp*`, value = c("1", "2", "3",
"4
Hi,
On Wed, Jun 30, 2010 at 11:44 AM, Aadhithya wrote:
>
> Hi,
> I have written a code in R for classifying microarray data using naive
> bayes, the code is given below:
> library(e1071)
> train<-read.table("Z:/Documents/train.txt",header=T);
> test<-read.table("Z:/Documents/test.txt",header=T);
OK, let me wipe the egg off of my face The problem wasn't with the
break statement, it was with how I had included my functions in the
"input.list" list. I promise, I pounded on this for hours and saw the
problem five minutes after I sent off the e-mail. Anybody else ever
have this happen?
On Jun 30, 2010, at 2:05 PM, Asha Sharma wrote:
Hi,
I am looking for a way to find the lower envelope of points on a
plot, preferably specifying what percentage of points should be
allowed to lie outside the envelope. There must be a straightforward
way to do this, but I do not seem to b
I did a standard install of R on Fedora 13 using yum as root, which I
assumed installed both the base packages and the devel packages needed
to install R Commander (there weren't any optional packages listed on
the yum info page). My version of R is updated to the latest 2.11
version.
But, running
Paul -
When you print a string, it escapes the quotes with a
backslash. That's a property of the print() function,
not the string itself.
If you want to see the string, use cat(). The nchar()
function is also useful:
str1 <- '"xyz"'
qr2 <- paste('abc',str1,sep='')
print(qr2)
[1] "abc\
Hi Erik,
The reported problem is with the rjson package.
Then I tried with RJSONIO, which worked fine and aparently is faster.
Thanks.
On Wed, Jun 30, 2010 at 4:05 PM, Erik Iverson wrote:
> You don't say what package fromJSON is in, or give us the ability to
> reproduce the error, since we do
Jim,
Thanks for the reply and your help on this.
In short, it's close but not quite there. In the plot you've produced, I'm
looking to get the trinagular points plotted over the top of the bar chart.
Does that make sense?
Just so you know, there are 2 other considerations:
- 1/ ideally, I'd l
Dear R community,
I am new to R, a reforming SAS user :) I am running R 2.10.1 on a Windows XP
machine. I would like to write linear functions of my coefficient parameter
estimates from a glm, but am having a difficult time understanding the
parameterization R uses. In the toy example belo
Hi,
How can I get double quotes embedded in the string?
Example:
--
str1 <- '"xyz"'
## desired output
# abc"xyz"
qr2 <- paste('abc',str1,sep='')
print(qr2)
-
Actual output:
> [1] "abc\"str\""
I also tried putting an escape sequence before the quote, but couldn'
Hi,
I have written a code in R for classifying microarray data using naive
bayes, the code is given below:
library(e1071)
train<-read.table("Z:/Documents/train.txt",header=T);
test<-read.table("Z:/Documents/test.txt",header=T);
cl <- c(c(rep("ALL",10), rep("AML",10)));
cl <- factor(cl)
mode
I'm having problems with this example, it is posted with reproduceable code
below, both with the normal 0-6 scale and the desired 3-6 scale (with bars
removed). How can I get the graph to have the desired 3-6 scale without
removing the bars. Thanks!
#Data
mean=as.numeric(c(5.117647059,5,4.9473684
Greg,
Just a quick one to say thanks for helping me out with my 2-y axis query --
your solution works a treat.
However, 2 extension points I was wondering if you could help with:
- 1/ Is there any way to invert the 2nd y axis -- i.e. highest entry at the
bottom of the axis? I can see that the
Hi,
I am looking for a way to find the lower envelope of points on a plot,
preferably specifying what percentage of points should be allowed to lie
outside the envelope. There must be a straightforward way to do this,
but I do not seem to be able to find it. I would greatly appreciate any
hel
On Wed, Jun 30, 2010 at 10:05 AM, Research wrote:
> Hello again,
>
> I merge different zoo time series with prices at different dates. This
> returns a multivariate zoo object with NA's at various points i.e.,
>
> 2010-02-28 NA NA NA NA 850.2 2444.4 NA NA
> NA
Just one small additional note below ...
Bert Gunter
Genentech Nonclinical Biostatistics
"But a lot of academics are not going to "waste" their time documenting code
properly, so others can reap the benefits of it. They would rather get on
with
the next project, to get the next paper. "
--
On 03/ 1/10 12:23 AM, Sharpie wrote:
John Maindonald wrote:
I came across this notice of an upcoming webinar. The issues identified
in the
first paragraph below seem to me exactly those that the R project is
designed
to address. The claim that "most research software is barely fit for
purp
On 2010-06-30 8:38, Tal Galili wrote:
Good question pdb,
I would suggest you to use:
par(bg = "white")
In the beginning of the code,
But it doesn't solve the general problem of how to get the "lines" to be
properly aligned.
I am curious for the answer from betteR people.
Best,
Tal
Instead
On Jun 30, 2010, at 12:27 PM, Charles C. Berry wrote:
see
?cut
?interaction
I had been thinking that findInterval or expand.grid might also be
useful, but was really waiting for a test data preparation to emerge.
--
David.
HTH,
Chuck
On Wed, 30 Jun 2010, LogLord wro
Thank you Erik!
That works nicely now. The file size in (in kilobytes) is equal to the
"File>Save As>PDF" method.
Still curious why the file sizes (in Kb), differ by a factor of ~2
between the two methods:
pdf()
dev2bitmap(method = "pdf")
I'm just *assuming* here that file size is inidcati
see
?cut
?interaction
HTH,
Chuck
On Wed, 30 Jun 2010, LogLord wrote:
Hi,
I have the following problem:
I have a large dataframe where each row is specified by two numerical value
(one 1:25 and the other one large specific number (e.g. 203043)). I have a
list of 60 categor
On 30-Jun-10 15:48:39, Barry Rowlingson wrote:
> On Wed, Jun 30, 2010 at 11:57 AM, Yen Ngo wrote:
>> Dear list,
>> I have a vector of letter strings as follow:
>>
>>> LETTERS[c(1:7,9,15,18:25)]
>> _[1] "A" "B" "C" "D" "E" "F" "G" "I" "O" "R" "S" "T" "U" "V" "W" "X"
>> "Y"
>>
>> I need to find sequ
So...
You really should give the results of sessionInfo().
There are (at least) two naive Bayes functions. I'm assuming that you
are using the one in klaR.
Look at the manual page ? predict.NaiveBayes: the output is "A list
with the conditional a-posterior probabilities for each class and the
es
On Wed, Jun 30, 2010 at 11:57 AM, Yen Ngo wrote:
> Dear list,
>
> I have a vector of letter strings as follow:
>
>
>> LETTERS[c(1:7,9,15,18:25)]
> [1] "A" "B" "C" "D" "E" "F" "G" "I" "O" "R" "S" "T" "U" "V" "W" "X" "Y"
>
> I need to find sequences of length 11, which are made from all possible
Yes, there is an analytical solution.
Here is how you do it:
bernoulli_anal <- function(t, R0, Rmax, a, b) {
# Note: a, b, R0, Rmax all have to be positive (strictly > 0)
R1 <- R0 / Rmax
k <- R1^b / (1 - R1^b)
R <- Rmax / (1 + exp(-a*b*t)/k)^(1/b)
return(R)
}
R0 <- 1
Rmax <- 2
a <- 0.5
b <- 1.0
Read the Posting Guide. Your attachment apparently did not meet the
requirements therein.
On Jun 30, 2010, at 10:52 AM, Setlhare Lekgatlhamang wrote:
Dear R Users (particularly tsDyn package users),
I am very new in the use of R and the contributed packages in need of
urgent assistance (see
Please follow the posting guide and tell us minimally what your
operating system is.
You might find:
http://cran.r-project.org/doc/manuals/R-intro.html#Scripting-with-R
or
http://code.google.com/p/batchfiles/#PROGRAM_LIST
useful.
jorge.conr...@cptec.inpe.br wrote:
Hi,
I'm s
On Jun 30, 2010, at 9:08 AM, jorge.conr...@cptec.inpe.br wrote:
Hi,
I'm starting use the R Package and I have some .R scripts. How
can I run these .R scripts.
?source
... and re-read "Introduction to R".
Conrado
__
R-hel
Welcome to a new world. You're using the _programming language_ R with
thousands of packages, and first of all you should be reading the
introduction material thoroughly :
http://cran.r-project.org/doc/manuals/R-intro.pdf
http://cran.r-project.org/doc/contrib/Owen-TheRGuide.pdf
Regarding your que
You don't say what package fromJSON is in, or give us the ability to
reproduce the error, since we don't know what 's' is. If those two
pieces of information are possible to give to the list, it will be much
easier to help.
dabd wrote:
Hi,
I am trying to consume a web service that returns a
Method 3:
> pdf(file="my_plot.pdf", paper="a4")
> dev.off()
The `pdf` function opens a *new* graphics device, you then send output
to the device before calling dev.off(), e.g.,
pdf(file = my_plot.pdf")
plot(1:10, 1:10)
dev.off()
-yields a .pdf file of 1kb (same plot example) and retu
Dear R Users (particularly tsDyn package users),
I am very new in the use of R and the contributed packages in need of
urgent assistance (see attachment for the explanation of the problem).
Could someone assist me on conducting threshold cointegration test in R
using the tsDyn package. I have gon
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