Try: mapply(..., SIMPLIFY = FALSE) On Mon, Oct 12, 2009 at 5:25 PM, Magnus Torfason <zulutime....@gmail.com> wrote: > I have a list of isometric structures, and I want to change the same part of > each structure in the list, assigning one element of a vector to each of > these parts. > > In other words, I want to achieve the following: > >> l <- list( list(a=1,b=2), list(a=3,b=4)) >> unlist(lapply(l, "[[", "a")) > [1] 1 3 >> >> # This will not actually work >> l[[]]["a"] <- 5:6 >> >> unlist(lapply(l, "[[", "a")) > [1] 5 6 > > I figure mapply is the solution to the problem, and I tried the following: > >> mapply( "[<-", l, "a", 5:6) > > But the result is not the same shape as the original. > > Any thoughts? > > Best, > Magnus > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >
______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
