[PHP] Notice: Undefined offset: 3 in ..........

[PartyPosters]

Hello, 
Please could someone tell me why I am getting (Notice: Undefined offset: 3 in 
..........) from using this code.


for ($i=0; $i<=3; $i++){
mysql_query("INSERT INTO shipped(userID, productID, distID, 
username,ship_company, ship_add1,ship_add2) VALUES(1, 
'$productID','$v_distIDArray[$i]', userID, 
'$v_companyArray[$i]','$v_add1Array[$i]','$v_add2Array[$i]')");
}


Thanks
Kaan

  ----- Original Message ----- 
  From: PartyPosters 
  To: php-general@lists.php.net 
  Sent: Tuesday, March 22, 2005 10:01 PM
  Subject: Passing Arrays between pages


  Hello,
  Please can someone tell me how you pass arrays between PHP pages.
  I have tried something like this and have tried many variations of this but
  nothing working yet ;


  Page 1
  $testArray[0] =Apple;
  $testArray[1] =Banana;
  $testArray[2] =Peach;

  echo "<INPUT NAME = \"kcompany[]\" TYPE = \"hidden\" VALUE=\"$testArray\">";

  Page2
  echo $testArray[1];


  On different variations of this I keep on getting 'Array' when I to return 
the variable on the second page

  Many Thanks.
  Kaan.