Wang, Zhaoming (NIH/NCI) [C] mail.nih.gov> writes:
> Is there any R package which can do 3-D splines (reconstruct a surface
interp in package akima. I you do not insist on splines, also check interp.loess
(tgp ?).
Dieter
__
R-help@r-project.org maili
On Wed, 22 Oct 2008, Paulo Cortez wrote:
This is becoming a nightmare and I am concluding that
installing java1.6 in CentOS5 is particularly hard,
specially if you installed previous jdk versions...
If you have multiple versions present, you are going to have
problems as the Sun Java release
Dear Omar
Your t.test is telling that the 2 groups are not different. Now it is not clear
if you want to compute the CI for the difference or for each group. If the
former, then the outputs provides you with that information.
Itd be clearer if you provide the full syntax of your t.test. For exam
Hi,
We built a small cluster in Debian and Torque and lam.
It is 8cpu per the node in two node.
Because it was troublesome to write as LoadLevelor,OpenPBS,LFS and
Torque, we made I/F of Web.
However, I understood that I said that it was more difficult to write
a document.
It is written to be cal
I have run a t.test in R, and received these results:
Two Sample t-test
data: rsa and umple
t = 0.9819, df = 10, p-value = 0.3493
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-76.1541 196.1541
sample estimates:
mean of x mean of y
50
I think you have to be either honest or careful, since the code you
submitted to Rweb is different with your former code! Why the
condition was changed from "test<-subset(X, GRADE == 7 & Y_Q10A < 9)"
to "test<-subset(X, PROV==48 & GRADE == 7 & Y_Q10A < 9)"?
By the way, please read the post guide
Gough, Lauren wrote:
I am using quadratcount in spatstat to divide a window containing a
point pattern into a grid of quadrats containing the intensity of
points in each quadrat.
However, when I look at the data for quadrat counts it seems the
function is not keeping the size of the quad
megh: assuming that i understand what you want, i think below does it
but check it carefully because i didn't.
i = 1:9
a = matrix(1:9, 3)
tempa <- lapply(i,function(.index) {
a^.index
})
tempb <- lapply(seq(1,dim(a)[1]*dim(a)[2],by=dim(a)[1]),function(.index)
{
do.call(rbind,tempa[.index
Thanks for your reply. Your solution is ok for this particular definition of
bi = a * i
. However I was looking for more general solution, like :
bi = a *a*a*(i-times)
Is there any better idea?
Thanks and regards,
Greg Snow-2 wrote:
>
> Does this help point you in a useful direction?
>
>>
Had the test wrong in the last one' try this:
> x
X value row col ID n
1 1 11.105009 5511625 3463000 1 -619.1125
2 2 10.324148 5499625 3465000 01.
3 3 8.744591 5503625 3475000 01.
4 4 9.523473 5494625 3475000 3 -578.2354
5 5 8.856097 5507625 348 4
Will this do it for you:
> x
X value row col ID n
1 1 11.105009 5511625 3463000 1 -619.1125
2 2 10.324148 5499625 3465000 01.
3 3 8.744591 5503625 3475000 01.
4 4 9.523473 5494625 3475000 3 -578.2354
5 5 8.856097 5507625 348 4 -619.1125
6 6 8.6368
Perhaps:
for(i in 2:4) plot(g[c(1, i)])
On Wed, Oct 22, 2008 at 8:56 PM, stephen sefick <[EMAIL PROTECTED]> wrote:
> #this does what I want is there a better way to do this
> a <- c(1:26)
> b <- rnorm(26)
> e <- rnorm(26)
> f <- rnorm(26)
> g <- data.frame(a,b,e,f)
>
> for(i in 1:3){
> plot(g[,i]
#this does what I want is there a better way to do this
a <- c(1:26)
b <- rnorm(26)
e <- rnorm(26)
f <- rnorm(26)
g <- data.frame(a,b,e,f)
for(i in 1:3){
plot(g[,i]~g[,"a"], ylab=colnames(g)[i])
}
On Wed, Oct 22, 2008 at 6:39 PM, stephen sefick <[EMAIL PROTECTED]> wrote:
> #sorry lets try that ag
Your terminology is confused. At least it confuses me. I think you are
mixing up ``bivariate distributions'' and ``mixture'' (of two)
distributions.
What you get by rbinding x.1 and x.2 is a sample from a mixture of
two *bivariate*
(Gaussian) distributions, one with mean c(0,0), and one wi
Dear All,
I hope the title speaks by itself.
I believe that there should be a solution when I see what Mclust is
able to do. However, this problem is quite
particular in that d3 is not known and does not necessarily correspond
to a common distribution (e.g. normal, exponential ...).
However it mu
This might not be the correct forum for this question for there might be some
flaws in my logic so the R function I'm looking for might not be the
correct, but I know there’s a lot of smart people in this forum so please
correct me if I'm wrong. I have been googling and searching in this forum
for
Thank you all for the useful responses. Problem solved!
J
On Thu, Oct 23, 2008 at 12:14 AM, Duncan Murdoch <[EMAIL PROTECTED]>wrote:
> On 22/10/2008 5:02 PM, jonas garcia wrote:
>
>> Dear list:
>>
>>
>>
>> I have the following problem: From a vector like this:
>>
>> vec<- c("mud_1999_area_A", "g
Pradheep K E wrote:
Is there any way to disable the auto-complete feature when we index a named
list?
E.g: a <- list ('longname'=1, 'anothername'=2)
a$l will return 1 and a$a will return 2
the '[[' operator behaves in the same way, the '[' operator does not do
autocomplete.
Is there any way to d
On 22-Oct-08 23:04:34, Barry Rowlingson wrote:
> 2008/10/22 Erin Hodgess <[EMAIL PROTECTED]>:
>> This is for programming purposes.
>>
>> I wanted my students to do some games, but I wanted to see if there
>> were items already out there.
>
> A quick googling (oooh, if ONLY R was called something
On 22/10/2008 5:02 PM, jonas garcia wrote:
Dear list:
I have the following problem: From a vector like this:
vec<- c("mud_1999_area_A", "gravel_2004_area_F")
I would like to get the year in a separate vector, such
y<- c("1999", "2004")
I´ve been looking to grep() but I'm not sure how
I have a dataframe with many hundreds of survey records containing:
tripid_nu, lineon, MuchOtherData, X1, X2, X3, X4
tripid_nu = identifier for each "Trip" {E.g. for EB MTA-901
leaving the first stop at 07:24}
lineon = identifier for each of the stop locations
Where X1 is
2008/10/22 Erin Hodgess <[EMAIL PROTECTED]>:
> This is for programming purposes.
>
> I wanted my students to do some games, but I wanted to see if there
> were items already out there.
A quick googling (oooh, if ONLY R was called something more googly!)
found Duncan Murdoch's poker package:
http
Many thanks to all for their help. Factors are indeed very tricky and
sided on the conversion to character.
Kind regards,
Ivan
On 22 Oct 2008, at 19:01, Duncan Murdoch wrote:
On 10/22/2008 12:09 PM, Ivan Alves wrote:
Dear all,
Thanks for all the replies.
I get something with Duncan's code (s
Is there any way to disable the auto-complete feature when we index a named
list?
E.g: a <- list ('longname'=1, 'anothername'=2)
a$l will return 1 and a$a will return 2
the '[[' operator behaves in the same way, the '[' operator does not do
autocomplete.
Is there any way to disable autocomplete fo
Dear list:
I have the following problem: From a vector like this:
vec<- c("mud_1999_area_A", "gravel_2004_area_F")
I would like to get the year in a separate vector, such
y<- c("1999", "2004")
I´ve been looking to grep() but I'm not sure how to do this.
Help?
Thanks in advance
J
This is for programming purposes.
I wanted my students to do some games, but I wanted to see if there
were items already out there.
Thanks,
Erin
On Wed, Oct 22, 2008 at 10:39 AM, Greg Snow <[EMAIL PROTECTED]> wrote:
> Why do you want this? To play during a break? Or to demonstrate
> probabili
#sorry lets try that agian here is data that should work
a <- c(1:26)
b <- rnorm(26)
e <- rnorm(26)
f <- rnorm(26)
g <- data.frame(b,e, a,f)
On Wed, Oct 22, 2008 at 6:35 PM, stephen sefick <[EMAIL PROTECTED]> wrote:
> a <- c(1:26)
> b <- rnorm(25)
> e <- rnorm(25)
> f <- rnorm(25)
> g <- data.fra
a <- c(1:26)
b <- rnorm(25)
e <- rnorm(25)
f <- rnorm(25)
g <- data.frame(b,e, a,f)
I would like to plot a agianst all possibilities and then shoot it out
to a pdf one graph per page. I think it would be okay to have this as
a lattice plot or a ggplot with many graphs per page. I can figure
all
Essers, Jonah wrote:
So I recognize that:
1. many people hate forward stepwise regression (i've read the archives)--but I need it
Why?
-Frank
2. step() or stepAIC are two ways to get a stepwise regression in R
But here's the thing: I can't seem to figure out how to specify that I want t
Hi all,
I am playing with some companies' balance sheets and income statements
and want to apply what I've just learned from Stats class to see if I
can forecast the companies earnings, sales and gross margin in the
short term (3rd and 4th Quarter), mid-term (2009) and long term (2011,
etc. )
I p
Re Doug's comment:
I apologize for being incomplete--I do know better.
I did explicitly include a data statement in the models, but didn't
write the model statements properly in my post. Here are the actual
model statements:
mod1 <- lmer(y ~ category + subcomp + (1 | id), data=prepchiefs08rm)
On Wed, Oct 22, 2008 at 4:18 PM, Lawrence Hanser <[EMAIL PROTECTED]> wrote:
> Dear R Colleagues,
>
> I run the following two models:
>
> mod1 <- lmer(y ~ category + subcomp + (1 | id))
> mod2 <- lmer(y ~ category + subcomp + category*subcomp + (1 | id)
>
> where:
> category has 4 possible values
>
charter.net> writes:
>
> In the documentation for 'optim' it gives the following function:
>
> fr <- function(x) { ## Rosenbrock Banana function
> x1 <- x[1]
> x2 <- x[2]
> 100 * (x2 - x1 * x1)^2 + (1 - x1)^2
> }
> optim(c(-1.2,1), fr)
>
> When I run this code I get:
>
> $par
>
Dear R Colleagues,
I run the following two models:
mod1 <- lmer(y ~ category + subcomp + (1 | id))
mod2 <- lmer(y ~ category + subcomp + category*subcomp + (1 | id)
where:
category has 4 possible values
subcomp has 24 possible values
id has approx 120 values (id is nested within category, and in
Hi
I conducted a binomial GLM (with 3-factor) but I need to make a contrasts test
between the averages of the treatments; I need know what treatment are equal. I
know that the contrasts are used only in ANOVA I suppose that is incorrect
doing this in a glm, there is some way to make contrasts m
It might be your return statement. Look up 'return' in the help file
and you will see that you can only return a single value. If you want
multiple values returned, use a list:
return(listGmean,Gsd))
On Wed, Oct 22, 2008 at 11:53 AM, Alex99 <[EMAIL PROTECTED]> wrote:
>
> Hi there,
>
> I have a
Hi,
A repeatable example with data would help, as that way we could
see what was happening.
>
> sampling=function(fname,Total,nSample,nPatient){
> trans=t(A)
What's A? It isn't one of the arguments to your function.
And what's the transpose of a non-existent thing?
You may well have it in your
In the documentation for 'optim' it gives the following function:
fr <- function(x) { ## Rosenbrock Banana function
x1 <- x[1]
x2 <- x[2]
100 * (x2 - x1 * x1)^2 + (1 - x1)^2
}
optim(c(-1.2,1), fr)
When I run this code I get:
$par
[1] 1.000260 1.000506
I am sure I am missing someth
I think this has already been fixed in version 3.9-1.
Also, you probably want to add na.rm=TRUE to the call
svyby(~p_igov,~div_a,desenho_nps,svytotal,drop.empty.groups=TRUE,vartype
=c("se","var","cvpct"), na.rm=TRUE)
otherwise the estimated total will be NA whenever any observation is NA.
On 10/22/2008 12:52 PM, Greg Snow wrote:
Does anyone know how to change the background color of the script window(s) in
Rgui on Windows?
I can use the "Gui Preferences" menu item under the Edit menu has an option
that lets you change the background color for the console window and any help/inf
2008/10/22 Markus Schmidberger <[EMAIL PROTECTED]>
>
> Hi Marce,
>
> there is a new mailing list for R and HPC: [EMAIL PROTECTED]
> This is probably a better list for your question.
>
> Probably Rmpi does not find the correct Rmpi implementation. Have you
> installed a second mpi implementation (la
Hello all,
I have a question about CODA. Using my R code as bellow, I drew two graphs
(the data comes from the example of the speed of light in the Gelman’s book
“Bayesian Data Analysis (Second edition)” (page 77)). My R code is:
library(R2WinBUGS)
y=c(28, 26, 33, 24, 34, -44, 27, 16, 40, -2,
Hi Yihui,
Thank-you for this information. This is the code I am entering into RWeb
after loading my data file:
#subset the file to only include certain values:
test<-subset(X, GRADE == 7 & Y_Q10A < 9)
#sort the data by province and the variable Y_Q10A
mydata<-test
mydataSorted<-mydata[ orde
Hi there,
I have a the following function which takes a name(fname), total number of
rows (Total), number of times to make a sample(nSample), number of
records/rows to be included in each sample(nPatient). then it generates
required samples and calculates the mean and standard deviation of the
c
So I recognize that:
1. many people hate forward stepwise regression (i've read the archives)--but I
need it
2. step() or stepAIC are two ways to get a stepwise regression in R
But here's the thing: I can't seem to figure out how to specify that I want the
criteria to be Mallow's Cp (and th
Hello
Is there any R package which can do 3-D splines (reconstruct a surface
based 3-D data input) ?
Thanks,
Zhaoming
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-projec
You could do something like this:
> Name.x=c('nx1','nx2',NA,NA)
> Name.y=c('ny1','NA','ny3',NA)
> Name=Name.x
> Name[is.na(Name.x)]=Name.y[is.na(Name.x)]
> Name
[1] "nx1" "nx2" "ny3" NA
Julian
Ivan Alves wrote:
Dear all,
I searched the mail archives and the R site and found no guidance (t
Does anyone know an alternate way of calculating R2n with spatial data other
than converting values into ltraj format (adehabitat package)?
I have a series of geographic xy coordinates (in metres). I imagine I can
subtract x1y1 from x2y2 to get the spatial difference (dxdy), but what
function
Many thanks, Greg!
Now I know why I thought that this does not work: I probably tried it with the
string names of the columns and rows instead of their numbers. The former does
not work (I think).
Thanks to all again!
Werner
- Ursprüngliche Mail
Von: Greg Snow <[EMAIL PROTECTED]>
Subscript using a 2 column matrix with the rows in the first column and the
cols in the 2nd column, e.g.:
> x <- matrix(1:9, 3)
> x[ cbind( c(1,2,3), c(3,2,1) ) ]
[1] 7 5 3
Hope this helps,
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
801.40
There is a basic interface to gnuplot in the TeachingDemos package (see the
help on gp.open), but it does not do surface plots (yet, I am working on that).
One way to create the datafile with gaps is:
tmp <- 'nameofdatafile.txt'
tmp2 <- data.frame(x=x, y=y, z=z)
tmp2 <- t
I thought I've tried this already and that it doesn't work -- madness.
Anyway, Jeff kindly sent me the solution:
m[cbind(c(1,2,3),c(1,3,1))]
does the trick.
Thanks,
Werner
Hi,
this is probably a very trivial question but I can't figure out the right terms
to find the solution in the list
Hi,
this is probably a very trivial question but I can't figure out the right terms
to find the solution in the list archive.
I have a matrix or a data.frame or the like:
> m <- matrix(ncol=3,seq(1,9))
> m
[,1] [,2] [,3]
[1,]147
[2,]258
[3,]369
and now I
On 22-Oct-08 17:09:27, Dennis Fisher wrote:
> Colleagues,
> I am working on a problem at the edge of my knowledge of statistics.
>
> Basically, I have values for two groups - I am trying to calculate the
> 90% confidence limits for the difference between means. I can
> implement this without d
Hi,
Should be a quickie:
I want to make a datafile in R for plotting in gnuplot (which has
friendlier 3D plotting options, as far as I can tell). So, I want to
create a file with contents along the lines of
#File begins
0 0 10
0 13 10
0.2 2 10
1 0 10.12
1 1 5
1 2 10
2 0 10
2 1 1
2 2 10
It's p
On Wed, Oct 22, 2008 at 1:57 PM, Borja Soto Varela <[EMAIL PROTECTED]> wrote:
> Dear R-users
>
> I would like to fit weibull parameters using "Method of moments" in order to
> provide the inital values of the parameter to de function 'fitdistr' . I
> don`t have much experience with maths and I don'
On 10/22/2008 12:52 PM, Greg Snow wrote:
Does anyone know how to change the background color of the script window(s) in
Rgui on Windows?
I can use the "Gui Preferences" menu item under the Edit menu has an option
that lets you change the background color for the console window and any help/inf
Those are the results that print, not what you get. Try saving the results of
the test in an object, then examine the saved object with the str function.
Then reread the section in "An Introduction to R" on extracting pieces of
lists. A reread of the help page for kruskal.test, specifically t
Colleagues,
I am working on a problem at the edge of my knowledge of statistics.
Basically, I have values for two groups - I am trying to calculate the
90% confidence limits for the difference between means. I can
implement this without difficulty based on standard equations that are
avail
On 10/22/2008 12:09 PM, Ivan Alves wrote:
Dear all,
Thanks for all the replies.
I get something with Duncan's code (slightly more compact than the
other two), but of class "integer", whereas the two inputs are class
"factor". Clearly the name information is lost. I did not see
anything on
Hello all,
I've searched the lists and the web and not found an obvious answer to
this; my apologies if I'm overlooking something.
I've used 2.6.x for awhile; this morning, after installing 2.8.0 on my
Mac OS X 10.5.5 machine, neither install.packages nor the "Packages &
Data/Package Ins
Does anyone know how to change the background color of the script window(s) in
Rgui on Windows?
I can use the "Gui Preferences" menu item under the Edit menu has an option
that lets you change the background color for the console window and any
help/info windows that pop up, but the script wind
Marcus Vinicius gmail.com> writes:
>
> Dear all,
> Is there anyone that may help me to use complex numbers and Bayesian
> Statistical Modelling?
> Thanks a lot.
> Best regards.
> Marcus Vinicius
>
This is a very vague question with little clear connection
to R. R has lots of capabilities fo
You may or may not see speed substantial improvements using Rmpi with
(or without) snow but you might -- depends on how the cluster is
configured, what version of MPI, etc.
In my experience using snow with sockets, pvm, or LAM/MPI for typical
computations running an a multi-core machine vs remote
subkeys.pgp.net has 6 IP addresses, but all of them seem to
have the key now.
el
On 22 Oct 2008, at 17:05 , Martyn Plummer wrote:
Have you tried other keys? (mine is 97D3544E if you want to try).
If nothing works then it is probably a firewall problem. Ask your
network administrator if port
Does this help point you in a useful direction?
> a <- matrix(1:9, 3) * 10
> b <- matrix(1:9, 3)
> kronecker(b,a)
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
[EMAIL PROTECTED]
801.408.8111
> -Original Message-
> From: [EMAIL PROTECTED] [mailto:[EMA
Thanks you! I'll look at this new list!
Well, I'm not the system administrator, and my installation of Rmpi and/or
pvm libraries for R crashes. As this is the first time I parallelize some
jobs, snow appealed as a first approach because 1) it compiled correctly
and 2) the use of the library is very
Dear all,
Thanks for all the replies.
I get something with Duncan's code (slightly more compact than the
other two), but of class "integer", whereas the two inputs are class
"factor". Clearly the name information is lost. I did not see
anything on this in the help page for ifelse.
On thi
Hi Marce,
there is a new mailing list for R and HPC: [EMAIL PROTECTED]
This is probably a better list for your question.
Probably Rmpi does not find the correct Rmpi implementation. Have you
installed a second mpi implementation (lammpi)?
How do you have installed Rmpi?
Did you compiled it to the
Hi Javier,
there is a new mailing list for R and HPC: [EMAIL PROTECTED]
This is probably a better list for your question.
I never tried torque with socket. We use torque and mpi or pvm (and R)
and it is working very well.
Why do you use socket as communication layer?
MPI was especially developed
hadley wickham wrote:
> On Wed, Oct 22, 2008 at 9:34 AM, Duncan Murdoch <[EMAIL PROTECTED]> wrote:
>
>> On 10/22/2008 10:02 AM, francois Guilhaumon wrote:
>>
>>> Hello,
>>>
>>> I'm looking for a way to get the "name" of an object when it is used
>>> within an "sapply".
>>>
>>> More precisel
Hi all,
now I'm testing R in a "virtual cluster", made it with VirtualBox. This one
has 3 nodes, running CentOS 5 and OpenMPI 1.2.8, and the principal node
(called "server") exports the /home to other nodes.
I have installed R and OpenMPI in /home, in fact, it seems work OK. Editing
the openmpi-def
Why do you want this? To play during a break? Or to demonstrate probabilities?
Or to simulate games using different strategies?
There are some functions with names like card.game in the kappalab package, but
they don't look like they do the type of card game you play. If you just want
to play
Well this is interesting. I have a working java setup (using OpenJDK).
But I can break it by running "R CMD javareconf -e". This command
exports a number of JAVA_* environment variables. The rJava configure
script uses these instead of querying R, but the compilation then fails.
It seems that the
On 10/22/2008 11:21 AM, Ivan Alves wrote:
Dear all,
I searched the mail archives and the R site and found no guidance
(tried "merge", "cbind" and terms like "coalesce" with no success).
There surely is a way to coalesce (like in SQL) columns in a
dataframe, right? For example, I would li
Not tested, but for data.frame 'df', try
df$coal <- ifelse(!is.na(df$Name.x), df$Name.x, df$Name.y)
But see the help page for 'ifelse' regarding issues with classes, and
the myriad R-help posts on the 'ifelse' function.
Erik
Ivan Alves wrote:
Dear all,
I searched the mail archives and the
Doug Bates is the authority of course, but perhaps a couple of quick inline
comments may suffice:
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of Mitchell Maltenfort
Sent: Wednesday, October 22, 2008 7:41 AM
To: r-help@r-project.org
Subject: [R] Think I'm
Hi everyone,
I am working on analyzing spectra which requires hundreds of kruskal wallis
tests to be performed. Once significant results are found post tests are
performed ect. My questions are: how do I perform all these kw tests and
save just the pvalues in a table? Is there anyway to have R
Selwyn McCracken wrote:
> Hi list,
>
> I want to find the total maximum resources I can spend given a set
> allocation proportion and some simple budget constraints.
>
> However, I get suboptimal results via lp and friends (i.e. lpSolve and
> simplex in the linprog and boot) .
>
> For example:
>
>
Bert, you've been very helpful. It sounds like for my meagre needs,
nlme is what I should stick with. However, I'll wait for Bates to
weigh in on the pros and cons of each. Thanks!
On Wed, Oct 22, 2008 at 11:23 AM, Bert Gunter <[EMAIL PROTECTED]> wrote:
> Doug Bates is the authority of course,
Hi list,
I want to find the total maximum resources I can spend given a set
allocation proportion and some simple budget constraints.
However, I get suboptimal results via lp and friends (i.e. lpSolve and
simplex in the linprog and boot) .
For example:
library(lpSolve)
proportions = c( 0.46, 0
Dear all,
I searched the mail archives and the R site and found no guidance
(tried "merge", "cbind" and terms like "coalesce" with no success).
There surely is a way to coalesce (like in SQL) columns in a
dataframe, right? For example, I would like to go from a dataframe
with two column
Thank you. This was very helpful.
-Original Message-
From: Gabor Grothendieck [mailto:[EMAIL PROTECTED]
Sent: Tuesday, October 21, 2008 6:22 PM
To: Boyce, Morgan
Cc: R-help@r-project.org
Subject: Re: [R] R Help
You can't mix character and numeric in a zoo object.
Also note that lag.zoo c
It is solved.
The query on http://keyserver.noreply.org/ with the key (E2A11821) does
not work but typing "Vincent Goulet" works fine...
Thanks a lot
Martyn Plummer wrote:
Have you tried other keys? (mine is 97D3544E if you want to try).
If nothing works then it is probably a firewall problem
Hi,
Iâm using the svyby for total statistics, for example:
svyby(~p_igov,~div_a,desenho_nps,svytotal,drop.empty.groups=TRUE,vartype
=c("se","var","cvpct"))
In the numerical variable p_igov (and others) I have many non responses
but if I maintain the NA it doesnât work.
summary(base
Dear all, I am new to this stuff. I need to fetch certain values from the
database and crate a curve fitting for the same using ROracle. I would like
to know how to work with R for that. I have been able to do something with
the code attached with this post. If anyone can help me in this regards,
Thanks for the many answers I received.
This is becoming a nightmare and I am concluding that installing java1.6
in CentOS5 is particularly hard, specially if you installed previous jdk
versions...
I tryed a wide range of solutions. I resume some of them:
1) Tryed to reinstall jdk1.6 and use
Have you tried other keys? (mine is 97D3544E if you want to try).
If nothing works then it is probably a firewall problem. Ask your
network administrator if port 11371 is blocked.
When I had this problem, neither "gpg --recv-keys" nor the web interface
at wwwkeys.pgp.net worked for me.
Martyn
O
Hi, Sorry for the confusion but I am looking to use R for regression
trees.
My query is stated below and I am not able to understand how can I use
tree library in this case
Rahul Agarwal
Analyst
Equities Quantitative Research
UBS_ISC, Hyderabad
On Net: 19 533 6363
-Original Message-
All right, I'll wait and see then.
Thanks
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, rep
On Wed, Oct 22, 2008 at 9:34 AM, Duncan Murdoch <[EMAIL PROTECTED]> wrote:
> On 10/22/2008 10:02 AM, francois Guilhaumon wrote:
>>
>> Hello,
>>
>> I'm looking for a way to get the "name" of an object when it is used
>> within an "sapply".
>>
>> More precisely, with a simple example :
>>
>> I have a
The impression I get from the list and the references I've perused is
that nlme is being phased out in favor of lme4, but lme4 still doesn't
have a complete feature set yet.
What I'm still fuzzy on, being a relative R newbie, is:
(a) what features in nlme are currently missing in lme4
(b) what's
No, I did
gpg --keyserver subkeys.pgp.net --recv-key E2A11821
I am getting broken packages unmet dependencies, but maybe
it'll take a while for everything to propagate :-)-O
el
on 10/22/08 4:31 PM Renaud Gaujoux said the following:
> Hi,
>
> well... that is what I would like to see indeed. :
Hi,
Does anyone know why the package MCRestimate is not part of the BioConductor
2.2 anymore?
I am looking for package doing support vector machine analyses including (i)
variable/feature selection and (ii) parameter tuning in one learning period.
Many thanks,
Stefan
--
On 10/22/2008 10:02 AM, francois Guilhaumon wrote:
Hello,
I'm looking for a way to get the "name" of an object when it is used
within an "sapply".
More precisely, with a simple example :
I have a named list of objects :
myList = list(a=rnorm(10),b=rnorm(10),c=rnorm(10))
I would like to creat
Hi list,
I want to find the total maximum resources I can spend given a set
allocation proportion and some simple budget constraints.
However, I get suboptimal results via lp and friends (i.e. lpSolve and
simplex in the linprog and boot) .
For example:
library(lpSolve)
proportions = c( 0.46, 0
Hi,
well... that is what I would like to see indeed. :(
But I keep getting my error, what's bothering me is that the web-based
tools also does not find the key...
Did you also try on http://keyserver.noreply.org/?
thanks
Dr Eberhard Lisse wrote:
gpg: requesting key E2A11821 from hkp server
gpg: requesting key E2A11821 from hkp server subkeys.pgp.net
gpg: key E2A11821: public key "Vincent Goulet
<[EMAIL PROTECTED]>" imported
gpg: no ultimately trusted keys found
gpg: Total number processed: 1
gpg: imported: 1
on 10/22/08 3:42 PM Renaud Gaujoux said the following:
> Hi,
Hi,
I'm trying to use ad.test or ad2.test to test whether a given data set is
exponential. I see that one of the function inputs is "distn", but I try
"exponential" and 5 other variants, but I still get the error message:
ad.test(test2, distn="exponential", fit=list(estimate = 0.167685), H=NA,
s
Hello,
I'm looking for a way to get the "name" of an object when it is used
within an "sapply".
More precisely, with a simple example :
I have a named list of objects :
myList = list(a=rnorm(10),b=rnorm(10),c=rnorm(10))
I would like to create a new object from each of the components of
myList
1 - 100 of 128 matches
Mail list logo
