Re: "jobs" builtin: print zero exit status

On 9/12/13 6:14 AM, Dmitry Bolshakov wrote: >Hi! >imho "jobs" should either print zero exit status or it should be >documented that "Done" means zero exit status >$ bash -c 'set -m; perl -e "sleep 1; exit 123"& { sleep 3; jobs -l; }' >[1]+е║ Exit 123е║е║е║е║е║е║е║е║е║е║е║е║е║е║е

"jobs" builtin: print zero exit status

Hi! imho "jobs" should either print zero exit status or it should be documented that "Done" means zero exit status $ bash -c 'set -m; perl -e "sleep 1; exit 123"& { sleep 3; jobs -l; }' [1]+е║ Exit 123е║е║е║е║е║е║е║е║е║е║е║е║е║е║е║ perl -e "sleep 1; exit 123" ok, I see exit status