See ?aggregate.zoo, e.g. library(zoo) z <- zoo(1:1000, as.Date("2000-01-01") + 0:999) aggregate(z, as.yearmon, mean)
or replace mean with whatever summarization you want. On Sun, Mar 7, 2010 at 5:29 PM, Erin Hodgess <erinm.hodg...@gmail.com> wrote: > Dear R People: > > The aggregate function works very well on regular time series. > > Is there a version for zoo or its that would take daily data and > convert it to monthly, please? > > Thanks in advance, > Sincerely, > Erin > > -- > Erin Hodgess > Associate Professor > Department of Computer and Mathematical Sciences > University of Houston - Downtown > mailto: erinm.hodg...@gmail.com > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.