multi line bash commands in a Makefile
How can i specify a multi line shell instruction as a recipe? The following returns an error: makefile27: e14: @echo var1=$(var1) makefile25: include makefile27 e12: @echo insidee12 makefile27: e13 if ( test $$count -eq 0) then echo "all: ;echo ppp" > makefile27;count=1;fi e13: ; make -f makefile25 if ( test $count -eq 0) then echo "all: ;echo ppp" > makefile27;count=1;fi /bin/sh: line 0: test: -eq: unary operator expected var1= Why it complains about needing a unary operator?
Re: multi line bash commands in a Makefile
On Sun, Apr 10, 2011 at 6:17 PM, ali hagigat wrote: > How can i specify a multi line shell instruction as a recipe? The > following returns an error: > > makefile27: > e14: >@echo var1=$(var1) > > makefile25: > include makefile27 > e12: >@echo insidee12 > makefile27: e13 >if ( test $$count -eq 0) then echo "all: ;echo ppp" > > makefile27;count=1;fi > When you test $count it's not assigned with a value yet. > e13: ; > > make -f makefile25 > if ( test $count -eq 0) then echo "all: ;echo ppp" > makefile27;count=1;fi > /bin/sh: line 0: test: -eq: unary operator expected > var1= > > Why it complains about needing a unary operator? > > -- Clark J. Wang
Re: multi line bash commands in a Makefile
Thanks Clark for the reply. 'count' is set by shell before doing make. like root> count=0 On Sun, Apr 10, 2011 at 3:10 PM, Clark J. Wang wrote: > On Sun, Apr 10, 2011 at 6:17 PM, ali hagigat wrote: >> >> How can i specify a multi line shell instruction as a recipe? The >> following returns an error: >> >> makefile27: >> e14: >> @echo var1=$(var1) >> >> makefile25: >> include makefile27 >> e12: >> @echo insidee12 >> makefile27: e13 >> if ( test $$count -eq 0) then echo "all: ;echo ppp" > >> makefile27;count=1;fi > > When you test $count it's not assigned with a value yet. > >> >> e13: ; >> >> make -f makefile25 >> if ( test $count -eq 0) then echo "all: ;echo ppp" > makefile27;count=1;fi >> /bin/sh: line 0: test: -eq: unary operator expected >> var1= >> >> Why it complains about needing a unary operator? >> > > -- > Clark J. Wang > >
Re: multi line bash commands in a Makefile
> root> count=0 > You didn't export it.
Re: multi line bash commands in a Makefile
On Sun, Apr 10, 2011 at 7:30 PM, ali hagigat wrote: > Thanks Clark for the reply. 'count' is set by shell before doing make. like > root> count=0 > > Have you exported the 'count' var before invoking make? > On Sun, Apr 10, 2011 at 3:10 PM, Clark J. Wang > wrote: > > On Sun, Apr 10, 2011 at 6:17 PM, ali hagigat > wrote: > >> > >> How can i specify a multi line shell instruction as a recipe? The > >> following returns an error: > >> > >> makefile27: > >> e14: > >>@echo var1=$(var1) > >> > >> makefile25: > >> include makefile27 > >> e12: > >>@echo insidee12 > >> makefile27: e13 > >>if ( test $$count -eq 0) then echo "all: ;echo ppp" > > >> makefile27;count=1;fi > > > > When you test $count it's not assigned with a value yet. > > > >> > >> e13: ; > >> > >> make -f makefile25 > >> if ( test $count -eq 0) then echo "all: ;echo ppp" > > makefile27;count=1;fi > >> /bin/sh: line 0: test: -eq: unary operator expected > >> var1= > >> > >> Why it complains about needing a unary operator? > >> > > > > -- > > Clark J. Wang > > > > > -- Clark J. Wang
UTF8 conversion issues in bash-4.2
I am seeing what appears to be some sort of UTF-8 conversion issue in bash-4.2. I do not see this in bash 4.1. I think the easiest way to describe this is: > bash41 --version GNU bash, version 4.1.9(2)-release (i686-pc-linux-gnu) > LC_ALL=ru_RU.UTF-8 bash41 -c привет bash: привет: command not found > bash42 --version GNU bash, version 4.2.8(2)-release (i686-pc-linux-gnu) > LC_ALL=ru_RU.UTF-8 bash42 -c привет bash: $'\320\277\321\200\320\270\320\262\320\265\321\202': команда не найдена > LC_ALL=ru_RU.KOI8-R bash42 -c привет bash: привет: ��� �� �� I'm not sure what further information is needed here, so let me know if you need anything else to replicate this. Allan
