Did the original PEP discussion cover debates about the shortcut
working for all assignment operators (like += and x[i] =) and the
difference between it being one-shot (doesnt affect x for the rest of
the function) or simply the unrolling into nonlocal x; x= y as it is?
On Mon, Dec 8, 2008 at 5:07
On Sun, Dec 7, 2008 at 2:45 PM, Amaury Forgeot d'Arc <[EMAIL PROTECTED]> wrote:
> Hello,
>
> Fabio Zadrozny wrote:
>> Hi,
>>
>> I'm currently implementing a parser to handle Python 3.0, and one of
>> the points I found conflicting with the grammar specification is the
>> PEP 3104.
>>
>> It says th
>> I'm currently implementing a parser to handle Python 3.0, and one of
>> the points I found conflicting with the grammar specification is the
>> PEP 3104.
>>
>> It says that a shortcut would be added to Python 3.0 so that "nonlocal
>> x = 0" can be written. However, the latest grammar specificati
Fabio Zadrozny wrote:
Hi,
I'm currently implementing a parser to handle Python 3.0, and one of
the points I found conflicting with the grammar specification is the
PEP 3104.
It says that a shortcut would be added to Python 3.0 so that "nonlocal
x = 0" can be written.
As near as I can tell fr
Hello,
Fabio Zadrozny wrote:
> Hi,
>
> I'm currently implementing a parser to handle Python 3.0, and one of
> the points I found conflicting with the grammar specification is the
> PEP 3104.
>
> It says that a shortcut would be added to Python 3.0 so that "nonlocal
> x = 0" can be written. Howeve
