On Sun, Apr 10, 2011 at 6:17 PM, ali hagigat <hagigat...@gmail.com> wrote:
> How can i specify a multi line shell instruction as a recipe? The > following returns an error: > > makefile27: > e14: > @echo var1=$(var1) > > makefile25: > include makefile27 > e12: > @echo insidee12 > makefile27: e13 > if ( test $$count -eq 0) then echo "all: ;echo ppp" > > makefile27;count=1;fi > When you test $count it's not assigned with a value yet. > e13: ; > > make -f makefile25 > if ( test $count -eq 0) then echo "all: ;echo ppp" > makefile27;count=1;fi > /bin/sh: line 0: test: -eq: unary operator expected > var1= > > Why it complains about needing a unary operator? > > -- Clark J. Wang
