Hello,
Consider MCMC sampling with metropolis / metropolis hastings proposals
and a density function with a given valid parameter space. How are MCMC
proposals performed if the parameter could be located at the very
extreme of the parameter space, or even 'beyond that' ? Example to
express i
Hi Hitesh,
while the rigth response not arrive, you can play with:
id<-1:10
x<-runif(10)
y<-runif(10)
plot(x,y)
identify(x, y , labels = id)
Try give a look on spatstat help. I am not quite sure, but may be there you
can find some solution (sorry if it is not true)
cheers
milton
On Wed, Aug 1
On Wed, 12-Aug-2009 at 12:38PM +0800, Leon Yee wrote:
> Hi, all
>
> I have a question of adjusting the output of a data frame with many
> columns. By default, print() will print out several columns according to
> the window size, and then it scrolls down and print out left columns.
> How
Hi Jill,
Completely not elegant, but may be usefull.
Of course other colleagues will solve this with 1 line command :-)
cheers
milton
df<-read.table(stdin(), head=T, sep=",")
V1,V2,V3,V4
DPA1*,DPA1*,DPB1*,DPB1*
0103,0104,0401,0601
0103,0103,0301,0402
df.new<-as.matrix(df)
for (i in 2:dim(df)[
On Tue, 11-Aug-2009 at 02:43PM -0500, Peng Yu wrote:
|> Hi,
|>
|> I frequently need to open multiple help pages in R, which requires the
|> start of multiple R sessions. I am wondering if there is a way to
|> invoke the help page from the command line just like 'man'.
If you use ESS (with Emacs)
Alternatively download the xlsReadWrite package from
http://treetron.googlepages.com/
install it an proceed as in older version of R.
--- On Tue, 11/8/09, Inchallah Yarab wrote:
> From: Inchallah Yarab
> Subject: [R] Re : How to Import Excel file into R 2.9.0 version
> To: r-help@r-project.o
Try
tempFun <- function(x) sum(!is.na(x))
nonZeros <- aggregate(pollution["pol"],format(pollution["date"],"%Y-%j"), FUN
= tempFun)
--- On Wed, 12/8/09, Tim Chatterton wrote:
> From: Tim Chatterton
> Subject: [R] Counting the number of non-NA values per day
> To: r-help@r-project.org
> Recei
Hi,
I'm training an SVM (C-classification from e1071 library)
Some of the variables in my data set are nominal. Is there some
easy/automatic way to convert them to numerical representations?
Thanks,
-N
__
R-help@r-project.org mailing list
https:/
Nancy (?),
see ?chisq.test (in particular the examples and the comment on "expected
frequency" there).
A rule of thumb (see any basic text book) for the chisquared
approximation being okay is that the expected value in each cell is at
least 5. The warning tells you that this does not hold true for
Hi,
this could be a simple question but I am looking into modifying a data frame
using a "condition" without the need to loop over that data, would that be
possible?
I have tried the following
x<-c(4,5,6,6,8)
y<-c("a","b","b","b","c")
data<-data.frame(x,y)
data
x y
1 4 a
2 5 b
3 6 b
4 6 b
Dear all,
How can I label/unlabel points on scatterplot with mouse pointer. As the
mouse approches near to point, it should label the closest point, then
unlabel when it moves away.
How can I do in R? I be very thankful.
Thanks and Regards,
Hitesh Singla
--
This message has been scanned for v
Hi All,
I did a google search and could not find the answer. Thus I post this
message. I found runmax only work for positive numbers.
x = rep(-1,10)
runmax(x,3)
x = rep(0, 10)
runmax(x,3)
for 32-bit R, i got very small numbers: 2.121996e-314
for 64-bit R, i got NaN.
Is it a bug in runm
Simple unlist() will not do. In case of repeated weights, unlike
permutations of indices permn(1:length(w)) some permutations of weights
are identical.
E.g. w <- c(3,2,2), permutations of indices c(1,2,3) and c(1,3,2) are
undistinguishable.
I think I have corrected the algorithm, but now I s
Hi All,
this could be a simple question but I am looking into modifying a data frame
using a "condition" without the need to loop over that data, would that be
possible?
I have tried the following
> x<-c(4,5,6,6,8)
> y<-c("a","b","b","b","c")
> data<-data.frame(x,y)
> data
x y
1 4 a
2 5 b
3
Hi, all
I have a question of adjusting the output of a data frame with many
columns. By default, print() will print out several columns according to
the window size, and then it scrolls down and print out left columns.
How can I make it print all the columns in the same line?
I found o
I have a long dataframe ("pollution") that contains a column of hourly
date information ("date") and a column of pollution measurements ("pol")
I have been happily calculating daily means and daily maximums using the
aggregate function
DMEANpollution = aggregate(pollution["pol"],
format(
Hi,
I am trying to edit a data frame such that the string in the first line is
appended onto the beginning of each element in the subsequent rows. The data
looks like this:
> df
V1 V2 V3 V4
1 DPA1* DPA1* DPB1* DPB1*
2 0103 0104 0401 0601
3 0103 0103 0301 0402
.
.
and what
Dear all,
I used fit.mult.impute in Dr. Harrell's Design package to fit a cox ph
regression model on five imputed datasets, where all missing predictors
were filled by multiple imputation using R package Mice. Are there any
functions able to do bootstrapping or cross-validation for the
aggregat
Hi,
I am trying to run a Chi squre test but I am getting the following message
Warning messages:
1: In chisq.test(t) : Chi-squared approximation may be incorrect
Does anyone what it means?
your help is appreciated
--
View this message in context:
http://www.nabble.com/Chi-squared-approxi
Hello,
I try estimate a MNL model but I need one coefficient as generic. How
can I get the same coefficient for all alternatives?
As example
Call:
multinom(formula = choice ~ time + costs, data = DATA)
Coefficients:
(Intercept)time costs
14.79-0.28
Hello,
Has anybody tried to use Generalized Path Seeking algorithm introduced by
Jerome H. Friedman and implemented using R? :
http://www-stat.stanford.edu/~jhf/r-gps/GPShelp.html
I have a problem using it and I hope that you could help me. I have tried to
run the GPS model for penalized logisti
It's a pretty inefficient way to do things (e.g. 5+ iterations [20
seconds] to find a good sample) but if you're not doing this often I
guess you could do something like:
checkNeighborEqual<-function(x){
#assuming the final value is not infinity
return(any(x==c(x[-1],Inf)))
}
#fake data
x<-
Hi,
I have an object in S4 class. Is there anyway that I can write to a
file and read it back to R? Thank you.
adschai
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-proje
Thanks. I can get it to work for facet_grid (which will do for my current
purposes) but am curious about whether there's a way to do the same
for facet_wrap (which doesn't have a "labeller" argument)?
cheers
Ben
hadley wrote:
>
> Have a look at the code and examples of label_value an
This will read it in all in and then you can decide
what you want to do with it:
Lines <- "DISKREAD,metadata about disks
MEM,metadata about memory
,observation-identifier,time,date
DISKREAD,observation-identifier,data about disks
MEM,observation-identifier,data about memory"
DF <- read.table(
Try this:
sum(sapply(l, '[[', 'b'))
On Tue, Aug 11, 2009 at 11:05 PM, R_help Help wrote:
> Hi,
>
> I have a list that contains about 100 elements. Each element contains
> the following matrix structure
>
> a b
> 1 1 4
> 2 2 5
> 3 3 6
>
> I'd like to sum column b across all elements. I'm thin
Have a look at the code and examples of label_value and label_both.
They should suggest how to write your own labeller to do what you
want.
Hadey
On Tue, Aug 11, 2009 at 1:44 PM, Ben Bolker wrote:
>
> just a quick question (to which I suspect the answer is "no"):
> does anyone know if, in the gg
Hi,
I have a list that contains about 100 elements. Each element contains
the following matrix structure
a b
1 1 4
2 2 5
3 3 6
I'd like to sum column b across all elements. I'm thinking of using
lapply or sapply but cannot get it to work. Any help would be really
appreciated. Thank you.
adsch
You might also want to have a look at the plyr package,
http://had.co.nz/plyr. This package is an attempt to
standardise and make consistent the various common uses of apply and friends.
Hadley
On Tue, Aug 11, 2009 at 3:09 PM, Peng Yu wrote:
> Hi,
>
> There are quiet a few different 'apply' func
Hi Kelvin,
I'm new to R and tm myself, however here is a way that you can sort your
corpus. Please keep in mind that there may be a more efficient approach --
but this will get the job done.
Basically, there are three steps (in pseudo code):
1. Extract the meta data for Age into a list
2. Sor
what are exactly "some operations"? if you could provide a
reproducible code, it would make it easier to understand what you're
trying to achieve.
for example, if you were to get the means, you could do something like:
theMeans <- rapply(test, mean)
cheers,
b
On Aug 11, 2009, at 8:59 PM,
Thanks Henrique. I would have not thought of the syntax you suggest, though
it embodies the sort of multilevel (not quite recursive) application of
lapply I was thinking of. However, it returns ³test² with V2 missing,
everything else intact. Strange; I can't really state in words what I think
it
On Tue, Aug 11, 2009 at 6:30 AM, Frank E Harrell
Jr wrote:
> Dear Group:
>
> I want to use lattice with a formula such as y ~ x | v to plot a data frame
> in which v varies to indicate which "x" is really being plotted. I know how
> to make the x-axis scales vary with the panel but is it possible t
On Tue, Aug 11, 2009 at 12:43 PM, Peng Yu wrote:
> Hi,
>
> I frequently need to open multiple help pages in R, which requires the
> start of multiple R sessions. I am wondering if there is a way to
> invoke the help page from the command line just like 'man'.
If you are feeling adventurous, you mi
Can you provide something reproducible and elaborate on
what "expected" means.
On Tue, Aug 11, 2009 at 4:11 PM, stephen sefick wrote:
> I would like to merge zoo objects that are stored in a list into one
> big zoo object with one index for all of the observations.
>
> I have created the list (74
Hi Frank
May I suggest
1.
?strip.custom
and get into strip.default for options
2. use the features of strip
and modify to suit your requirements
http://finzi.psych.upenn.edu/R/Rhelp02/archive/104004.html
http://finzi.psych.upenn.edu/R/Rhelp02/archive/100977.html
Regards
Duncan Mackay
Depart
If I understand correctly your question, you can try something about like
this:
# Access all elements named 'V1' in your list
lapply(test, lapply, '[', 'V1')
On Tue, Aug 11, 2009 at 3:49 PM, Bryan Hanson wrote:
> Hello Again R Folks:
>
> I¹m trying to clean up some code. Suppose I have an obj
Roaman wrote:
Hi,
I have a problem with the metaplot-function in rmeta.
After plotting a Forest Plot with "metaplot", no y-axis is shown for normal
plots anymore.
Does someone know, why this is and how I can solve it?
Thank you in advance!
Kind regards,
Roman
This is a guess, because we
Hi,
Are there any way to include "repeated measures" components in Markov
chain model?
I am using msm package, but it doesn't allow to include repeated-
measures.
All I want to get is q matrix and the significance of the covariates
in state transitions.
Thanks
> -Original Message-
> From: r-help-boun...@r-project.org
> [mailto:r-help-boun...@r-project.org] On Behalf Of Peng Yu
> Sent: Tuesday, August 11, 2009 1:09 PM
> To: r-h...@stat.math.ethz.ch
> Subject: [R] Is there a summary on different version of
> 'apply' functions?What is the meaning
Scott,
Thanks! That works great. I appreciate the help.
Jonathan
- Original Message -
From: "Scott Sherrill-Mix"
To: "Jonathan R. Blaufuss"
Cc: r-help@r-project.org
Sent: Tuesday, August 11, 2009 4:18:18 PM GMT -06:00 US/Canada Central
Subject: Re: [R] Paste symbol and calculation in
I'm no expert at this but it seems like ?plotmath is saying to do
something like:
text(2,0.35,bquote(sigma==.(mySigma),list('mySigma'=round(sd(Data),digits=3
Scott
Scott Sherrill-Mix
Department of Microbiology
University of Pennsylvania
402B Johnson Pavilion
3610 Hamilton Walk
Philadelphi
Yes, thanks Steve and also to everyone else for helping me clear this up.
The issue was definitely the existence of other objects named X and Y that
I inadvertently referred to in my command statement. Only when these
objects are removed AND the data frame in question is attached, will the
comman
You might want to check vif in the Design package.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Tomas Zelinsky
Sent: Tuesday, August 11, 2009 3:20 PM
To: r-help@r-project.org
Subject: [R] Heteroscedasticity in binary logit models
Hello,
I have this script in my PATH :
#!/bin/env Rscript
args <- commandArgs( TRUE )
if( length( args ) == 1 ){
       h <- help( args )
} else if( length(args) == 2 ) {
       h <- help( args[2] , package = args[1] )
} else{
       stop( "usage: rman [package] functi
Dear all,
I was trying to do some contrasts within ANOVA. I searched the archive and
found a clue posted by Steffen Katzner
( http://tolstoy.newcastle.edu.au/R/help/06/01/19385.html)
I have three levels for a factor names "StdLot". I just want to make three
comparisons, 1 vs 2, 1 vs 3 and 2 vs 3.
?help.search
help.search("apply")
Problem is, various packages have added their own apply-type functions; so
what you get depends on what packages you have downloaded.
Bert Gunter
Genentech Nonclinical Biostatisics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bou
I would like to merge zoo objects that are stored in a list into one
big zoo object with one index for all of the observations.
I have created the list (74 dataframes) with the code below, and have
tried the do.call(merge, foo) in the call and the output is not what I
expected. Any help would be
Hi,
There are quiet a few different 'apply' functions, such as lapply,
sapply and many more. I'm very familiar with the 'Apply' function in
Mathematica. Can somebody point me a summary of all the 'apply'
functions in R. Also, I'm curious that what 'l' and 's' (and other
prefixes) stand for in 'lap
?with
Bert Gunter
Genentech Nonclinical Biostatisics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Steve Lianoglou
Sent: Tuesday, August 11, 2009 12:27 PM
To: Jim Bouldin
Cc: r-help@r-project.org
Subject: Re: [R] problem selecting
Hi,
On Aug 11, 2009, at 3:43 PM, Peng Yu wrote:
Hi,
I frequently need to open multiple help pages in R, which requires the
start of multiple R sessions. I am wondering if there is a way to
invoke the help page from the command line just like 'man'.
I haven't been paying attention, but are yo
On Tue, 11-Aug-2009 at 07:15PM +0100, Cecilia Carmo wrote:
> Hi everyone.
>
> Could anyone help me to reshape my data?
>
> Reproducible example:
> firm<-sort(rep(1:1000,10),decreasing=F)
> year<-rep(1998:2007,1000)
> industry<-rep(c(rep(1,10),rep(2,10),rep(3,10),rep(4,10),rep(5,10),rep(6,10),rep(7
I'm trying to annotate a density plot and I would like to have R calculate the
standard deviation and place it in the plot next to the standard deviation
symbol
"sigma". I can successfully use the text command to paste "StDev
=",round(sd(Data),digits=3))
on the plot. However, I have trouble whe
Hello, I''ve looked around and I can't seem to find a package to do data
mining in R for a mixture of categorical and numerical attributes.
If you have this data set:
## dummy data
set.seed(123)
dummy <- data.frame(A = sample(paste("tasks",1:100), 1,B =
sample(paste("loads",1:100), 1,
Hi,
I frequently need to open multiple help pages in R, which requires the
start of multiple R sessions. I am wondering if there is a way to
invoke the help page from the command line just like 'man'.
Regards,
Peng
__
R-help@r-project.org mailing list
Hi,
See comments in line:
On Aug 11, 2009, at 2:45 PM, Jim Bouldin wrote:
No problem John, thanks for your help, and also thanks to Dan and
Patrick.
Wasn't able to read or try anybody's suggestions yesterday. Here's
what
I've discovered in the meantime:
What I did not include yesterday
Hi,
I'm trying to randomize a sequence of trials for an experimental
design. The trials consist of values for each of two factors. As is
there are 30 combinations of the two factors, and I want them to be
ordered randomly but with the requirement that for one of the factors,
the value can n
Do you just want to assign an identifier to each line, that is call the first
33 lines are speciman A the next are speciman b etc?
Assuming the data set is in a data.frame called xx try something like this
group <- rep(1:33, each=79)
data.frame (group,xx)
John
--- On Tue, 8/11/09, Fabio Murta
Hello,
is there any tool to test heteroscedasticity in binary logit models?
Thanks.
Tomas
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
Hello,
I wonder whether it's possible to use vif{car} for binary logit models
(estimated by using glm() function). And what about a case if all
explanatory variables are binary as well? Is VIF still a good criterion
for multicollinearity detection?
Thanks a lot.
Tomas
Ben Bolker wrote:
I can see that fortune("S4") is going to produce more than one possible
response
soon ... (is Achim Zeleis listening?)
Ben
In all fairness, it should probably be noted that quite a few people
swear BY S4 in addition to those who swear AT it.
-p
Frank E Harrell J
Hello Again R Folks:
I¹m trying to clean up some code. Suppose I have an object like this:
> str(test)
List of 2
$ G:List of 2
..$ cls:'data.frame':101 obs. of 2 variables:
.. ..$ V1: num [1:101] -0.0019 -0.0019 -0.00189 -0.00188 -0.00186 ...
.. ..$ V2: num [1:101] 0.000206 0.000247
here is an intermediate solution that works just fine. Thank you all
for your help.
Stephen Sefick
#level logger read in
read.ll <- function(path){
library(chron)
library(zoo)
list.of.files <- list.files(path)
length.files <- length(list.of.files)
df <- vector(mode = "list", length = len
Greetings, all.
I've got a datafile I've been working with that has an ideosyncratic,
heterogeneous format. It's grossly like:
[...]
DISKREAD,metadata about disks
MEM,metadata about memory
,observation-identifier,time,date
DISKREAD,observation-identifier,data about disks
MEM,observation-
Hi all, i have a dataset of 3D coordinates and can't figure out how
to' tell R which One Are the individuals:
I have 3 columns which i named x,y and z
And then i have 2607 Lines, but each specimen is 33 Lines (79 specimens)
How can i tell R to' categorize individuals every 33 Lines?
Thanks
No problem John, thanks for your help, and also thanks to Dan and Patrick.
Wasn't able to read or try anybody's suggestions yesterday. Here's what
I've discovered in the meantime:
What I did not include yesterday is that my original data frame, called
"data", was this:
X Y V3
1 1 1 0.
just a quick question (to which I suspect the answer is "no"):
does anyone know if, in the ggplot2 package, there's a way to
override the default names of the facets in facet_wrap (which
correspond to the levels of the factor used to facet)? I know
that I go back and change the levels of the fa
Nevermind. I had both the ppc and ppc64 versions of tcl and tk
installed. I removed ppc64 versions and everything works now. Must
have been a conflict.
Ryan Golhar wrote:
I'm trying to install R on an IBM P570 running Redhat Enterprise Linux
v4. When I run ./configure, I see:
checking fo
I'm trying to install R on an IBM P570 running Redhat Enterprise Linux
v4. When I run ./configure, I see:
checking for tclConfig.sh... no
checking for tclConfig.sh in library (sub)directories...
/usr/lib64/tclConfig.sh
checking for tkConfig.sh... no
checking for tkConfig.sh in library (sub)di
I can see that fortune("S4") is going to produce more than one possible
response
soon ... (is Achim Zeleis listening?)
Ben
Frank E Harrell Jr wrote:
>
> spencerg wrote:
>> Hi, Terry:
>>
>> Thanks for the comments. I too vastly prefer S3 to S4. Your
>
> Me too. My summary is t
Hi everyone.
Could anyone help me to reshape my data?
Reproducible example:
firm<-sort(rep(1:1000,10),decreasing=F)
year<-rep(1998:2007,1000)
industry<-rep(c(rep(1,10),rep(2,10),rep(3,10),rep(4,10),rep(5,10),rep(6,10),rep(7,10),rep(8,10),rep(9,10),
+ rep(10,10)),1000)
X1<-rnorm(1)
X2<-rnorm(
On Tue, 2009-08-11 at 12:45 -0500, stephen sefick wrote:
> I am running into a problem with allocating these files to a list as
> they are read in through a for loop. I know I am probably doing
> something wrong, but I can't figure out what. I know this is not
> reproducible. I am ending up with
On Tue, 11 Aug 2009, stephen sefick wrote:
I am running into a problem with allocating these files to a list as
they are read in through a for loop. I know I am probably doing
something wrong, but I can't figure out what. I know this is not
reproducible. I am ending up with a data frame of th
Thanks. The replacePatterns() is from the text mining package tm().
Bert Gunter wrote:
>
> Don't use replacePatterns() (-- and what package is that from, btw??).
>
> gsub("abc|def","Yes",sample[[1]])
>
> Incidentally, "sample" is a rather bad name for your dataset, as it is the
> name of a c
Don't use replacePatterns() (-- and what package is that from, btw??).
gsub("abc|def","Yes",sample[[1]])
Incidentally, "sample" is a rather bad name for your dataset, as it is the
name of a commonly use R function. Ergo, possibility of confusion.
Bert Gunter
Genentech Nonclinical Biostatisics
On Tue, 2009-08-11 at 17:49 +, Inchallah Yarab wrote:
> Hi,
> what is meaning this errors !!!
> Error in names(o.pr)[p.ok] <- names(qs) :
> incompatible types (from NULL to character) in subassignment type fix
I can replicate this error by 'qs' not having names. what does
names(qs)
show?
On 8/11/2009 1:24 PM, spencerg wrote:
Hi, Terry:
Thanks for the comments. I too vastly prefer S3 to S4. Your
comparison is based on much greater experience than mine.
Could you please check the link you sent? I couldn't get it to
work.
It's a small typo, the correction
spencerg wrote:
Hi, Terry:
Thanks for the comments. I too vastly prefer S3 to S4. Your
Me too. My summary is this:
If you love computer science more than you value your own time, use S4.
Frank Harrell
comparison is based on much greater experience than mine.
Could you please
Hi,
what is meaning this errors !!!
Error in names(o.pr)[p.ok] <- names(qs) :
incompatible types (from NULL to character) in subassignment type fix
In addition: Warning message:
In Ops.factor(from, (0:(length.out - 1)) * by) :
+ not meaningful for factors
thank you very much
I am running into a problem with allocating these files to a list as
they are read in through a for loop. I know I am probably doing
something wrong, but I can't figure out what. I know this is not
reproducible. I am ending up with a data frame of the very last file
to be read in. I know it is
Dear R Users,
I'm using Rmpi package for paralleling computing. It's very useful.
But I have two question:
1. before running processes on slaves, all the data should be sent to
them. however, if i forget to broadcast some of the data, the master
will freeze, and I have to kill the process manuall
Hi, Terry:
Thanks for the comments. I too vastly prefer S3 to S4. Your
comparison is based on much greater experience than mine.
Could you please check the link you sent? I couldn't get it to
work.
Thanks again.
Spencer
Terry Therneau wrote:
For 90 percent of
On Tue, Aug 11, 2009 at 08:46 +0200, Alexandros Droseltis wrote:
> I wrote a script file with the following commands
>
> postscript()
> [...]
> barplot(pr, xlab="Länge")
>
> In the output file (Rplots.ps) the german umlaut is printed as "L..nge".
> How could I set the encoding correctly?
I found
rajclinasia escribió:
Hi Every one,
my question is, How to Import more than one sheet in a single excel file
(e.g. 10 sheets in one excel file) into R and create datasets for all the
sheets in a single excel file without specifying the sheetnames.
Thank you in Advance.
Hello,
One way is to use
For 90 percent of what I do I strongly prefer the loose (S3) rather than the
rigid (S4) classes. So I'm closer to Rolf. My summary of S4 vs S3
A large increment in
1. nuisance to write
2. difficulty to debug
3. ability to write very obscure code
4. design
Gain
5. ability to dir
Hi all,
I wonder how you can replace all words that need to be changed using
replacePatterns(). The following is my code. I want to replace both "abc"
and "def" to " Yes ". However, I can only replace the first occurrence in
sample[[1]].
> sample[[1]]
[1] abc def ghi
> change <- c("abc","def"
Cindy,
I dont know of a better way to do this than what Ted Harding showed.
Dan
Daniel J. Nordlund
Washington State Department of Social and Health Services
Planning, Performance, and Accountability
Research and Data Analysis Division
Olympia, WA 98504-5204
From: cindy Guo [mailto
Does 'unlist' do it for you:
> w <- c(3,3,2,1) # vector of weights
> q <- 4 # theshold
>
> # computes which coordinate of w is decisive in each permutation
> res <- unlist(sapply( permn(w), function(x) which(w == x[min(which(cumsum(x)
> >=q))]) ))
>
> # complies the frequencies
> prop.table( ta
> Paul Emberson
> try pa + scale_colour_brewer() and
> see ?scale_colour_brewer for options
> Also see scale_colour_manual where you can use the values parameter to
> choose your own colours.
> Thierry.ONKELINX
> Have a look at scale_colour_manual()
> (http://had.co.nz/ggplot2/scale_manual.html)
I'm trying to run an SEM, but I keep getting the following error message.
In sem.default(ram = ram, S = S, N = N, param.names = pars, var.names = vars, :
Could not compute QR decomposition of Hessian.
Optimization probably did not converge.
I have 4 latent variables (plant, AMF, abiotic, and s
Rnewbie wrote:
sorry, I still have a question. What is the difference between an empty
vector and a vector of length 0?
When I assign
x<-c()
is.null(x) is TRUE
x<-integer(0)
is.null(x) is FALSE
NULL is a special object in R. is.null() returns TRUE for it. c()
returns it.
integer(0) is
Hi John,
Try pa + scale_colour_brewer() and
see ?scale_colour_brewer for options
Also see scale_colour_manual where you can use the values parameter to
choose your own colours.
Cheers,
Paul
John Kane wrote:
>> Paul Emberson "You need to map colour to a variable. Try
>> geom_segment(mapping=
John,
Have a look at scale_colour_manual()
(http://had.co.nz/ggplot2/scale_manual.html)
HTH,
Thierry
PS My solution was exactly the same as Paul's.
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Res
Hi,
When I use Rscript, I want that it load an additional Rprofile file
besides the default ones. I don't find such an option. Can somebody
let me know if there is such an option?
Regards,
Peng
__
R-help@r-project.org mailing list
https://stat.ethz.ch/
Hello,
I'm having difficulty passing an object name to a lapply function. Can
somebody tell me the trick to make this work?
#Works
T13702 <- TRACKDATA[["13702.xls"]][["data"]]
min(unlist(lapply(list(T13702), function(x) mdy.date(x[1, 2], x[1, 1],
x[1, 3]
16553
#Works
d<-2
assign(paste("T",s
> Paul Emberson
> "You need to map colour to a variable. Try
> geom_segment(mapping=aes(colour=Food)) "
That did it. Apparently I have not gotten to 'mapping' yet in the book!
> Thierry.ONKELINX
> You need to change colour = "darkgreen" into aes(colour = Food). This
> will give a different col
Hello!
I have the following combinatorial problem.
Consider the cumulative sums of all permutations of a given weight vector
'w'. I need to know how often weight in a certain position brings the
cumulative sums equal or above the given threshold 'q'. In other words,
how often each weight is deci
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
sorry, I still have a question. What is the difference between an empty
vector and a vector of length 0?
When I assign
x<-c()
is.null(x) is TRUE
x<-integer(0)
is.null(x) is FALSE
Duncan Murdoch-2 wrote:
>
> Rnewbie wrote:
>> dear all,
>>
>> I tried to use grep to match IDs in two dataframes
>
Hi,
I have a problem with the metaplot-function in rmeta.
After plotting a Forest Plot with "metaplot", no y-axis is shown for normal
plots anymore.
Does someone know, why this is and how I can solve it?
Thank you in advance!
Kind regards,
Roman
--
View this message in context:
http://www.n
1 - 100 of 137 matches
Mail list logo