Hi!
libreadline6 exists only inside Factory, not in 11.1.
Are you sure you clicked on the correct link?
Otherwise I have no quick idea how a readline6 could slip into the build
process.
Report back, please, if the problem persists.
Detlef
On Tue, 16 Feb 2010 04:11:48 +0100
wrote:
> here is t
Hi!
I am not expert in R, but perhaps you can try the following -
X = as.numeric(read.csv('quantity.csv'))
Y = read.csv('equity_price.csv')
Y = Y[, -1]
Z = X*Y
port_val = NULL
for(i in 1 : nrow(Z))
{
port_val[i] = sum(Z[i,])
}
write.csv(data.frame(Z, port_val = port_val), 'PORTFOLIO
Dear R helpers,
I have two input files as 'quantity.csv' and 'equity_price.csv' as (for
example) given below.
'quantity.csv'
GOOG YHOO
1000 100
'equity_price.csv'
sr_no GOOG_price YHOO_price
1 15.22 536.40
2 15.07 53
It seems to me that R returns the unpenalized log-likelihood for the ratio
likelihood test when ridge regression Cox proportional model is implemented. Is
this as expected?
In the example below, if I am not mistaken, fit$loglik[2] is unpenalized
log-likelihood for the final estimates of coeffi
Hi Jessica,
As far as I know that's the expected behavior (at least it's not OS
X-specific: I get the same on OpenSuse 11.2). What happens if you do
download.packages("ape", destdir = "~/Desktop/")
?
Also, out of curiosity, why are you using download.packages() instead
of install.packages()?
Be
Hi,
I'm trying to fit nonlinear mixed effects model using nlme function but getting
an error message. Here is what I have:
fitted_model = nlme(scores~spline(b1,b2,b3,kt,time),
fixed = list(b1~1, b2~1, b3~1, kt~1),
random = b1+b2+b3~1,
groups= ~id,
da
On Feb 15, 2010, at 10:51 PM, Jessica Joganic wrote:
I apologize for not including my entire script. What I typed into
the shell was:
download.packages(ape)
to which R responded with a Tcl/Tk interface allowing me to set my
CRAN. After I did so it proceeded to spit out the following error
Hi R users
Thanks in advance
I have time series data sets. Is there any package in R that helps detect the
outliers using wavelet methods.
Thanks
email: ( assaed...@yahoo.com )
[[alternative HTML version deleted]]
__
R-help@r-p
I apologize for not including my entire script. What I typed into the shell
was:
*download.packages(ape)*
to which R responded with a Tcl/Tk interface allowing me to set my CRAN.
After I did so it proceeded to spit out the following error:
*Loading Tcl/Tk interface ... done*
Error in **file.info
Just one further point. If you do run out of memory using #2 then try
this which is the same as #2 but adds a dbname argument to force the
computation to be done from disk rather than memory.
sqldf("select d1.x - d2.x, count(*) from d1, d2 group by d1.x - d2.x",
dbname = tempfile())
On Mon, Feb 1
Hi Jonathan,
If minDate = min(Condition1) - max(Condition2) and maxDate = max(Condition1) -
min(Condition2) then all your differences would be between minDay and maxDay,
and hopefully this is not a very big range (unless you are going many thousands
years into the past or the future). So basica
Here are two approaches to try:
> # test data
> d1 <- data.frame(x = Sys.Date() + 1:3)
> d2 <- data.frame(x = Sys.Date() - 1:3)
> # 1. you might not have enough memory for this but its short
> table(outer(1:3, -(1:3), "-"))
2 3 4 5 6
1 2 3 2 1
> # 2. this one performs all the operations outsid
here is the message I get upon trying to upgrade R from the provided RPM
package for SuSE 11.1
YaST2 conflicts list - generated 2010-02-15 14:00:50
nothing provides libreadline.so.6()(64bit) needed by
R-patched-2.10.1-50.1.x86_64
[ ] do not install R-patched-2.10.1-50.1.x86_64
On Feb 15, 2010, at 8:58 PM, Jessica Joganic wrote:
Hi Fellow R Users,
I recently upgraded to Mac OS X 10.5 (Snow Leopard) and had some
issues
downloading and running R 2.10.1. I fixed the tcl/tk problem I was
originally having but it was replaced with another. I run R out of
the shell
(t
If you use map() with the projection= option, then see ?mapproject, which
allows you to
project arbitrary (long/lat) points with the previously defined projection.
Then you use
points() to overlay them onto the map.
HTH,
Ray Brownrigg
On Tue, 16 Feb 2010, Shaun Langley wrote:
> I have lat/lo
Hi Andrej, Uwe, Bill
isn't the central keyword 'tesseract', on which and it's extensions we
have extensive literature?
e.g., starting from http://en.wikipedia.org/wiki/Tesseract
I remember an article by Martin Gardner on the construction principles,
too.
I have lat/lon coordinates in Michigan GeoRef that I need to re-project so
they can be shown over a Michigan county map generated from the Maps
library. I'm very confused as to how to do this. Can anyone help?
Thanks,
Shaun
[[alternative HTML version deleted]]
Let me fix a couple of typos in that email:
Hi All:
Let's say I have two dataframes (Condition1 and Condition2); each
being on the order of 12,000 and 16,000 rows; 1 column. The entries
contain dates.
I'd like to calculate, for each possible pair of dates (that is:
Condition1[1:12,000] and Cond
Hi Fellow R Users,
I recently upgraded to Mac OS X 10.5 (Snow Leopard) and had some issues
downloading and running R 2.10.1. I fixed the tcl/tk problem I was
originally having but it was replaced with another. I run R out of the shell
(terminal) and when I ask it to download.packages() it gives me
Hi,
I'm using version 0.5.1 of tm package with R 2.10.1. It looks to me
as if after the following
reuters21578 <- Corpus(DirSource(corpusDir), readerControl =
list(reader = readReut21578XMLasPlain))
reuters21578 <- tm_map(reuters21578, stripWhitespace)
reuters21578 <- tm_map(reuters
Hi all,
The problem I am trying to solve is the following: I have a 'trace' of
half-hourly data across an entire year - i.e. I have 17,500
observations (one for every half-hour of every day of a year). The
data follows a daily, weekly and seasonal pattern that is important to
preserve. What I want
Hi All:
Let's say I have two dataframes (Condition1 and Condition2); each
being on the order of 12,000 and 16,000 rows; 1 column. The entries
contain dates.
I'd like to calculate, for each possible pair of dates (that is:
Condition1[1:10,000] and Condition2[1:10,000], the number of days
differen
On Feb 15, 2010, at 6:24 PM, Oddie wrote:
I have a data set (date, concentration) were i applied the spline
interpolation. I would like to use, though, the Spline () command
R is a functional language. We don't "do" commands. You give us
something, we return something.
in order
to get
I have a data set (date, concentration) were i applied the spline
interpolation. I would like to use, though, the Spline () command in order
to get the predicted values that correspond not only to points used but also
to the points inbetween. Is there a way to set the time step for which i
will ge
The ls() or objects() functions will be a place to start.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Gui
Hello all,
Disclaimer, I know very little about statistics :-|
I am running a series of regressions for friends, the goal being to
determine the AIC, BIC and logLik values from the result/summary of
each regression. We are doing this as part of an evolutionary
algorithm, so it is important that
See the packages:
CircSpatial
CircStats
circular
At 10:58 PM +0100 2/15/10, Francisco Javier Santos Alamillos wrote:
Dear R users,
I would like to know if it is possible to calculate the Mean Error (ME),
the Root Mean-squared error (RMSE) and absolute error (MAE) for two
temporal series of
blue sky wrote:
x=list(a=1,b=NULL)
is.null(x$b)
is.null(x$c)
Both the above two commands give me TRUE, but in the first one, b is
NULL, in the second one, c doesn't exist. Are there functions that can
help me distinguish the two different nulls?
__
R-
x=list(a=1,b=NULL)
is.null(x$b)
is.null(x$c)
Both the above two commands give me TRUE, but in the first one, b is
NULL, in the second one, c doesn't exist. Are there functions that can
help me distinguish the two different nulls?
__
R-help@r-project.org
On 02/16/2010 09:50 AM, joonR wrote:
Hey,
I need either to plot more than one series of data on the same plot,
or to color the points of a single series with different colors according to
some parameter,
how can I do that?
(data are 2 coordinates point that I want to plot in 2D)
Hi joonR,
Loo
On Feb 15, 2010, at 5:50 PM, joonR wrote:
Hey,
I need either to plot more than one series of data on the same plot,
or to color the points of a single series with different colors
according to
some parameter,
how can I do that?
(data are 2 coordinates point that I want to plot in 2D)
?pl
Hey,
I need either to plot more than one series of data on the same plot,
or to color the points of a single series with different colors according to
some parameter,
how can I do that?
(data are 2 coordinates point that I want to plot in 2D)
THANKS!
--
View this message in context:
http://n4.
library(sqldf)
library(ggplot2)
t = data.frame(t = seq.Date(as.Date("2009-01-01"), to =
as.Date("2009-12-01"), by = "month"))
x = data.frame(x = rnorm(5))
df = sqldf("select * from t, x")
qplot(factor(df$t), df$x, geom = "boxplot") + theme_bw()
qplot(factor(df$t), df$x, geom = "boxplot") + the
Hi Duncan,
I finally got this to work, i.e. to extract my file two pages down. Thanks a
lot for your help. I think there is some problem with the HTML source code
of "http://www.expasy.ch/tools/protscale.html";. When I use the
getHtmlFormDescription function the output that I get is not what I wou
The problem was because attr(predict(model, list(DOY=days))) didn't provide
any gradient, it returned NULL. To correct this we need to specify the
gradient by using deriv3() function. Then, when you use predict(model,
list(DOY=days)) will be provided the gradient at this new experimental
points.
You may want to use tkwait.window(tt)
If the below is in a function, then tkwait.window(tt) will wait until the
window goes away (the user clicking on the button) before continuing with the
code, then you can return the result after that.
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Stati
Dear R-help suscribers,
I am doing a meta-analysis of sea urchin growth data in R. I am
fitting a non-linear growth function using nlme(). Most of my
observations are means, and I want to give them weights according to
the number of individuals that were used to obtain those means (as I
do not h
What do you mean by "ignored"? Do you want to drop those sites
from the ordination? If so, you need to subset your data beforehand.
Or if you mean that you have presence data, and not really absences
(common in ecology), and want to ignore joint absences, then you
need to select a dissimilarity me
Dear R users,
I would like to know if it is possible to calculate the Mean Error (ME),
the Root Mean-squared error (RMSE) and absolute error (MAE) for two
temporal series of directional data. Where Can I get documentation about it?
Thanks in advance
[[alternative HTML version deleted]
Achim showed you how, but you might want to consider why.
If you are trying to learn more about your data, then plots or other strategies
may work better than the test.
If you are testing for normality in order to meet the assumptions of a test,
then the test may not be accomplishing what you t
On Feb 15, 2010, at 4:35 PM, Jay wrote:
Hello,
silly question I suppose, but somehow I can't manage to extract the
probabilities from a glm.predict() result:
str(res)
Named num [1:9] 0.00814 0.01877 0.025 0.02941 0.03563 ...
- attr(*, "names")= chr [1:9] "1" "2" "3" "4" ...
I got from:
#
Hi,
I am tryng to use Non-metric multi-dimensional (MDS) to illustrate the
difference in mixed-species flock composition between two species of birds.
It is part of a thesis I am currently working on.
My data consists of 18 columns and 62 rows, with numbers ranging from 0 to
7. I have car
Hello,
silly question I suppose, but somehow I can't manage to extract the
probabilities from a glm.predict() result:
> str(res)
Named num [1:9] 0.00814 0.01877 0.025 0.02941 0.03563 ...
- attr(*, "names")= chr [1:9] "1" "2" "3" "4" ...
I got from:
# A Gamma example, from McCullagh & Nelder (
Without a reproducible example, it's impossible to give you any more
suggestions.
Hadley
On Mon, Feb 15, 2010 at 2:16 PM, Dimitri Shvorob
wrote:
>
> Trying
>
> + scale_x_date(format = "%b")
>
> produces a peculiar result: Apr and Dec facets are labeled "Jan", remaining
> labels are blank.
> --
>
Hello
You are more likely to get help if you provide a subject more
informative than "no subject".
On 2/15/10, hussain abu-saaq wrote:
> is there a good notes for loops(if else and while) in r.
>
Check this [1][3], but also the R manuals [2].
[1] http://www.r-project.org/doc/Rnews/Rnews_2008-
Trying
+ scale_x_date(format = "%b")
produces a peculiar result: Apr and Dec facets are labeled "Jan", remaining
labels are blank.
--
View this message in context:
http://n4.nabble.com/Problems-with-boxplot-in-ggplot2-qplot-tp1555338p1556573.html
Sent from the R help mailing list archive at N
Thank you, Hadley. I try
jpeg(file, width = 800, height = 600, quality = 100)
qplot(factor(closed$close.month), closed$closing.balance, geom = "boxplot",
main = "Monthly distributions of closing balances", xlab = "Month",
ylab = "Balance, USD") + theme_bw() + scale_x_date(major = "months",
Dear Peter
Thank you that is an error in the code but unfortunately the problem is
still apparent.
I think it is related to calculating the gradient
Tom
--
View this message in context:
http://n4.nabble.com/Confidence-intervals-nls-tp1556487p1556585.html
Sent from the R help mailing list arch
is there a good notes for loops(if else and while) in r.
I have a code written in Matlab and I tried to rewrite it in R but it does not
give me the write result . for example in matlab the result is (1 2 3 4)
In r it is give my only 2
One more question if I have variable,lets say x and I use
On 2010-02-15 12:01, FishR wrote:
Dear All
I am quite new to R and would appreciate some help fitting 95% confidence
intervals to a nls function. I have the data
DOY CET
90 5.9
91 8
92 8.4
93 7.7
95 6.6
96 6.8
97 7.1
98 9.7
99 12.3
100 12.
try
Rgraphviz
diagram
At 6:07 PM + 2/15/10, Oliver Kullmann wrote:
Hello,
I wonder whether binary (rooted) trees with simple
labels (say, integers) can be drawn by some R-package?
Couldn't find one.
Just to make sure (since "trees" can be many things): I mean
those computer-science creatu
Perfect!
Thank you, Dimitris.
AC
On Mon, Feb 15, 2010 at 1:45 PM, Dimitris Rizopoulos
wrote:
> try this:
>
> MRfit <- function (...) {
> models <- list(...)
>> do.call(anova, models)
>> }
>>
>>
>> I hope it helps.
>>
>> Best,
>> Dimitris
>>
>>
>> AC Del Re wrote:
>>>
>>> Hi All,
>>>
Dear Colleagues,
John Mandel ( Chain block designs with two-way elimination of heterogeneity.
Biometrics 10, 251-272 ,1954).
extended the class of chain block designs (Youden & Conner (1953)
to elimination of both row and column (blocks) effects.
These experimental designs can be useful in engin
try this:
MRfit <- function (...) {
models <- list(...)
do.call(anova, models)
}
I hope it helps.
Best,
Dimitris
AC Del Re wrote:
Hi All,
I am interested in creating a function that will take x number of lm
objects and automate the comparison of each model (using anova). Here
is a
Is anyone else using the 'geepack' package?
>>>
From: "Steve Taylor"
To:
Date: 11/Feb/2010 11:28 a.m.
Subject: [R] using step() with package geepack
I'm using the package geepack to fit GEE models.
Does anyone know of methods for add1 and drop1 for a 'geeglm' model object, or
perhaps a method
Hi All,
I am interested in creating a function that will take x number of lm
objects and automate the comparison of each model (using anova). Here
is a simple example (the actual function will involve more than what
Im presenting but is irrelevant for the example):
# sample data:
id<-rep(1:20)
Here's another way to have different behaviour only for interactive sessions:
if (interactive()) {
winMenuAdd(menuname, NULL, NULL) # etc.
}
>>>
From: Duncan Murdoch
To:
CC:
Date: 13/Feb/2010 6:15 a.m.
Subject: Re: [R] Selective load of .First() function just for Rgui.exe
On 12/02/2010 11:
Hi Dimitri,
Have you looked at the examples for scale_x_date -
http://had.co.nz/ggplot2/scale_date.html? They show you how to both
set the limits and control the labels.
Hadley
On Sun, Feb 14, 2010 at 1:34 PM, Dimitri Shvorob
wrote:
>
> ... Unfortunately, a problem remains: I cannot label x ti
Dear All
I am quite new to R and would appreciate some help fitting 95% confidence
intervals to a nls function. I have the data
DOY CET
90 5.9
91 8
92 8.4
93 7.7
95 6.6
96 6.8
97 7.1
98 9.7
99 12.3
100 12.8
102 11
103 9.3
104 9.8
When I wrap those values in to a matrix will it be still independent ? ( non
zero correlation).
Can I do this for any multivariate distribution which has the univariate
form?
Thank you for the response.
Haneef
--
View this message in context:
http://n4.nabble.com/Sampling-from-Bivariate-Unif
Hi,
Thanks for the reply but I think you are confusing monotonic and
strictly increasing/decreasing. I also just used the y-value of the last
knot as a simple example as that is not the bit where it goes wrong. It
will still produce a non-monotonic spline if you use for example
x <- 1:8
y <- c(-
Since you're on Windows, try the 'snow' package... the other suggestions
are highly suggested and recommended as well
hth
c
thomas.schwan...@mvv.de wrote:
Dear all,
I'm sitting here just in front of my new p...@work and wonder about the
following question:
* How can I adress multipl
blue sky wrote:
I don't find print.list. Could somebody let me know which method is
called when I run command print(a_list), where a_list is a list? Is
'print.default' used for printing a list?
Yes. You can always debug functions to investigate what's going on, too.
See ?debug.
__
I don't find print.list. Could somebody let me know which method is
called when I run command print(a_list), where a_list is a list? Is
'print.default' used for printing a list?
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r
On 2010-02-15 9:38, vaibhav dua wrote:
Hi Peter,
Thanks for quick reply. Like I said that I'm aware that it needs a vector but I
want to use diagonal matrix.
As you have noted, It could be possible that rlaplace reading dispDiag as a
vector and not matrix like c(3,0,0,0,.20,0,0,0,.1) so I tho
On Feb 15, 2010, at 1:06 PM, Tim Heaton wrote:
Hi,
Thanks for the reply but I think you are confusing monotonic and
strictly increasing/decreasing. I also just used the y-value of the
last
knot as a simple example as that is not the bit where it goes wrong.
It
will still produce a non-mon
Hello,
I wonder whether binary (rooted) trees with simple
labels (say, integers) can be drawn by some R-package?
Couldn't find one.
Just to make sure (since "trees" can be many things): I mean
those computer-science creatures, with roots and subtrees.
Thanks for your consideration in any case
Ol
On Mon, Feb 15, 2010 at 5:07 PM, blue sky wrote:
>> x=3
>> `class<-`(x,'something')#this command prints
> [1] 3
> attr(,"class")
> [1] "something"
>> x=3
>> class(x)='something'#this command doesn't print anything
>
> The first of the above two commands print the content of 'x' but the
> second do
On Feb 15, 2010, at 10:59 AM, Tim Heaton wrote:
Hi,
In my version of R, the stats package splinefun code for fitting a
Fritsch and Carlson monotonic spline does not appear to guarantee a
monotonic result. If two adjoining sections both have over/undershoot
the way the resulting adjustment of a
This is not so much a user help question, as a bug report (I think!)
Previous versions of R allowed the option --with-iconv=no to used to disable the
use of iconv. That option is no longer documented. However, using that option on
the latest does not generate an error message, but is silently i
Hi,
In my version of R, the stats package splinefun code for fitting a
Fritsch and Carlson monotonic spline does not appear to guarantee a
monotonic result. If two adjoining sections both have over/undershoot
the way the resulting adjustment of alpha and beta is performed can give
modified values
> x=3
> `class<-`(x,'something')#this command prints
[1] 3
attr(,"class")
[1] "something"
> x=3
> class(x)='something'#this command doesn't print anything
The first of the above two commands print the content of 'x' but the
second doesn't, although both of them set the argument 'x'. I'm
wondering
Go through the procedure outlined where you signed up. I can't take
you off of the list.
On Mon, Feb 15, 2010 at 10:39 AM, Audra Taylor wrote:
> I would like to be removed from the R mailing list
>
>
>
> [[alternative HTML version deleted]]
>
>
On Feb 15, 2010, at 10:02 AM, geir wrote:
Sorry, i did indeed mean function - not package.
kde2d lets you determine the grid - you choose "n" and "lims", which
gives
you and n x n matrix for which the density is estimated (Seems like
the
output is meant for graphical purposes). But i have
I would like to be removed from the R mailing list
[[alternative HTML version deleted]]
__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-g
On Feb 15, 2010, at 2:29 AM, Johannes Graumann wrote:
Rolf Turner wrote:
On 15/02/2010, at 9:40 AM, Johannes Graumann wrote
(In response to some advice from David Winsemius):
I am quite certain that this is the most elaborately worded
version of
"RTFM" I have ever come across.
I no
Hi Peter,
Thanks for quick reply. Like I said that I'm aware that it needs a vector but I
want to use diagonal matrix.
As you have noted, It could be possible that rlaplace reading dispDiag as a
vector and not matrix like c(3,0,0,0,.20,0,0,0,.1) so I thought to change the
code little bit:
d
On Mon, Feb 15, 2010 at 11:24 AM, David Winsemius
wrote:
>
> On Feb 15, 2010, at 11:01 AM, hadley wickham wrote:
>
>>> I, personally, utilize the ifelse(test,statement,statement) function when
>>> possible over the methodology outlined.
>>
>> if + else and ifelse perform quite different tasks, and
Hi David,
Thank you for your advice. I have just figured why neither the
suggestion of 'par("din")' or "dev.size()" works for me. Having
specified 'rescale="fixed"' in a preceding windows() command seems to
prevent R from reporting the current window size. See here:
windows(width=7.5,height=6,r
On Feb 15, 2010, at 11:01 AM, hadley wickham wrote:
I, personally, utilize the ifelse(test,statement,statement)
function when possible over the methodology outlined.
if + else and ifelse perform quite different tasks, and in general can
not (and should not) be exchanged. In particular, note
> I, personally, utilize the ifelse(test,statement,statement) function when
> possible over the methodology outlined.
if + else and ifelse perform quite different tasks, and in general can
not (and should not) be exchanged. In particular, note that for
ifelse, "the class attribute of the result
Benilton Carvalho-2 wrote:
>
> http://cran.r-project.org/web/views/HighPerformanceComputing.html
>
Also, of the links at the bottom of that page, I found the journal article:
"State of the Art in Parallel Computing with R"
To be a particularly helpful and easy to read overview of the avail
On 2010-02-15 8:26, vaibhav dua wrote:
Hi,
I'm using rlaplace distribution to draw non normal random deviates. I'm using
rmutil package for this. I know rlaplace needs location and dispersion
parameters but I want to pass diag matrix as dispersion parameters and I'm not
getting the correct va
Roy Mendelssohn wrote:
>
> Hi All:
>
> Even after reading the web pages, it is unclear to me exactly how it is
> decided what goes into the base distribution, and more to the point, which
> list I should post to if I want to suggest that a functionality now done
> by a contributed package be a
Hi All:
Even after reading the web pages, it is unclear to me exactly how it is decided
what goes into the base distribution, and more to the point, which list I
should post to if I want to suggest that a functionality now done by a
contributed package be added to the base packages.
Thanks fo
Hi,
I'm using rlaplace distribution to draw non normal random deviates. I'm using
rmutil package for this. I know rlaplace needs location and dispersion
parameters but I want to pass diag matrix as dispersion parameters and I'm not
getting the correct values. Here is my code snippet:
disp
On 2010-02-15 7:06, Martin Ivanov wrote:
Dear R users,
I think I have spotted a bug in R, but as I am not sure, I first post it to you.
Here is a minimal working example:
default<- par(no.readonly=TRUE);
par(font=1, adj=0.5, cex=1, cex.lab=1, cex.axis=0.5, font.axis=2, lend=2,
family="Times"
Hello everyone,
Barry : Thanks for the link to Rscript.
I will check this possibility
(the os was not given in the text, but in subject :-))
Romain : I think my skills at computing are too low for your solution (I
only know a bit of R and of Quick Basic ... nothing with C, C++, ...) and I
also d
On Feb 15, 2010, at 9:49 AM, wrote:
Dear Prof Ripley,
Thank you very much for your advice. In fact, I have already tried
'par("din")'. It does not seems to pick up the changes made to the
window. For example, I issued the par command after the plot:
par("din")
[1] 7.5 7.0
[changed window si
Sorry, i did indeed mean function - not package.
kde2d lets you determine the grid - you choose "n" and "lims", which gives
you and n x n matrix for which the density is estimated (Seems like the
output is meant for graphical purposes). But i have a matrix consisting of
points (x,y) where i want
Dear Prof Ripley,
Thank you very much for your advice. In fact, I have already tried
'par("din")'. It does not seems to pick up the changes made to the
window. For example, I issued the par command after the plot:
> par("din")
[1] 7.5 7.0
[changed window size]
> par("din")
[1] 7.5 7.0
The res
Esmail wrote:
> Ah .. so the fact that this is inside a block (in this case a function)
> makes a difference .. I see .. well this is certainly different from other
> languages I have worked with, but the explanation is clear.
Yes. I think most people involved have realized that it was a design
b
http://cran.r-project.org/web/views/HighPerformanceComputing.html
2010/2/15 :
> Dear all,
>
> I'm sitting here just in front of my new p...@work and wonder about the
> following question:
> * How can I adress multiple CPUs (cores) out of R to speed up the
> simulations I run?
> *
here is the message I get upon trying to upgrade R from the provided RPM
package for SuSE 11.1 (http://cran.r-project.org):
YaST2 conflicts list - generated 2010-02-15 14:00:50
nothing provides libreadline.so.6()(64bit) needed by
R-patched-2.10.1-50.1.x86_64
[ ] do not install R-
Dear all,
I'm sitting here just in front of my new p...@work and wonder about the
following question:
* How can I adress multiple CPUs (cores) out of R to speed up the
simulations I run?
* What are the prerequisites to do so?
Maybe anyone could give me a hint where to start read
On 15-Feb-10 09:27, lee.ad...@luminant.com wrote:
I, personally, utilize the ifelse(test,statement,statement) function when
possible over the methodology outlined.
Haven't used that construct before, I'll check it out.
Thanks. And mystery solved.
Esmail
On 15-Feb-10 09:13, jim holtman wrote:
This is a common question. The problem
is basically when input commands at the command line, when you hit the
carriage return it is assuming there is a complete command.
Within a function, or a block like the 'for' loop, the statement is
not complete until
On Mon, 15 Feb 2010, edmond...@lshtm.ac.uk wrote:
Dear R-listers,
I am writing a function that will generate a simple plot for the
user . The size of the window (that contains the plot) may not be
what the user wants.
Supposing the user adjusts the window to a size of her/his choice, I
wou
Lauri Nikkinen wrote:
> The answer is:
>
>> .libPaths()
> [1] "E:/R/R-2.10.1/library"
>
> stats package is found under
>
> .../library/
Sorry about the delay Lauri, I don't have the time to skim r-help very
well these days, so your note sort of whizzed by.
However, I'm not sure I get the p
I tried twice to install package "e1071"as it provides the Hamming distance.
The installation failed twice.
I am running R version 2.9.0 (2009-04-17).
Any suggestion is welcome.
Thank you,
Maura
tutti i telefonini TIM!
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