How can i specify a multi line shell instruction as a recipe? The
following returns an error:
makefile27:
e14:
@echo var1=$(var1)
makefile25:
include makefile27
e12:
@echo insidee12
makefile27: e13
if ( test $$count -eq 0) then echo "all: ;echo ppp" >
makefile27;count=1;f
On Sun, Apr 10, 2011 at 6:17 PM, ali hagigat wrote:
> How can i specify a multi line shell instruction as a recipe? The
> following returns an error:
>
> makefile27:
> e14:
>@echo var1=$(var1)
>
> makefile25:
> include makefile27
> e12:
>@echo insidee12
> makefile27: e13
>
Thanks Clark for the reply. 'count' is set by shell before doing make. like
root> count=0
On Sun, Apr 10, 2011 at 3:10 PM, Clark J. Wang wrote:
> On Sun, Apr 10, 2011 at 6:17 PM, ali hagigat wrote:
>>
>> How can i specify a multi line shell instruction as a recipe? The
>> following returns an er
> root> count=0
>
You didn't export it.
On Sun, Apr 10, 2011 at 7:30 PM, ali hagigat wrote:
> Thanks Clark for the reply. 'count' is set by shell before doing make. like
> root> count=0
>
>
Have you exported the 'count' var before invoking make?
> On Sun, Apr 10, 2011 at 3:10 PM, Clark J. Wang
> wrote:
> > On Sun, Apr 10, 2011 at 6
I am seeing what appears to be some sort of UTF-8 conversion issue in
bash-4.2. I do not see this in bash 4.1. I think the easiest way to
describe this is:
> bash41 --version
GNU bash, version 4.1.9(2)-release (i686-pc-linux-gnu)
> LC_ALL=ru_RU.UTF-8 bash41 -c привет
bash: привет: command
