Thanks for your answer. I hadn't found this possibility by web search.
Since sqldf also allows the import of tables from csv files, complex
SELECT queries and even joins on tables, I have the impression that
there aren't any reasons for using a SQLite database to organise the
data for R.
But then w
Hi
r-help-boun...@r-project.org napsal dne 14.01.2010 08:05:14:
> Hello All,
>
> I am trying to create a column of weights based off of factor levels
> from another column. I am using the weights to calculate L scores.
> Here is an example where the first column are scores, the second is my
> "
On 01/13/2010 01:50 AM, Primoz PETERLIN wrote:
Hello everybody,
Is it possible to coax legend() into displaying more than one simbol per
line in legend? I have a graph like the one attached to this mail; I would
like to reorganize the legend in such a way that the duplicate text would be
omitted
Hi
r-help-boun...@r-project.org napsal dne 13.01.2010 23:15:05:
>
> I have a file like this:
> idn1n2 n3 n4 n5 n6
> 1 3 47 8 102
> 2 4 12 4 3 10
> 3 7 00 0 0 8
> 4 1010 0 2 3
> 5
There is a recode function in the Hmisc package that might help:
library(Hmisc)
example$X3 <- recode(example$X2, 1:4, c(-3,-1,1,3))
-Ista
On Thu, Jan 14, 2010 at 2:05 AM, Joshua Wiley wrote:
> Hello All,
>
> I am trying to create a column of weights based off of factor levels
> from another col
Hello All,
I am trying to create a column of weights based off of factor levels
from another column. I am using the weights to calculate L scores.
Here is an example where the first column are scores, the second is my
"factor" and the third I want to be a column of weights. I can do
what I want
Hi again,
It's the \samp (and thus the HTML span tag) that does it. I removed the
\samp from one of the links and rebuilt, and the link is properly
translated.
Jim
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLE
Hi Core Team,
I received an email about a problem with the help on the plotrix
package. Apparently the \link tags in the help pages were showing up as
literal text. I couldn't see this problem, nor any problem with the Rd
files. Since the plotrix package hasn't been built for a while, I
rechec
Julian Ramirez wrote:
Hi Ted,
You need to unzip and untar the files that are inside that file, and then
build the package using R CMD build --binary PackageName. However, for
compiling a package under a windows environment you will need Rtools2.10
from Duncan Murdoch, along with Miktex, and html
Jim Silverton wrote:
>
> I want to create the mixture formulation of a discrete uniform ie, say
> f(x) = 1/10, for i = 1,2,3,4,5,6,7,8,9 and 10 and
> another discrete distribution which has the same values of x, but he
> probabilities can vary. Can this be done on any package in R? an if so,
>
Hi Ted,
You need to unzip and untar the files that are inside that file, and then
build the package using R CMD build --binary PackageName. However, for
compiling a package under a windows environment you will need Rtools2.10
from Duncan Murdoch, along with Miktex, and html workshop from microsoft
Hi all,
I'm using windowsXP and R 2.10.0. I downloaded "randomForest
4.5-33.tar.gz" from its archive, but how do I make it into a
installation ZIP file?
Thanks,
Ted
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
P
I have the following code:
## to check correlation between the simulated uniform data
x2 <- uni[,1] ; x2[1:10]
y2 <- uni[,2] ; y2[1:10]
result2 <- boot(cbind(x2,y2), f, 20)
# get 95% confidence interval
boot.ci(result2, type="bca")
cor.test(x2,y2, method="pearson", conf.level=0.95)
part of my
thank Max.
you are so responsible, every time, you give me a lot of help. On my
learning road, you are my guide, though we do not know each other.
best wishes
kevin
å¨2010-01-14ï¼"Max Kuhn [via R]"
åéï¼ -åå§é®ä»¶-
å件人:"Max Kuhn [via R]"
åéæ¶é´:2010å¹´1æ
Thank you very much! It works now perfectly. I even extended it to be
able to apply it to the whole dataset:
data<-read.delim("mhc_data.txt", stringsAsFactors=FALSE)
lettermatch <- function(a, b) {
tb <- merge(as.data.frame(table(strsplit(a, ""))),
as.data.frame(table(strsplit(b, ""))), by
Hi,
I'm struggling to install RCurl for 32-bit linux and am hoping for
some suggestions.
I obtained RCurl_1.3-1.tar.gz from CRAN today, and am using a very
recent version of R:
R version 2.10.1 Patched (2010-01-12 r50970).
I'm not the sysadmin for this system (disclaimer: my sysadmin skil
Thanks you solved and share with us.
But, why don't you use the RMySQL, which connects to MySQL without the
need of ODBC?
Caveman
On Wed, Jan 13, 2010 at 1:48 AM, Marcus, Jeffrey
wrote:
> I think I figured this out. I should not have put the Driver name in
> braces. Changing it from {MySQL} to
steve_fried...@nps.gov wrote:
>
> I am searching for a method to calculate a normal distribution.
>
> For example this equation is used to calculate the normal curve when the
> mean and standard deviation are know.
> p(x) = (1/σ*sqrt(2π)) x exp (- (x-μ)2/2σ2)
>
> However, some of the literatu
Hi Aaron! It's always nice to see a former student doing well.
Thanks for the notes and references, too!
albyn
On Wed, Jan 13, 2010 at 07:29:57PM -0500, Aaron Mackey wrote:
> FYI, in bioinformatics, we use dynamic programming algorithms in similar
> ways to solve similar problems of finding gua
See ?rep where it says that the argument must be a vector. Try
rep(list(sin), 3)
On Wed, Jan 13, 2010 at 8:11 PM, Matthew Walker
wrote:
> Hi everyone,
>
> Would somebody please explain (or point me to a reference that explains) the
> following error:
>
> "Error: object of type 'closure' is no
Dear Uwe and all,
First of all, I want to congratulate you for your dedication in providing
and maintaining R for 64bit operating systems. I tried the 64bit version of
R, under a windows server 2003 system. It seems to work properly, but am
concerned since I need to use the package "fields", which
Hi everyone,
Would somebody please explain (or point me to a reference that explains)
the following error:
"Error: object of type 'closure' is not subsettable"
I was trying to use rep() to replicate a function:
> example_function <- function() { return(TRUE) }
> rep(example_function, 3)
Erro
>From: b.rowling...@googlemail.com [mailto:b.rowling...@googlemail.com] On
>Behalf Of Barry Rowlingson
>Sent: Wednesday, January 13, 2010 7:03 PM
>To: Muenchen, Robert A (Bob)
>Cc: r-help@r-project.org
>Subject: Re: [R] Updated comparison table for SAS-SPSS Add-ons and R Functions
>
>Maybe the fir
FYI, in bioinformatics, we use dynamic programming algorithms in similar
ways to solve similar problems of finding guaranteed-optimal partitions in
streams of data (usually DNA or protein sequence, but sometimes numerical
data from chip-arrays). These "path optimization" algorithms are often
calle
Try this:
> x
id n1 n2 n3 n4 n5 n6
1 1 3 4 7 8 10 2
2 2 4 1 2 4 3 10
3 3 7 0 0 0 0 8
4 4 10 1 0 0 2 3
5 5 11 1 0 0 0 5
> delete <- with(x, n2 == 0 & n3 == 0 & n4 == 0 & n5 == 0)
> delete
[1] FALSE FALSE TRUE FALSE FALSE
> x[!delete,]
id n1 n2 n3 n4 n5 n6
1 1 3
yourdataframe = subset(yourdataframe, !(n2==0 & n3==0 & n4==0 & n5==0))
>>>
From: karena
To:
Date: 14/Jan/2010 12:24 p.m.
Subject: [R] a question about deleting rows
I have a file like this:
idn1n2 n3 n4 n5 n6
1 3 47 8 102
2 4 12 4
On Wed, Jan 13, 2010 at 11:53 PM, Muenchen, Robert A (Bob) wrote:
> Hi All,
>
> I have substantially expanded the table that compares SAS and SPSS
> add-on modules to somewhat equivalent R packages. This new version is
> at:
> http://r4stats.com/add-on-modules
> and I would very much appreciate a
Hi All,
I have substantially expanded the table that compares SAS and SPSS
add-on modules to somewhat equivalent R packages. This new version is
at:
http://r4stats.com/add-on-modules
and I would very much appreciate any feedback you might have on it.
The site http://r4stats.com is the replacemen
Greg - thanks for posting this interesting problem.
Albyn - thanks for posting a solution. Now, I have some questions: (1) is
the algorithm guaranteed to find a "best" solution? (2) can there be
multiple solutions (it seems like there can be more than 1 solution
depending on the data)?, and (3) i
thank you very much!
--
View this message in context:
http://n4.nabble.com/merging-issue-tp1013356p1013433.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
This is great all.
It works perfectly. Thank-you.
Cheers,
Jesse
On Wed, Jan 13, 2010 at 14:27, Adrian Dusa wrote:
> Hi Jesse,
>
> If your vector is called "aa", then how about:
>
> > table(aa)
> aa
> spp1 spp10 spp2 spp3 spp4 spp5 spp6 spp7 spp8 spp9
>7 216 815
I have a file like this:
idn1n2 n3 n4 n5 n6
1 3 47 8 102
2 4 12 4 3 10
3 7 00 0 0 8
4 1010 0 2 3
5 1110 0 0 5
what I want to do is: only if n2=0 and n3=0
Hi,
does this do what you want?
d <- cbind(d,apply(d[,c(2,3,4)],1,mean),apply(d[,c(2,3,4)],1,sd))
HTH,
Stephan
Abhishek Pratap schrieb:
Hi All
I have a data frame in which there are 4 columns .
Column 1 : name
Column 2-4 : values
I would like to calculate mean/Standard error of values i
Hi Jesse,
If your vector is called "aa", then how about:
> table(aa)
aa
spp1 spp10 spp2 spp3 spp4 spp5 spp6 spp7 spp8 spp9
7 216 815 9 910 915
Hope this helps,
Adrian
On Thursday 14 January 2010, Jesse Sinclair wrote:
> Hi all,
>
> I have a vec
Did you consider to look at the help page for merge?
h
At 22:01 13.01.2010, karena wrote:
hi, I have a question about merging two files.
For example, I have two files, the first file is like the following:
id trait1
110.2
211.1
39.7
610.2
78.9
10 9.7
11 10.2
The second
Hi Karean,
If your first object is called obj1 and the second called obj2, then:
> merge(obj1, obj2, all.x=TRUE)
id trait1 trait2
1 1 10.29.8
2 2 11.1 10.8
3 39.7 NA
4 6 10.2 10.1
5 78.9 NA
6 109.7 NA
7 11 10.2 NA
Hope this helps,
Adrian
On Wed
You could look at read.csv.sql in sqldf (http://sqldf.googlecode.com) as well.
On Wed, Jan 13, 2010 at 2:00 PM, Juliet Jacobson wrote:
> Hello everybody out there using R,
>
> I'm using R for the analysis of biological data and write the results
> down using LaTeX, both on a notebook with linux i
?table
On 14/01/2010, at 11:12 AM, Jesse Sinclair wrote:
Hi all,
I have a vector of strings and need to count the number of times a
string
appears in the vector.
eg:
[1] spp6 spp10 spp6 spp6 spp4 spp2 spp9 spp10 spp5 spp2
spp2 spp3
[13] spp4 spp3 spp6 spp10 spp6 spp4 sp
Jesse,
see ?table and try
table(stringVector)
Greg
On 1/13/10 2:12 PM, Jesse Sinclair wrote:
Hi all,
I have a vector of strings and need to count the number of times a string
appears in the vector.
eg:
[1] spp6 spp10 spp6 spp6 spp4 spp2 spp9 spp10 spp5 spp2 spp2 spp3
[13] spp4
Thanks all for a very quick solution. It is actually good to know different
ways to do the same things. It expands my limited understanding of R :).
-A
On Wed, Jan 13, 2010 at 5:12 PM, Stephan Kolassa wrote:
> Hi,
>
> does this do what you want?
>
> d <- cbind(d,apply(d[,c(2,3,4)],1,mean),apply(
Hi all,
I have a vector of strings and need to count the number of times a string
appears in the vector.
eg:
[1] spp6 spp10 spp6 spp6 spp4 spp2 spp9 spp10 spp5 spp2 spp2 spp3
[13] spp4 spp3 spp6 spp10 spp6 spp4 spp9 spp3 spp6 spp1 spp10 spp8
[25] spp2 spp10 spp9 spp7 spp
hi, I have a question about merging two files.
For example, I have two files, the first file is like the following:
id trait1
110.2
211.1
39.7
610.2
78.9
10 9.7
11 10.2
The second file is like the following:
idtrait2
1 9.8
2 10.8
4 7.8
5 9.8
6 10.1
See the dep function defined here:
http://tolstoy.newcastle.edu.au/R/e6/help/09/03/7159.html
On Wed, Jan 13, 2010 at 11:39 AM, Colin Millar wrote:
> Hi there,
>
> My question relates to getting information about R packages. In particular i
> would like to be able to find from within R:
> what
Look at the apply function
?apply
x = data.frame(x1=c(1,2,3,4,5),x2=c(2,4,6,8,10),x3=c(1,3,5,7,9))
x$x5=apply(x,1,mean)
x$x6=apply(x,1,sd)
print(x)
Abhishek Pratap wrote:
>
> Hi All
>
> I have a data frame in which there are 4 columns .
>
> Column 1 : name
>
> Column 2-4 : values
>
> I w
See:
http://tolstoy.newcastle.edu.au/R/help/04/03/1446.html
On Wed, Jan 13, 2010 at 3:45 PM, Pete B wrote:
>
> Hi
>
> I would like to understand how to extend the function (FUN) I am using in
> rollapply below.
>
> ##
> With the following simplified data, test
Try the merge function
?merge
in1 = "id trait1
110.2
211.1
39.7
610.2
78.9
10 9.7
11 10.2
"
in2 = "id trait2
1 9.8
2 10.8
4 7.8
5 9.8
6 10.1
1210.2
1310.1
"
data1 = read.table(textConnection(in1), header=T)
data2 = read.table(tex
Hi All
I have a data frame in which there are 4 columns .
Column 1 : name
Column 2-4 : values
I would like to calculate mean/Standard error of values in column 2-4 and
store them in column 5,6 respectively.
I have done the following but doesn't seem to work
mean_N_SE <-function(x)
{
name
Thanks all, I fixed it.
On Wed, Jan 13, 2010 at 2:47 PM, Don MacQueen wrote:
> If I do
>
> b <- rnorm(4332)
> hist(b,probability=T,breaks=30,col='lightblue',ylim=c(0,1))
> rug(b)
>
> The plot looks entirely reasonable.
>
> As far as being different from SAS, perhaps SAS and R use different
If I do
b <- rnorm(4332)
hist(b,probability=T,breaks=30,col='lightblue',ylim=c(0,1))
rug(b)
The plot looks entirely reasonable.
As far as being different from SAS, perhaps SAS and R use different
breakpoints, that is, different boundaries between the histogram bars.
-Don
At 11:58 A
Hi
I would like to understand how to extend the function (FUN) I am using in
rollapply below.
##
With the following simplified data, test1 yields parameters for a rolling
regression
data = data.frame(Xvar=c(70.67,70.54,69.87,69.51,70.69,72.66,72.65,73.36),
Hello everybody out there using R,
I'm using R for the analysis of biological data and write the results
down using LaTeX, both on a notebook with linux installed.
I've already tried two options for the import of my data:
1. Import from a SQLite database
2. Import from individual csv files edited
On 14/01/2010, at 6:00 AM, Nathalie Yauschew-Raguenes wrote:
Hello,
I find a way to convert data in factor type to numeric :
data_numeric <- as.numeric(as.character(data_factor)).
It's treaky but works.
Possibly even more ``treaky'' but more efficient is:
data_numeric <- as.numeric(
The sp package provides class definitions for spatial data, and utilities
for spatial data handling and manipulation.
The release of sp version 0.9-56 introduces changes in the ways in which
Polygon, Polygons, and SpatialPolygons objects are created, moving from R
code to compiled C code. Beca
Hello,
I am searching for a method to calculate a normal distribution.
For example this equation is used to calculate the normal curve when the
mean and standard deviation are know.
p(x) = (1/σ*sqrt(2π)) x exp (- (x-μ)2/2σ2)
or
(Embedded image moved to file: pic27350.jpg)Normal Probability Dis
In caret, see ?trainControl. Use returnResamp = "all"
Max
On Wed, Jan 13, 2010 at 9:47 AM, bbslover wrote:
>
> Hello,
> I am learning randomForest, now I want to boxplot mse and mtry using 20
> 5-fold cross-validation(using median value), but I have no a good method to
> do it, except a not g
Hi, please read the posting guide. You are not likely to get an extensive
answer to your question from this list. Your question is a "please
solve/explain my statistical problem for me" question. There are two things
problematic with that. First, "statistical", and second "please solve for
me."
Fi
Try this:
dat <- data.frame(x=11:14, pa=1:4/10, pb=4:1/10)
f <- function(numreps, data){
pmat <- as.matrix(data[-1])
x <- data[,1]
result <- matrix(0, nrow=numreps, ncol=ncol(pmat))
colnames(result) <- c("A", "B")
for(i in seq_len(numreps)){
result[i,] <- apply(pmat, 2, function(p)
The key idea is that you are building a matrix that contains the
solutions to smaller problems which are sub-problems of the big
problem. The first row of the matrix SSQ contains the solution for no
splits, ie SSQ[1,j] is just the sum of squares about the overall mean
for reading chapters1 through
Hi,
On Wed, Jan 13, 2010 at 12:58 PM, Yi Du wrote:
> Hi,
>
>
> I use a vector of data to draw the histogram, but it is different from the
> graph by SAS. Can you check it for me please?
How are we supposed to check something without data, pictures, etc?
What do you want checking, exactly?
> b i
On 01/13/2010 05:41 PM, Peter Ehlers wrote:
> S Devriese wrote:
>> On 01/13/2010 10:47 AM, Ahmet Temiz wrote:
>>> hello
>>>
>>> could you give me a hint to convert data in factor type to numeric
>>> (float) ?
>>>
>>> regards
>>>
>>> --
>>> Open WebMail Project (http://openwebmail.org)
>>>
>>>
>
Hi,
I use a vector of data to draw the histogram, but it is different from the
graph by SAS. Can you check it for me please?
b is a column vector of 4332
hist(b,probability=T,breaks=30,col='lightblue',ylim=c(0,1))
rug(b)
When I used rug, I find the records are smaller than 4332. I don't know
w
If the trials are not connected then I would consider melting the table
using melt() from the reshape package.
And then using lapply() with the function
random.function <- function(my.prob, number.of.observations = 10)
{
sum(rbinom(number.of.observations, 1, my.prob))
}
in case the trials are con
If your matrix were a data.frame, it could work like this:
df <- data.frame(age=1:100, sex=rep(1:2, 50))
with(df, by(age, sex, mean))
without the "lapply, sapply etc. family".
h
At 18:16 13.01.2010, Doran, Harold wrote:
with(yourdataframe, tapply(age,sex,mean))
-Original Message-
Fro
WOW, your results give about half the variance of my best optim run (possibly
due to my suboptimal use of optim).
Can you describe a little what the algorithm is doing?
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
> -Ori
Dear friends,
If I have a table like this, first row A B C D ... are different
levels of the variable, first column 0 1 2 4 ... are the levels of the
"numbers", the numbers inside the table are the probabilities of the
"number" occuring.
A B C D...
0 0.20.30.1
On Wed, 2010-01-13 at 15:59 +0100, Alex Roy wrote:
> Dear R users,
> I am running a R code which gives me 10 columns and
> 160 rows. I need to run the code for 100 times and each time I need to store
> the results in a single file.
> I do not know how can I store them in a s
try this:
with(Data, tapply(Age, Sex, mean))
I hope it helps.
Best,
Dimitris
John Sorkin wrote:
R 2.9
Windows XP
I have a matrix, Data, which contains a factor Sex and a continuous variable
Age.
I want to get mean age by sex. I know I can do this with two statements,
mean(Data["Age,Data[,
with(yourdataframe, tapply(age,sex,mean))
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of John Sorkin
Sent: Wednesday, January 13, 2010 12:11 PM
To: r-help@r-project.org
Subject: [R] Applying function to parts of a matrix based on a
R 2.9
Windows XP
I have a matrix, Data, which contains a factor Sex and a continuous variable
Age.
I want to get mean age by sex. I know I can do this with two statements,
mean(Data["Age,Data[,"Sex"]=="Male") and
mean(Data["Age,Data[,"Sex"]=="Female")
I know this can be done in a single comman
Hello,
I find a way to convert data in factor type to numeric :
data_numeric <- as.numeric(as.character(data_factor)).
It's treaky but works.
Peter Ehlers a écrit :
S Devriese wrote:
On 01/13/2010 10:47 AM, Ahmet Temiz wrote:
hello
could you give me a hint to convert data in factor type to
Hello
I am currently investing software code metrics for a variety of software
projects of a company to determine the worst parts of software products
according to specified quality characteristics.
As the gathering of metrics correlates with effort, I would like to find a
subset of the metrics
Hello,
I am learning randomForest, now I want to boxplot mse and mtry using 20
5-fold cross-validation(using median value), but I have no a good method to
do it, except a not good method.
randomforest package itself did not contain cross-validating method, and
caret package contain cross vali
Hello List,
I have a data frame object (wa2) that I am exporting for use in
another statistics package. Using
library(foreign)
write.foreign(wa2, choose.files(), choose.files(), package='SPSS')
I noticed that there were several differences between the data sets as
seen within R (View(wa2)) and w
S Devriese wrote:
On 01/13/2010 10:47 AM, Ahmet Temiz wrote:
hello
could you give me a hint to convert data in factor type to numeric (float) ?
regards
--
Open WebMail Project (http://openwebmail.org)
you could try as.numeric but without more details it is difficult to see
if this will
Hi there,
My question relates to getting information about R packages. In particular i
would like to be able to find from within R:
what are a packages dependencies
what are a packages reverse dependencies
does a package contain a dll
The reason i ask is:
The organisation that i work
Collect the results in a list (one entry for each matrix) and then 'save'
the list. When you 'load' it back in, you can easily reference each element
for further processing.
On Wed, Jan 13, 2010 at 9:59 AM, Alex Roy wrote:
> Dear R users,
>I am running a R code which giv
You could put all of your results into a single list, then just save the list.
Or, functions like write.table and write have an append argument, set that to
true and the information will be appended to the file rather than overwriting
it.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Actually, the data that I used are measurements of plant growth during
an entire year.It is usual to model the growth with logistic models.
I have already tried the simple logistic model (which works). But the
problem is that with this model the inflexion point occurs half-way up
or down the logis
On 1/12/2010 8:29 PM, Yi Du wrote:
Hi,
Is that okay to let R to read data set more than 1 rows and
use it to do some kernel density estimation? Thanks.
Yi
Why don't you just try it and see? Nothing bad will happen - the
absolute worst case scenario is that R will hang.
But I can tell y
On 13/01/2010 10:45 AM, Don MacQueen wrote:
I would suggest that first you look at the results of
(as.numeric(as.character(dfpr2_r$pr2))) > 0.2 && (dfpr2_r$landa > 10)
by itself. Does it give all FALSE ?
I'd guess the problem is using && instead of &.
Duncan Murdoch
Then look at eac
I would suggest that first you look at the results of
(as.numeric(as.character(dfpr2_r$pr2))) > 0.2 && (dfpr2_r$landa > 10)
by itself. Does it give all FALSE ?
Then look at each of the parts separately. What are the results of
(as.numeric(as.character(dfpr2_r$pr2))) > 0.2
and
dfpr2_r$l
> My question is how could I estimate those initial values so that the nls
> fitting works.
>
You can't. Your parameters are almost certainly nonidentifiable (which is
what Gabor told you more gracefully).
Just because you believe in a complex (often mechanistic) nonlinear model
and have some data
A few packages have support for basic download from Yahoo Finance. If that's
what you are trying to achieve - you may want to try quantmod (getSymbols
function) or tseries (get.hist.quote function). If you want to do something not
supported yet - first take a look at their source code.
Regards
Yupp, FAQ 7.31 is definitely your friend here.
You might also want to take a look at these two very recent threads on
this help list:
"Strange behaviour of as.integer()"
http://tolstoy.newcastle.edu.au/R/e9/help/10/01/index.html#547
"Newbie question on precision"
http://tolstoy.newcastle.edu.
hello
is it wrong with this expression:
subset(dfpr2_r,(as.numeric(as.character(dfpr2_r$pr2))) > 0.2 && (dfpr2_r$landa
> 10))
it gives nothing
regards
--
Open WebMail Project (http://openwebmail.org)
--
This message has been scanned for viruses and
dangerous content by MailScanner, and is
You could try the brute force of nls2 package; however, note that you
have 8 parameters and only 16 points so you might look for a more
parsimonious model. Plotting it it seems somewhat gaussian in shape
so:
mod <- nls(y ~ a * dnorm(x, b, c), start = c(a = mean(y)/dnorm(0, 0,
sd(x)), b = mean(x),
Dear R users,
I am running a R code which gives me 10 columns and
160 rows. I need to run the code for 100 times and each time I need to store
the results in a single file.
I do not know how can I store them in a single file without over writting
the results?
Thanks
Alex
I have been having the same problem as poster Hodgess, below. It appears
that her question was never answered, so I would like to share a solution
with the community.
The problem is the (apparent?) inability to produce moving range process
behavior (a.k.a. "control") charts with individuals data i
Hi,
I'm trying to make a regression of the form :
formula <- y ~ Asym_inf + Asym_sup * ( (1 / (1 + (n1 * (exp( (tmid1-x)
/ scal1) )^(1/n1) ) ) ) - (1 / (1 + (n2 * (exp( (tmid2-x) / scal2)
)^(1/n2) ) ) ) )
which is a sum of the generalized logistic model proposed by richards.
with data such
To R-helpers,
Running
R version 2.10.0 (2009-10-26)
Linux ... 2.6.25.20-0.5-default #1 SMP 2009-08-14 01:48:11 +0200 x86_64
x86_64 x86_64 GNU/Linux
openSUSE 11.0 (X86-64)
and having difficulties reading a fifo from within R.
A short example that I find simply haning is shown as 'SHORT SCR
On 13/01/2010 8:09 AM, e-letter wrote:
On 13/01/2010, Duncan Murdoch wrote:
> On 13/01/2010 7:36 AM, e-letter wrote:
>> Readers,
>>
>> For a data set 'x':
>>
>> 1 a
>> 2 b
>> 3 c
>> 4 d
>> 5 e
>> 6 f
>> 7 g
>> 8 h
>> 9 i
>>
>> How to select multiple subscripts to plot? For example to plot values
--- Begin Message ---
--- End Message ---
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reprod
Dear UseRs,
I did not have any answer to my previous message ("Is there a way to define
"manually" columns width when using write.dbf function from the library
foreign ?"), so I tried to modify write.dbf function to do what I want.
Here is my modified version :
write.dbfMODIF <- function (datafr
On 13/01/2010, e-letter wrote:
> On 13/01/2010, Duncan Murdoch wrote:
>> On 13/01/2010 7:36 AM, e-letter wrote:
>>> Readers,
>>>
>>> For a data set 'x':
>>>
>>> 1 a
>>> 2 b
>>> 3 c
>>> 4 d
>>> 5 e
>>> 6 f
>>> 7 g
>>> 8 h
>>> 9 i
>>>
>>> How to select multiple subscripts to plot? For example to pl
On 13/01/2010, Duncan Murdoch wrote:
> On 13/01/2010 7:36 AM, e-letter wrote:
>> Readers,
>>
>> For a data set 'x':
>>
>> 1 a
>> 2 b
>> 3 c
>> 4 d
>> 5 e
>> 6 f
>> 7 g
>> 8 h
>> 9 i
>>
>> How to select multiple subscripts to plot? For example to plot values
>> 1:3 and 9:10:
>>
>> plot(x[1:3,1],x[,
Hi,
Can R do FMOLS(Fully Modified OLS) and DOLS(Dynamic OLS)?
I cannot find any useful thing in the present package.
Thanks in advance!
--
View this message in context:
http://n4.nabble.com/How-to-do-FMOLS-and-DOLS-tp1012976p1012976.html
Sent from the R help mailing list archive at Nabble.com
On 13/01/2010 7:36 AM, e-letter wrote:
Readers,
For a data set 'x':
1 a
2 b
3 c
4 d
5 e
6 f
7 g
8 h
9 i
How to select multiple subscripts to plot? For example to plot values
1:3 and 9:10:
plot(x[1:3,1],x[,2])
and
plot(x[9:10,1],x[,2])
into one plot?
Neither of those will work, because yo
Hi
see ?points or ?lines which you would surely found out if you bother to
look at ?plot help page
Regards
Petr
r-help-boun...@r-project.org napsal dne 13.01.2010 13:36:57:
> Readers,
>
> For a data set 'x':
>
> 1 a
> 2 b
> 3 c
> 4 d
> 5 e
> 6 f
> 7 g
> 8 h
> 9 i
>
> How to select multiple
Hi,
Thanks a lot for your suggestions and the very detailed instructions, I needed
them...
Everything worked fine also in the full dataset, up until the last suggestion
(the box plots)
Here I also got an error message, but a different one from what you got. And no
output...
Here are the last
Readers,
For a data set 'x':
1 a
2 b
3 c
4 d
5 e
6 f
7 g
8 h
9 i
How to select multiple subscripts to plot? For example to plot values
1:3 and 9:10:
plot(x[1:3,1],x[,2])
and
plot(x[9:10,1],x[,2])
into one plot?
Yours,
rhelpatconference.jabber.org
r251
_
1 - 100 of 112 matches
Mail list logo
