rrookie1982 wrote: > > I want to write a formula of the type > > http://n4.nabble.com/file/n1016112/expression.gif > > into my plot, where the values 1.234 and -0.567 should origin from > variables in the program. >
Uwe Ligges-3 wrote: > > It is much easier, just write the formula down in R syntax and > substitute the relevant variables as in: > > text(0, 7.5, substitute(tau(A) == a*lg(A^b), list(a=1.234, b=-0.567))) > Gabor Grothendieck wrote: > > Try bquote: > > a <- 0.1; b <- 0.2 > plot(0, main = bquote(tau(A) == .(a)*lg(A^.(b)))) > Wow, those two examples are indeed much simpler than my tries and work just fine. Now I just will have two choose which way to go: > suba <- 1.234; subb <- -0.567 > text(0, 5,substitute(tau(A) == a*lg(A^b), list(a=suba, b=subb)),pos=4) ## > and > text(0, 5,bquote(tau(A) == .(suba)*lg(A^.(subb))),pos=4) both work exactly how I wanted them to do. Thank you Uwe and Gabor -- View this message in context: http://n4.nabble.com/plotting-Formulas-with-greek-letters-and-variable-values-expression-substitute-paste-tp1016112p1016416.html Sent from the R help mailing list archive at Nabble.com. ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
