Re: in-line calls to functions cause "exit" in the function to act like "return"

On 12/18/21 8:07 AM, yesxorno via Bug reports for the GNU Bourne Again SHell wrote: > When 'exit' is executed in a function called to "in-line" its output to > stdout, the 'exit' acts like return, leaving the function scope, but not > terminating the bash process. I assume by "in-line" you

Re: in-line calls to functions cause "exit" in the function to act like "return"

x=$( exit 2 ) ; printf $?\\n On Sat, Dec 18, 2021, 17:03 Kerin Millar wrote: > On Sat, 18 Dec 2021 13:07:03 + > yesxorno via Bug reports for the GNU Bourne Again SHell > wrote: > > > Description: > > > > When 'exit' is executed in a function called to "in-line" its output to > stdout, the '

Re: in-line calls to functions cause "exit" in the function to act like "return"

On Sat, 18 Dec 2021 13:07:03 + yesxorno via Bug reports for the GNU Bourne Again SHell wrote: > Description: > > When 'exit' is executed in a function called to "in-line" its output to > stdout, the 'exit' acts like return, leaving the function scope, but not > terminating the bash proces

Re: in-line calls to functions cause "exit" in the function to act like "return"

you execute it in a separate bash subshell via $( .. ) this code parsing layer u bring to exit On Sat, Dec 18, 2021, 16:50 yesxorno via Bug reports for the GNU Bourne Again SHell wrote: > (Composed using 'bashbug')