Dale Steele wrote: > > > x <- 1:5; sum(x) > y <- 6:10; sum(y) > > data <- c(x,y) > S <- sum( data[seq_along(x)] ) > S > T <- sum( data[seq_along(y)] ) > T > >
If in doubt, divide and conquer: seq_along(x) [1] 1 2 3 4 5 > seq_along(y) [1] 1 2 3 4 5 You expected that the second vector is 6,7... Dieter -- View this message in context: http://n4.nabble.com/behavior-of-seq-along-tp1569033p1569049.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
