Try bquote: a <- 0.1; b <- 0.2 plot(0, main = bquote(tau(A) == .(a)*lg(A^.(b))))
On Sun, Jan 17, 2010 at 12:47 PM, rrookie1982 <dess...@uni-bonn.de> wrote: > > Hallo together, > > I want to write a formula of the type > > http://n4.nabble.com/file/n1016112/expression.gif > > > > > > > > into my plot, where the values 1.234 and -0.567 should origin from variables > in the program. The threads in this forum gave me some ideas that the > functions expression(), paste(), and substitute() will get me there but I > just cannot figure out how to do it. The closest I got is: > > text(0,7.5,substitute(expression(paste(symbol("t"),"(A) = ",c1 + > lg(A^c2),sep="")),list(c1=0,456,c2=-0.123)),pos=4) > > Thankful for any suggestions! > Daniel > -- > View this message in context: > http://n4.nabble.com/plotting-Formulas-with-greek-letters-and-variable-values-expression-substitute-paste-tp1016112p1016112.html > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
