On Mon, Jan 19, 2015 at 03:22:36PM -0800, marc.coiff...@gmail.com wrote:
> Here is the minimal code sample to reproduce the bug (present in version 4.2,
> corrected in 4.3 as far as I can tell) :
>
> arr1=( "" "" )
> arr2=( "${arr1[@]:1}" )
Seems to be either a Debian-specific bug, or a bug
Hi,
It seems with bash 4.3.30(1)-release (and probably others) that embedded
functions are output with a leading 'function ' keyword when using declare
-f / typeset -f. This is different to all other shells that support declare
/ typeset that I've tested (pdksh, mksh, Mac OS X ksh, which I think i
On 1/20/15 9:09 AM, Raphael Cohn wrote:
> Hi,
>
> It seems with bash 4.3.30(1)-release (and probably others) that embedded
> functions are output with a leading 'function ' keyword when using declare
> -f / typeset -f. This is different to all other shells that support declare
> / typeset that I'v
Chet,
Thank you. I'll look at a regex hack-up...
Raph
On 20 January 2015 at 15:58, Chet Ramey wrote:
> On 1/20/15 9:09 AM, Raphael Cohn wrote:
> > Hi,
> >
> > It seems with bash 4.3.30(1)-release (and probably others) that embedded
> > functions are output with a leading 'function ' keyword wh
> Seems to be either a Debian-specific bug, or a bug that was fixed in a
> later patch than Debian is using.
Great ! Thank you for the quick response.
If you have time for a followup question, do you know who I should contact to
get these patches pushed to Debian ? I am writing a completion help
On Tue, Jan 20, 2015 at 01:39:02PM -0800, marc.coiff...@gmail.com wrote:
> If you have time for a followup question, do you know who I should contact to
> get these patches pushed to Debian ? I am writing a completion helper library
> (based on parser combinators) and it needs this feature to funct
On Tue, Jan 20, 2015 at 01:39:02PM -0800, marc.coiff...@gmail.com wrote:
> > Seems to be either a Debian-specific bug, or a bug that was fixed in a
> > later patch than Debian is using.
>
> Great ! Thank you for the quick response.
>
> If you have time for a followup question, do you know who I s