On Sat, 18 Dec 2021 13:07:03 +0000
yesxorno via Bug reports for the GNU Bourne Again SHell <bug-bash@gnu.org>
wrote:
> Description:
>
> When 'exit' is executed in a function called to "in-line" its output to
> stdout, the 'exit' acts like return, leaving the function scope, but not
> terminating the bash process.
It does, in fact, exit the subshell in question.
>
> Repeat-By:
>
> Sample script:
>
> #!/bin/bash
>
> set -x
>
> function bar()
> {
> exit 1
> }
>
> foo="$(bar)"
Here, the use of a command substitution causes a subshell to be created. The
command, exit 1, is not run by the shell that the kernel loaded to interpret
your script.
--
Kerin Millar
