On Thursday 08 August 2002 08:59, Nick Lindsell said: > At 14:34 08/08/2002 +0200, you wrote: > > "File_21_05082002" and i would like to > > extract "21" from this. > >How can i do it with 'sed'? > > No need for sed, cut is simpler:- > $extract= echo "File_21_05082002"|cut -c 6-7
Cut is easier for this problem but I'd modify it one bit.... $extract= `echo "File_21_05082002"|cut -d_ -f2` This assumes (*cough*) that you want the value between the two "_" characters. To answer your original question..... In sed: $extract=`echo $Fname | sed -e "s/^File_//" -e "s/_[0-9]*$//"` Should come very close to what you wanted (I think...) -- redhat-list mailing list unsubscribe mailto:[EMAIL PROTECTED]?subject=unsubscribe https://listman.redhat.com/mailman/listinfo/redhat-list
