[PHP] Passing Arrays between pages

2005-03-22 Thread PartyPosters
Hello,
Please can someone tell me how you pass arrays between PHP pages.
I have tried something like this and have tried many variations of this but
nothing working yet ;


Page 1
$testArray[0] =Apple;
$testArray[1] =Banana;
$testArray[2] =Peach;

echo "";

Page2
echo $testArray[1];


On different variations of this I keep on getting 'Array' when I to return the 
variable on the second page

Many Thanks.
Kaan.


Re: [PHP] Passing Arrays between pages

2005-03-22 Thread PartyPosters
Thanks for all your help!!!  managed it with -
$testArray = implode('|', $testArray);
On next page: $testArray = explode('|', $testArray);


- Original Message -
From: <[EMAIL PROTECTED]>
To: "PartyPosters" <[EMAIL PROTECTED]>
Cc: 
Sent: Tuesday, March 22, 2005 10:06 PM
Subject: Re: [PHP] Passing Arrays between pages


> 1. you can put your array in string using implode() function and on next
> page create the array back using explode() function.
> $testArray = implode('|', $testArray);
> #   you will get: "Apple|Banana|Peach"
> On next page: $testArray = explode('|', $testArray);
>
> 2. use serialize()/unserialize() functions
>
> For more info read manual.
>
> -afan
>
> PartyPosters wrote:
>
> >Hello,
> >Please can someone tell me how you pass arrays between PHP pages.
> >I have tried something like this and have tried many variations of this
but
> >nothing working yet ;
> >
> >
> >Page 1
> >$testArray[0] =Apple;
> >$testArray[1] =Banana;
> >$testArray[2] =Peach;
> >
> >echo "";
> >
> >Page2
> >echo $testArray[1];
> >
> >
> >On different variations of this I keep on getting 'Array' when I to
return the variable on the second page
> >
> >Many Thanks.
> >Kaan.
> >
> >
> >
>

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[PHP] Notice: Undefined offset: 3 in ..........

2005-03-22 Thread PartyPosters
Hello, 
Please could someone tell me why I am getting (Notice: Undefined offset: 3 in 
..) from using this code.


for ($i=0; $i<=3; $i++){
mysql_query("INSERT INTO shipped(userID, productID, distID, 
username,ship_company, ship_add1,ship_add2) VALUES(1, 
'$productID','$v_distIDArray[$i]', userID, 
'$v_companyArray[$i]','$v_add1Array[$i]','$v_add2Array[$i]')");
}


Thanks
Kaan

  - Original Message - 
  From: PartyPosters 
  To: php-general@lists.php.net 
  Sent: Tuesday, March 22, 2005 10:01 PM
  Subject: Passing Arrays between pages


  Hello,
  Please can someone tell me how you pass arrays between PHP pages.
  I have tried something like this and have tried many variations of this but
  nothing working yet ;


  Page 1
  $testArray[0] =Apple;
  $testArray[1] =Banana;
  $testArray[2] =Peach;

  echo "";

  Page2
  echo $testArray[1];


  On different variations of this I keep on getting 'Array' when I to return 
the variable on the second page

  Many Thanks.
  Kaan.


[PHP] Converting to a string

2005-03-23 Thread PartyPosters
Hello guys,
i am using  date("l dS of F Y h:i:s A") and want to put the value in a database 
as a string,
How do I converting it to a string, this is what I have got so far:-
$v_ship_date = date("l dS of F Y h:i:s A");


Lots of thanks.


  - Original Message - 
  From: PartyPosters 
  To: php-general@lists.php.net 
  Sent: Tuesday, March 22, 2005 10:01 PM
  Subject: Passing Arrays between pages


  Hello,
  Please can someone tell me how you pass arrays between PHP pages.
  I have tried something like this and have tried many variations of this but
  nothing working yet ;


  Page 1
  $testArray[0] =Apple;
  $testArray[1] =Banana;
  $testArray[2] =Peach;

  echo "";

  Page2
  echo $testArray[1];


  On different variations of this I keep on getting 'Array' when I to return 
the variable on the second page

  Many Thanks.
  Kaan.


Re: [PHP] Converting to a string

2005-03-23 Thread PartyPosters
Thanks guys, you were right - I needed to change the format of the field in
the database.

:D


- Original Message -
From: "Daniel Gerzo" <[EMAIL PROTECTED]>
To: "PartyPosters" <[EMAIL PROTECTED]>; 
Sent: Wednesday, March 23, 2005 8:58 PM
Subject: Re: [PHP] Converting to a string


Hello PartyPosters,

Wednesday, March 23, 2005, 9:43:30 PM, si odoslal:

> Hello guys,
> i am using  date("l dS of F Y h:i:s A") and want to put the value in a
database as a string,
> How do I converting it to a string, this is what I have got so far:-
> $v_ship_date = date("l dS of F Y h:i:s A");

  well, php doesn't really cares if you got string or bool or integer
  like c or pascal does. php is converting automatically integers to
  strings and so far, you can add your value to the database whithout
  any manual converting...

> Lots of thanks.

--
Later

+--==/\/\==--+   (__)  FreeBSD
|  DanGer <[EMAIL PROTECTED]>  |\\\'',)  The
| [EMAIL PROTECTED] ICQ261701668 |  \/  \ ^Power
|   http://danger.rulez.sk   |  .\._/_)To
+--==\/\/==--+ Serve

[ Ved evidenciu o svojich udajoch, je to dokaz tvojej prace. ]

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[PHP] Sending a Table Via mail

2005-03-23 Thread PartyPosters
Hello is there any way I can send a table (or just tabulated data) via email.
I've tried this but comes up with an error.
$to = [EMAIL PROTECTED];

$re = "Test Email from system";

$msg = "hello"


mail($to, $re, $msg);


Thanks in advance.



Re: [PHP] Sending a Table Via mail

2005-03-23 Thread PartyPosters
Great thanks! Sorry I didn't realise it was in there.

what I've got so far is the following, I want to include a variable in there
but have tried different combos but can't get it to work reading the
variable.



$to = [EMAIL PROTECTED]

# subject of message
$re = "Test Email from system";
$tablecontent = "http://www.w3.org/TR/html4/loose.dtd'>Untitled
Documenthello";
#message from the form
$msg = $tablecontent;

$message = '


  Birthday Reminders for August


  Here are the birthdays upcoming in August!
  
   
 PersonDayMonthYear
   
   
 Joe3rdAugust1970
   

"$username"


  


';



// To send HTML mail, the Content-type header must be set
$headers  = 'MIME-Version: 1.0' . "\r\n";
$headers .= 'Content-type: text/html; charset=iso-8859-1' . "\r\n";



# send the mail now
mail($to, $re, $message,$headers);
### MAIL ENDS HERE
?>



- Original Message -
From: "John Nichel" <[EMAIL PROTECTED]>
To: 
Sent: Wednesday, March 23, 2005 9:37 PM
Subject: Re: [PHP] Sending a Table Via mail


> PartyPosters wrote:
> > Hello is there any way I can send a table (or just tabulated data) via
email.
> > I've tried this but comes up with an error.
> > $to = [EMAIL PROTECTED];
> >
> > $re = "Test Email from system";
> >
> > $msg = "hello"
> >
> >
> > mail($to, $re, $msg);
>
> It's in the manual...
>
> http://us4.php.net/manual/en/function.mail.php
>
> --
> John C. Nichel
> ÜberGeek
> KegWorks.com
> 716.856.9675
> [EMAIL PROTECTED]
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>

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[PHP] Simple Alert Message then Redirect?

2005-04-07 Thread PartyPosters
Hello I want to display an alert message then after users click ok I want to 
automatically goto a URL   

if ($var_stock_count == 0){  
alert("Message")
  redirect("http://www.google.co.uk";);

}


Can someone help me put this right.

Thanks
Kaan.


Re: [PHP] Simple Alert Message then Redirect?

2005-04-07 Thread PartyPosters
Thanks for you reply.
I need to be able to test the php variable though, is the anyway I can call
the
 java funtion from my if statement?


- Original Message -
From: "Josip Dzolonga" <[EMAIL PROTECTED]>
To: "PartyPosters" <[EMAIL PROTECTED]>
Cc: 
Sent: Thursday, April 07, 2005 6:55 PM
Subject: Re: [PHP] Simple Alert Message then Redirect?


> PartyPosters wrote:
>
> >Hello I want to display an alert message then after users click ok I want
to automatically goto a URL
> >
> >if ($var_stock_count == 0){
> >alert("Message")
> >  redirect("http://www.google.co.uk";);
> >
> >}
> >
>
> This should be done with JavaScript, not PHP, so something like :
>
> 
> alert("Message");
> window.location = "<a  href="http://www.google.com"">http://www.google.com"</a>;;
> 
>
> should do the work ;-).
>
> Hope this helps,
>
> --
> Josip Dzolonga
> http://josip.dotgeek.org
>
> jdzolonga[at]gmail.com
>
>

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[PHP] php and javascript

2005-04-10 Thread PartyPosters
Hello, I have a form that when I hit sumbit I want to test the varialble in 
javascript. I can get it working using test variables in php but I want to be 
able to call the input box in my form, the only problem is the name of the box 
is in an array (i think) as it's in a list. You can see the 2 samples of the 
code below which will hopefully make more sence.

Can anyone help me out?
Thanks.



function checkdata() {
alert(document.Selection.quantity[0].value)
alert("TEST")
return true
}


---

while ($row=mysql_fetch_array($mysql_result))
{
echo "

";
}


[PHP] Simple Problem

2005-04-12 Thread PartyPosters
I can't figure out what I am doing wrong,
this sql string seems to filter out the information I want but it duplicates 
the all info, as 'num_rows' is total of rows in the table and not the correct 
value of the filtered information?

$sql="SELECT products.productID, products.title, products.number_per_box, 
products.stock_level, products.image, users.username, users.email, users.userID 
FROM users, products  WHERE products.userID = $userID";
$mysql_result=mysql_query($sql,$connection);
$num_rows=mysql_num_rows($mysql_result);


this is the old sql statement which works fine - 
$sql="SELECT productID, title, number_per_box, stock_level, image, userID FROM 
products WHERE userID = '$userID'";
$mysql_result=mysql_query($sql,$connection);
$num_rows=mysql_num_rows($mysql_result);

what I am I doing wrong.

Thanks
Kaan.




[PHP] Creating a Directory

2005-04-12 Thread PartyPosters
Hello, I am using the following script to upload files to my server. Is there 
anyway I can create a directory (on the fly) for the new image to go, as I want 
people to be able to upload files with the same name.


Thanks

$uploadDir = 'uploads/';
$uploadFile = $uploadDir . $_FILES['form_data']['name'];
print "";
if (move_uploaded_file($_FILES['form_data']['tmp_name'], $uploadFile))
{
print "File is valid, and was successfully uploaded. ";
   # print "Here's some more debugging info:\n";
#print_r($_FILES);
}
else
{
 print "File is invalid. ";
   # print "Possible file upload attack!  Here's some debugging info:\n";
 #   print_r($_FILES);
}
print "";


[PHP] Insert Chars into a string

2005-04-14 Thread PartyPosters
Hello,
I have a variable that contains a filename, I want to be able to insert the 
date and time just before for the ".jpg"
for example if my filename is 'pic.jpg' I want it to read 'pic_Monday 15th of 
January 2003 05:51:38 AM.jpg (or if anyone else knowshow to write the time and 
time all in numbers it would be appreciated as I'm using ate("l dS of F Y h:i:s 
A") which obviously is a bit long.

Many thanks.
Kaan