Or for real power and flexibility, see the 'convert()' function in package tis.
Jeff Gabor Grothendieck <ggrothendi...@gmail.com> writes: > See ?aggregate.zoo, e.g. > > library(zoo) > z <- zoo(1:1000, as.Date("2000-01-01") + 0:999) > aggregate(z, as.yearmon, mean) > > or replace mean with whatever summarization you want. > > On Sun, Mar 7, 2010 at 5:29 PM, Erin Hodgess <erinm.hodg...@gmail.com> wrote: >> Dear R People: >> >> The aggregate function works very well on regular time series. >> >> Is there a version for zoo or its that would take daily data and >> convert it to monthly, please? >> -- Jeff ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.