Re: eval a=b\ c

OK, I can make it to work in bash if I say echodo a=b\\ c but then zsh tries to execute c. Can’t win. The problem is: how do I write this function so that it can be invoked identically in zsh and bash with identical results of setting a variable to a value with a space in it? > On 2015-05-26,

typo in bash manual

In http://www.gnu.org/software/bash/manual/bashref.html#GNU-Parallel Where you say ls *.gz | parallel -j+0 "zcat {} | bzip2 >{.}.bz2 && rm {}" This will recompress all files in the current directory with names ending in .gz using bzip2, running one job per CPU (-j+0) in parallel. it should be ls

RFE: a way to echo the arguments with quoting

I have an ugly function I wrote for zsh that does this: Sat 14:17:25 ip2 yost /Users/yost 1 634 Z% echo-quoted xyz \$foo 'a b c ' '\n' xyz '$foo' 'a b c ' '\n' Sat 14:17:53 ip2 yost /Users/yost 0 635 Z% It would be nice if there were an easy way to do this in bash. Here is my use case: echo-c

Re: bash problem with #!, rev 2

Thanks for your learned analysis. 1. I kind of like the way zsh handles it. 2. In any case, I'll use #!/usr/bin/env http://Yost.com/computers/compileAndGo 3. I'll change my pages to reflect the change by around noon 15:00 UTC+8. Thanks again. Dave ___

bash problem with #!, rev 2

[added a diagnosis near the end.] Please see http://Yost.com/computers/compileAndGo That page describes a #!/bin/bash script called compileAndGo, which is used as the program for a #! script. In other words, a program starting with #!/usr/local/bin/compileAndGo should invoke /usr/local/bi

bash problem with #!

Please see http://Yost.com/computers/compileAndGo That page describes a #!/bin/bash script called compileAndGo, which is used as the program for a #! script. In other words, a program starting with #!/usr/local/bin/compileAndGo should invoke /usr/local/bin/compileAndGo, and compileAndGo is