On 9/12/13 6:14 AM, Dmitry Bolshakov wrote: > Hi! > imho "jobs" should either print zero exit status or it should be > documented that "Done" means zero exit status > $ bash -c 'set -m; perl -e "sleep 1; exit 123"& { sleep 3; jobs -l; }' > [1]+е║ Exit 123е║е║е║е║е║е║е║е║е║е║е║е║е║е║е║ perl -e "sleep 1; exit 123" > ok, I see exit status > but > $ bash -c 'set -m; perl -e "sleep 1; exit 0"& { sleep 3; jobs -l; }' > [1]+е║ Doneе║е║е║е║е║е║е║е║е║е║е║е║е║е║е║е║е║е║е║ perl -e "sleep 1; exit 0" > imho "Exit 0" would be better for scripting
The format of the text isn't in the man page at all. Parsing the output of jobs is a really terrible way to figure out a job's exit status. You might try using `wait'. Chet -- ``The lyf so short, the craft so long to lerne.'' - Chaucer ``Ars longa, vita brevis'' - Hippocrates Chet Ramey, ITS, CWRU c...@case.edu http://cnswww.cns.cwru.edu/~chet/