Or for real power and flexibility, see the 'convert()' function in package
tis.

Jeff

Gabor Grothendieck <ggrothendi...@gmail.com> writes:
> See ?aggregate.zoo, e.g.
>
> library(zoo)
> z <- zoo(1:1000, as.Date("2000-01-01") + 0:999)
> aggregate(z, as.yearmon, mean)
>
> or replace mean with whatever summarization you want.
>
> On Sun, Mar 7, 2010 at 5:29 PM, Erin Hodgess <erinm.hodg...@gmail.com> wrote:
>> Dear R People:
>>
>> The aggregate function works very well on regular time series.
>>
>> Is there a version for zoo or its that would take daily data and
>> convert it to monthly, please?
>>

-- 
Jeff

______________________________________________
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.

Reply via email to