[EMAIL PROTECTED] wrote:
nate wrote:Actually, the 172 address is a Class B. The first 16 bits are the network and the last 16 bits are the hosts.
Hello,Hello,that would be a class C - /24 or 255.255.255.0
What is the subnet-mask of IP "172.16.0.1" - "172.16.0.253" ?
How to calculate ?
since the 2nd to last number(octet) is the same, you can use
this chart as a reference:
http://portal.aphroland.org/resources/subnet/subnet.txt
nate
Thank for your help first !
How to study / learn about the file "subnet.txt"
I don't understand "netmask","aggregate","addresses" and "wild bits"....
Thank for your help more again !
Edward.
That gives you 65536 total hosts and 65534 useable hosts
The subnet mask is /16 or 255.255.0.0
-
Anthony Hologounis
"Only two things in this world are infinite. The Universe and human stupidity. And we're not even sure about the first one."
-Einstein
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