>From info gcc:
`-mcpu=CPU TYPE'
Assume the defaults for the machine type CPU TYPE when scheduling
instructions. The choices for CPU TYPE are: `i386', `i486',
`i586' (`pentium'), `pentium', `i686' (`pentiumpro') and
`pentiumpro'. While picking a specific CPU TYPE will schedule
things appropriately for that particular chip, the compiler will
not generate any code that does not run on the i386 without the
`-march=CPU TYPE' option being used.
`-march=CPU TYPE'
Generate instructions for the machine type CPU TYPE. The choices
for CPU TYPE are: `i386', `i486', `pentium', and `pentiumpro'.
Specifying `-march=CPU TYPE' implies `-mcpu=CPU TYPE'.
`-m386'
`-m486'
`-mpentium'
`-mpentiumpro'
Synonyms for -mcpu=i386, -mcpu=i486, -mcpu=pentium, and
-mcpu=pentiumpro respectively.
>From what I can tell I'd be warry of the -march option. Do lots of
testing if you use this. You may have to recompile everything on your
box using this option to get things stable.. This is what I gathered
from playing with it. Precompiled binary distributions were a problem
for me. Your mileage may vary.
----- Original Message -----
From: Jon Knews <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>; patrick <[EMAIL PROTECTED]>
Cc: <[EMAIL PROTECTED]>
Sent: Sunday, November 07, 1999 1:07 AM
Subject: Celeron and Pentium Pro / Same ???
> On Sat, 06 Nov 1999, patrick wrote:
> > >%_I have been trying to optimize the compilation
> > of a new kernel for my celeron 300a system. I am trying to get it
compiled for a
> > pentium-pro based system, NOT a 386/486 generic
> > system but it wont let me.
> >
>
> Patrick and all,
>
> I have a Celeron 500 and when I boot the system optimized for a
Pentium II
> speed computer (assume that doesn't make a diff if rpm is compiled for
i386, I
> understand). But I did previously see some sw or whatever that
basically
> saw my Celeron as a Pentium Pro also. So is that what happened to the
> Pentium Pro? It got renamed and resold as Celeron???? On what level
does
> the Pro sit, somewhere between Pentium and PII ? or somewhere
> above a PII but less than PIII ? Just out of curiousity.
>
>
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