You will find this discussed in the list archives: most recently see the
thread starting
https://stat.ethz.ch/pipermail/r-help/2008-August/170562.html
Bottom line: the package maintainer needs to correct a bug in the package
code (and did not do so in the subsequent release 0.6-1), but meantim
On Thu, Nov 6, 2008 at 8:53 AM, dinesh kumar <[EMAIL PROTECTED]> wrote:
> Dear R users,
>
> I have a matrix like
>
> A X1
> B Y2
> C Z3
>
> I want to reshape this matrix into this format
>
>X Y Z
> A 1
> B 2
> C 3
>
is this what you
amy rheanita yahoo.com> writes:
> I'm a student. now, I'm studying Nelson-Siegel Extended, a term structure
> model. I can analyze - estimate parameters and make aplot - manually,
> from data bond in a day.
> I can analyze bond data in a month, like make multiple plot for different
> bont dat
Hi, R core team
I am using the function {aidsEst} in package [micEcon] to do an AIDS
model now. So far, everything is good. But I want to test the auto
correlation and heteroskedasticity of the individual equation from AIDS
demand system. How can I return the individual equation?
PS: ser
Please could you clarify for me for me when using the lars (lasso) package
what the parameter 'intercept' refers to and what the advantages and
disadvantages of making this TRUE or FALSE are and when it should be
TRUE and when FALSE. Also please could you clarify how 'eps' works and
when it shoul
Dear R users,
I have a matrix like
A X1
B Y2
C Z3
I want to reshape this matrix into this format
X Y Z
A 1
B 2
C 3
Thanks in advance for your help.
Dinesh
--
Dinesh Kumar Barupal
Junior Specialist
Metabolomics Fiehn Lab
UC
I am using R 2.8 and the latest versions of RMySQL on a Windows XP 64 bit
machine.
I was wondering if someone could help me figure out how to use dbWriteTable
without inserting \r into my table. Consider the following code snippet,
which is
run after I connect to my database.
myDFOut = dbReadTab
Jiqiang Guo gmail.com> writes:
> As we know when we use R to execute a r program we can add arguments like
> '--args p1 p2'. But when I am sourcing another file, is there a way to set
> up some arguments for the sourced program. Thanks!
>
In general, you can use Sys.getenv() and .setenv() to
Please note that a more accurate subject line would be
'Problems with links generated by the search page in HTML help in your browser here> on obsolete versions of R'
The problem is almost certainly your browser, not R. Later versions (>=
2.7.2) of R mention this in the R-admin manual and pro
I have this problem with R 2.6.1 and 2.7.1 (have not tried others)
running on Windows XP:
Html help has wrong links to help files. The index.html is correctly
found from
file:///C:/PROGRA~1/R/R-26~1.1/doc/html/index.html
as well as the search engine
file:///C:/PROGRA~1/R/R-26~1.1/doc/html/s
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Xing Yuan
> Sent: Wednesday, November 05, 2008 9:37 PM
> To: Simon Blomberg
> Cc: r-help@r-project.org
> Subject: Re: [R] Convert text into a variable name
>
> Thanks for the reply, Simon!
>
> I just
Hi,
if you instead do:
setConstructorS3("ClassB", function(B=15) {
extend(ClassA(), "ClassB",
.size2 = B
);
})
then you'll get:
> objB <- ClassB();
> objB
[1] "Class B: 15"
What was wrong with your setup?
What you ended up doing was to "extend" an object of class 'character'
(with val
Thanks for the reply, Simon!
I just want to name a object as the text string. So I have "AGE" then how
can I do
somecommand("AGE") = 39
then I should have
AGE = 39 in my data set.
Joe
On Thu, Nov 6, 2008 at 12:28 AM, Simon Blomberg <[EMAIL PROTECTED]>wrote:
> ?assign
>
> On Thu, 2008-11-0
?assign
On Thu, 2008-11-06 at 00:03 -0500, Xing Yuan wrote:
> Hello R users,
>
> Does anybody know what command I should use to convert the text string "AGE"
> to be variable name AGE so I can assign value to it
> e.g. AGE = 39?
>
> Thank you very much!
>
> Joe
>
> [[alternative HTML ver
HI, All,
As we know when we use R to execute a r program we can add arguments like
'--args p1 p2'. But when I am sourcing another file, is there a way to set
up some arguments for the sourced program. Thanks!
Regards,
[[alternative HTML version deleted]]
__
Hello R users,
Does anybody know what command I should use to convert the text string "AGE"
to be variable name AGE so I can assign value to it
e.g. AGE = 39?
Thank you very much!
Joe
[[alternative HTML version deleted]]
__
R-help@r-project.o
?try
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Kyeongmi Cheon
> Sent: Thursday, 6 November 2008 4:56 p.m.
> To: R help mailing list
> Subject: [R] trouble with for loop
>
> Hello,
> I'm having two similar problems with for loop and I would
Hello,
I'm having two similar problems with for loop and I would appreciate
any help or comment.
I want to use "for loop" to calculate series of initial values for an
optimization problem. But
some initial values have my function quit due to problems like
calculating the inverse of singular
mat
Sorry I have a bad English.
I'm a student. now, I'm studying Nelson-Siegel Extended, a term structure model.
I can analyze - estimate parameters and make aplot - manually, from data bond
in a day.
I can analyze bond data in a month, like make multiple plot for different
bont date and make a mult
On 6/11/2008, at 11:13 AM, Lucas Eggert wrote:
Dear Experts,
I am new to R and unfortunately cannot start with a simply statistical
analysis:
I manually determined the volume of the right and left hippocampus in
a group of meditators and in a group of controls. My data-sheet looks
as follows:
You can eliminate the loop like this (untested):
cnt <- function(file) {
data <- scan(file, quiet = TRUE)
hist(data, plot = FALSE, breaks = breaks)$counts
}
Reduce("+", sapply(files, cnt))
On Wed, Nov 5, 2008 at 8:01 PM, Andre Nathan <[EMAIL PROTECTED]> wrote:
> Hello
>
> I need to build a his
On 6/11/2008, at 2:01 PM, Andre Nathan wrote:
Hello
I need to build a histogram from data (numbers in the [0,1] interval)
stored in a number of different files. The total amount of data is
very
large, so I can't load everything to memory and then simply call
hist().
Since what I actually n
On 6/11/2008, at 11:39 AM, Armin Meier wrote:
Hi all,
I want to optimize a function fn using optim. This function fn calls
the .C function in it with a function name and arguments given to fn,
i.e. something like this pseudocode:
fn <- function(par, "some params for fn") {... .C
("Cfunction",
Hi
If you want to use MKL10(no 8 or 9), you should obey instructions of R-admin.
MKL10 needs openmp. This needs gcc4.2 or later.
OpenMP for Intel was necessary with MKL10.0.1.x (There was not it in a
manual of MKL).
# Please try an additional effect of "-liomp5" in the %*%
# fp-model of Linux of
Hello
I need to build a histogram from data (numbers in the [0,1] interval)
stored in a number of different files. The total amount of data is very
large, so I can't load everything to memory and then simply call hist().
Since what I actually need are the histogram counts, I'm currently doing
it l
read.table doesn't realize the first column should be row names. Try
read.table("C:/Data/R/NewTarget.csv", header=TRUE, sep=",",
na.strings="NA", dec=".", row.names="tripid_nu")
Kellie Wills
Engineering Service Manager
REvolution Computing
[EMAIL PROTECTED]
On Nov 5, 2008, at 3:51 PM, Farl
I'm having a problem reading data to set control totals for a dataframe.
I want to adjust a dataframe based on a 2-d table of values, which I get
by using :
> CurrentX1Sums <- as.matrix(xtabs(~tripid_nu+lineon, data=SurveyData))
> CurrentX2Sums <- apply(CurrentX1Sums, 1, sum)
I've created a
I am trying to use a background photo in a lattice plot. I am using the
rimage and TeachingDemos packages to plot the photo and translate from
the photo coordinates in pixels to geographic coordinates, which is what
I want to use for plotting contours, lines, etc. The (unrunable) code
below does
I don't think that this answers the poster's question, as he explicitly
mentioned that some row and column indices could be missing.
I think it's simpler and much faster to do this by matrix indexing:
mx <- matrix(NA,nr = max(foo[,1]),ncol = max(foo[,2])) ## fill with NA's
mx[as.matrix(foo[,1:2])
Dear Experts,
I am new to R and unfortunately cannot start with a simply statistical
analysis:
I manually determined the volume of the right and left hippocampus in
a group of meditators and in a group of controls. My data-sheet looks
as follows:
observation subject group age ge
Philipp Pagel wrote:
Dear R experts,
Suppose I have a data frame of three variables:
foo <- data.frame(row=1:5, col=1:3, val=rnorm(15))
foo
row col val
11 1 -1.00631642
22 2 0.77715344
33 3 0.17358793
44 1 -1.67226988
55 2 1.08218836
61
#reshape package should do it
library(reshape)
foo <- data.frame(row=1:5, col=1:3, val=rnorm(15))
cast(foo, row~col)
On Wed, Nov 5, 2008 at 5:47 PM, Philipp Pagel <[EMAIL PROTECTED]> wrote:
>
>Dear R experts,
>
> Suppose I have a data frame of three variables:
>
>> foo <- data.frame(row=1:
Dear R experts,
Suppose I have a data frame of three variables:
> foo <- data.frame(row=1:5, col=1:3, val=rnorm(15))
> foo
row col val
11 1 -1.00631642
22 2 0.77715344
33 3 0.17358793
44 1 -1.67226988
55 2 1.08218836
61 3 1.32961329
7
Hello,
I ran the coxph model and everything worked fine. When I extract the
output from the basehaz(y) function and was wondering if that baseline
is cumulative or not.
I then do:
F(t,t+1)=1-exp(h_0(t+1) exp(coeff(1)*covariate(1)+...))
Does this give me the probability of death from t to t+1 (in
Hi all,
I want to optimize a function fn using optim. This function fn calls
the .C function in it with a function name and arguments given to fn,
i.e. something like this pseudocode:
fn <- function(par, "some params for fn") {... .C("Cfunction", ...) ...}
optim(par, fn, "some params for fn")
In
Folks,
I'm making progress moving from Windows to Linux and have RKward up and
running. I read somewhere that Rkward's supposed to be the Tinn-R for linux and
Tinn-R has worked out great for me. So naturally I'd like to do the following,
if possible,
1. How to ask Rkward not to load the last s
I believe that it depends on the operating system.
memory.limit()
I think this is in the FAQ and search the R email list archive
On Wed, Nov 5, 2008 at 2:53 PM, Alan Cohen <[EMAIL PROTECTED]> wrote:
> Hello,
>
> I have several very large data sets (1-7 million observations, sometimes
> hundreds o
Ricardo Bandin gmail.com> writes:
>
> Dear colleagues
>
> I found duplicate coordinates trying to convert a dataframe object (see the
> attached file) into a geodata one ('geoR' package is needed). My dataframe
> object consists of 2 columns with UTM geographical coordinates and a 3rd
> column
Thanks for your help
the codes you gave me worked vey well!
cheers
Maria
--
-
[EMAIL PROTECTED]
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Hello,
I have several very large data sets (1-7 million observations, sometimes
hundreds of variables) that I'm trying to work with in R, and memory seems to
be a big issue. I'm currently using a 2 GB Windows setup, but might have the
option to run R on a server remotely. Windows R seems basi
How are you starting R ?
It is not a directory. Usually, if you simply say
R
at a shell prompt, it starts R for you.
2008/11/6 Aimin Yan <[EMAIL PROTECTED]>
> In linux, when I start R,
>
> I get some message like this:
>
> Error:unexpected '/' in '"/"
>
> Does anyone know why?
>
> AMY
>
> Than
Try starting it as, R --vanilla , do you still get the error?
Do you have a file called .Rprofile in your home directory?
Aimin Yan wrote:
In linux, when I start R,
I get some message like this:
Error:unexpected '/' in '"/"
Does anyone know why?
AMY
Thanks,
__
In linux, when I start R,
I get some message like this:
Error:unexpected '/' in '"/"
Does anyone know why?
AMY
Thanks,
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-p
On Wed, Nov 5, 2008 at 11:12 AM, pilar schneider
<[EMAIL PROTECTED]> wrote:
> Dear all
> I need some help with R.
> How can I save the estimates of a regression model in a file?
>
> here is what I did:
>
> 1) this is my regression model:
> fit1 <- lm(logmilk ~ logdays + days, data=data2)
>
> 2) how
Le mer. 5 nov. à 12:11, Robert Zimbardo a écrit :
Hi all
Is there going to be a binary of R 2.8.0 for Ubuntu Intrepid Ibex
i386 -
i.e., not just amd 64bit?
I was going to reply that the binaries have been there for a few days
already, but I realize I forgot to copy them to my repository.
http://www.ats.ucla.edu/stat/R/faq/sort.htm
A great tutorial about sorting data in R.
HTH,
_
Patrick Richardson
Biostatistician - Program of Translational Medicine
Van Andel Research Institute - Webb Lab
Grand Rapids, MI 49503
-Original Message-
Hi Ramya,
You're almost there. Just specify that you want to order all the data set
based-on the third column. Here is an example:
# Data
information=data.frame(
geneset=letters[1:7],
chromosome=1,
hit=c(51,24,30,17,35,55,61))
# New data
information
Dear colleagues
I found duplicate coordinates trying to convert a dataframe object (see the
attached file) into a geodata one ('geoR' package is needed). My dataframe
object consists of 2 columns with UTM geographical coordinates and a 3rd
column with fish densities .
To overcome the handicap I m
Geneset_name #Chromosome #Hit_in_Biomart
original_geneset_len Missing.genes
[1,] "AGUIRRE_PANCREAS_CHR12" "1" "51"
"59" "8"
[3,] "AGUIRRE_PANCREAS_CHR9" "1" "24"
Hi all
Is there going to be a binary of R 2.8.0 for Ubuntu Intrepid Ibex i386 -
i.e., not just amd 64bit?
Thx,
RZ
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PLEASE do r
Uwe;
sorry for my last mail. In effect, as you say ,I just needed to explicitly
print() the object to be sinked within the loops.
Thanks you,
Javier
>
>
> [EMAIL PROTECTED] wrote:
>> Hello;
>> It seems to me that this could even by a FAQ, but I cannot find an
>> answer:
>>
> -Original Message-
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of [EMAIL PROTECTED]
> Sent: Wednesday, November 05, 2008 10:19 AM
> To: Uwe Ligges
> Cc: r-help@r-project.org
> Subject: Re: [R] sink() within a loop
>
> Well, I'll put a foo example of my problem:
>
>
Well, I'll put a foo example of my problem:
I'got a list:
>a <- list()
>a$sublist.1 <- list()
>a$sublist.1$subsublist.1 <- list()
this code works:
>zz <- file("foo.txt","w")
>sink(zz)
>a
>sink()
>close(zz)
and generates a correct "foo.txt" file containing the structure of the list
but this co
On 11/5/2008 12:12 PM, pilar schneider wrote:
> Dear all
> I need some help with R.
> How can I save the estimates of a regression model in a file?
>
> here is what I did:
>
> 1) this is my regression model:
> fit1 <- lm(logmilk ~ logdays + days, data=data2)
>
> 2) however, I want to get the par
On 11/5/2008 10:59 AM, EVANS David-William wrote:
Fellow R users,
I often use « text » to annotate plots in 2 dimensions. Having grown up to 3
dimensions recently, I am looking for a similar function. Could anyone provide
code for how to annotate points in a 3-d plot?
You need to descr
Stoesser, Jochen wrote:
Hi all,
I have two vectors of data:
The first vector contains timestamps (as integers), however the
difference between these dates varies. For instance, the vector can be
c(0, 5 , 10, 20, 25, 30) so that there is a "jump" between the third and
the fourth element.
If
[EMAIL PROTECTED] wrote:
Hello;
It seems to me that this could even by a FAQ, but I cannot find an answer:
Why a piece of code that uses sink() does not sinks anything if it is
executed within a for loop?
Without sink(), does it print anything in the console? If not: use
print() in order to
Hello;
It seems to me that this could even by a FAQ, but I cannot find an answer:
Why a piece of code that uses sink() does not sinks anything if it is
executed within a for loop?
Thanks,
Javier
__
R-help@r-project.org mailing list
https://stat.ethz.c
EVANS David-William wrote:
Fellow R users,
I often use « text » to annotate plots in 2 dimensions. Having grown up to 3
dimensions recently, I am looking for a similar function. Could anyone provide
code for how to annotate points in a 3-d plot?
Depends on the framework you are usin
Jon Wong wrote:
Hi,
I was wondering if I could get some help on importing data into a
three-dimensional array?
I am importing data from several text files:
dsdir<-"c:/documents and settings/desktop/07082008/" # path to files
dsfb1<-"07082008-DI4129b.dat" # file base name
firsthour<-13 # firs
Borja Soto Varela wrote:
Dear R-users,
I'm using R (2.7.1) under windows and I've got a function written in R that
calls a Fortran 77 subroutine using both interface function (.C and
.Fortran). The Fortran 77 source was compiled to a shared library using g77
(3.4.5).
When I call the R wrapper
Dear R-users,
I'm using R (2.7.1) under windows and I've got a function written in R that
calls a Fortran 77 subroutine using both interface function (.C and
.Fortran). The Fortran 77 source was compiled to a shared library using g77
(3.4.5).
When I call the R wrapper function, it will use the 100
Hi,
I was wondering if I could get some help on importing data into a
three-dimensional array?
I am importing data from several text files:
dsdir<-"c:/documents and settings/desktop/07082008/" # path to files
dsfb1<-"07082008-DI4129b.dat" # file base name
firsthour<-13 # first hour of observatio
R-geographers...
I'm trying to solve a problem to implement a line-by-line tiled
processing using RGDAL (read 1 line of an image, process the one line,
write one line of the image to a binary file). Everything except for
the final step I'm able to do using a combination of RGDAL and r-base
c
Dear all
I need some help with R.
How can I save the estimates of a regression model in a file?
here is what I did:
1) this is my regression model:
fit1 <- lm(logmilk ~ logdays + days, data=data2)
2) however, I want to get the parameters estimates for each individual (by
group):
so i did the fol
sounds like plyr although I have never used it... If you want help
with code you need to provide reproducible examples.
On Wed, Nov 5, 2008 at 5:11 AM, Bert Jacobs
<[EMAIL PROTECTED]> wrote:
>
>
>
>
> Hi,
>
> I've written the following line of code to make a summary of some data:
>
>
>
> Final.Da
I wanted to install the package "gdata". Here are the commands I gave and the
responses:
install.packages("gdata")
Warning in install.packages("gdata") :
argument 'lib' is missing: using '/Users/dbae/Library/R/library'
trying URL
'http://cran.uk.r-project.org/bin/macosx/universal/contrib/2.8/gd
Oliver Bandel wrote:
Hello,
many thanks!
BTW: I read your book. :)
It's quite good.
Thank you.
But I didn'tfoud the precision-stuff in it.
Adding information about this topic in the next
edition might be a good idea.
These numeric things are an interesting and important topic, of cours
Hello -
Rajasekaramya wrote:
Hi there,
I have a dataframe length.unique.info
length.unique.info
abc 12 345
def 16 550
lmn 6 600
Is this really the output when you print your data.frame? You may have
column names for columns 1, 2, and 3? Is the first column a column of
row.names, o
Dear Murali,
Here is one way:
set.seed(123)
a <- matrix(abs(rnorm(100)), 10)
b <- rnorm(10)
apply(a,2,function(x) ifelse(b>quantile(b,probs=0.75),-x,x))
HTH,
Jorge
On Wed, Nov 5, 2008 at 11:30 AM, <[EMAIL PROTECTED]> wrote:
> Folks,
>
> I have a matrix:
>
> set.seed(123)
> a <- matrix(rn
Fellow R users,
I often use « text » to annotate plots in 2 dimensions. Having grown up to 3
dimensions recently, I am looking for a similar function. Could anyone provide
code for how to annotate points in a 3-d plot?
Your help is greatly appreciated.
For Sébastien Velazquez.
-
you almost have it, e.g., check the following:
set.seed(123)
a <- matrix(rnorm(100), 10)
b <- rnorm(10)
ind <- b > quantile(b, 0.75)
a[ind, ] <- -a[ind, ]
a
I hope it helps.
Best,
Dimitris
[EMAIL PROTECTED] wrote:
Folks,
I have a matrix:
set.seed(123)
a <- matrix(rnorm(100), 10)
And a v
Dear Sirs,
Is there a R function to read an Idrisi image (*.rdc & *.rst)
Thanks
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PLEASE do read the posting g
Hello,
many thanks!
BTW: I read your book. :)
It's quite good.
But I didn'tfoud the precision-stuff in it.
Adding information about this topic in the next
edition might be a good idea.
Nevertheless it explains crucial points very good,
and from that starting point, it's easier to understand the
Folks,
I have a matrix:
set.seed(123)
a <- matrix(rnorm(100), 10)
And a vector:
b <- rnorm(10)
Now, I want to switch the signs of those rows of a corresponding to
indices in b whose values exceed the 75 %-ile of b
which(b > quantile(b)[4])
[1] 2 6 10
so I want, in effect:
a[2, ] <- -a[2,
Yes ! Many thanks Gabor.I'll email the relevant people on Axis about this.
Tolga
Tolga Uzuner
Cross-Markets
Chief Investments Office
JP Morgan
6th Floor, 100 Wood Street
London EC2V 7RF
United Kingdom
Asst. Lee Hesketh
Tel: +44-20-3303
Fax: +44-20-77422840
"Gabor Grothendieck" <[EMAIL PR
homework? Anyway, look at the code for kruskal.test I think, and that
should be a good start.
On Tue, Nov 4, 2008 at 5:59 PM, Swanton0822 <[EMAIL PROTECTED]> wrote:
>
> Hi,
> again i am stuck in my presentation, and i have never learn R before in my
> life but need this to be done, so please help
Hi there,
I have a dataframe length.unique.info
> length.unique.info
abc 12 345
def 16 550
lmn 6 600
I want those names that fall under the condition (length.unique.info[,2][i]
<=5 && length.unique.info[,3][i] >=500)
abcder<-length.unique.info[which(length.unique.info[,2][i] <=5 &&
length.
There will be a meeting of the Ottawa Gatineau R Users Group on Monday
November 10 from 4pm to 6pm. More details are provided below. Please
pass this message along to friends you think may be interested.
Paul Gilbert
_
Dear R friends:
To get OGRUG going again I've reserved room DMS 61
I think the problem is that there is a bug in R itself. If we use axis instead
of Axis it works even with no check at all:
plotmonths<-function(z,...){
plot(z,xaxt="n",...)
tt <- time(z)
m <- unique(as.Date(as.yearmon(tt)))
jan <- format(m, "%m") == "01"
mlab <- substr(months(m[!jan]), 1, 1)
I don't have R on this machine to try it but it looks good to me. I had even
got as far as seq() but completely missed the use of "each".
Thanks very much.
--- On Wed, 11/5/08, Gustaf Rydevik <[EMAIL PROTECTED]> wrote:
> From: Gustaf Rydevik <[EMAIL PROTECTED]>
> Subject: Re: [R] Simple rep(
On Wed, Nov 5, 2008 at 4:02 PM, John Kane <[EMAIL PROTECTED]> wrote:
>
> I want to create a data.frame of time and date for a year. I started with
> the idea of simply producing two vectors (time and date)
>
> The first part ( time) is easy.
> rep(1:24, 365)
>
> But how do I get a series of 24 d
Dear R-help listers,
I am a new convert to R. I am trying to use a r package to conduct latent
class analysis as a triangulation check of my cluster analysis using the
cluster package in R. I have about 30 cases and 6 indicators, some of which
are binary indicators and others are ratio-level varia
> From: Alessandro <[EMAIL PROTECTED]>
> Subject: [R] merge 2 txt file
> To: [EMAIL PROTECTED], r-help@r-project.org
> Received: Tuesday, November 4, 2008, 6:52 PM
> Hi all,
>
>
>
> I have two txt file with X,Y,Z column and I need to merge
> together
>
>
>
> I tried
>
> file_all <-
> merg
Hi Gabor,
Thanks very much.
I tried that:
plotmonths<-function(z,...){
plot(z,xaxt="n",...)
tt <- time(z)
m <- unique(as.Date(as.yearmon(tt)))
jan <- format(m, "%m") == "01"
mlab <- substr(months(m[!jan]), 1, 1)
Axis(side = 1, at = m[!jan], labels = mlab, tcl = -0.3, cex.axis = 0.7)
#if(a
I want to create a data.frame of time and date for a year. I started with the
idea of simply producing two vectors (time and date)
The first part ( time) is easy.
rep(1:24, 365)
But how do I get a series of 24 dates for O1 January 2005 and repeat this to 31
December 2005.
It should be easy
sprintf() for displayed numbers perhaps.
--- On Wed, 11/5/08, Oliver Bandel <[EMAIL PROTECTED]> wrote:
> From: Oliver Bandel <[EMAIL PROTECTED]>
> Subject: [R] Internal and displayed precision of numbers
> To: r-help@r-project.org
> Received: Wednesday, November 5, 2008, 8:38 AM
> Hello,
>
> c
Try
if (any(jan)) ...
On Wed, Nov 5, 2008 at 8:55 AM, <[EMAIL PROTECTED]> wrote:
>
> By way of follow-up, this will not work if the time series does not run over
> a year, as the replacement of January by the year fails on the second call
> to Axis.
>
> The following tests for this:
>
> plotmon
"DM" == David Masson <[EMAIL PROTECTED]>
on Wed, 05 Nov 2008 15:13:37 +0100
DM> I have a question concerning avoiding loops.
DM> I know the function "apply" and I have used it several times, but I feel
DM> blocked
DM> with this situation :
DM>
DM> E <- array(X, dim =
I have a question concerning avoiding loops.
I know the function "apply" and I have used it several times, but I feel
blocked
with this situation :
E <- array(X, dim = c(L,nlon,nlat) )
data <- matrix(Y, nrow=nlon, ncol=nlat )
G <- vector(length=L)
for (l in 1:L)
{
G[l] <- function.F(
Hi,
Sorry about that. Sure, here is some further information:
> summary(InekeReduc)
segorg intorg l2group mani score
Belfast:3782 Belfast:3782 1: 2604 1 :2480 Min. : 1.000
L2 :7502 L2 :7440 2:12462 2 :2542 1st Qu.: 1.000
German :37
Oliver Bandel wrote:
Hello,
can the displayed and/or used precision of numbers be
configured? And if... how?
See ?.Machine for the internally used precision.
See ?options and ?format/?formatC/?print for the printed precision.
Uwe Ligges
Ciao,
Oliver
__
Sorry for don't make the data available. My bad.
But anyway the Richard's fourth solution works quite well.
Thank you very much!
Rodrigo.
-Mensagem original-
De: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
Enviada em: quarta-feira, 5 de novembro de 2008 10:59
Para: Rodrigo Aluizio
Cc: r
By way of follow-up, this will not work if the time series does not run
over a year, as the replacement of January by the year fails on the second
call to Axis.
The following tests for this:
plotmonths<-function(z,...){
plot(z,xaxt="n",...)
tt <- time(z)
m <- unique(as.Date(as.yearmon(tt)))
Hi everybody,
I am trying to implement lasso using the lars package but I don't know how to
extract the optimal solution. There is predict.lars function to extract the
coefficients against some specified "s".
I want to know how I can get the optimal choice of "lambda" i.e. the lagrange's
mul
Hello,
can the displayed and/or used precision of numbers be
configured? And if... how?
Ciao,
Oliver
__
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PLEASE do read the posting guide http://www.R-project.org/posting
Just one comment. The code posted works as shown
but if in your case Lines is actually composed of separate
lines rather than one big string as in my example then
you will need to add a simplify = c argument to
each strapply call.
On Wed, Nov 5, 2008 at 7:32 AM, Gabor Grothendieck
<[EMAIL PROTECT
On Wed, Nov 5, 2008 at 5:42 AM, Fredrik Karlsson <[EMAIL PROTECTED]> wrote:
> Dear list,
>
> Sorry to ask you this, but I just ran a TukeyHSD on an model with a
> two thee level factors as independent variables and a numeric score
> dependent variable.
> The aov gives a significant interaction effe
> I’m using barplot function. I pretend to create a horizontal barplot
with
> two different information (side by side) for a species list. Well I can
> generate the graph easily, but the problem is that the labels with the
> species names are cut by device window!! I’ve tried lots of par
function
On 05/11/2008 7:16 AM, Rodrigo Aluizio wrote:
Hi List, well I’ve already asked this before, but I can’t figure out a
solution for the problem after trying many different ways.
So I writing again…
I’m using barplot function. I pretend to create a horizontal barplot with
two different information
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