On Mon, 16 Nov 2009 19:54:08 -0800 (PST) ychu066 wrote:
> here is the codes that i tried.
>
> > png(paste("hist",i,".png",sep="")
> + library(lattice)
> Error: unexpected symbol in:
> "png(paste("hist",i,".png",sep="")
> library"
There is a missing ')' at the end of the first line.
If you
On Mon, 16 Nov 2009 10:43:38 -0500 Andrew Miles
wrote:
> Thanks! Using the plyr package and the approach you outlined seems to
> work well for relatively simple functions (like wtd.mean), but so far
> I haven't had much success in using it with more complex descriptive
> functions like des
I don't think this function is same as gcc's option -MM. Because gcc
checks pre-compile command #include, in which the filename can be
fetched definitely. But in your scenario, the filename may be from
some variables, which can not be determined by the R script only.
Maybe you can write a tool by y
Dear All,
How to do Hodrick-Prescott Filter in R?
Thanks!
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PLEASE do read the posting guide http://www.R-project.org/posting-gui
Dear All,
How to do band-pass filters,low-pass filters,high-pass filters in R?
Thanks!
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PLEASE do read the posting guide ht
here is the codes that i tried.
> png(paste("hist",i,".png",sep="")
+ library(lattice)
Error: unexpected symbol in:
"png(paste("hist",i,".png",sep="")
library"
> for(i in 8:153){
+ histogram(~ data[,i] | data[,2],
data=data,ylab="Frequency",xlim=c(1,5),xlab="Score",ylim=c(0,100)))
Error: u
I have the following codes but can anyone make it shorter i.e making these
FOR loop into one loop ...
thanks...
par(mfrow=c(2,4))
for(i in 16:23){
hist(data[,i],main=paste(colnames(data)[i],sep=""),ylab="Frequency",xlim=c(1,5),xlab="Score",ylim=c(0,100))
}
png("histogram.png
still doesnt work ...
Karl Ove Hufthammer wrote:
>
> On Thu, 12 Nov 2009 19:10:52 -0800 (PST) ychu066 @aucklanduni.ac.nz> wrote:
>> And I also want to save each histogram in each separate pdf file using
>> the
>> following codes ?.
>> png("hist.png[i]")
>> dev.off()
>
> Try png(paste("hist",i
Hi,
how can I parse Google search results? The following code returns
"integer(0)" instead of "1" although the results of the query clearly
contain the regex "cran".
address <- url("http://www.google.com/search?q=cran";)
open(address)
lines <- readLines(address)
grep("cran", lines[3])
##
I want to do a non homogeneous poisson process model in R.
Any advice, or know of places where i can get some, ive googled it but
nothing came up relating to R.
--
View this message in context:
http://old.nabble.com/non-homogeneous-poisson-process-tp26378037p26378037.html
Sent from the R help
JOIN YOUR COLLEAGUES FOR THE 20TH HIGHLY ACCLAIMED
INTERNATIONAL FORUM TO HEAR THE LATEST IMPLEMENTATIONS OF
BIOMETRICS...
THE WINTER 2010 BIOMETRICS SUMMIT:
Practical Implementation Strategies, Market Trends
And Best Practices In Government And Business
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Thanks to all who helped. These are all great suggestions.
Jeff
-Original Message-
From: Gabor Grothendieck [mailto:ggrothendi...@gmail.com]
Sent: Monday, November 16, 2009 6:27 PM
To: Hao Cen
Cc: r-help@r-project.org
Subject: Re: [R] extracting the last row of each group in a data fram
On Sun, Nov 15, 2009 at 8:45 PM, Peng Yu wrote:
> gcc has options like -MM, which can generate the dependence files for
> a C/C++ file that I can be used by gnu make. I'm wondering if there is
> a tool that can generate dependence file for an R script.
>
> For example, I have an R script test.R
>
i have used excel almost exclusively to import data files and CSV is fine.
why dont you just go to the bottom of the excel sheet after you convert to
CSV and clean out the last rows, delete the end rows. also maybe try another
spread sheet program like open office, openoffice.org.
cls59 wrote:
>
Gabor Grothendieck wrote:
>
> That doesn't necessarily follow since the various methods don't use
> Excel itself to create the csv file.
>
I was trying to point out cases where I have seen this behavior and R wasn't
involved. Now that I think about it, I have observed to blank cells in a
Goo
> -Original Message-
> From: Gabor Grothendieck [mailto:ggrothendi...@gmail.com]
> Sent: Monday, November 16, 2009 4:52 PM
> To: Duncan Murdoch
> Cc: Steven McKinney; R Help
> Subject: Re: [R] Where are usages like "== 2L" documented?
>
> On Mon, Nov 16, 2009 at 7:25 PM, Duncan Murdoch
>
I don't know how to do this in the way you describe.
Easy alternatives include:
- putting the part of the script that is to be executed
conditionally into a separate file, and then source it or not based
on some condition.
- simply wrapping the different parts of the script in if, then, el
As the OP, I will say that I had deduced that it probably was a way of
specifying type integer, so I went to the ?integer page hoping for further
info. I agree there should be some kind of short comment or see also at
that page. I've been a self-taught user of R for about a year and a half,
and t
On Mon, Nov 16, 2009 at 7:25 PM, Duncan Murdoch wrote:
> On 16/11/2009 6:47 PM, Steven McKinney wrote:
>>
>> ?NumericConstants
>>
>> will bring up a help page that mentions
>> "All other numeric constants start with a digit or period and are either a
>> decimal or hexadecimal constant optionally f
On 16/11/2009 6:47 PM, Steven McKinney wrote:
?NumericConstants
will bring up a help page that mentions
"All other numeric constants start with a digit or period and are either a decimal
or hexadecimal constant optionally followed by L."
and
"An numeric constant immediately followed by L
I was missing something. Thx Dennis.
-- Forwarded message --
From: Dennis Murphy
Date: Tue, Nov 17, 2009 at 12:34 AM
Subject: Re: dendrogram
To: jorism...@gmail.com
Hi,
There are a couple of things you could do to pull the text back into
the dendrogram plot,
both of which I fo
R users doing data analysis may be interested in the following paper:
http://methodsblog.wordpress.com/2009/11/13/first-paper-now-online/?utm_source=feedburner&utm_medium=feed&utm_campaign=Feed%3A+wordpress%2Fmethodsblog+(methods.blog)
All data and R code is available.
Alain
-
---
?NumericConstants
will bring up a help page that mentions
"All other numeric constants start with a digit or period and are either a
decimal or hexadecimal constant optionally followed by L."
and
"An numeric constant immediately followed by L is regarded as an integer number
when possible
Hello,
I am using the lmomco package (lmom.ub and pargev) to compute the GEV
parameters (location, scale, and shape), which are used to estimate
return values. I was wondering how/if I can calculate upper and lower
confidence (CI_u, CI_l) intervals for each return frequency using the
GEV par
That doesn't necessarily follow since the various methods don't use
Excel itself to create the csv file.
On Mon, Nov 16, 2009 at 1:22 PM, cls59 wrote:
>
>
> Gabor Grothendieck wrote:
>>
>> You could try one of the other methods of reading Excel files and see
>> if they are affected:
>>
>
> I woul
Bryan Hanson wrote:
Gurus:
I keep seeing other people¹s code that contain ideas like
If (x == 2L)
X[-1L]
X - 1L
I have some idea of what¹s going on, but where is the use of concepts like
³2L² documented?
In the R Language Definition manual. In this case, look in section
3.1.1, "Constant
On Nov 16, 2009, at 6:22 PM, Bryan Hanson wrote:
Gurus:
I keep seeing other people’s code that contain ideas like
If (x == 2L)
X[-1L]
X - 1L
I have some idea of what’s going on, but where is the use of
concepts like
“2L” documented?
Not sure where exactly, and it would depend on where y
Try this:
> aggregate(DF[-1], DF[1], tail, 1)
Name Value
1A 3
2B 8
3C 2
4D 3
On Mon, Nov 16, 2009 at 2:42 PM, Hao Cen wrote:
> Hi,
>
> I would like to extract the last row of each group in a data frame.
>
> The data frame is as follows
>
> Name Value
> A 1
> A
Gurus:
I keep seeing other people¹s code that contain ideas like
If (x == 2L)
X[-1L]
X - 1L
I have some idea of what¹s going on, but where is the use of concepts like
³2L² documented?
Thanks, Bryan
*
Bryan Hanson
Acting Chair
Professor of Chemistry & Biochemistry
DePauw University,
The actual code for the lda example is below. If anyone can reproduce the
error,
let me know. Thanks.
library(MASS)
Iris <- data.frame(rbind(iris3[,,1], iris3[,,2], iris3[,,3]),
Sp = rep(c("s","c","v"), rep(50,3)))
train <- sample(1:150, 75)
table(Iris$Sp[train])
z <- lda(Sp
Hi All,
I was hoping someone could save me the trouble of reading through source code
and answer a quick question of mine regarding poly(). Does the poly() function
use a classical orthogonal polynomial series to fit polynomial models, or does
poly() generate a unique series of orthogonal poly
If t1-t5 are all correlated with the outcome and with each other, than which
are significant will depend on variations in the data (it is possible to have a
set of values t1-t5 that predict the outcome well, but which all have
nonsignificant p-values when taking the others into account). Allowi
I don't think that the p-value concept is as well defined for multivariate
distributions. Do you want the area under the curve corresponding to (x < t.x
& y < t.y) or (x < t.x | y < t.y) or ( t.x + t.y < C ) or all the area where
the height of the density is less than at t.x,t.y? or possibly o
You should be able to do this effectively in 1 line:
> my.data <- lapply( paste( 'data', 1:N, '.dat', sep='' ), read.table )
Then everything is in my.data, if you want them named then do a second line:
> names(my.data) <- paste( 'data', 1:N, '.dat', sep='' )
Doing the same analysis on each data
Try this:
x <- rexp(100, 1/3)
xp <- scale(x)
cor.mat <- rbind( c(1, 0.8, 0.7), c(0.8, 1, 0.3), c(0.7, 0.3, 1) )
x23 <- matrix( rnorm( 100 * 2, 1/3 ), ncol=2 )
x23 <- cbind(xp, scale(x23))
x23 <- x23 %*% solve(chol(var(x23))) ## skip if you don't want exact cor's
x.new <- x23 %*% chol(cor.ma
On Nov 16, 2009, at 2:39 PM, helpme wrote:
I am receiving an error when trying to connect to the Oracle
Database using
RODBC on a 64-bit Windows Server OS. The version of R is 2.10.0-
win32.exe
Is this the wrong version. Does RODBC only work with 32-bit ODBC
drivers?
've read over all th
Hi,
I am using a script to initialize variables in the global workspace.
Based on some condition, I would like to stop evaluation of a script
sourced on the command-line, without issuing an error.
My current solution is the following hack that uses a repeat { }
statement
--- init.R
Thanks David.
My code is ok if I did not wrap it up. The problem poped up after i make it
as a function.
In my step() call, i just make it a little bit more general.
I do not like stepwise method too, but need it as a comparison.
samer
On Mon, Nov 16, 2009 at 3:03 PM, David Winsemius wrote:
I am receiving an error when trying to connect to the Oracle Database using
RODBC on a 64-bit Windows Server OS. The version of R is 2.10.0-win32.exe
Is this the wrong version. Does RODBC only work with 32-bit ODBC drivers?
've read over all the posts and documentation manuals.
The system is Wind
On 16 November 2009 at 11:42, Blair Christian wrote:
| I have k identical parallel pieces of code running, each using n.rand
| random numbers. I would like to use the same RNG (for now), and set
| the seeds so that I can guarantee that there are no overlaps in the
| random numbers sampled by the
Tobias
The grangertest function in the lmtest package might be simpler for your
application.
Regards
Schalk Heunis
On Mon, Nov 16, 2009 at 5:31 PM, tobiasfa wrote:
>
> Hi useRs..
>
> I cant figure out how to test for causality using causality() in vars
> package
>
> I have two datasets (A, B)
On Nov 16, 2009, at 3:13 PM, David Winsemius wrote:
On Nov 16, 2009, at 3:06 PM, smu wrote:
hello,
sep="\n" will seperate each column by \n which is not what you want.
I think a csv would be the best solution.
write.table(yourdataframe,sep=",")
Excel will also read (and even prefers in
I would use pkg:plyr, but just to show how
versatile R is:
ind <- cumsum(rle(as.numeric(dat$Name))$lengths)
dat[ind, ]
where I'm assuming that your data frame is
called 'dat'.
-Peter Ehlers
Hao Cen wrote:
Hi,
I would like to extract the last row of each group in a data frame.
The data fram
On 16-Nov-09 19:22:10, Jack Luo wrote:
> Hi,
> I am trying to fit a logistic regression using glm, but my
> explanatory variables are of mixed type: some are numeric,
> some are ordinal, some are categorical, say
>
> If x1 is numeric, x2 is ordinal, x3 is categorical, is the
> following formula OK
anna_l wrote:
Hello, I am having trouble by using the write.table function to write a data
frame of 4 columns and 7530 rows. I don´t know if I should just use a
sep="\n" and change the .xls file into a .csv file. Thanks in advance
-
Anna Lippel
new in R so be careful I should be asking a l
On Nov 16, 2009, at 3:06 PM, smu wrote:
hello,
sep="\n" will seperate each column by \n which is not what you want.
I think a csv would be the best solution.
write.table(yourdataframe,sep=",")
Excel will also read (and even prefers in some sense) tab delimited
files, so:
write.table(yo
On Nov 16, 2009, at 2:53 PM, Jack Luo wrote:
> David,
>
> Thanks for your reply. Since I am kinda new to this forum, could you
> please advise me on where to read those questions in R-help?
http://search.r-project.org/nmz.html
http://search.r-project.org/cgi-bin/namazu.cgi?query=%22ordered+fa
hello,
sep="\n" will seperate each column by \n which is not what you want.
I think a csv would be the best solution.
write.table(yourdataframe,sep=",")
or use write.csv directly.
regards,
stefan
On Mon, Nov 16, 2009 at 11:49:28AM -0800, anna_l wrote:
>
> Hello, I am having trouble by using
anna_l wrote:
>
> Hello, I am having trouble by using the write.table function to write a
> data frame of 4 columns and 7530 rows. I don´t know if I should just use
> a sep="\n" and change the .xls file into a .csv file. Thanks in advance
>
Base R cannot write .xls files by it's self. You s
On Nov 16, 2009, at 2:31 PM, shuai yuan wrote:
Hi, there,
My appologize if someone ask the same question before. I searched the
mailing list and found one similar post, but not what i want.
The problem for me is, I use the step( glm()) to do naive forward
selection for logistic regression
jeffc wrote:
>
> Hi,
>
> I would like to extract the last row of each group in a data frame.
>
> The data frame is as follows
>
> Name Value
> A 1
> A 2
> A 3
> B 4
> B 8
> C 2
> D 3
>
> I would like to get a data frame as
> Name Value
> A 3
> B 8
> C 2
> D 3
>
> Thank you for your suggesti
Dear Jeff,
Here is a suggestion using tapply:
data.frame(last = with(x, tapply(Value, Name, function(x) x[length(x)])))
See ?tapply for more information.
HTH,
Jorge
On Mon, Nov 16, 2009 at 2:42 PM, Hao Cen <> wrote:
> Hi,
>
> I would like to extract the last row of each group in a data frame
On Nov 16, 2009, at 2:42 PM, Hao Cen wrote:
Hi,
I would like to extract the last row of each group in a data frame.
The data frame is as follows
Name Value
A 1
A 2
A 3
B 4
B 8
C 2
D 3
by(dfname$Value, dfname$Name, tail, 1) #which gets you a list
Or:
aggregate(dfname$Value, list(dfname$N
Thank you. I will check that.
Cindy
On Mon, Nov 16, 2009 at 1:45 PM, cls59 wrote:
>
>
> David Winsemius wrote:
> >
> > ?order
> >
>
> cindy Guo wrote:
> >
> > Do you mean if the numbers in each row are ordered? They are not, but if
> > it's needed, we can order them. The matrix only has 5000 row
David,
Thanks for your reply. Since I am kinda new to this forum, could you please
advise me on where to read those questions in R-help? In addition, I did not
pay much attention to the na.action, probably I should use na.action =
na.omit instead of na.pass.
-Jack
On Mon, Nov 16, 2009 at 2:32 PM
Hi,
You could try plyr,
library(plyr)
ddply(d,.(Name), tail,1)
Name Value
1A 3
2B 8
3C 2
4D 3
HTH,
baptiste
2009/11/16 Hao Cen :
> Hi,
>
> I would like to extract the last row of each group in a data frame.
>
> The data frame is as follows
>
> Name Value
> A
Hello, I am having trouble by using the write.table function to write a data
frame of 4 columns and 7530 rows. I don´t know if I should just use a
sep="\n" and change the .xls file into a .csv file. Thanks in advance
-
Anna Lippel
new in R so be careful I should be asking a lt of que
On Nov 16, 2009, at 2:41 PM, cindy Guo wrote:
> Do you mean if the numbers in each row are ordered? They are not,
> but if it's needed, we can order them. The matrix only has 5000 rows.
>
No, I mean type ?order at the R command line and read the help page.
> On Mon, Nov 16, 2009 at 1:34 PM, D
David Winsemius wrote:
>
> ?order
>
cindy Guo wrote:
>
> Do you mean if the numbers in each row are ordered? They are not, but if
> it's needed, we can order them. The matrix only has 5000 rows.
>
No, he's suggesting you check out the order() function by calling it's help
page:
?order
o
Hi,
I would like to extract the last row of each group in a data frame.
The data frame is as follows
Name Value
A 1
A 2
A 3
B 4
B 8
C 2
D 3
I would like to get a data frame as
Name Value
A 3
B 8
C 2
D 3
Thank you for your suggestions in advance
Jeff
__
Do you mean if the numbers in each row are ordered? They are not, but if
it's needed, we can order them. The matrix only has 5000 rows.
On Mon, Nov 16, 2009 at 1:34 PM, David Winsemius wrote:
>
> On Nov 16, 2009, at 2:32 PM, cindy Guo wrote:
>
> I forgot to say that there are no ties in each ro
Gunadi wrote:
>
> I am sure this is easy but I am not finding a function to do this.
>
> I have two columns in a matrix. The first column contains multiple entries
> of numbers from 1 to 100 (i.e. 10 ones, 8 twos etc.). The second column
> contains unique numbers. I want to sum the numbers in
On Nov 16, 2009, at 2:32 PM, cindy Guo wrote:
> I forgot to say that there are no ties in each row. So any number
> can occur only once in each row. Also as I mentioned earlier,
> actually I only need the top 50 most frequent pairs, is there a more
> efficient way to do it? Because I have 1
On 11/16/2009 1:54 PM, William Dunlap wrote:
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Doran, Harold
Sent: Monday, November 16, 2009 10:45 AM
To: r-help@r-project.org
Subject: [R] No Visible Binding for global variable
Whil
I forgot to say that there are no ties in each row. So any number can occur
only once in each row. Also as I mentioned earlier, actually I only need the
top 50 most frequent pairs, is there a more efficient way to do it? Because
I have 15000 numbers, output of all the pairs would be too long.
Than
On Nov 16, 2009, at 2:22 PM, Jack Luo wrote:
Hi,
I am trying to fit a logistic regression using glm, but my explanatory
variables are of mixed type: some are numeric, some are ordinal,
some are
categorical, say
If x1 is numeric, x2 is ordinal, x3 is categorical, is the following
formula
Hi, there,
My appologize if someone ask the same question before. I searched the
mailing list and found one similar post, but not what i want.
The problem for me is, I use the step( glm()) to do naive forward
selection for logistic regression. My code is functional
in the open environment. B
Hi,
I am trying to fit a logistic regression using glm, but my explanatory
variables are of mixed type: some are numeric, some are ordinal, some are
categorical, say
If x1 is numeric, x2 is ordinal, x3 is categorical, is the following formula
OK?
*model <- glm(y~x1+x2+x3, family=binomial(link="l
I forgot to mention that it's running Windows Server 2003 x64 OS version
On Mon, Nov 16, 2009 at 11:22 AM, helpme wrote:
> I'm stumped. When trying to connect to Oracle using the RODBC package I get
> an error:
> *[RODBC] Data source name not found and no default driver specified.
> ODBC connect
?order
?sort
2009/11/16 frenchcr :
>
>
>
> In excel a handy tool is the sort data by column ...i.e. i can highlight the
> whole dataset and sort it according to a particular column...like sort the
> data in a column in acending or decending order where all the other columns
> change aswell.
>
> I
In excel a handy tool is the sort data by column ...i.e. i can highlight the
whole dataset and sort it according to a particular column...like sort the
data in a column in acending or decending order where all the other columns
change aswell.
I need to do this in R now but dont know how.
...he
Try this:
with(DF, rowsum(Col2, Col1))
On Mon, Nov 16, 2009 at 3:49 PM, Gunadi wrote:
>
> I am sure this is easy but I am not finding a function to do this.
>
> I have two columns in a matrix. The first column contains multiple entries
> of numbers from 1 to 100 (i.e. 10 ones, 8 twos etc.). The
The VarCorr function will extract the components of the random effects
covariance matrix, but note the quirk that it returns values as
characters:
library(nlme)
f1 <- lme(distance ~ age, data = Orthodont, random = ~1 + age|Subject)
(vc <- VarCorr(f1))
# Subject = pdLogChol(1 + age)
# V
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Doran, Harold
> Sent: Monday, November 16, 2009 10:45 AM
> To: r-help@r-project.org
> Subject: [R] No Visible Binding for global variable
>
> While building a package, I see the
On Nov 16, 2009, at 1:38 PM, baptiste auguie wrote:
Hi,
Try this,
set.seed(2) # reproducible
d = matrix(sample(1:20,20), 4, 5)
d
d[ d[ ,2] == 18 , ]
You may need to test with all.equal if your values are subject to
rounding errors.
HTH,
baptiste
2009/11/16 frenchcr :
I have 20 columns
While building a package, I see the following:
* checking R code for possible problems ... NOTE
cheat.fit: no visible binding for global variable 'Zobs'
plot.jml: no visible binding for global variable 'Var1'
I see the issue has come up before, but I'm having a hard time discerning how
solutions
Hi,
Try this,
set.seed(2) # reproducible
d = matrix(sample(1:20,20), 4, 5)
d
d[ d[ ,2] == 18 , ]
You may need to test with all.equal if your values are subject to
rounding errors.
HTH,
baptiste
2009/11/16 frenchcr :
>
>
> I have 20 columns of data, and in column 5 I have a value of 17600 but
P=data.frame(x=c(1,1,2,3,2,1),y=rnorm(6))
tapply(P$y,P$x,sum)
regards,
stefan
On Mon, Nov 16, 2009 at 09:49:17AM -0800, Gunadi wrote:
>
> I am sure this is easy but I am not finding a function to do this.
>
> I have two columns in a matrix. The first column contains multiple entries
> of n
Hi,
An alternative with ggplot2,
library(ggplot2)
ggplot(data=coords) +
geom_segment(aes(x=a, xend=b, y=c, yend=c))
HTH,
baptiste
2009/11/16 David Winsemius :
>
> On Nov 16, 2009, at 12:40 PM, Tim Smith wrote:
>
>> Hi,
>> I wanted to make a graph with the following table (2 rows, 3 columns
I have 20 columns of data, and in column 5 I have a value of 17600 but I
dont know which row this value is in (i have over 300,000 rows).
I'm trying to do 2 things:
1) I want to find out which row in column 5 has this number in it.
2) Then I want to print out that row with all the column heade
I am sure this is easy but I am not finding a function to do this.
I have two columns in a matrix. The first column contains multiple entries
of numbers from 1 to 100 (i.e. 10 ones, 8 twos etc.). The second column
contains unique numbers. I want to sum the numbers in column two based on
the inde
Gabor Grothendieck wrote:
>
> You could try one of the other methods of reading Excel files and see
> if they are affected:
>
I would guess that since Excel includes the blank rows when exporting to
CSV, then blank cells are being stored by Excel in the data files--
therefore any method of ext
You could try one of the other methods of reading Excel files and see
if they are affected:
http://wiki.r-project.org/rwiki/doku.php?id=tips:data-io:ms_windows
On Mon, Nov 16, 2009 at 8:19 AM, anna_l wrote:
>
> Hello everybody, here is the code I use to read an excel file containing two
> rows,
On Nov 16, 2009, at 12:58 PM, David Winsemius wrote:
On Nov 16, 2009, at 12:40 PM, Tim Smith wrote:
Hi,
I wanted to make a graph with the following table (2 rows, 3
columns):
a b c
x 1 3 5
y 5 8 6
The first column represents the start cordinate, and the second
column contains the end cor
Thanks Charlie, well yes it included one row with two NA datas. I guess there
is an explanation, let´s wait and see if someone knows more about it :)
cls59 wrote:
>
>
> anna_l wrote:
>>
>> Hello everybody, here is the code I use to read an excel file containing
>> two rows, one of date, the o
anna_l wrote:
>
> Hello everybody, here is the code I use to read an excel file containing
> two rows, one of date, the other of prices:
> library(RODBC)
> z <- odbcConnectExcel("SPX_HistoricalData.xls")
> datas <- sqlFetch(z,"Sheet1")
> close(z)
> It works pretty well but the
On Nov 16, 2009, at 12:40 PM, Tim Smith wrote:
Hi,
I wanted to make a graph with the following table (2 rows, 3 columns):
a b c
x 1 3 5
y 5 8 6
The first column represents the start cordinate, and the second
column contains the end cordinate for the x-axis. The third column
contains the y-a
Hi Tim,
On Nov 16, 2009, at 12:40 PM, Tim Smith wrote:
Hi,
I wanted to make a graph with the following table (2 rows, 3 columns):
a b c
x 1 3 5
y 5 8 6
The first column represents the start cordinate, and the second
column contains the end cordinate for the x-axis. The third column
contains
Hi,
I wanted to make a graph with the following table (2 rows, 3 columns):
a b c
x 1 3 5
y 5 8 6
The first column represents the start cordinate, and the second column contains
the end cordinate for the x-axis. The third column contains the y-axis
co-ordinate. For example, the first row in the m
On Mon, 16 Nov 2009, Blair Christian wrote:
Hi All,
I have k identical parallel pieces of code running, each using n.rand
random numbers. I would like to use the same RNG (for now), and set
the seeds so that I can guarantee that there are no overlaps in the
random numbers sampled by the k pie
Can you think of any systemic changes that might interefere with R
besides Symantec EndPoint and LiveUpdate? I have removed those
programs and allocated more memory to R, but it is still way too
slow.
On Nov 13, 10:45 pm, J Dougherty wrote:
> On Friday 13 November 2009 07:17:28 am Jgabriel wrote:
I have been trying to write a function for the following problem:
Suppose I have three vectors a,b,c of different lengths:
e.g. a=c(a1,a2,a3,...) where a[i] form the basis of our function variables:
if we define a table for example:
and define the fn(x) <-function{..
Hi useRs..
I cant figure out how to test for causality using causality() in vars
package
I have two datasets (A, B) and i want to test if A (Granger)cause B.
How do I write the script? I dont understand ?causality. How do I get x to
"contain" A and B. Further using the command VAR() to specify x
I have been trying to write a function for the following problem:
Suppose I have three vectors a,b,c of different lengths:
e.g. a=c(a1,a2,a3,...) where a[i] form the basis of our function variables:
if we define a table for example:
and define the fn(x) <-function{..
Hi,
I am trying to plot two types of data on the same graph: points and
distributions. I am attempting to use the panel.groups function, but cannot
seem to get it to work. I have a melted data set and put in a FLAG column to
separate my data into the two groups that I would like to plot, point d
On Mon, 16 Nov 2009, Jopi Harri wrote:
I am doing cluster analysis [hclust(Dist, method="average")] on
data that potentially contains redundant objects. As expected,
the inclusion of redundant objects affects the clustering result,
i.e., the data a1, = a2, = a3, b, c, d, e1, = e2 is likely to
cl
Assuming that your data is in a dataframe 'cordata' , then following
should work:
cordata$cor2_value <- sapply(1:nrow(cordata), function(.row){
cor2[cordata$rowname[.row], cordata$colname[.row]]
}
On Mon, Nov 16, 2009 at 11:44 AM, Lee William wrote:
> Hi! All,
>
> I have 2 correlation matric
Hi! All,
I have 2 correlation matrices of 4000x4000 both with same row names and
column names say cor1 and cor2. I have extracted some information from 1st
matrix cor1 which is something like this:
rowname colname cor1_value
a b0.8
b a0.8
c
Hi All,
I have k identical parallel pieces of code running, each using n.rand
random numbers. I would like to use the same RNG (for now), and set
the seeds so that I can guarantee that there are no overlaps in the
random numbers sampled by the k pieces of code. Another side goal is
to have repro
sounds like bivariate density contours may be what you're looking for.
Andy
From: Eric Nord
>
> I'm attempting to produce something like a violin plot to
> display how y
> changes with x for members of different groups (My specific
> case is how
> floral area changes over time for several spe
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