Hi,
There is a command or a function for One way ANOVA if I know the
numbers of subjects for each group, the mean and di standard deviation
for each group?
Thanks
Angelo Scozzarella
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mai
See also bigglm() in package biglm.
On Sat, 9 Aug 2008, Pradheep K E wrote:
Hi R-experts,
Does anyone have experience using R for handling large scale data (millions
of rows, hundreds or thousands of features)?
What is the largest size of data that anyone has used with glm?
I've used 700,00
In apparently a late response to
https://stat.ethz.ch/pipermail/r-help/2008-July/169578.html
on Sat, 9 Aug 2008, Andrew Harris wrote:
For cross-building a mature package, I stumbled across a convenient utility
provided by the R Windows maintainer:
_http://win-builder.r-project.org/
It is in
Hi,
I want to plot the mean of a variable and add the standard deviation
as a line going above and below the mean (like the whiskers in a
boxplot) but I don't know how to add these residual-lines.
Is there an easy way to do that or do I have to use the line()-
function to create them on my
For cross-building a mature package, I stumbled across a convenient
utility provided by the R Windows maintainer:
_http://win-builder.r-project.org/
_This takes a little while, so for iteration it is much better to
install the Rtools, but for a package or two it is great.
Best,
Andrew Harris,
Hi R-experts,
Does anyone have experience using R for handling large scale data (millions
of rows, hundreds or thousands of features)?
What is the largest size of data that anyone has used with glm?
Also, is there a library to read data in sparse data format (like SVMlight
format)?
Thanks
Pradh
I have a vector:
alleles.present<-c("D3", "D16", ... )
The alleles present changes given the case I'm dealing with - i.e. either
all of the alleles I use for my calculations are present, or some of them.
Depending on what alleles are present, I need to make matrices and do
calculations on those a
Resending. Previous message was truncated. Sorry for possible confusion.
> From: [EMAIL PROTECTED]
> To: r-help@r-project.org
> Date: Sat, 9 Aug 2008 18:25:47 -0400
> Subject: [R] Converting nested "for" loops to an "apply" function(s)
>
>
> Hello,
>
par(bty="l")
boxplot(count ~ spray, data = InsectSprays, col = "lightgray")
#is that what you want?
Stephen
Thanks! That's what I needed.
On Sat, Aug 9, 2008 at 8:12 PM, Jörg Groß <[EMAIL PROTECTED]>
wrote:
Hi,
I want to draw a boxplot and I want to get rid of the surrounding
box.
Hello all,
I recently installed rgdal 0.5.24-1 (kyngchaos framework) and I am having
trouble making sense of the row, col information provided.
> a = new("GDALDataset", "dummy.tif")
> GDALinfo("dummy.tif")
rows420
columns 660
bands 1
ll.x-55.5
ll.y-14.5
res.x
par(bty="l")
boxplot(count ~ spray, data = InsectSprays, col = "lightgray")
#is that what you want?
Stephen
On Sat, Aug 9, 2008 at 8:12 PM, Jörg Groß <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I want to draw a boxplot and I want to get rid of the surrounding box.
> So that there are only the axis lines
Hi,
I want to draw a boxplot and I want to get rid of the surrounding box.
So that there are only the axis lines left on the bottom and on the
left.
I tried a litte bit with box() but I dont get it the way I want.
Can somebody help me out?
__
R-he
Dear Marc,
Marc Schwartz wrote:
>
> On Fri, 2007-05-18 at 11:25 -0400, Hao Liu wrote:
>> Dear All:
>>
>> I am running some GUI functions in linux environment, they runs fine,
>> however I constantly get this kind of message in R console:
>>
>> Warning: X11 protocol error: BadWindow (invalid
It seems that this solution provided by Dan (and also available in
SPoetry; I'm sorry I didn't notice it) is the fastest and simplest. I was
using a more standard approach:
V <- t(A)[(0:(nrow(A)-1))*ncol(A)+X],
That wasn't bad, but I was confident that you, R gurus, could outperform
this. This is
Felipe Carrillo wrote:
Hi Ted:
Thanks for your prompt reply and explanation.
That's what I was wondering, why would one need to test mu=0 ,which is the t.test default. But reading Peter Dalgaard's book and looking at some examples online, I saw t.test being used like that; t.test(datasetname) wi
Hello,
I would like to know more about how to use the "apply" family and have
attempted to convert nested "for" loops in example code from Contributed
Documentation ("The Friendly Beginners' R Course” by Toby Marthews (ZIP,
2007-03-01)") to an "apply" function(s). The relevant code is:
dista
I take it back, Peter Dalgaard's book uses t.test with mu=7725 and no mu=0. I
got the script online.
Hi Ted:
Thanks for your prompt reply and explanation.
That's what I was wondering, why would one need to test mu=0 ,which is the
t.test default. But reading Peter Dalgaard's book and looking at
Hi Ted:
Thanks for your prompt reply and explanation.
That's what I was wondering, why would one need to test mu=0 ,which is the
t.test default. But reading Peter Dalgaard's book and looking at some examples
online, I saw t.test being used like that; t.test(datasetname) with no other
arguments.
On Saturday 09 August 2008 23:25, Arne Henningsen wrote:
> > -Original Message-
> > From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
> > Sent: Monday, August 04, 2008 5:15 PM
> > To: Zhang Yanwei - Princeton-MRAm
> > Subject: RE: [R] Multivariate Regression with Weights
> >
> > the syste
On 09-Aug-08 20:31:33, Felipe Carrillo wrote:
># Hi all:
> #I got a vector with fish lengths(mm)
> # Can someone help me interpret the output of
> # a t.test in plain english?
> # Based on the t.test below I can say that
> # I reject the null hypothesis because
> # th
> -Original Message-
> From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
> Sent: Monday, August 04, 2008 5:15 PM
> To: Zhang Yanwei - Princeton-MRAm
> Subject: RE: [R] Multivariate Regression with Weights
>
> the systemfit package can do that and the documentation is quite nice
> also.
T
# Hi all:
#I got a vector with fish lengths(mm)
# Can someone help me interpret the output of
# a t.test in plain english?
# Based on the t.test below I can say that
# I reject the null hypothesis because
# the p-value is smaller than the the significance
# leve
I believe tsdiag() uses the correct degrees of freedom in applying Box.test,
but the graphic shows "lag" on the horizontal axis when it should display
"degrees of freedom".
raf.rossignol wrote:
>
> Hello,
>
> Prof Brian Ripley wrote:
>>
>> I think you are referring to its application to t
on 08/09/2008 12:45 PM Marc Schwartz wrote:
on 08/09/2008 12:13 PM Charles C. Berry wrote:
On Fri, 8 Aug 2008, Kenn Konstabel wrote:
There's more to this trend: SPSS and Statistica now advertise "R
language
support" :
http://www.statsoft.com/industries/Rlanguage.htm
http://www.spss.com/spssd
on 08/09/2008 12:13 PM Charles C. Berry wrote:
On Fri, 8 Aug 2008, Kenn Konstabel wrote:
There's more to this trend: SPSS and Statistica now advertise "R language
support" :
http://www.statsoft.com/industries/Rlanguage.htm
http://www.spss.com/spssdirections/na/sessions.cfm?sessionType=2
If
On Fri, 8 Aug 2008, Kenn Konstabel wrote:
There's more to this trend: SPSS and Statistica now advertise "R language
support" :
http://www.statsoft.com/industries/Rlanguage.htm
http://www.spss.com/spssdirections/na/sessions.cfm?sessionType=2
If you can't beat R, join R.
---
Should someone s
I have mange to use the library reshape to give me data structures that I want.
Specifically:
m2008 <- melt(t2008, id.var=c("DayOfYear","Category","SubCategory","Sku"),
measure.var=c("Quantity"))
m2007 <- melt(t2007, id.var=c("DayOfYear","Category","SubCategory","Sku"),
measure.var=c("Quantity
On Sat, 9 Aug 2008, baptiste auguie wrote:
Thank you all for the precious tips. For memory I've made the following
wrapper function for this. I wonder whether a short note on these regular
expressions could be useful on the help page of cut().
Already there in R-devel
cutIntervals <
On Mon, 28 Jul 2008, Nutter, Benjamin wrote:
Try sourcing in the 'new.legend' function below. It's the legend
function with a new argument called 'box.col'. The argument will change
the color of the box surrounding the legend. If I understand what it is
you are looking for, this should work.
on 08/09/2008 06:52 AM Dan Davison wrote:
On Sat, Aug 09, 2008 at 06:29:59AM -0500, Marc Schwartz wrote:
on 08/09/2008 06:01 AM [EMAIL PROTECTED] wrote:
Hi;
If we have a matrix A, and a vector X, where length(X)=nrow(A), and X
contains a wanted column for each row in A, in row ascending order.
Thank you all for the precious tips. For memory I've made the
following wrapper function for this. I wonder whether a short note on
these regular expressions could be useful on the help page of cut().
cutIntervals <- function(x, ...){
dotArgs <- unlist(c(...))
if( any(names(dotArgs
On Fri, 2008-08-08 at 16:04 -0300, Megan J Bellamy wrote:
> Hello all,
>
> I have created a barplot that shows change in hardwood/softwood density from
> 1965 to 2005 in 5 year periods (1965,1970, etc). I would like to have an
> X-axis where the labels for the years line up after every two bars
Hi Tom,
>> 1|ass%in%pop%in%fam
This is "non-standard," but as you have found, it works. The correct
translation is in fact
1|fam/pop/ass
and not 1|ass/pop/fam as suggested by Harold Doran. Dropping %,
ass%in%pop%in%fam reads [means] as: nest ass in pop [= pop/ass], and then
nest this in fam ==
On Sat, Aug 09, 2008 at 06:29:59AM -0500, Marc Schwartz wrote:
> on 08/09/2008 06:01 AM [EMAIL PROTECTED] wrote:
>> Hi;
>> If we have a matrix A, and a vector X, where length(X)=nrow(A), and X
>> contains a wanted column for each row in A, in row ascending order. How
>> would be the most effective
on 08/09/2008 06:01 AM [EMAIL PROTECTED] wrote:
Hi;
If we have a matrix A, and a vector X, where length(X)=nrow(A), and X
contains a wanted column for each row in A, in row ascending order. How
would be the most effective way to extract the desired vector V (with
length(V)=nrow(A))?
A <- matri
Hi;
If we have a matrix A, and a vector X, where length(X)=nrow(A), and X
contains a wanted column for each row in A, in row ascending order. How
would be the most effective way to extract the desired vector V (with
length(V)=nrow(A))?
Wishes,
Javier
__
On Sat, 9 Aug 2008, baptiste auguie wrote:
Dear list,
I have the following example, from which I am hoping to retrieve numeric
values of the factor levels (that is, without the brackets):
x <- seq(1, 15, length=100)
y <- sin(x)
my.cuts <- cut(which(abs(y) < 1e-1), 3)
levels(my.cuts)
his
I think a bit of standardization and commercial exposure would help R, given
the fact it is much much better than any other expensive stats package yet
has no gotten the market share it deserves because everyone is either
building it or using it, hence no one has actually taken the effort to
promot
Hi all,
with a lot more fiddling around, I've come up with this solution:
x <- seq(1, 15, length=100)
y <- jitter(cos(x), a=0.2)
plot(x, y)
findZero <- function(x, y, guess = mean(range(x)), exclusion=
5*diff(range(x))/length(x))
{
interval <- c(guess - exclusion, guess+exc
Not sure what you're looking for, but does this help?
Extending your code,
> library(gsubfn)
> t(strapply(levels(my.cuts),"([0-9.]+),([0-9.]+)",
+ function(...) as.numeric(c(...)),backref=-2,simplify=TRUE))
[,1] [,2]
[1,] 15.9 38.3
[2,] 38.3 60.7
[3,] 60.7 83.1
- Original Mes
Dear list,
I have the following example, from which I am hoping to retrieve
numeric values of the factor levels (that is, without the brackets):
x <- seq(1, 15, length=100)
y <- sin(x)
my.cuts <- cut(which(abs(y) < 1e-1), 3)
levels(my.cuts)
hist() does not suit me for this, as it does n
On Fri, Aug 08, 2008 at 07:27:13PM -0700, Alessandro wrote:
> Hi All.
>
>
>
> I have a file txt with 3 columns (X, Y and Z). every rows has 4 decimal
> place (i.e. x.). I use read.table to import the data in R, but with
> summary(), I don't see the decimal place after the dot. Is there any
On Fri, Aug 08, 2008 at 04:44:13PM -0700, Alessandro wrote:
> Hi All,
>
>
>
> I have 2 questions:
>
> 1. Import: when I import my txt file (X,Y and Z) in R with "testground
> <- read.table(file="c:/work_LIDAR_USA/R_kriging/ground26841492694149.txt",
> header=T)", I lost the 4 number afte
On 09.08.2008 01:05 (UTC+1), Deepayan Sarkar wrote:
On Fri, Aug 8, 2008 at 2:38 PM, Rainer Hurling <[EMAIL PROTECTED]> wrote:
Dear community,
I am looking for a possibility to draw 'regression lines' instead of
'smooth' lines in grouped xyplots. The following code should give you a
small exampl
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