Because, data[seq_along(x)] == data[seq_along(y)],
You need this: sum(data[length(x) + seq_along(y)]) On Thu, Feb 25, 2010 at 11:02 AM, Dale Steele <dale.w.ste...@gmail.com> wrote: > I'm trying to understand the behavior of seq_along in the following example: > > x <- 1:5; sum(x) > y <- 6:10; sum(y) > > data <- c(x,y) > S <- sum( data[seq_along(x)] ) > S > T <- sum( data[seq_along(y)] ) > T > > Why is T != sum(y) ? > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > -- Henrique Dallazuanna Curitiba-Paraná-Brasil 25° 25' 40" S 49° 16' 22" O ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
